On 14 Gru, 04:36, Dan Drake wrote:
> On Tue, 13 Dec 2011 at 06:38PM -0800, kcrisman wrote:
> > > Proposed bugfix: symbolic integration should reject floats.
>
> > Yikes! So we wouldn't want
>
> > sage: integrate(1.0*x,x,0,2)
> > 2
>
> > to work any more? (Pace the error messages below.)
>
> >
On Dec 13, 8:27 pm, Nils Bruin wrote:
> On Dec 13, 11:07 am, kcrisman wrote:
>
> > Yes, we try to turn it off as much as possible -
> > seehttp://hg.sagemath.org/sage-main/file/9e29a3d84c48/sage/interfaces/ma...
> > and the keepfloat:true. What an unhelpful error message, then!
>
> I think th
On Dec 13, 3:48 pm, kcrisman wrote:
> On Dec 12, 10:11 pm, Dan Drake wrote:
>
>
>
> > I'm doing some integrals:
>
> > sage: a, b, t = var('a b t')
> > sage: f(a,b,t) = sin(t)^2/(a + b*cos(t))^2
> > sage: integrate(f(3/2,1,t), (t,0,2*pi))
> > -2/5*(sqrt(5) - 3)*pi*sqrt(5)
>
> > Okay, that's fine
Maybe the following workaround attempt
will be helpful?
var('x,mp,me')
eq=mp-sqrt(x^2+me^2)==x
assume(mp>0)
solve(eq^2,x)
[x == 1/2*(me^2 - mp^2)/mp, x == -1/2*(me^2 - mp^2)/mp]
On 15 Maj, 01:34, Dox wrote:
> Hi again list,
>
> This time I come with a problem of solving an algebraic expression
With precision(1) also works
Sage 4.6.2 64bit Fedora13 Dell Vostro1720
On 18 Kwi, 20:17, achrzesz wrote:
> After replacing precision(1) by precision(53) it works for me
>
> On 18 Kwi, 17:36, Jeroen Demeyer wrote:
>
> > Executing the following "not tested" doct
After replacing precision(1) by precision(53) it works for me
On 18 Kwi, 17:36, Jeroen Demeyer wrote:
> Executing the following "not tested" doctest from
> sage/interfaces/maxima.py gives trouble, anybody has a clue what is
> going wrong?
> I doesn't work neither on sage-4.6.2 nor on sage-4.7.alp
Continuing my example:
sage: maxima(f).powerseries('r',infinity)
-4*r*'sum((2^(2*i3-1)-1)*2^(2*i3-1)*bern(2*i3)*r^(2*i3-1)/
(2*i3)!,i3,0,inf)
(NOT CHECKED)
A Ch
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sage: var('r');
sage: f=2*r/sinh(2*r)
sage: f.taylor(r,0,5)
14/45*r^4 - 2/3*r^2 + 1
sage: maxima(f).powerseries('r',0)
-4*r*'sum((2^(2*i2-1)-1)*2^(2*i2-1)*bern(2*i2)*r^(2*i2-1)/
(2*i2)!,i2,0,inf)
Andrzej Chrzeszczyk
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sage: import scipy.integrate
sage: scipy.integrate.quad(lambda x:log(1+x)/(x^2+1),0,1)
(0.27219826128795022, 3.0220077694481673e-15)
A Ch
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On 16 Lut, 18:54, Marshall Buck wrote:
> In the Putnam solutions by Manjul Bhargava, Kiran Kedlaya, et al, it is
> observed that the definite integral
>
> integrate(log(1+x)/(x^2+1),(x,0,1))
>
> can be evaluated successfully by mathematica. This is true, and the answer
> is log(2)*pi/8
> sag
sage: s=solve(3*x^3-9*x+10==0,x,solution_dict=True)
sage: [n(t[x]) for t in s]
[1.06780542232902 - 1.84949324407141*I, #
0.0277635108030695 + 1.24902476648341*I, # WRONG!
-1.09556893313209 + 0.600468477588001*I]#
sage: s=solve(3*x^3-9*x
+10==0,x,solution_dict=True,to_poly_solve='forc
Hello
Can I ignore the SeLinux alert which I obtain from time to time
starting sage 4.2.1 compiled from sources in Fedora 12 on QuadCore
2.4GHz, 4GB RAM
Podsumowanie: (Summary:)
SELinux is preventing /home/andy/Pobrane/sage-4.2.1/local/bin/python
from making the program stack executable.
Szczegó
In the present example all data are exact and the results is OK
In the previous example you have mixed symbolic and numerical data
(0.1) and that was risky
Andrzej
On 5 Mar, 23:59, David Harvey <[EMAIL PROTECTED]> wrote:
> Begin forwarded message:
>
>
>
> > From: Andrzej Chrzęszczyk <[EMAIL PROTE
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