Good.
On Sep 15, 2014, at 9:20 AM, Daniel Bastos wrote:
> On Fri, Sep 12, 2014 at 6:43 PM,
> Matthias Felleisen wrote:
>
>
> On Sep 12, 2014, at 4:40 PM, Daniel Bastos wrote:
>
> > Again, we start with (2) and apply a series of substitutions.
> >
> > (f f)
> > = ( ) ;; since f is
On Fri, Sep 12, 2014 at 6:43 PM,
Matthias Felleisen wrote:
> On Sep 12, 2014, at 4:40 PM, Daniel Bastos wrote:
>
> > Again, we start with (2) and apply a series of substitutions.
> >
> > (f f)
> > = ( ) ;; since f is a
> > = ( ) ;; since is a subset of
> >
> > However, ( ) is not by
On Sep 12, 2014, at 4:40 PM, Daniel Bastos wrote:
> Again, we start with (2) and apply a series of substitutions.
>
> (f f)
> = ( ) ;; since f is a
> = ( ) ;; since is a subset of
>
> However, ( ) is not by definition a value. It is an
> expression which may or may not /have/ a val
On Mon, Sep 8, 2014 at 9:51 PM,
Matthias Felleisen wrote:
On Sep 2, 2014, at 11:45 AM, Daniel Bastos wrote:
>
> > A candidate for a solution.
> >
> > Exercise 20.1.1. Assume the Definitions window in DrScheme contains
> > (define (f x) x). Identify the values among the following expressions:
> >
On Sep 2, 2014, at 11:45 AM, Daniel Bastos wrote:
> A candidate for a solution.
>
> Exercise 20.1.1. Assume the Definitions window in DrScheme contains
> (define (f x) x). Identify the values among the following expressions:
>
> (1) (cons f empty)
> (2) (f f)
> (3) (cons f (cons 10 (cons (f 10)
A candidate for a solution.
Exercise 20.1.1. Assume the Definitions window in DrScheme contains
(define (f x) x). Identify the values among the following expressions:
(1) (cons f empty)
(2) (f f)
(3) (cons f (cons 10 (cons (f 10) empty)))
Explain why they are values and why the remaining express
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