Dear all,
I have a string, let's say "testing", and I would like to extract in
sequence each letter (character) from it. But when I use substr() I only
properly get the first character, the rest is empty (""). What am I getting
wrong?
For example, I have this code:
>>>
x <- "testing"
k <- nchar(x)
u should get what you want.
> Cheers,
> Tim
>
> > Date: Sun, 21 Jan 2018 10:50:31 -0500
> > From: Ek Esawi
> > To: Luigi Marongiu , r-help@r-project.org
> > Subject: Re: [R] substr gives empty output
> > Message-ID:
> > > ri_...@mail.gmail.com
Dear all,
I have a dataframe with a column representing the names of the
elements (a, b, etc) and one with their frequencies.
How can I plot the frequencies so that each element has an associated
frequency value?
I have been thinking of a histogram, but I have found it difficult to
implement. I hav
ou are after?
>
> group <- c("a", "b", "c", "d", "e")
> freq <-c(1, 2, 2, 5, 3)
> x = rep(group, freq)
> barplot(table(x))
>
> Cheers,
> Ben
>
>
>
> On Jun 7, 2018, at 6:00 AM, Luigi Marongiu wrote:
>
> Dear a
uot;e")
> freq <-c(1, 2, 2, 5, 3)
> x = rep(group, freq)
> barplot(table(x))
>
> Cheers,
> Ben
>
>
>
> On Jun 7, 2018, at 6:00 AM, Luigi Marongiu wrote:
>
> Dear all,
> I have a dataframe with a column representing the names of the
> elements
I suggest getting a your hands on a
> copy of https://www.r-project.org/doc/bib/R-books_bib.html#R:Sarkar:2008 It's
> really worth it if you plan to spend time with lattice.
>
> Cheers,
> Ben
>
>
> On Jun 7, 2018, at 7:02 AM, Luigi Marongiu wrote:
>
> also, w
Dear all,
I have made a barplot using lattice in which the bars are stacked
horizontally. I would like to stack them vertically, but if I use the
parameter 'horizontal = FALSE' I get the error: 'Error in FUN(X[[i]],
...) : invalid 'type' (character) of argument'. The problem I face is
that, in draw
c("yellow", "orange"))
> ),
> strip = strip.custom(factor.levels = c("Cases","Controls"),
> strip.levels=TRUE,
> strip.names=FALSE,
> par.strip.text = list(cex = 1)
> )
Dear all,
I am working on Linux Ubuntu 16.04 and I have installed R 3.2. I need
to upgrade to R 3.3 and I tried several options available online with
no success. I downloaded the tar.gz file for R 3.3 and I would like to
ask how can I use this file in order to accomplish the upgrade.
Many thanks,
L
Dear all,
I have a vector with a certain range of values including infinity and
NA. I would like to remove the values that are outside a given range
(lower level = ll and upper level = ul) but I am getting the error due
to the NA values (missing value where TRUE/FALSE needed). I then
included the !
lt;- NA
} else {
x[i] <- x[i]
}
}
return(x)
}
(X<-clipper(x, ll, ul))
that works all right.
Best regards
Luigi
On Fri, Apr 17, 2015 at 11:43 PM, Marc Schwartz wrote:
> On Apr 17, 2015, at 5:23 PM, Luigi Marongiu wrote:
>>
>> Dear all,
>> I have a vector with a c
Dear all,
I am trying to plot the results of a PCR experiments that involves 384
individual plots. Admittedly the space for the plots will be tiny, but
I just nedd some icon to have a feeling of the layout of the
experiment and a quick comparison of the plots.
I believe that lattice would be the ri
Dear all,
I have a flat file (tab delimited) derived from an excel file which is
subdivided in different parts: a first part is reporting metadata,
then there is a first spreadsheet indicated by [ ], then the actual
data and the second spreadsheet with the same format [ ] and then the
data.
How can
Dear all,
with the most useful help of Duncan I updated a script to plot high
density data in the form of 384 squares containing tiny plots. The
function works and it is possible to create a pdf version of the
output. but when i try to make a function out of this script, the
resulting pdf file is e
\tCycle \tTarget \tName \tRn
\t1 \t1 \tAdeno 1 \t0.82
\t1 \t2 \tAdeno 1\ \t0.93
...
\t2 \t1 \tAdeno 2 \t0.78
...
On Mon, Apr 20, 2015 at 12:17 PM, Duncan Murdoch
wrote:
> On 20/04/2015 3:28 AM, Luigi Marongiu wrote:
>> Dear all,
>> I have a flat file (tab delimited) derived from a
Dear all,
I would like to add an outer strip or something like that on a lattice
plot I am making. Such plot contains 384 cells and, since I am not
interested in the axis values, I set:
scales = list(
x = list(draw = FALSE),
y = list(draw = FALSE),
gt; and
> https://stat.ethz.ch/pipermail/r-help/2007-July/135551.html
>
> otherwise have a look at ?trellis.focus and
> https://stat.ethz.ch/pipermail/r-help/2006-July/109585.html
>
> failing that ?gridRect and ?gridText from library(grid)
>
> Regards
>
> Duncan
>
&
uncan Mackay wrote:
> Hi Luigi
>
> If you wanted to add some text you could use grid.text from the grid package
>
> I use it regularly for annotating
>
> See also
> https://stat.ethz.ch/pipermail/r-help/2005-February/066264.html
>
> https://stat.ethz.ch/pipermai
Dear all,
I am adding some text to the panels of a graph generated through the
lattice function using the argument:
xyplot( ...,
panel =
function(x, y,...)
{
panel.xyplot(x,y,...)
panel.text(0,0,labels=V[panel.numb
Dear all,
I have a vector that comes from some calculations I am making and this
vectors turns out to be in character format rather than numerical. I
can convert it in numerical format but then the calculations are not
correct, as you can see in the following example. I was also expecting
that roun
Dear all,
I am writing some text into several panels which I can do with this
script (in capital the variables):
xyplot(Y ~ X | Z,
data = DATAFRAME,
groups = Z,
ylab= "Y",
xlab="X",
main="TITLE",
scales = list
Dear all,
I would like to clip the data of a dataframe by forcing the value of
the elements below a cut-off to 0. I believe that the function to be
used is sapply but I could not have the call working properly.
Would you have any tip?
Best regards
Luigi
>>>
value <- c(5.43, 6.63, 0, 6.2, 5.61, 0,
Dear all,
I am calculating the optimal cut-off for a test against a gold
standard measure. I can determine the cut-off (in the following
example 5.905) but I would like to assign it to an atomic variable so
that the cut-off is updated every time the data is changed. I am using
the ROC and roc funct
Dear all,
I would like to run RAxML for phylogenetic analysis as indicated on
Paradis' "Analysis of phylogenetic and evolution with R" (p. 158) thus I
tried to use the package phyloch and its function raxml(). I am using
Linux Ubuntu 14 and I was able to successfully install RAxML on my machine
adas
Em 28-12-2014 23:09, Luigi Marongiu escreveu:
Dear all,
I would like to run RAxML for phylogenetic analysis as indicated on
Paradis' "Analysis of phylogenetic and evolution with R" (p. 158) thus I
tried to use the package phyloch and its function raxml(). I am using
Linux Ubuntu 1
t; devtools package will make this easier:
>
> library(devtools)
> nstall_url("http://www.christophheibl.de/phyloch_1.5-5.tar.gz";)
> library(phyloch)
> example(raxml)
>
> HTH,
> Ista
>
> On Mon, Dec 29, 2014 at 9:23 AM, Luigi Marongiu
> wrote:
>> Dear R
Dear all,
I am drawing a phylogenetic tree using the zoom() function of the ape
package. Since I have 476 sequences in my allagnment, this allows me to
have the outlook of the main tree and then highlight a portion of it,
and this works fine.
However I would like to draw a scale bar using add.s
Dear all,
I am drawing a phylogenetic tree using the zoom() function of the ape package.
Since I have 476 sequences in my alignment, this allows me to have the outlook
of
the main tree and then highlight a portion of it, and this works fine.
At the moment I am using the approach of indicating th
Dear all,
I am trying to create a neighbour joining tree using the nj() function
of ape. I would like to add also the bootstrap. I created a distance
matrix with the Kimura 80 algorithm using the muscle function. If I use
nj on the distance matrix without any other argument I do obtain the
tre
Dear all,
I am trying to build a maximum likelihood (ML) tree using the raxml
function of the package ips. I implemented the following script:
tr<-raxml(seq.align,exec = "/usr/bin/raxmlHPC",b = 100,
N = 10)
where tr is the resulting tree, seq.align is the DNA alignment created
wi
Dear all,
what code should I write in order to extract the file name from a give
path? Let's say that I want to get the file "my file.xls" which is in
the directory/folder "My documents"; since I work both with Windows
and Linux, the paths I am looking at are in the format:
path.windows<-"\\home$\
Dear all,
I have been trying to apply the Cy0 algorithm of the package qpcR by
creating an object "obj" with the normalized fluorescent data from a
384 plate whose characteristics were TaqMan chemistry and 45 cycles.
The import of the object was successful but when I implemented the
pcrfit model (i
Dear all,
I am trying to set a model using the pcrfit() function of the qpcR
package. I have defined a dataframe with 45 cycles (rows) and 4
readings (columns) derived from a TaqMan qPCR with relative
quantification. The data is based on the normalized fluorescent
results (main fluorescence minus R
Dear all,
I am trying to open excel files using the gdata package. I can do that
using a .xls file, but the same file, containing the same data,
formatted in .xlsx gives error (R does not recognize the pattern from
where to start reading the data).
Doen anybody knows whether it is possible to read
Dear all,
i am trying to calculate the Cy0 from a series of PCR runs in the
384-well. I can create the regression model using the modlist
function:
ml<-modlist(
obj,
cyc = 1,
model = l4,
norm = "FALSE",
remove = "none"
)
where obj is the dataframe with the fluo
Dear all,
I would like to erase the content of a dataframe -- but not the
dataframe itself -- in a simple and fast way.
At the moment I do that by re-defining the dataframe itself in this way:
> df <- data.frame(A = numeric(),
+ B = numeric(),
+ C = character())
Dear all,
I am trying to overlap two series of boxplots on the same graph. In
order to distinguish the outliers from one series to the other, would
be possible to colour the outliers?: instead of the standard black, is
it possible to give a chosen colour?
Thank you
>>>
This is the example. I could
Dear all,
I am using boxplot to draw some data. Would be possible to have the
X-axis linear (as in a scatter plot) instead of the standard
categorical axis?
The data I have is subdivided into three groups at the numerical
values 1, 3, 5; boxplot treats these as categorical values; in fact, I
can wr
xplot(y~x)
>
>
> Bill Dunlap
> TIBCO Software
> wdunlap tibco.com
>
> On Fri, Sep 28, 2018 at 3:05 AM, Luigi Marongiu
> wrote:
>>
>> Dear all,
>> I am using boxplot to draw some data. Would be possible to have the
>> X-axis linear (as in a scatter plot)
Dear all,
I would like to draw two plots in the same device so that there is a
single row and two columns, with the first column being 1/3 of the
device's width.
I am creating a PNG object with width = 30 and height = 20 cm.
I know that I should use split.screen or layout but I am lost with the
mat
ng much more flexibly(and therefore requiring more effort to learn).
>>
>> Cheers,
>> Bert
>>
>>
>> Bert Gunter
>>
>> "The trouble with having an open mind is that people keep coming along and
>> sticking things into it."
>> -- Op
Dear all,
I have a data frame with character values where each character is a
level; however, not all columns of the data frame have the same
characters thus, when generating the data frame with stringsAsFactors
= TRUE, the levels are different for each column.
Is there a way to provide a single ve
Thank you,
that worked fine for me.
Best wishes of merry Christmas and happy new year,
Luigi
On Wed, Dec 19, 2018 at 12:19 PM Duncan Murdoch
wrote:
>
> On 19/12/2018 5:58 AM, Luigi Marongiu wrote:
> > Dear all,
> > I have a data frame with character values where each charac
Dear all,
I am using the package e1071 for modeling SVM. I obtain a model from
the data and I can plot the results; the plot shows the support
vectors (as 'X's) and the shaded areas as it should be.
However, I don't like the plot generated from the model and I would
like instead to have more contro
Dear all,
I have generated a model with KERNLAB using the following steps:
the data is a dataframe df of two numerical variables x and y, and
each point is assigned a z value that is a factor of two levels:
positive and negative. The data has the strucutre:
> str(df)
'data.frame': 1574 obs. of 3 va
Dear all,
I have a set of data in this form:
> str
'data.frame': 1574 obs. of 14 variables:
$ serial: int 12751 14157 7226 15663 11088 10464 1003 10427 11934 3999 ...
$ plate : int 43 46 22 50 38 37 3 37 41 11 ...
$ well : int 79 333 314 303 336 96 235 59 30 159 ...
$ sample: int 266 295
ation.
>
> [1] https://stat.ethz.ch/pipermail/r-help/2018-December/461010.html
>
> On January 7, 2019 4:26:20 AM PST, Luigi Marongiu
> wrote:
> >Dear all,
> >I have a set of data in this form:
> >> str
> >'data.frame': 1574 obs. of 14 variables
th(df$cons)
>
> > > plot(mod, data = df)
> > > kernlab::plot(mod, data = df)
> > but I get this error:
> >
> > Error in .local(x, ...) :
> > Only plots of classification ksvm objects supported
> >
>
> seems to me selfexplanatory. What did ma
Dear all,
is there a way to add the labels of the points to a 3D scatter plot
obtained with lattice's cloud?
I can now plot the data, but when trying to add the label I get the error:
`Error in multiple && !outer : invalid 'x' type in 'x && y'`
The script I wrote runs like this:
>>>
df = data.fr
Dear all,
is it possible to add points to a lattice cloud plot (3D scatter)? I
can plot the main data, but what if I wanted to add another point. In
R there is the high level plotting function plot(), then the low level
points() or lines() etc. What is the equivalent for lattice?
Thank you
>>>
indeed a double ll at the start
>
> Michael
>
> On 28/02/2019 10:39, Luigi Marongiu wrote:
> > Dear all,
> > is it possible to add points to a lattice cloud plot (3D scatter)? I
> > can plot the main data, but what if I wanted to add another point. In
> > R there
39 a.m., Luigi Marongiu wrote:
> > Dear all,
> > is it possible to add points to a lattice cloud plot (3D scatter)? I
> > can plot the main data, but what if I wanted to add another point. In
> > R there is the high level plotting function plot(), then the low level
> >
ing how you structure the data before you create the plot. Read
> the vignette and some tutorials.
>
> On February 28, 2019 7:38:52 AM PST, Luigi Marongiu
> wrote:
> >I see. I have been thinking of superimposing two plots with
> >par(new=TRUE), but how could I remove all th
Dear all,
I am trying to display multivariate data using the library plot3D. I
have 3 variables that go on the axis and a fourth that I would like to
display as a color shade. However, the scale differs between plots
because the data I am using varies.
Would be possible to maintain a single scale s
6, cex = 2,clim=c(0.5,3))
> scatter3D(X, Y, K, col.var = K, pch = 16, cex = 2,clim=c(0.5,3))
>
> Jim
>
> On Thu, Mar 14, 2019 at 9:32 PM Luigi Marongiu
> wrote:
> >
> > Dear all,
> > I am trying to display multivariate data using the library plot3D. I
> >
Dear all,
I would like to ask whether is possible to draw a scatterplot using
the simple plot() function when the data is factorial. Without the
addition of the argument factor(), plot() represent the factorial data
on a linear scale whereas using this argument transforms plot() from a
scatterplot
Dear all,
I am drawing a barchart plot with lattice and the resulting strips are
taking the value of the variable being compared (in this example
"assay"). However I would like to write myself the value to place into
the strips, let's say I want to call the variables as "molecular test"
and "serolo
Dear all,
I have a data frame and I would like to do the following:
a) replace value of one variable "a" according to the value of another one "b"
b) remove all the instances of the variable "b"
For the sake of argument, let's say I have the following data frame:
test <- rep(c("Adenovirus", "Rotav
Dear all,
i would like to convert a list onto a data frame object. Is there an
easy way of doing it? I know I should use unlist() but I am not sure
about the implementation for the addition of the row numbers; or I
could extract one member at the time with something like x <-
my.list[[i]] but then
Dear all,
I am reading a txt file into the R environment to create a data frame,
however I have notice that some entries have a truncated version of a
field, so for instance I get "Astro" instead of "Astro 1-Astro 1" and
"Sapo" for "Sapo #1-Sapo_1" and "Sapo #2-Sapo_2", but I also get
"Adeno 40/41
Dear all,
if I have a sample set of the following numbers x1=0.09, x2=0.94,
x3=0.48, x4=0.74, x5=0.04 I can calculate the variance easily.
But if each x is actually a subset of multiple values, what would be
the formula to calculate the variance? and it is possible to implement
such mathematical f
mple
> and/or http://adv-r.had.co.nz/Reproducibility.html for suggestions on how to
> pose a question here. In particular data should be supplied in dput() format
> as it gives us a copy of exactly how the data is formatted on your machine.
>
>
> John Kane
> Kingston ON Canada
&g
Dear all,
how can I calculate the global variance of repeated measurements? can
I simply use the var() function or shall i use more sophisticated
tools such as aov()? and in the latter case, how can i extract the
variance value?
I am providing an example.
Thank you.
best regards
luigi
>>>
samp <-
Dear all,
I am trying to do some cluster analysis, both with the base R and the
apcluster. Both methods give 2 clusters, which is what I am looking
for since I am interested in identifying positive and negative
results. However I could not find a way to fine-tuning the analysis
in order to properl
Dear all,
I am plotting the count of some data subdivided in different groups.
the variables i am using are:
A = tests performed
B = positive/negative results (but in this case the results are all
positive, so all 1)
C = multiple (1) or single (0) test applied
D = count of instances
E = cases (1) o
Dear all,
I am plotting some data using lattice's barchart. One of the counts I
am plotting has a very large value with respect to the other variables
and I would like to introduce a break in the axis to compensate for
this 'anomaly' and give more breath to the other bars. In this example
the high
Dear all,
I am trying to use neural networks to discriminate positive and
negative outcomes from a test; this outcome is given in the z variable
of the example I am providing. Each outcome is associated with a pair
of variables x and y and I was planning to identify the cut-offs that
could separate
Dear all,
I am a newbie in interpolation using R and I would like to learn
better the procedure.
I am applying interpolation to quantify nucleic acid targets using an
assay known as PCR. To do this, I have two sets of variables: standard
of known concentrations and query for which I need to identif
Dear all,
I am trying to train a predictive neural network to guess the
positivity/negativity of some tests I have done. I am using the
library pnn and I have empirically identified the best sigma to use in
the algorithm but the results I got are affected by false positive
results.
The actual datas
dear all,
I have a set of data that can be defined as bimodal; would be possible
to define a cut-off to split it? my mathematical/statistical knowledge
is limited, my apologies, thus i am not sure what kind of area this
problem belongs to; at the moment I can fit -- thanks to previous help
from the
Dear all,
I am using mixtols to find cut-off values from datasets. At the moment
I can run the parametric function normalmixEM from the library
mixtools, but I owuld like to generalize the procedure with the non
parametric version npEM. However I am confused regarding the arguments
to use in this i
Dear all,
I am using the package changepoint to identify a cut-off between positive
and negative values for an assay. I followed the vignette of the package
and the results are replicated, so I tried with a dataset of my choice. In
the assay, the positive have a value above 0.8 and the negative bel
dear all,
i have a set of data that is separated in the variables: cluster (two
runs), type (blank, negative and positive) and target (A and B), each
duplicated. I am plotting it with lattice and the result is a 2x2 matrix
plot in which the top two cells (or panels) are relative to run 2, the
lower
dear all,
I have a set of data that is subdivided in cluster (run 1/run 2) and in
target (A/B). When plotting, I obtain a panel strip with "run 1" and "run
2" for each "A" and "B" panel, so "run 1" appears twice and so does "run
2". It is possible to merge the strip together so that I will have "ru
; my.data$clus2 <- with(my.data, interaction(cluster, target))
>
> and call: dotplot(value ~ type| clus2, ... )
>
>
> Philip
>
>
> On 22/02/2017 8:03 PM, Luigi Marongiu wrote:
>
>> dear all,
>> I have a set of data that is subdivided in cluster (run 1/run
> par.strip.text = list(cex = 1) ),
>xlab = "Target",
>ylab = "Reading",
>auto.key = T,
>panel = panel.superpose
> )
>
> dotplot(
> value ~ type|cluster,
> mdata2,
> groups = typeT,
> par.settings
quot;Negative", "Positive"), col="black"),
rectangles = list(col=c("grey", "green", "red"))
)
)
)
<<<
also, the answer provided by Paul does the job all right, but uses the
package grid instead of lattice. The stripless package (Bert
Dear all,
I am analyzing some multivariate data that is organized like this:
1st variable = cluster (A or B)
2nd variable = target (a, b, c, d, e)
3rd variable = type (blank, negative, positive)
4th variable = sample (the actual name of the sample)
5th variable = average (the actual reading -- plea
tive"), col="black"),
> rectangles = list(col=c("grey", "green", "red"))
> )
>)
> )
>
> FWIW, I think adding 1 sd bars is a bad idea statistically.
>
> And though it made no difference here, please post in pain
t; "The trouble with having an open mind is that people keep coming along
> and sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>
>
> On Thu, Mar 16, 2017 at 1:38 AM, Luigi Marongiu
> wrote:
>> dear Bert,
&
Dear all,
I have set a function to draw some data using lattice; the drawing
works when I use lattice on its own, but if I put it into my custom
function, the final plot is empty, yet the terminal reports RStudioGD
1
as normal.
What am I missing?
regards,
Luigi
>>>
cluster <- c(rep("A", 90
Dear all,
I am plotting some data using lattice and the function useOuterStrips
to make use of more labels. It is possible to customize the labels of
useOuterStrips so I can decide what to write in it? instead of having,
let's say, A and B I could put something more descriptive.
best regards
luigi
Actually,
in the working example, Hutcheson himself did not report the term
µ1µ2: `t0 = h1-h2/(var1-var2)^1/2`. so I think we can live without it.
Case closed.
Thank you
On Fri, Sep 11, 2020 at 11:11 AM Luigi Marongiu
wrote:
>
> Hello,
> I have just realized in the original paper, the
Thank you for the clarification.
On Fri, Sep 11, 2020 at 2:36 PM Karl Schilling
wrote:
>
> Dear Luigi:
>
> no, µ1µ2 is not "missing"
>
> First, it should actually be "µ1 - µ2".
>
> And as your usual null-hypothesis when comparing h1 and h2 is that they
> are not different (i.e. µ1 = µ2), the latt
Hello,
I have an experiment measuring optical density (OD) when comparing
three parameters:
a) concentration of the target
b) concentration of the probe
c) concentration of the reporter antibody.
Using plotrix I can nicely draw the first two into clusters, but I
can't get separation for the third p
> way I could think of to show the nesting was dots with horizontal
> > > lines and it looked messy and was quite hard to visualize the nesting.
> > > If you do have any great ideas I always welcome contributions to
> > > plotrix.
> > >
> > > Jim
>
Hello,
I have a dataframe df with a column x that has these unique values:
"L" "M" "V" "N" "H". I can assign a factor to it:
```
df$x = as.factor(df$x)
> [1] L M V N H
Levels: H L M N V
```
I now need to get a subset of this dataframe. I could do the same
thing as before on the subset sf, but I wou
rows with the same level. It will be on you to decide what statistical
> properties (proportions?) you want to maintain between the full data set and
> your subset.
>
> On October 20, 2020 6:42:27 AM PDT, Luigi Marongiu
> wrote:
> >Hello,
> >I have a dataframe df with a col
Hello,
I am running SVM and showing the results with ggplot2. The results
include the decision boundaries, which are two dashed lines parallel
to a solid line. I would like to remove the dashed lines and use a
shaded area instead. How can I do that?
Here is the code I wrote..
```
library(e1071)
lib
n-lines-using-g
> gplot-in-r
>
> Cheers
> Petr
>
> > -Original Message-
> > From: R-help On Behalf Of Luigi Marongiu
> > Sent: Friday, October 23, 2020 9:59 AM
> > To: r-help
> > Subject: [R] How to shade area between lines in ggplot2
> >
On Fri, Oct 23, 2020 at 10:26 AM PIKAL Petr wrote:
>
> Hi
>
> Did you try google? I got several answers using your question
>
> e.g.
> https://stackoverflow.com/questions/54687321/fill-area-between-lines-using-g
> gplot-in-r
>
> Cheers
> Petr
>
> > -Orig
n-lines-using-g
> gplot-in-r
>
> Cheers
> Petr
>
> > -Original Message-
> > From: R-help On Behalf Of Luigi Marongiu
> > Sent: Friday, October 23, 2020 9:59 AM
> > To: r-help
> > Subject: [R] How to shade area between lines in ggplot2
> >
>
min = slope_1*x + intercept_1 - 1/w[2],
> ymax = slope_1*x + intercept_1 + 1/w[2], fill = "grey70", alpha=0.1))
>
> Cheers
> Petr
>
> > -Original Message-
> > From: Luigi Marongiu
> > Sent: Friday, October 23, 2020 11:11 AM
> > To: PIKAL P
1*x + intercept_1 + 1/w[2]), fill = "yellow", alpha=0.1)
>
> Cheers
> Petr
>
> > -Original Message-
> > From: Luigi Marongiu
> > Sent: Friday, October 23, 2020 3:30 PM
> > To: PIKAL Petr
> > Cc: r-help
> > Subject: Re: [R] How to shade area b
Hello,
I am using e1071 to run support vector machine. I would like to plot
the data with lattice and specifically show the hyperplanes created by
the system.
I can store the hyperplane as a contour in an object, and I can plot
one object at a time. Since there will be thousands of elements to
plot
Awesome, thanks!
On Wed, Oct 28, 2020 at 7:00 AM Deepayan Sarkar
wrote:
>
> On Tue, Oct 27, 2020 at 6:04 PM Luigi Marongiu
> wrote:
> >
> > Hello,
> > I am using e1071 to run support vector machine. I would like to plot
> > the data with lattice and specificall
Hello,
I have a large dataframe (1 000 000 rows, 1000 columns) where the
columns contain a character. I would like to determine the most common
character for each row.
In the example below, I can parse one row at the time and find the
most common character (apart for ties...). But I think this will
t;>
>> library(prettyR)
>> apply(as.matrix(df),1,Mode)
>> [1] "C" "B" "D" ">1 mode" ">1 mode" ">1 mode" "D"
>> [8] "C" "B" ">1 mode"
Hello
is it possible to color the data of a dataframe according to the
values of one column?
I have a dataframe that OI have subdivided into X and Y, with a third
Z with the sample number. I would like to plot Y~X but coloring using
Z. But I would like to use base R and not lines.
Is that possible?
- reshape(ROI, v.names = "Y", timevar = "Z", idvar = "X",
> direction = "wide")
> matplot(roi_wide, type = "l", lwd = 3, lty = "solid", col = colrs)
>
>
> Hope this helps,
>
> Rui Barradas
>
> Às 14:48 de 24/01/21, Lui
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