Yes, lambda expression have an implicit begin in the body.
> (begin . (1 2 3))
3
> (begin (1 2 3))
application: not a procedure;
expected a procedure that can be applied to arguments
given: 1
arguments...:
Here (begin . (1 2 3)) is the same as (begin 1 2 3).
The doc
Does that mean that lambda expressions have an implicit (begin …) block in them?
(begin ((displayln 1) (displayln 2) (displayln 3))) leads to an error
(begin . ((displayln 1) (displayln 2) (displayln 3))) displays to 1 2 3
Thank you for the detailed explanation I think I get it now.
> On 13 Mar
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