Hi,
I was wondering about current status of Moby. Is it still active? How
stable? What is and is not yet supported?
Thanks.
--
Talk to you soon,
Scott Klarenbach
PointyHat Software Corp.
www.pointyhat.ca
p 604-568-4280
e sc...@pointyhat.ca
#308 - 55 Water St.
Vancouver, BC V6B1A1
I've started going through "A Little Java a Few Patterns" to learn
some basic OOP techniques and patterns but I've been using Racket
instead of Java (I don't know Java so I'd prefer to stick with
Racket). Is it possible to use Typed Racket instead of Racket with
classes and objects, so I can put
How is this:
#lang racket
(define graph%
(class object%
(field ((n nodes) '()))
(public (get get-fields))
(define/public (all) (get))
(define (get) n)
(super-new)))
(define graph (new graph%))
(define fields (get-field nodes graph))
(equal? (send graph get-fields) fiel
Assuming Jamel does a self study.
I think Jamel ment (/ (+ (* n n) 300) (* 13 n)).
Grant, with your definition:
(define (f n) ( + ( * n 2 ) 300))
(f 5) -> 310
As Jamel is expecting 325, I assume n*2 is ment as an exponentiation.
There are many ways to write this down, for example:
(define (f n
On Jan 11, 2013, at 9:08 PM, Jamel Hamani wrote:
> how do I formulate this expression in racket?
>
> (n*2+ 300) / (13n)
>
> I got the first part done
>
> (define (f n)
> ( + ( * n n ) 300))
That already looks odd. When you write "n*2", do you mean n times 2, or n
raised to the power of 2
The Racket reference says:
5.2.3.3 Internal and External Names
Each method declared with public, override, augment, pubment,
overment, augride, public-final, override-final, augment-final,
inherit, inherit/super, inherit/inner, rename-super, and rename-inner
can have separate internal and external
(/ (+ (* n 2) 300) (* 13 n))
On Fri, Jan 11, 2013 at 8:08 PM, Jamel Hamani wrote:
> (n*2+ 300) / (13n)
--
Grant Rettke | ACM, AMA, COG, IEEE
gret...@acm.org | http://www.wisdomandwonder.com/
Wisdom begins in wonder.
((λ (x) (x x)) (λ (x) (x x)))
Racket Users list:
how do I formulate this expression in racket?
(n*2+ 300) / (13n)
I got the first part done
(define (f n)
( + ( * n n ) 300))
So lets say I pick 5.
(f 5) would give me 325.
But how would I do the second part- dividing it by (13n)?
Racket Users list:
http://lists.racke
On 2013-01-09 14:49:34 +0200, Răzvan Rotaru wrote:
>[2]http://planet.racket-lang.org/trac/ticket/385
>Is there a way to push the fix back into the repository (other than
>emailing the owner)?
I think the only way to upload new versions of a package onto PLaneT is
to be the package owne
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