>
>
> From: Neil Van Dyke [mailto:n...@neilvandyke.org]
> Sent: 19 July 2010 00:22
> To: Jos Koot
> Cc: 'plt-scheme'
> Subject: Re: [racket] hash-ref
>
> Jos Koot wrote at 07/18/2010 09:26 AM:
>
> (hash-ref a-hash a-ke
loop ((...))
...
(hash-ref! hash key default)
...)
I am pretty sure that in this case the identity function is constructed once
only.
Jos
_
From: Neil Van Dyke [mailto:n...@neilvandyke.org]
Sent: 19 July 2010 00:22
To: Jos Koot
Cc: 'plt-scheme'
Subject: Re: [racket] hash-ref
Jos K
Jos Koot wrote at 07/18/2010 09:26 AM:
(hash-ref a-hash a-key a-value)
In the past a-value was required to be a procedure.
Now it can be anything.
[...]
In short, I do not well understand the reason to relax the contract of
hash-ref and hash-ref!.
This behavior seems a little on the uncomfo
Robby and Matthew,
Thanks, I understand, I think.
Jos
_
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At Sun, 18 Jul 2010 22:55:44 +0200, "Jos Koot" wrote:
> Now consider:
>
> (let ((var ...))
> ...
> (hash-ref hash key (lambda () var))
>
> Do I understand well that this thunk is not cq cannot be compiled to a
> constant?
Correct.
> When compiling the thunk, the location of var relative to th
ack is known, is it not?
> Thanks,
> Jos
>
>> -Original Message-
>> From: Matthew Flatt [mailto:mfl...@cs.utah.edu]
>> Sent: 18 July 2010 22:43
>> To: Jos Koot
>> Cc: 'Robby Findler'; 'plt-scheme'
>> Subject: Re: [racket] hash-ref
>&g
age-
> From: Matthew Flatt [mailto:mfl...@cs.utah.edu]
> Sent: 18 July 2010 22:43
> To: Jos Koot
> Cc: 'Robby Findler'; 'plt-scheme'
> Subject: Re: [racket] hash-ref
>
> Actually, you're right. A `lambda' form like
>
> (lambda () #f)
>
om] On Behalf Of Robby Findler
> > Sent: 18 July 2010 15:39
> > To: Jos Koot
> > Cc: plt-scheme
> > Subject: Re: [racket] hash-ref
> >
> > It is for performance reasons. Specifically you can avoid
> > creating the procedure ove
Of Robby Findler
> Sent: 18 July 2010 15:39
> To: Jos Koot
> Cc: plt-scheme
> Subject: Re: [racket] hash-ref
>
> It is for performance reasons. Specifically you can avoid
> creating the procedure over and over (if you're calling
> hash-ref over and over).
>
> R
It is for performance reasons. Specifically you can avoid creating the
procedure over and over (if you're calling hash-ref over and over).
Robby
On Sunday, July 18, 2010, Jos Koot wrote:
>
>
>
>
>
> (hash-ref
> a-hash a-key a-value)
> In the past
> a-value was required to be a procedure.
> Now i
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