On Thu, Aug 21, 2008 at 5:11 PM, William Stein <[EMAIL PROTECTED]> wrote:
> On Thu, Aug 21, 2008 at 8:09 AM, William Stein <[EMAIL PROTECTED]> wrote:
>> On Thu, Aug 21, 2008 at 4:44 AM, Andelf <[EMAIL PROTECTED]> wrote:
>>> I am a starter, so I don't understand why this goes wrong
>>>
>>> I typed:
On Thu, Aug 21, 2008 at 11:11 PM, William Stein <[EMAIL PROTECTED]> wrote:
>
> On Thu, Aug 21, 2008 at 8:09 AM, William Stein <[EMAIL PROTECTED]> wrote:
> > On Thu, Aug 21, 2008 at 4:44 AM, Andelf <[EMAIL PROTECTED]> wrote:
> >> I am a starter, so I don't understand why this goes wrong
> >>
> >> I
On Aug 21, 7:44 am, Andelf <[EMAIL PROTECTED]> wrote:
> I am a starter, so I don't understand why this goes wrong
>
> I typed:
>
> x = var('x')
> f = log(2+sqrt(arctan(x)*sin(1/x)))
> lim(f, x=0)
>
> and got:
> Traceback (click to the left for traceback)
> ...
> Is sin(1/x)*atan(x) positive or zer
On Aug 21, 9:09 am, "William Stein" <[EMAIL PROTECTED]> wrote:
> Use the assume command, as illustrated below. You'll eventually get log(2):
Looks like this is fixed in more recent versions of Maxima.
With current 5.16.2:
limit (log (2 + sqrt (atan (x) * sin (1/x))), x, 0);
=> log(2)
(No que
On Thu, Aug 21, 2008 at 8:09 AM, William Stein <[EMAIL PROTECTED]> wrote:
> On Thu, Aug 21, 2008 at 4:44 AM, Andelf <[EMAIL PROTECTED]> wrote:
>> I am a starter, so I don't understand why this goes wrong
>>
>> I typed:
>>
>> x = var('x')
>> f = log(2+sqrt(arctan(x)*sin(1/x)))
>> lim(f, x=0)
>>
>>
On Thu, Aug 21, 2008 at 4:44 AM, Andelf <[EMAIL PROTECTED]> wrote:
> I am a starter, so I don't understand why this goes wrong
>
> I typed:
>
> x = var('x')
> f = log(2+sqrt(arctan(x)*sin(1/x)))
> lim(f, x=0)
>
> and got:
> Traceback (click to the left for traceback)
> ...
> Is sin(1/x)*atan(x) po
