Thanks to all.
The previous examples included a couple of extra "" causing the str error.
This works fine now.
Would you consider adding this to the documentation?
I find the documentation/wiki coverage a bit short. These examples help
a lot.
Quoting Laurent Gautier on 06/11/2008 05:57 PM:
> i
import rpy
foo = rpy.r.list(a=1, b=2, c=3)
rpy.r["names"](foo)
tmp = rpy.r["names<-"](foo, ['d', 'e', 'f'])
rpy.r.str(tmp)
List of 3
$ d: int 1
$ e: int 3
$ f: int 2
2008/6/11 Renato Alves <[EMAIL PROTECTED]>:
> Still can't get it to work... Am I missing something?
>
> b <- r("'rownames<-'"
Grr. I need to slow down a bit. Lets see... I just tried this and it works
properly:
from rpy import *
set_default_mode(NO_CONVERSION)
x = r.matrix( r.rnorm(100), nrow=5 )
x = r.get("rownames<-")(x, ['a','b','c','d','e'] )
r.print_(x)
A similar trick can be used for column
On Jun 11, 2008, at 10:45 AM, Renato Alves wrote:
> Still can't get it to work... Am I missing something?
>
> b <- r("'rownames<-'")(b, a)
> TypeError: 'str' object is not callable
I think you were right before -- in Python, that should be:
b = r("'rownames<-'")(b, a)
etc. The "<-" syn
Still can't get it to work... Am I missing something?
b <- r("'rownames<-'")(b, a)
TypeError: 'str' object is not callable
I'm with RPy version 1.0.3 [R version 2.7.0 (2008-04-22)]
Quoting Warnes, Gregory on 06/11/2008 05:34 PM:
> Sorry, I gave you the wrong magic
>
> x <- r("'rownames<-'")(x, f
Sorry, I gave you the wrong magic
x <- r("'rownames<-'")(x, foo)
-G
On 6/11/08 12:01PM , "Renato Alves" <[EMAIL PROTECTED]> wrote:
> Hi Gregory,
>
> I've been trying to understand how to do the equivalent with the
> colnames function... without much success.
>
> I haven't been able to use yo
Hi Gregory,
I've been trying to understand how to do the equivalent with the
colnames function... without much success.
I haven't been able to use your suggestion. I always get the error:
unexpected '[' in "["
Apart from this, is <- valid python syntax? Or did you meant to say = ?
An example
Hi Gregory,
Changing that to mod instead of r(mod) results in the following error
Traceback (most recent call last):
File "C:\Documents and Settings\Administrator\Desktop\pls\pls.py",
line 40, in
predicted=r.predict(mod, type='response', ncomp = 10, newdata = accFAS )
RPy_RException: Erro
