> pnorm(37:39,lower.tail=FALSE)
> [1] 5.725571e-300 0.00e+00 0.00e+00
>
> This is just a limitation of double precision floating-point arithmetic
> ...
>
> curve(pnorm(x,lower.tail=FALSE),from=30,to=40,log="y")
> .Machine$double.xmin
But note
curve(pnorm(x,lower.tail=FALSE, log=T),fr
> I'm generating some images in R to put into a document that I'm producing
> using Latex. This document in Latex is following a predefined model, which
> does not accept compilation with pdflatex, so I have to compile with latex
> -> dvi -> pdf. Because of that, I have to generate the images in R
On Mon, Apr 13, 2009 at 4:15 AM, Peter Dalgaard
wrote:
> Stavros Macrakis wrote:
>
>> It would of course be nice if the existing difftime class could be fit
>> into this, as it is currently pretty much a second-class citizen. For
>> example, c of two time differences is currently a numeric vector
In general, how can I increase a vector of length m (< n) to length n
by padding it with m - n missing values, without losing attributes?
The two approaches I've tried, using length<- and adding missings with
c, do not work in general:
> a <- as.Date("2008-01-01")
> c(a, NA)
[1] "2008-01-01" NA
>
plyr is a set of tools for a common set of problems: you need to break
down a big data structure into manageable pieces, operate on each
piece and then put all the pieces back together. For example, you
might want to:
* fit the same model to subsets of a data frame
* quickly calculate summary
> Levels: a
>>
>
> R. Raubertas
> Merck & Co
>
>
>> -Original Message-
>> From: r-help-boun...@r-project.org
>> [mailto:r-help-boun...@r-project.org] On Behalf Of hadley wickham
>> Sent: Wednesday, April 15, 2009 10:55 AM
>> To: r-help
&g
, namef)
> res <- c(res, get(namef))
> }
> names(res) <- namesf
> }
> return(res)
> }
>
> df <- data.frame(id = 1:50, x = sample(c(NA, 1), 50, T), y = sample(1:2, 50,
> T), z = sample(letters[1:2], 50, T))
>
>> freq1(df$x)
> $freq_1
>
On Fri, Apr 17, 2009 at 9:59 AM, Paul Warren Simonin
wrote:
> Hello!
> Thanks for reading this request for assistance. I have a question regarding
> creating a histogram-like figure from data that are not currently in the
> correct format for the "hist" command.
> Specifically, my data have been
On Fri, Apr 17, 2009 at 12:19 PM, jim holtman wrote:
> try this:
>
>> matrixx<-function(A){
> + B=matrix(NaN,nrow=(A+1),ncol=4)
> + k <- 1
> + for (i in 3:A){
> + for (j in i:A) {
> + B[k,] <- c(NaN, i-2, i-1, j)
> + k <- k + 1
> + }
> + }
>
Look at the output of pal.cr((0:40)/40)
Hadley
On Fri, Apr 17, 2009 at 2:42 PM, Etienne B. Racine wrote:
>
> I try to use ColorRamp as ColorRampPalette (i.e. with the same gradient), but
> it seems there is a nuance that I've missed.
>
> pal.crp<-colorRampPalette( c("blue", "white", "red"), space
On Fri, Apr 17, 2009 at 2:07 PM, Paul Warren Simonin
wrote:
> Thank you all for your advice.
> I have received some good tips, but it was suggested I write back with a
> small simulated data set to better illustrate my needs. So, currently my
> data frame looks something like:
>
> ID (date) Temp
> Am I doing something wrong, here? If not, which are the real AIC and logLik
> values for the different models?
I don't think it's reasonable to expect that the log-likelihood
computed by different functions be should comparable. Are the
constant terms included or dropped?
Hadley
--
http://ha
ggplot2
ggplot2 is a plotting system for R, based on the grammar of graphics,
which tries to take the good parts of base and lattice graphics and
avoid bad parts. It takes care of many of the fiddly details
that make plotting a hassle (l
> "Have you read the posting guide and the FAQs? If you do not get a reply
> within two days, you may want to look at both and think about reformulating
> your query. Oh, and while you are at it, look through the archives, a lot of
> questions have already been asked and answered before."
As I say
On Thu, Apr 23, 2009 at 5:11 PM, ozan bakis wrote:
> Dear R Users,
> I have the following data frame:
>
> v1 <- c(rep(10,3),rep(11,2))
> v2 <- sample(5:10, 5, replace = T)
> v3 <- c(0,1,2,0,2)
> df <- data.frame(v1,v2,v3)
>> df
> v1 v2 v3
> 1 10 9 0
> 2 10 5 1
> 3 10 6 2
> 4 11 7 0
> 5 11
On Fri, Apr 24, 2009 at 5:50 AM, Duncan Murdoch wrote:
> Toby wrote:
>>
>> I'm trying to figure out how I can get a generalized 2D
>> list/array/matrix/whatever
>> working. Seems I can't figure out how to make the variables the right
>> type. I
>> always seem to get some sort of error... out of
Hi Steve,
The general answer is yes, but the specific will depend on your
problem. Could you provide a small reproducible example to illustrate
your problem?
Hadley
On Fri, Apr 24, 2009 at 1:19 PM, sjaffe wrote:
>
> Perhaps this is a common question but I haven't been able to find the answer.
On Fri, Apr 24, 2009 at 3:12 PM, sjaffe wrote:
>
> small example:
>
> a<-c(1.1, 2.1, 9.1)
> b<-cut(a,0:10)
> c<-data.frame(b,b)
> d<-table(c)
> dim(d)
> ##result: c(10, 10)
>
> But only 9 of the 100 cells are non-zero.
> If there were 10 columns, the table have 10 dimensions each of length 10, so
>> I want to (1) create a deep copy of pop,
>
> I have already said *I* do not know how to create a "deep copy" in R.
Creating a deep copy is easy, because all copies are "deep" copies.
You need to try very hard to create a reference in R.
Hadley
--
http://had.co.nz/
_
he original were changed; the sort of behavior that
> might be seen in a spreadsheet that had a copy "by reference".
>
> On Apr 26, 2009, at 11:28 AM, hadley wickham wrote:
>
>>>> I want to (1) create a deep copy of pop,
>>>
>>> I have already said *I*
Have a look at the plyr package and associated documentation -
http://had.co.nz/plyr
Hadley
On Sun, Apr 26, 2009 at 12:42 PM, wrote:
> After a year my R programming style is still very "C like".
> I am still writing a lot of "for loops" and finding it difficult to recognize
> where, in place o
In statistics, a bumps chart is more commonly called a parallel
coordinates plot.
Hadley
On Sun, Apr 26, 2009 at 5:45 PM, Andreas Christoffersen
wrote:
> Hi there,
>
> I would like to make a 'bumps chart' like the ones described e.g.
> here: http://junkcharts.typepad.com/junk_charts/bumps_chart/
]
> library(ggplot2)
> qplot(year,value, data=data,label=countries, geom=c("line","text"),
> group=countries, col=countries)
>
> But I would like to have the text labels show only once - e.g. at 1990
> - and also control the size of the text. In my crude qplot, setting
> size=2 e.g. changes not onl
It's hard to check without a reproducible example, but the following
code should give you a 3d array of lat x long x time:
library(reshape)
df$lat <- round_any(df$LATITUDE, 5)
df$long <- round_any(df$LONGITUDE, 5)
df$value <- df$TIME
cast(df, lat ~ long ~ time, mean)
On Thu, Apr 30, 2009 at 10
On Fri, May 1, 2009 at 12:22 PM, MUHC-Research
wrote:
>
> Dear R-users,
>
> I would have another question about the ggplot() function in the ggplot2
> package.
>
> All the examples I've read so far in the documentation make use of a single
> neatly formatted data.frame. However, sometimes, one may
> Is situation anything better with ggplot2? It seems rather easy to get e.g.
> line plots with error bars, provided that one feeds the data to some
> modeling/regression function and passes the result over for plotting.. but
> what
> if I have generated my own error bar data? This is almost tri
> My issue is self-evident: using this method resulted in a 30 fold
> increase in time. My question is why? If I time the individual
> components separately, nothing is unusual. My hunch is the
> "interaction" between the model.matrix and nsga2 methods.
>
> Any ideas on how to speed this proces
On Fri, May 1, 2009 at 2:38 PM, Zeljko Vrba wrote:
> On Fri, May 01, 2009 at 01:06:34PM -0500, hadley wickham wrote:
>>
>> It should be trivial with ggplot2 too, but it's hard to provide
>> concrete advice without a concrete problem.
>>
> Elementary prob
Hi David,
I think the revolution blog is fantastic and a great service to the R
community. Thanks for all your hard work!
Hadley
On Fri, May 1, 2009 at 4:54 PM, David M Smith
wrote:
> I write about R every weekday at http://blog.revolution-computing.com
> . In case you missed them, here are so
On Thu, Apr 30, 2009 at 2:03 PM, MUHC-Research
wrote:
>
> Dear R-users,
>
> I recently began using the ggplot2 package and I am still in the process of
> getting used to it.
>
> My goal would be to plot on the same grid a number of curves derived from
> two distinct datasets. The first dataset (ca
> If you do write your own, the hardest part will be picking the nice tick
> marks. They should be approximately evenly spaced, but at nice round values
> of the original variable: that's hard to do in general. R has the pretty()
> function for the linear scale, and doesn't do too badly on log a
On Tue, May 5, 2009 at 3:03 PM, jwg20 wrote:
>
> I have a data set that I'm trying to melt and cast in a specific way using
> the reshape package. (I'll use the ff_d dataset from reshape so I don't have
> to post a toy data set here. )
>
> Lets say I'm looking for the interaction of treatment with
On Tue, May 5, 2009 at 3:55 PM, jwg20 wrote:
>
> Thanks for your help! I wasn't sure what the margins variable did, but I'm
> beginning to understand. I'm almost there, but with my data (and with ff_d)
> I tried to margin over two variable names, however it only does one of them.
> So with ff_d I
> Take a look at plyr and reshape packages (http://had.co.nz/), I have a hunch
> that they would have saved me a lot of headache had I found out about them
> earlier :)
As the author of these two packages, I'm admittedly biased, but I
think R is unparalleled for data preparation, manipulation, and
Hi Robert,
I'm organising one - sign up to the mailing list,
http://groups.google.com/group/houston-r. I'm hoping to organise our
first meeting this summer.
Hadley
On Wed, May 6, 2009 at 10:15 AM, Robert Sanford wrote:
> I'm looking for a Users Group in or near Houston, TX.
>
> Many thanks!
>
Hi Mark,
Could you send a the results of dput(l)? It will make exploration easier.
Hadley
On Wed, Jan 6, 2010 at 8:07 AM, Mark Heckmann wrote:
>
> Hi,
>
> I have an issue concerning plyr.
> I have a list l as output from dlply.
>
>> l
> $`1`
> (0.5,1.5] (1.5,2.5] (2.5,3.5] (3.5,4.5]
> f5_
> What I'd really like is for someone who has good taste to redesign the look
> of the whole system. I think one or two people are working on packages to
> do this, and I'd much rather spend time providing whatever low level support
> they need, rather than doing it myself.
Have you looked at add
>> I have to close all the tabs and call help to open them
>> again. Also, the R-supplied java tool for searching help is ancient and
>> underwhelming.
>
> Then contribute a new one.
And this would be pretty easy to, since you can program it in R.
There are heaps of possibilities - you could use
> I see. Well, I never lacked any of these capabilities... Please understand
> that people who use R to do their work may have different objectives than the
> developers - and they form the majority of R users.
Well how about a documentation system that could look back over your
history and noti
Dear list,
Many people seem unhappy with the new documentation server because you
need to have R running to access it, and it's not immediately obvious
how to bookmark references so they work long-term. One solution to
this problem is to have a globally available website that provides
access to al
>> Many people seem unhappy with the new documentation server because you
>> need to have R running to access it, and it's not immediately obvious
>> how to bookmark references so they work long-term. One solution to
>> this problem is to have a globally available website that provides
>> access to
> http://pledgie.com/campaigns/7707 - here you can donate as much or as
> little as you like to support this project. You won't pay until the
> total amount has been pledged.
I misread the documentation - do you actually pay right away. If I
don't reach the $1000, I'll pass on the money to a goo
y:
>
>> dput(l)
> list(structure(c(0.182198327359618, 0.473715651135006, 0.29689366786141,
> 0.0471923536439665), .Dim = c(1L, 4L), .Dimnames = list("f5_9",
> c("(0.5,1.5]", "(1.5,2.5]", "(2.5,3.5]", "(3.5,4.5]"
>
> Mark
&
On Fri, Jan 15, 2010 at 5:30 PM, Janko Thyson
wrote:
> Dear List,
>
> I am not really familiar with any other language than R, but I’ve heard that
> in other languages there is something called “self referencing”.
>
> Here’s what I’m trying to get an answer for:
> Suppose there is a function that
>> If you can point me towards a doc that explains this in simple terms I
>> would be obliged. Don't expect you to have to provide the answer.
>
> Any of the introductory texts should explain the various forms of indexing
> and the use of the apply family of functions. They are both central to
> ef
> Ouch! Hmmm. From the "Value" section of the apply docs... "If each call
> to FUN returns a vector of length n, then apply returns an array of
> dimension c(n, dim(X)[MARGIN]) if n > 1." Since I set MARGIN to 1, then I
> was operating on rows where n is 3.
>
>> c(n, dim(X)[MARGIN])
> [1] 3 2
On Mon, Jan 18, 2010 at 1:54 PM, Bert Gunter wrote:
> One way to do it:
>
> 1. Convert your date column to the Date class using the as.Date() function.
> This allows you to do the necessary arithmetic on the dates below.
> dt <- as.Date(a[,4],"%d/%m/%Y")
>
> 2. Create a factor out of your first th
> Note that in the documentaton ?"[.data.table" where I say that 'by' is slow,
> I mean relative to how fast it could be. Its seems, in this specific
> example anyway, and with the code posted so far, to be significantly faster
> than sqldf and plyr.
Of course the best of both worlds would be to
On Wed, Jan 20, 2010 at 8:43 AM, Matthew Dowle wrote:
> Sounds like a good idea. Would it be possible to give an example of how to
> combine plyr with data.table, and why that is better than a data.table only
> solution ?
Well, ideally, you'd do:
adt <- data.table(a)
ans2 <- ddply(a, c("var1", "
On Wed, Jan 20, 2010 at 4:37 PM, Dimitri Liakhovitski wrote:
> Hello!
>
> I have a data frame with a factor and a numeric variable:
>
> x<-data.frame(factor=c("b","b","d","d","e","e"),values=c(1,2,10,20,100,200))
>
> For each level of "factor" - I would like to divide each value of
> "values" by t
On Mon, Jan 25, 2010 at 4:43 AM, Paul Hiemstra wrote:
> Brad Patrick Schneid wrote:
>>
>> ### The following is very helpful # listOfFiles <-
>> list.files(pattern= ".txt") d <- do.call(rbind, lapply(listOfFiles,
>> read.table)) ###
>>
>> but what if each file c
Hi Dieter,
It looks like a bug:
Order works fine with bars:
qplot(factor(dur),weight=p,data=cf1, fill=score, geom = "bar", order =
rev(score))
but not with areas:
qplot(dur, p, data=cf1, fill=score, geom = "area", order = rev(score))
I'll add it to my to do list.
Hadley
On Tue, Jan 26, 2010 a
> can you also reproduce the “triangles” problem? Is it just a trivial
> corollary of the order-bug?
The triangles are there because you have a layer of points (from the
qplot default) and layer of areas. Setting geom = "area" in qplot
fixes that.
Hadley
--
http://had.co.nz/
>
> In case you have a temporary workaround, it would be nice to have it. It’s a
> show stopper for my report. Bars are not an option, because the curve looks
> too jaggy.
>
I just remember that to work around the problem, you can just manually
order the data frame:
cf1 <- cf1[with(cf1, order(d
Hi Chuck,
It looks like a scoping bug in spmx to me:
f <- function() {
x <- data[data$id=="111",]
print(spm(x$value ~ f(1:nrow(x
}
f()
I'd suggest you contact the package maintainer directly.
Hadley
On Fri, Jan 29, 2010 at 1:34 PM, Chuck White wrote:
> Hello -- I posted this question
On Sun, Jan 31, 2010 at 5:05 PM, Sunny Srivastava
wrote:
> Dear R-Helpers,
> I have a data.frame (df) and the head of data.frame looks like
>
> ProbeUID ControlType ProbeName GeneName SystematicName
> 1665 1577 0 pSysX_50_22_1 pSysX_50 pSysX_50
> 5422 5147
> Really? Where exactly is the loophole in 'If the question relates to a
> contributed package ... try contacting the package maintainer first.'?
How about the general R philosophy that if you dare to mistakenly
submit a bug report that turns out to be a "feature", not a bug, you
shall be well and
On Wed, Feb 3, 2010 at 11:06 AM, David Freedman <3.14da...@gmail.com> wrote:
>
> also,
>
> library(plyr)
> ddply(d,~grp,function(df) weighted.mean(df$x,df$w))
Or
ddply(d, "grp", summarise, mean = weighted.mean(x, w))
which is convenient if you want more than one output
Hadley
--
http://had.
> It will of necessity be slower (because there's more machinery underlying
> the sqldf package); but I doubt whether it would be noticeably slower than
> the native R solution in most practical situations. The same would be true
> for plyR's implementation (it relies on the proto package, which sl
Hi Thomas,
Please provide a reproducible example. The most likely explanation is
that after loading your data you haven't converted your "date"
variable from a factor into a real date.
Hadley
On Wed, Feb 3, 2010 at 1:15 PM, Thomas Adams wrote:
> All:
>
> I am using the command: qplot(date,MAE,
> The ddply invocation would look like so:
>
> R> my <- ddply(iris, .(w=Sepal.Length < 5.5, Species), transform,
> grmean=mean(Petal.Width))
> R> head(my)
> w Sepal.Length Sepal.Width Petal.Length Petal.Width Species
> grmean
> 1 FALSE 5.8 4.0 1.2 0.2 s
On Fri, Feb 5, 2010 at 9:29 AM, jim holtman wrote:
> Does this help:
>
>> x <-
>> c("1234567.z3.abcdef-gh.12","1234567.z3.abcdef-gh.12","1234567.z3.abcdef-gh.12")
>> y <- strsplit(x, '[.]')
Here's another way with the stringr package:
library(stringr)
x <-
c("1234567.z3.abcdef-gh.12","1234567.
Hi Titus,
The latest version of reshape is 0.8.3 - perhaps upgrading will fix
your problem.
Hadley
On Sat, Feb 6, 2010 at 4:51 AM, Titus von der Malsburg
wrote:
> Hi list,
>
> I run R on Linux and OSX. On both systems I use R version 2.9.2 (2009-08-24)
> and reshape version: 0.8.2 (2008-11-04)
On Sun, Feb 7, 2010 at 11:32 AM, Jacob Wegelin wrote:
>
> The example below creates parallel time-series plots of three different y
> variables conditioned by a dichotomous factor. In the graphical layout,
>
> • Each y variable inhabits its own row and is plotted on its
> own distinct
Hi all,
Is there a fast way to determine the number of lines in a file? I'm
looking for something like count.lines analogous to count.fields.
Hadley
--
http://had.co.nz/
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-he
> parser::nlines does it in C.
Looks promising, but I need something that uses connections because
I'm working with big bzipped files.
Hadley
--
http://had.co.nz/
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEAS
Hi Ken,
> How about something like
> length(readLines(fname))
I'm trying to avoid the overhead of reading the file in twice. (I'm
trying to preallocate a data structure for a chunked read)
Hadley
--
http://had.co.nz/
__
R-help@r-project.org mailin
On Mon, Feb 8, 2010 at 10:39 AM, Jonathan wrote:
> Hi all,
> I'm feeling a little guilty to ask this question, since I've
> written a solution using a rather clunky for loop that gets the job
> done. But I'm convinced there must be a faster (and probably more
> elegant) way to accomplish what
Hi Paul,
That's a bug in the current version of ggplot. I'm working on update
for later this week.
Hadley
On Mon, Feb 8, 2010 at 5:56 PM, Paul Sutcliffe wrote:
>
>
> In ggplot2 how do you justify the legend text ?
> In the example below the opts(legend.text = theme_text(size = 9,hjust=0))
> c
> I was looking for a fast line counter as well a while ago and ended up
> writing a small function in R:
>
> countLines() in the R.utils package
>
> At least at the time, it was faster than readLines() [for unknown
> reasons]. It is also more memory efficient. It supports connections.
> I don'
Hi Liam,
Your syntax is a little off. You want:
p <- ggplot2(~, aes(x = ~, y = ~, colour = Type)) +
geom_area(aes(fill = Type), position = 'stack')
Position isn't an aesthetic.
Hadley
On Sun, Feb 7, 2010 at 10:40 PM, Liam Blanckenberg
wrote:
> Hi all,
>
> I have been hunting around for hou
st like vertically summing an area chart).
> Really all I'm after is a stacked area chart where the fill for each
> 'Type' has been removed, leaving only a line for each (stacked) Type's
> value...
>
> I hope this is somewhat clear!
>
> Many thanks,
I'd recommend two places to get started:
* https://r4ds.had.co.nz/data-visualisation.html for a quick intro to
ggplot2 (and the rest of the book explains the general tidyverse
philosophy)
* https://ggplot2-book.org for the full details of ggplot2.
Hadley
On Wed, Nov 18, 2020 at 11:37 AM C W wr
On Tuesday, January 12, 2021, Duncan Murdoch
wrote:
> On 12/01/2021 1:12 p.m., Sigbert Klinke wrote:
>
>> Hi,
>>
>> thanks a lot, but maybe I was to vague.
>>
>> I do not want to replace \eqn{...} and \deqn{...} by \mjseqn{...} and
>> \mjsdeqn{...}. I would like to use $...$ and $$...$$ as in Rma
If this happens again in the future, you might try the development
version of pak:
install.packages("pak", repos = "https://r-lib.github.io/p/pak/dev/";)
pak::pak("tidyverse")
pak automatically diagnoses a number of common problems that causes
install.packages() to fail.
Hadley
On Sun, Apr 25,
On Sun, Dec 4, 2022 at 12:50 PM Hervé Pagès wrote:
>
> On 03/12/2022 07:21, Bert Gunter wrote:
> > Perhaps it is worth pointing out that looping constructs like lapply() can
> > be avoided and the procedure vectorized by mimicking Martin Morgan's
> > solution:
> >
> > ## s is the string to be sear
On Sun, Dec 4, 2022 at 1:22 PM wrote:
>
> This may be a fairly dumb and often asked question about some functions like
> strsplit() that return a list of things, often a list of ONE thing that be
> another list or a vector and needs to be made into something simpler..
>
> The examples shown bel
This often indicates you need to restart R.
Hadley
On Friday, February 3, 2023, Nick Wray wrote:
> Hello When trying to call various packages eg
> library(raster)
> library(sp)
> library(rgdal)
>
> I get this error message:
> Loading required package: sp
> Error: package or namespace load faile
I'm not aware of widespread problems, but it's possible that some
combination of OS, RStudio version, and R version might be causing
problems. Unfortunately I don't think there's enough information in
this thread for anyone to tell if that's the case.
Hadley
On Fri, Apr 7, 2023 at 1:18 PM Sorkin,
See this new vignette in dev ggplot2:
https://ggplot2.tidyverse.org/dev/articles/ggplot2-in-packages.html
Hadley
On Saturday, November 16, 2019, Rolf Turner wrote:
>
> I need to call ggplot() from another function with the names of the
> faceting variables supplied as arguments to the calling f
You can get pretty close with label_number_si():
pounds <- scales::label_number_si(prefix = "£")
pounds(10 ^ (0:7))
#> [1] "£1""£10" "£100" "£1K" "£10K" "£100K" "£1M" "£10M"
Created on 2019-12-09 by the [reprex
package](https://reprex.tidyverse.org) (v0.3.0.9001)
Hadley
On Fri, Dec
> I am not sure what your example means but text to image conversion can be
> done quite easily in many programming environments and does not need an AI
> unless you are using it to hunt for info. I mean you can open up many Paint
> or Photo programs and look at the menus and often one allows you
It sounds like you might want a rolling join, e.g.
https://dplyr.tidyverse.org/reference/join_by.html#rolling-joins.
(And data.table has similar functionality which inspired dplyr)
Hadley
On Mon, Aug 7, 2023 at 9:32 PM Naresh Gurbuxani
wrote:
>
>
> I have two dataframes, each with a column for
You might find this chapter of R for Data Science helpful:
https://r4ds.hadley.nz/databases
Hadley
On Tue, Aug 29, 2023 at 3:47 AM Stephen H. Dawson, DSL via R-help
wrote:
>
> Good Morning,
>
>
> I am doing some research to develop a new course where I teach. I am
> looking for a book to use in
These days I'd recommend duckdb
(https://cran.r-project.org/web/packages/duckdb/index.html) instead.
It's a similar design to RSQLite (i.e. you don't need a separate
server) but it's designed for the needs of data science.
Hadley
On Tue, Aug 29, 2023 at 9:22 AM Martin Møller Skarbiniks Pedersen
You're getting confused between the contents of the string and the
printed representation of the string. There's a little bit about this
in R4DS: https://r4ds.hadley.nz/strings#escapes
(or in brief, do writeLines(trailing.7.message))
Hadley
On Fri, Sep 8, 2023 at 7:23 AM Christopher Ryan via R-h
The place to start for such problems is always usethis::git_sitrep()
Hadley
On Thu, Jun 20, 2024 at 11:17 PM Robert Baer wrote:
> I am trying to install a package from github which has worked fine in
> the past, but now seems to be stuck on some new authentication issues.
> Does anyone know how
features, and we believe that there are now better approaches to
solving the same problem.
Hadley
On Mon, Aug 17, 2020 at 3:58 AM Eric Berger wrote:
>
> Thanks for this information Thierry. I was not aware.
> The author of the packages is Hadley Wickham. He writes on Github that he
> d
> | but they won't receive any new
> | features, and we believe that there
> | are now better approaches to solving
> | the same problem.
>
> Is tidyr::pivot_longer this better
> solution? It is an easier to understand
> version of the now retired and confusing
> (for me) tidyr::gather which at le
On Wed, Aug 19, 2020 at 10:03 AM Ivan Calandra wrote:
>
> Dear useRs,
>
> I'm new to the tidyverse world and I need some help on basic things.
>
> I have the following tibble:
> mytbl <- structure(list(files = c("a", "b", "c", "d", "e", "f"), prop =
> 1:6), row.names = c(NA, -6L), class = c("tbl_d
Dear all,
The latest issue of The R Journal is now available at
http://journal.r-project.org/archive/2013-1/
Many thanks to all contributors.
Hadley
--
Editor-in-chief, The R Journal
___
r-annou...@r-project.org mailing list
https://stat.ethz.ch/mail
Hi all,
Any insight into the code below would be appreciated - I don't
understand why two methods which I think should have equal distance
from the call don't.
Thanks!
Hadley
# Create simple class hierarchy
setClass("A", "NULL")
setClass("B", "A")
a <- new("A")
b <- new("B")
setGeneric("f", f
> The class AB inherits from A and from B, but B already inherits from class A.
> So actually you only have an object of class B in your object of class AB.
> When you call the function f R looks for a method f for AB objects. It does
> not find such a method and looks for a method of the object
> In my opinion the reason for the behavior lies in the specific multiple
> inheritance structure between AB, B and A.
So what if we don't make such a weird inheritance structure, and
instead have A and B inherit from a common parent:
setClass("A", contains = "list")
setClass("B", contains = "li
On Wed, Aug 14, 2013 at 11:36 AM, Simon Zehnder wrote:
> Because the signature is always (A,A) or (B,B). Then, as in AB we have A and
> B and no relationship between A and B, R chooses the method
> lexicographically. The result is as expected: f for A is chosen.
It's not as expected, because it
> For tasks which don't involve I/O but fail with mclapply, how does one
> work out where the problem is? The handy browser() function which
> allows for interactive diagnosis won't work with parallel jobs.
>
> What other approaches can one use?
?dump.frames - interactive debugging after the fac
Hi Earl,
Have you read the libCurl documentation for CURLOPT_COOKIEJAR? :
Pass a file name as char *, zero terminated. This will make libcurl
write all internally known cookies to the specified file when
curl_easy_cleanup(3)is called. If no cookies are known, no file will
be created. Specify "-"
It's not really the inverse of assign (that's get), but I think you
want substitute.
See http://adv-r.had.co.nz/Computing-on-the-language.html for more details.
Hadley
On Tue, Aug 27, 2013 at 4:13 PM, Robert Lynch wrote:
> I am looking for a way to extract the name of a variable that has been
>
On Wed, Aug 28, 2013 at 4:32 PM, ivo welch wrote:
> is it possible to temporarily change the destination environment where
> objects are written to? I am thinking
>
> a <- new.env()
> attach(a)
> ### run some code, such as...
> b <- function(x) x
> detach(a)
> a$b
>
> obviously, this
> As a user of your package, I would find it irritating if example(foo) didn't
> run anything. It would be more irritating (and would indicate sloppiness
> on your part) if the examples failed when I cut and pasted them. These both
> suggest leaving the examples running.
>
> As the author of you
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