You are confusing 'segmentation fault' with 'accessing memory not
(yet) allocated'. A program has certain space allocated to it by
the OS. To use this memory in an organized manner, you use (m)alloc.
So in your program you are accessing your memory only, and that is
why no seg-fault(and hence no c
Hi
During the processing of compiling the kernel and getting it running, I
observed that my kernel not only contains software for my current hardware
configuration, but also for other hardware as well.(both in the kernel and
as modules). and during bootup, the kernel identifies the hardware and
e
pls ignore.
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