Hey all,
I ran into a problem saving a graph to postscript recently. Here's what I
did:
plot.options['plot_division'] = 4
plot.options['plot_points'] = 2
P=plot(sin(5/(x)), x,0,1)
P.save('filename.eps', xmin = -.25, xmax = 1)
Attempting to open the resulting file on my MacBook Pro with e
On Jul 10, 2007, at 3:12 PM, William Stein wrote:
> On 7/10/07, Justin C. Walker <[EMAIL PROTECTED]> wrote:
>> On Jul 10, 2007, at 2:45 PM, Robert Bradshaw wrote:
[snip]
>>> If you are writing an method that goes through each (or many)
>>> entries
>>> of a matrix, it is the thing to use if you
Wrapping up this, for the record, from a couple of weeks back:
On Jun 29, 2007, at 12:48 AM, Robert Bradshaw wrote:
> As other people have mentioned, there's a factor of 2 overhead in the
> first loop. I'm not sure why you're indexing from 1 either.
Thanks for the comments...
Indeed, I managed
And to me please!!
On 7/13/07, William Stein <[EMAIL PROTECTED]> wrote:
>
> On 7/13/07, William Stein <[EMAIL PROTECTED]> wrote:
> > > I was writing a function to calculate the structure of cuspidal subgroup
> > > of
> > > J_0(N) without using modular symbols. I came across the following puzzli
On 7/13/07, William Stein <[EMAIL PROTECTED]> wrote:
> > I was writing a function to calculate the structure of cuspidal subgroup of
> > J_0(N) without using modular symbols. I came across the following puzzling
How are you doing that? I didn't know there was an algorithm to compute
the structur
Soroosh Yazdani wrote:
> Hi,
>
> I was writing a function to calculate the structure of cuspidal subgroup
> of J_0(N) without using modular symbols. I came across the following
> puzzling bug. Here is a procedure which produces a matrix
> def generate_cond5(l,r):
> M=Matrix(QQ,l,r)
> fo
On 7/13/07, Soroosh Yazdani <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I was writing a function to calculate the structure of cuspidal subgroup of
> J_0(N) without using modular symbols. I came across the following puzzling
> bug. Here is a procedure which produces a matrix
> def generate_cond5(l,r):
>
Hi,
I was writing a function to calculate the structure of cuspidal subgroup of
J_0(N) without using modular symbols. I came across the following puzzling
bug. Here is a procedure which produces a matrix
def generate_cond5(l,r):
M=Matrix(QQ,l,r)
for j in range(l):
divpoint=2**j
