Re: [Rpy] Result rpy2.rinterface.SexpVector

2010-10-04 Thread BB
I realized I can have R seperate out the result. So I have robjects.r('M0 = lmer (y ~ 1 + (1 | county))') res = robjects.r('coef(M0)') coef function returns the detailed result. From this print res.rclass print res.r_repr() I get structure(list(county = structure(list("(Intercept)" = c(1

Re: [Rpy] Result rpy2.rinterface.SexpVector

2010-10-04 Thread BB
Also I do print res.r_repr(), I get -- Virtualization is moving to the mainstream and overtaking non-virtualized environment for deploying applications. Does it make network security easier or more difficult to achi

[Rpy] Result rpy2.rinterface.SexpVector

2010-10-04 Thread BB
I was able to call lmer using this: robjects.r.assign('y',y) robjects.r.assign('x',x) robjects.r.assign('county',county) res = robjects.r('lmer (y ~ 1 + (1 | county))') Printing res displays a nice summary. But I need all the information in the result object, res.rclass displays rpy2.rinter

Re: [Rpy] Can't get rpy2 to work with new version of R

2010-10-04 Thread Laurent Gautier
There might be a more serious issue. Your traceback refers to an older (and unstable) version of rpy2: """ Referenced from: /Users/davidrobinson/.python-eggs/rpy2-2.1.0alpha2dev_20100129-py2.6-macosx-10.3-fat.egg-tmp/rpy2/rinterface/rinterface.so """ Did you follow the recommendations when upgra