Cc: users@racket-lang.org
Subject: Re: [racket] novice question about expressions
(/ (+ (* n 2) 300) (* 13 n))
On Fri, Jan 11, 2013 at 8:08 PM, Jamel Hamani wrote:
(n*2+ 300) / (13n)
--
Grant Rettke | ACM, AMA, COG, IEEE
gret...@acm.org | http://www.wisdomandwonder.com/
Wisdom begins
On Jan 11, 2013, at 9:08 PM, Jamel Hamani wrote:
> how do I formulate this expression in racket?
>
> (n*2+ 300) / (13n)
>
> I got the first part done
>
> (define (f n)
> ( + ( * n n ) 300))
That already looks odd. When you write "n*2", do you mean n times 2, or n
raised to the power of 2
(/ (+ (* n 2) 300) (* 13 n))
On Fri, Jan 11, 2013 at 8:08 PM, Jamel Hamani wrote:
> (n*2+ 300) / (13n)
--
Grant Rettke | ACM, AMA, COG, IEEE
gret...@acm.org | http://www.wisdomandwonder.com/
Wisdom begins in wonder.
((λ (x) (x x)) (λ (x) (x x)))
Racket Users list:
how do I formulate this expression in racket?
(n*2+ 300) / (13n)
I got the first part done
(define (f n)
( + ( * n n ) 300))
So lets say I pick 5.
(f 5) would give me 325.
But how would I do the second part- dividing it by (13n)?
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