Dear R users:
I am hoping that someone can help with constructing a list that consists of
list with the number of lists variable.
i.e. to find a convenient express(or loop sentences) to realize the
following:
list( list(para1=p1, para2=p2), list(para1=p1, para2=p2), ,
list(para1=p1,para2=p2) )
[1] 5 6 7 8 9
[[5]]
[[5]]$para1
[1] 1 2 3 4 5
[[5]]$para2
[1] 5 6 7 8 9
[[6]]
[[6]]$para1
[1] 1 2 3 4 5
[[6]]$para2
[1] 5 6 7 8 9
On Fri, Mar 12, 2010 at 3:06 AM, Jim Lemon wrote:
> On 03/12/2010 05:13 PM, Zhongyi Yuan wrote:
>
>> Dear R users:
>>
>> I am hoping th
ing replicate:
>
> replicate(6, list(para1 = 1:5, para2 = 5:9), simplify = FALSE)
>
> On Fri, Mar 12, 2010 at 2:51 PM, Zhongyi Yuan
> wrote:
> > Hi Jim,
> >
> > Dennis Murphy solved my problem by the following code.
> > Thank you for you suggestion. Will check out
Dear R users:
I am drawing a graph with the following code:
Tau<-seq(0.05,0.95,0.05);
Pi <- seq(0.19,0.01,-0.01);
par(cex.axis=0.8,ps=9,mar=c(1.5,1,0.5,1), oma=c(1,1,0.2,1) ,tck=-0.01);
plot(Tau,Pi, type='l', xlab="Tau",ylab="Pi",col=4);
I want to make the graph take as little space as possible.
t="n", yaxt="n");
> axis(1,labels=F)
> axis(1,line=-1, lwd=0)
> axis(2,labels=F)
> axis(2,line=-0.5, lwd=0)
> mtext("x_txt",side=1, line=0.5)
> mtext("y_txt",side=2, line=1.2)
>
> cheers
>
> milton
> On Tue, Mar 16, 2010 at 12
Hi,
Could anybody please help me with this? In the following function, I try to
return a good format of x, i.e. if my x[1] is 800, I don't want it to give
me 800.0.
I tried format(x, trim = TRUE), but didn't work.
If my x has only first three components, which are all integers, I don't run
into th
Hi everyone,
I run into this problem and hope somebody can help. Thank you in advance.
I have an excel file with the first column being a list of names.
What I want is to add values that I compute for each person to the right of
the corresponding names.
Can someone help me with this? Thanks.
Bes
Dear R users,
I am leaning MCMC sampling, and have a problem while trying to sample
exponential r.v.'s via the following code:
samp <- MCMCmetrop1R(dexp, theta.init=1, rate=2,
mcmc=5000, burnin=500,
thin=10, verbose=500, logfun=FALSE)
I tried o
nt to cc the
> package maintainer in case this happens to be a bug:
> > maintainer('MCMCpack')
> [1] "Andrew D. Martin "
>
> I don't know enough about the package to help you, but providing this
> information to the list will increase the probability of a s
Dear R users,
I run into the following problem and hope someone can help me out. Thank you
in advance for your time.
I have a function defined recursively as follows:
recFun = function(k,x){ #i is less than 10. x can be any real number. I need
the value of recFun(k=1,2,3,4, x=0.12).
if(k==1)
i
ion(paste(alpha," = ", 1)),
expression(paste(alpha," = ", 2))),col=c('black','red'))
Is it possible to make it red? Thanks in advance for your help.
Best,
Zhongyi Yuan
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_
me a black "alpha = 2".
> >
> > x=y=1:100
> > z=seq(0.5,50,by=0.5)
> > plot(x,y,type='l',col='black')
> > lines(x,z,col='red')
> > legend('topleft',c(expression(paste(alpha," = ", 1)),
> > expression(pa
hat is, the first column is numerically grouped and only the first item in
each group is wanted. The second column is in increasing order within each
group. My actual data will be of size 10^6 by 100 so I am hoping to solve
this by a simple function. Thank you very much for your help.
Best,
Zhongy
Worked like a charm. Thanks.
Zhongyi
On Wed, Jul 25, 2012 at 11:58 PM, MK wrote:
> Very simple
>
> mat[!duplicated(mat[, 1]), ]
>
> M
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