Re: Capturing output

2003-03-04 Thread Patrick Strasser
Tom Freeman wrote: Hi folks, I am running rsync via a perl script run in a cronjob. my $message = `/usr/bin/rsync --rsh=/usr/local/openssh/bin/ssh -avu $directory $destination`; I want to be able to write this data to a log file, so that if things don't work, I can find out what's wrong. Is this a

Re: Capturing output

2003-03-04 Thread Aaron W Morris
It may be helpful to capture STDERR with STDOUT. my $message = `/usr/bin/rsync --rsh=/usr/local/openssh/bin/ssh -avu $directory $destination 2>&1`; See: http://perldoc.com/perl5.8.0/pod/perlop.html#%60STRING%60 At 05:47 PM 3/4/2003 +, you wrote: Hi folks, I am running rsync via a perl scri

Re: Capturing output

2003-03-04 Thread Max Bowsher
Tom Freeman wrote: > Hi folks, > I am running rsync via a perl script run in a cronjob. > > Here's the command i'm running > > my $message = `/usr/bin/rsync --rsh=/usr/local/openssh/bin/ssh -avu > $directory $destination`; > > At the moment when I run the script it writes all output to the > scr

Capturing output

2003-03-04 Thread Tom Freeman
Hi folks, I am running rsync via a perl script run in a cronjob. Here's the command i'm running my $message = `/usr/bin/rsync --rsh=/usr/local/openssh/bin/ssh -avu $directory $destination`; At the moment when I run the script it writes all output to the screen. I want to be able to write this da