9 90 91 92 93 94 95 96 97 98 S Z
Thanks,
Raz
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PLEASE do read
r (j in 6:144){
if (AX[i,j]==1 & AX[i+1,j]==0){
AX[i,j]<-'A'
}
if (AX[i,j]==0 & AX[i+1,j]==1){
AX[i,j]<-'B'
}
if (AX[i,j]==1 & AX[i+1,j]==1){
AX[i,j]<-'HT'
}
if (AX[i,j]==1 & AX[i+1,j]=="-"){
AX[i,j]<-'Aht'
}
if (AX[i,
be substituted according to their unique values e.g "A1"
will be "1", "A2" will be "2" and so on (this is only a part of a large
table). It would be better if I could change all unique values in dat1 to
numbers 1:unique(n). if not then how do I change all
that dont fit, any ideas?
Thanks,
Raz
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PLEASE do read the posting guide http://www.R
Hello,
I'm trying to add a symbol (Delta) to plot legend with text using
"expression(paste())" but this disables the text.font that allows to use
bold or italic text.
as follows:
x=c(1:10)
y=c(1:10)
plot(x,y)
legend(1,10,legend=c("A","B","C",expression(paste(Delta, D))),
pch=c(24,18,17,16),
Hello,
I have a data frame with the following columns: "date","name","value"
the name is the same for each date
I would like to get TukeyHSD p-value for the differences of "value" between
"name"s in each "date" separately I tried different ANOVA (aov()) but can
only get either tukey by "name" or b
Hey,
I have this TukeyHSD output from which I would like to extract only the
P-values (p adj, last number).
The problem is that the test output is a character list.
How can I "break" this sentence to separate the Pv?
Tukey multiple comparisons of means
95% family-wise confidence level
Fit:
Hi,
I would like to compare row data in the same column through a data frame
and remove all rows that do not fit the criteria.
for example if I have the following data frame:
line start A1 21 A2 22 A3 23 B4 19 B2 24 B6 12
I would like to compare the 'start' value of each line to the value
How can I condition any error bar function that use the arrows() function,
such as 'CI.plot' (see example below) or 'error.bars', to draw only upper
error bar (upper CI) if the bar value (mean) is positive and the lower
error bar (lower CI) if bar value is negative?
CI.plot <- function(mean, se,le
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