I hope someone can point me in the right direction please.
I have a data frame with a column containing names. I want to identify the
columns that contain names in a list.
namestofind <- c('fred','bill',a long list)
If I only wanted to identify a single name I would use
which(z$name == 'bi
I am doing calculations in a loop and then plotting the results by adding a
point to each of 2 charts at the end of the loop. Its very informative as
you can see the progression through time.
My problem is, if I have 2 plots, I don't know how to get the focus back to
the first plot.
layout(matri
Thanks Henrique, that appeared to work, but now I have another issue.
If I add a ylim to the plot then when I plot another line it gets plotted on
the wrong scale.
#this works as expected
plot(iris[,1],col="red",ylim=c(-10,10)) #plot1
lines(iris[,4],col="black")
#this does not
par(mfrow=c(2,1
Does there exist a site where snippets of r code examples can be deposited,
such as the one that exists for matlab?
http://www.mathworks.com/matlabcentral/fileexchange/
ps
I also noted from the main r site
http://www.r-project.org/
when you click on the nabble link under the search link, I end
rection as to how I can automatically purge
my data file of these useless fields.
Thanks in advance,
pdb
train <- read.csv("TrainingData.csv")
library(gbm)
i.gbm<-gbm(TargetVariable ~ . ,data=train,distribution="bernoulli.
1: In gbm.fit(x, y, offset = offs
in advance,
pdb
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Yep - that is what I want.
Cheers Jim you Legend.
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Awsome!
It made sense once I realised SD=standard deviation !
pdb
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R
Hi,
I want to repeatedly do a task, so thought I could put it in a function and
then just call the function.
The task is just clearing all the graphics devices and then opening a new
one of a specified size.
Now, when I call the function below, nothing appears to happen. But when I
run the 2 lin
as, silly me.
clearG()
this now works!
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I'm confused, hope someone can point out what is not obvious to me.
I thought I was creating a new data frame by 'deleting' rows from an
existing dataframe - I've tried 2 methods.
But this new data frame seems to remember values from its parent - even
though there are no occurences.
Where doe
Thanks, but that was what I just discovered myself the hard way.
What I really wanted to know was how to solve this issue.
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There seems to be 2 functions call ecdf...
http://lib.stat.cmu.edu/S/Harrell/help/Hmisc/html/ecdf.html
http://127.0.0.1:11885/library/stats/html/ecdf.html
How do I get the one ecdf {Hmisc} to run instead of the ecdf {stats}
A pointer in the right direction would be greatly appreciated.
Trie
Thanks for the quick response, but that doesn't seem to help
What do I need to do to get it to work?
> Hmisc:::ecdf(...)
Error in get(name, envir = asNamespace(pkg), inherits = FALSE) :
object 'ecdf' not found
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I've just tried to merge 2 data sets thinking they would only keep the common
columns, but noticed the column count was not adding up. I've then
replicated a simple example and got the same thing happening.
q1. why doesn't 'b' have a column name?
q2. when I merge, why does the new column 'y' hav
I have 2 data frames (A & B) with some common column names.
A has 10 rows.
B has 20 rows.
How do I combine them so I end up with a data frame with 30 rows that only
contains the common columns.
I was trying 'merge' (Merge two data frames by common columns .etc. )
but that is not giving me w
Thanks Dennis - easy when you know how !
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Hi,
I'm struggling to understand the documentation.
?lag.zoo
x - a "zoo" object.
k, lag - the number of lags (in units of observations). Note the sign of k
behaves as in lag.
differences - an integer indicating the order of the difference.
What does the above line actually mean? I've trie
Thanks for the response.
I can figure out the 'lag' parameter to the function, but I dont understand
the 'differences' parameter.
differences - an integer indicating the order of the difference
What does the 'order of the difference' mean in English?
How are these numbers calculated?
> x <- i
Hi,
Hopefully someone can point me in the right direction on how I would go
about solving the following.
I have some data and need to find the column name of the maximum value in
each row.
This could be the data...
> a <- data.frame(x = rnorm(4), y = rnorm(4), z = rnorm(4))
> a
x
I have Windows 7 64 bit and 64 bit version of R.
I have installed Tinn R.
Everytime I start R from within Tinn R it gives me the message
"The preferred R term was not defined. Do you desire to do this now"
I then tell Tinn R where the Rterm.exe and Rgui.exe are.
Rterm works OK - I can open r
Ok - I found the correct forum and that this seems to be a common problem.
http://sourceforge.net/projects/tinn-r/forums/forum/481900/topic/3741784
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Hi,
I am writing a function that requires a specific package to be installed.
Is there a way of checking if the package is installed and returning a TRUE
/ FALSE result so my function can return an appropriate error message and
exit the function gracefully rather than just bombing out?
I'm thi
Hi,
I am wanting to look at frequent item sets using the arules package. I need
to transform my data into a "transactions" object. The data I read in from a
file has 2 columns, an ID and an item. How do I convert data like this into
a transactions object?
I've tried
class? transactions
but it o
Hi,
Can someone please tell me how to change the column name of a specific
column. How do I change the name of the column 'Species'?
Thanks in advance
d <- iris
colnames(d)
[1] "Sepal.Length" "Sepal.Width" "Petal.Length" "Petal.Width" "Species"
ind <- which(names(d)=='Species')
ind
[1
I want to use caret to build a model with an algorithm that actually has no
parameters to find.
How do I stop it from repeatedly building the same model 25 times?
library(caret)
data(mdrr)
LOGISTIC_model <- train(mdrrDescr,mdrrClass
,method='glm'
Hi Max,
But in this example, it says the sample size is the same as the total number
of samples, so unless the sampling is done by columns, wouldn't you get
exactly the same model each time for logistic regression?
ps - great package btw. I'm just beginning to explore its potential now.--
View th
Thanks for the clarification Max - I should have realised that.
One final question, I like caret because it lets me pass in data to all
functions in the same way. For glm I have only ever used the formula
notation and did not see a way to pass in predictors and a target
individually. How do I do t
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Thanks again Max - a great time saver this is.
Now just for my sanity, if I use glm.fit to build a model where I have the
matrices, how do I then use the predict function without getting an error
message?
> LOGISTIC_model1 <- glm.fit(mdrrDescr,mdrrClass,
> family=binomial(link="logit"))
Warning
Hi Max,
I tried your suggestion but cam up with errors:
fitControl<-trainControl(number=1)
LOGISTIC_model <- train(mdrrDescr,mdrrClass
,method='glm'
,trControl = fitControl
)
Fitting: parameter=none
Error in if (all.equal(so
Is there an r function that will be able to identify the computer the code is
running on?
I have some common code that I run on several computers and each has a
database with a different server name - although the content is identical.
I need to set thisServer depending on which machine the code
Hi,
I'm experimenting with random forests and want to perform a binary
classification task.
I've tried some of the sample codes in the help files and things run, but I
get a message to the effect 'you don't have very many unique values in the
target - are you sure you want to do regression?' (so
Hi,
I want to time how long a function takes to execute. Any clues on what to
search for to achieve this?
Thanks in advance.
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In a boxplot - how can I prevent groups where the number of cases is less
than a set threshold from being plotted.
set.seed(42)
DF <- data.frame(type=sample(LETTERS[1:5], 100, replace=TRUE),
cost=rnorm(100))
count <- boxplot(cost ~ type, data=DF, plot = 0)
count$n
## how to only include plo
I have 'x' variables that I need to find the optimum combination of, with the
constraint that the sum of all x variables needs to be exactly 100. I need
to test all combinations to get the optimal mix.
This is easy if I know how many variables I have - I can hard code as below.
But what if I don't
I have a data frame that contains dates, but when I use as.POSIXlt() I lose
the hours on all records. I traced this down to a particuar hour which
causes the issue...
> as.POSIXlt('2004-10-31 02:00:00')
[1] "2004-10-31"
> as.POSIXlt('2004-10-31 03:00:00')
[1] "2004-10-31 03:00:00"
How do I tell a
I'll rephrase the question...
If you try...
as.POSIXlt('2004-10-31 02:00:00')
you get
[1] "2004-10-31"
What do I need to do to make it return
[1] "2004-10-31 02:00:00"
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I found this...
https://stat.ethz.ch/pipermail/r-help/2009-January/184745.html
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I am running a series of scripts sequentially and they all need some global
parameters. These will be included in a file in a known sub directory as the
scripts themselves.
The scripts need to be run by anyone without ANY editing.
Question is:
Is there a command to return the directory of the c
I know this is not a revolution support forum, but as anyone noticed the
following?
I have a foreach loop to generate random samples. If I run the exact code
below in normal r (2.14.1) it works as expected, but if I run it from
revolution 4.2.0 each loop returns the same numbers.
The only way I c
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