[Rpy] Rpy handling kmeans

2008-02-22 Thread Ding Zhou
Hi, I was trying get the rpy to work but was stuck. Would you help us with these simple rpy commands? I did the following: python from rpy import r x = r.matrix(r.rnorm(100), 50, 2) r.kmeans(x, 2) The error was: Traceback (most recent call last): File "", line 1, in ? rpy.RException: Erro

Re: [Rpy] r.predict()

2008-02-22 Thread Gregory Warnes
The basic problem is that by default, RPy converts objects returned to python to a python object. Unfortunately, this conversion loses some information, including the type of the original R object. To avoid this conversion add two lines to your code: On Feb 22, 2008, at 12:36PM , marco hof

Re: [Rpy] r.predict()

2008-02-22 Thread Sean Davis
On Fri, Feb 22, 2008 at 12:36 PM, marco hofmann <[EMAIL PROTECTED]> wrote: > Hi all, > I have a problem with the predict command. Here is an example: > > from rpy import * > r.library("nnet") > model = r("Fxy~x+y") > > df = r.data_frame(x = r.c(0,2,5,10,15) >,y = r.c(0,2,5,

[Rpy] r.predict()

2008-02-22 Thread marco hofmann
Hi all, I have a problem with the predict command. Here is an example: from rpy import * r.library("nnet") model = r("Fxy~x+y") df = r.data_frame(x = r.c(0,2,5,10,15) ,y = r.c(0,2,5,8,10) ,Fxy = r.c(0,2,5,8,10)) NNModel = r.nnet(model, data = df