also considering to use the function « lapply », but I don’t think I can use it
in this case, isn’t it?
Thank you very much for your help !
Sarah
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read t
> Le 24 oct. 2014 à 09:23, Sarah a écrit :
>
> Thank you very much, it helped a lot!
>
> I just have another question know. I want to make plot for every species. I
> just add the function « plot correlog » to the previous function and I have
> now
I am trying to fit a linear model with seasonal effects but keep getting
'Incorrect number of dimensions'. I have no idea what this means or how to
fix it. I am following instructions received from an instructor and it
worked for him, so I assume it has something to do with my data. Here is my
Hello,
I would like to run a script in which a loop is included. Since I'm new to
R, I cannot manage the following problem. I really hope someone could help
me out.
Data in the variable Y should be removed from the simulated data set with
probability 0.50 if the variable X has a value below zero
, there are no NA's to impute)
Does anyone knows how to rewrite the last bit of the script
(if...else...-part), in order to keep the 6 'deleted/missing' values in the
data set, and give them a value mar.y=1 (or NA, or any other value),
together with the 34 'observed ones' (mar
a larger design, I have to stick
to this example.)
Hope someone has an answer.
Wishing you a very happy 2011,
Sarah.
--
View this message in context:
http://r.789695.n4.nabble.com/dataframe-simulating-data-tp3169246p3169246.html
Sent from the R help mailing li
),34-length(which(df$mar.y==0, ]
}
while 40 cases are needed.
Thanks for your replies.
Sarah.
--
View this message in context:
http://r.789695.n4.nabble.com/dataframe-simulating-data-tp3169246p3169354.html
Sent from the R help mailing list archive at Nabble.com.
__
Thanks, Petr! With your script my problem is solved.
David, thanks for your help and time as well!! I really appreciate it.
--
View this message in context:
http://r.789695.n4.nabble.com/dataframe-simulating-data-tp3169246p3170764.html
Sent from the R help mailing list archive at Nabble.com.
_
Hi,
I want to impute the missing values in my data set multiple times, and then
combine the results (like multiple imputation, but manually) to get a mean
of the parameter(s) from the multiple imputations. Does anyone know how to
do this?
I have the following script:
y1 <- rnorm(20,0,3)
y2 <- rn
Hi Daisey,
Thanks for your answer! You've mentioned to change the name of the dataset.
Is it possible to rename the data set with each run (so read in the
incomplete dataset, do the imputation, and call it dataset 1; read in the
(same) incomplete dataset, do another imputation, and call it datase
Hi all,
How can I calculate the mean from several imputed data sets with the package
mice?
I know you can estimate regression parameters with, for example, lm and
subsequently pool those parameters to get a point estimate using functions
included in mice. But if I want to calculate the mean value
Dear R-users,
I want to multiple impute missing scores, but only for a few subgroups in my
data (variable 'subgroups': only impute for subgroups 2 and 3).
Does anyone knows how to do this in MICE?
This is my script for the multiple imputation:
imp <- mice(data, m=20, predictorMatrix=pred, post=p
le to suggest a work-around for a function of unknown
purpose and origin.
(The posting guide for this list suggests you include all of that
information when you inquire.)
Sarah
On Tue, Oct 31, 2017 at 2:04 PM, Scott Anderwald via R-help
wrote:
> To whom it might concern. I am working on a
rting with?
What kind of maps do you want to produce?
Sarah
On Fri, Nov 17, 2017 at 3:40 AM, Stefano Sofia
wrote:
> Dear R users,
> I need to produce rainfall maps using R.
> I know that this is possible, I looked though the web, I found the example
> below reported (the author is A
for this act of kindness.
>
> Best Wishes
> Ali Hassan Shabbir
--
Sarah Goslee
http://www.functionaldiversity.org
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
1.431341 -14.10790
20 1.425015 -14.06372
If instead you use abline(regressor, lty=2) you will get a
nice-looking dashed line.
Or, if you want only the data extent, you could use just the points
for the minimum and maximum values of x.
Sarah
On Mon, Dec 4, 2017 at 12:13 PM, jean-philippe
wrote:
> d
Hi Andrew,
Yes, you cannot have NA values in your matrices.
Instead, you could incorporate a model matrix.
See Legendre, P. & Fortin, M.J. Vegetatio (1989) 80: 107.
https://doi.org/10.1007/BF00048036
for ideas.
Sarah
On Sun, Dec 31, 2017 at 12:55 PM, Andrew Marx wrote:
> I'm tryin
gestions. Nabble is another good choice, and simply entering "r
> > [topic]" in a search engine will usually yield hundreds of results.
> >
>
> __
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
&
assign the result to anything: as.matrix() does not work in
place.
CR1 <- as.matrix(CR1)
Now try.
If that doesn't work, then provide a reproducible example so we can
offer further advice.
Sarah
On Sat, Mar 17, 2018 at 11:08 AM, Shivi Bhatia wrote:
> Created a new data set with 3 numer
tcars)
M <- cor(mtcars)
corrplot(M)
Sarah
On Sat, Mar 17, 2018 at 12:00 PM Shivi Bhatia wrote:
> Hi Sarah,
> Thank you for your help.
>
> I tried using CR1<-as.matrix(CR1) but gives error Error in corrplot(CR1,
> method = "circle") : The matrix is not in [-1, 1]!. I
", "13141", "13142", "14151", "14152"))
> levels(datn$STATUS)
[1] "ENTRY" "11121" "11122" "12131" "12132" "13141" "13142" "14151" "14152"
Reorder the levels to
t, then use dput(abc) to provide a
reproducible example, and submit that to the list. We can't tell the
format of the various columns from a copy and paste.
Sarah
On Sun, Apr 22, 2018 at 6:10 PM, wrote:
> From the help file for plotrix:
> " ... x - a list of task labels, st
ing about, because it is
looking for particular names.
If you fix those problems, it works fine.
colnames(cdfg) <- c("labels", "starts", "ends")
cdfg$labels <- as.character(cdfg$labels)
gantt.chart(cdfg)
Sarah
On Sun, Apr 22, 2018 at 7:50 PM, wrote:
&g
tput to look like, please provide
more information.
Sarah
On Thu, May 10, 2018 at 9:04 AM, Marcelo Mariano Silva
wrote:
> Hi,
>
> I am a begginer in R programming.
>
> I am traying to create a a column in my data frame filled down with a
> number.
>
>> df$newcolumn <- num
way using rle()
dat1$C2 <- rep(seq_len(length(unique(dat1$B))),
times=rle(as.vector(dat1$B))$lengths)
(That second will work even if B is a factor.)
> dat1
N B C1 C2
1 1 29_log 1 1
2 2 29_log 1 1
3 3 29_log 1 1
4 4 27_cat 2 2
5 5 27_cat 2 2
6 6 1_log 3 3
7
Hi,
You're mixing base plot and ggplot2 grid graphics, which as you've
discovered doesn't work.
Here's av strategy that does:
https://cran.r-project.org/web/packages/egg/vignettes/Ecosystem.html
This vignette has a good overview, well as info specific to that package.
Sa
/mirmon_report.html#us
Pick a different mirror, and it should work.
Sarah
On Wed, Jun 6, 2018 at 12:27 PM, LMH wrote:
> Hello,
>
> I recently upgraded my version of R and find I need to reinstall packages
> (unless there is some method to import my old profile and files). I have set
> m
Here are two options:
> # for one occurrence
> help("help", help_type="html")
starting httpd help server ... done
>
> # to set the default for your R session
> options(help_type = "html")
> ?help
If you read the help file for help(), you will
ed through profiling and
careful thought: 3 days to 3 seconds, even.
Sarah
On Thu, Jun 21, 2018 at 6:28 AM, akshay kulkarni wrote:
> dear members,
> I a Day Trader based in INDIA. I use R for my
> research. I have a function ygusa(snlq,snlcqn) which takes 208 stoc
; bind_rows(lapply(employees4BList, function(x) rbind.data.frame(c(t(x)
>
> # This produces a nice list of data frames, except for the names
>
> lapply(employees4BList, function(x) rbind.data.frame(c(t(x
>
> # This list is a disaster. I am looking for a solution that wor
've posted.
https://stackoverflow.com/questions/48255675/subgraphmining-package-not-available
Or, ideally, convince the book author to upgrade the package to use igraph.
Sarah
On Thu, Jul 5, 2018 at 2:01 PM, Maryam R via R-help
wrote:
> Hi, I’m maryam that ask question about "igraph0&q
The short answer is that hold isn't a list-like object, and $ only
works with list-like objects (lists and data frames, mainly).
You can get the full explanation (VERY full), at
?Extract
or any of its aliases, like
?'$'
or
?'['
Sarah
On Fri, Mar 31, 2017 at 7
resulting html file is copied to the server.
It sounds like exactly what you need.
Sarah
On Sat, Apr 22, 2017 at 10:29 PM, Chris Battiston
wrote:
> Good evening,
>
> I’m relatively new to using R and am trying to find a way to create a series
> of interconnected graphs where I h
are after.
Sarah
On Mon, May 8, 2017 at 9:21 AM Elahe chalabi via R-help <
r-help@r-project.org> wrote:
> Any idea?!
>
> On Sunday, May 7, 2017 5:56 PM, Elahe chalabi via R-help <
> r-help@r-project.org> wrote:
>
>
> Hi all,
>
> Does anyone know what is
There are various ways to do this. It shouldn't take forever as a loop,
with only 215 entries.
I find crosstab() from the ecodist package helpful. The current version is
on GitHub, but not yet CRAN (soon!).
Sarah
On Fri, May 26, 2017 at 7:47 AM A M Lavezzi wrote:
> Dear R-Users
&g
undefined columns selected
I would really appreciate if anyone could provide advice on how to
correct this error. I am using the plspm package in order to analyze
my data for my masters thesis at the University of Waterloo.
Thank you!
Sarah
__
This is pretty badly mangled (please don't post in html), but
?aggregate
is probably what you want.
Sarah
On Sun, Jun 25, 2017 at 5:27 PM, Jackson Rodrigues
wrote:
> Hi everybody,
>
> My name is Jackson and come here ask for a help to organize data.
> I really need help from yo
my questions have to do with what your objective actually is,
like what you are modeling and what you are doing with the
predictions. But my sample code might be enough to get you headed in
the right direction regardless.
Sarah
On Fri, Jun 30, 2017 at 9:27 AM, Ahmed Attia wrote:
> Hi folks,
>
&g
Once again, you are over-writing your variable. This time, you are overwriting
the entirety of Stand_Height with the timeseries of height.
Perhaps you should spend some time with one of the good introductory R
resources out there, and think a bit more about your procedure.
Sarah
On Fri, Jun 30
You appear to already have something named subtree in your environment:
The following object is masked _by_ ‘.GlobalEnv’:
subtree
You could get rid of it, or you could specify that you want to use
subtree from extracat
hcs <- extracat::subtree(hc, k = 7)
Sarah
On Sat, Sep 9, 2017 at 8
On Tue, May 31, 2016 at 11:09 AM, Jeff Newmiller
wrote:
>
>
> However, please don't apply R like a magic answers box, because you can
> mislead others and cause harm.
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.eth
pch=2)
Notice that even though the boxplot labels are 4, 9, 15 the plot
coordinates are 1, 2, 3.
Sarah
On Thu, Jun 2, 2016 at 11:36 AM, Thomas Adams wrote:
> Hello all:
>
> I've been beating my head on this for over a day and I have done a lot of
> Google'ing with no luck.
maintainers.
Sarah
On Sun, Jun 5, 2016 at 5:23 AM, Ranjit Sen via R-help
wrote:
>
>
>
> Dear Sir:
> This is Dr Ranjit Sen, Senior Scientific Officer, Soil Science Division,
> Bangladesh Agricultural Research Institute(BARI). For my research on climatic
> variability
ction(x)testdf)
>
> system.time(r.df <- do.call("rbind", testdf.list))
user system elapsed
195.105 36.419 231.930
>
> system.time({
+ testm.list <- lapply(testdf.list, as.matrix)
+ r.m <- do.call("rbind", testm.list)
+ })
user system elapsed
0.603
clude
packages beyond the base functionality). In general, though, using
matrices is faster than using data frames, and using do.call is faster
than using a pre-allocated loop, which is much faster than growing an
object.
Sarah
> testsize <- 5000
>
> set.seed(1234)
> testdf <- data.frame(mat
On Mon, Jun 27, 2016 at 11:34 PM, Jeff Newmiller
wrote:
> Sarah, you make it sound as though everyone should be using matrices, even
> though they have distinct disadvantages for many types of analysis.
I'm saying that if you don't need the special features of a data
frame, man
#x27;s suggestion
text(2, 3, expression(paste(bolditalic(p)^"*"))) # repeat Rolf's original
text(locator(1), "*", cex=3) # click on the asterisk: how big do you want it?
Sarah
On Thu, Jun 30, 2016 at 4:46 AM, Rolf Turner wrote:
> On 30/06/16 19:38, Göra
47916 169344 421824 889056 1687500
Sarah
On Fri, Jul 1, 2016 at 10:15 AM, Steven Yen wrote:
> A is a 5 x 3 matrix and a is a 3-vector. I like to exponentiate A[,1] to
> a[1], A[,2] to a[2], and A[,3] to a[3], and obtain the product of the
> resulting columns, as in line 3.
>
&g
","text A5","text A6","text
> A7","text A8")
> varB = c("link B1","link B2","link B3","link B4","link B5","link B6","link
> B7","link B8")
> df = data.fram
le to help with specific
questions even if we've never used a particular package.
Sarah
On Mon, Jul 11, 2016 at 4:47 PM, lily li wrote:
> I still haven't heard back from anyone. Please let me know as I think it is
> better to discuss here.
>
> On Sun, Jul 10, 2016 at 1:25 P
ls like dim() and str()
until I found the problem.
There are more fully-developed debugging tools available, but for such
a short function I wouldn't bother.
Sarah
On Tue, Jul 12, 2016 at 9:29 AM, Samsad Afrin Himi
wrote:
> Dear R-team,
>
> I have written this code for calculatio
ting colvar to your chosen levels gives
you the result you expect.
Thanks for the complete reproducible example. I wouldn't have even
looked at your problem without something to test.
Sarah
On Thu, Jul 14, 2016 at 1:55 PM, Jorge I Velez wrote:
> Dear R-help,
>
> I am using the plot3
ot;EQ", "AU", "AV",
"AW", "AC", "AY", "EQ")), .Names = c("ATP.Group", "Business.Event",
"Category"), class = "data.frame", row.names = c(NA, -9L))
hasEQ <- subset(mydat, Category == "EQ&
md 'ab'
> instead of
> cmd 'a\tb'
>
> How can I prevent system to interpret 'a\tb' to 'ab'?
>
>
> Thanks
--
Sarah Goslee
http://www.functionaldiversity.org
__
R-help@r-project.org ma
Hi,
It's really a good idea to use dput() or some other reproducible way
to provide data. I had to guess as to what your data looked like.
It appears that order doesn't matter?
Given than, here's one approach:
combs <- structure(list(V1 = c(65L, 77L, 55L, 23L, 34L), V2 = c(23L, 34L,
34L, 77L, 6
Rhelp have to guess. Because we tend to guess in
ways that make the most sense after extensive R experience, and that's
probably not what you have.
Sarah
On Wed, Jul 27, 2016 at 1:29 PM, sri vathsan wrote:
> Hi,
>
> Thanks for the solution. But I am afraid that after running this co
arning
and
plot(teste2)
makes me think this did what you wanted. At least, it did something.
Sarah
On Thu, Jul 28, 2016 at 2:11 PM, Arthur Rodrigues Stilben
wrote:
> Sorry, I forgot to mention:
>
>> install.packages("sets")
> ...
>> library(sets)
>> teste = fuzz
On Thu, Jul 28, 2016 at 2:46 PM, Arthur Rodrigues Stilben
wrote:
>
>
> Em 28-07-2016 15:45, Arthur Rodrigues Stilben escreveu:
>>
>> Sarah,
>>
>> First of all, thanks for reply.
>>
>> Second, It really works, but in fact I would to like t
As already discussed, yes, but you can't specify corners and height
twice in a single call.
Please do read the help for the functions you're interested in, and
perhaps go back to refresh yourself on some basic R.
> sets_options("universe", seq(from = 0, to = 10, by = 0.1))
> test1 = fuzzy_variable
vector with subset() to get the population that answered all of your
questions.
The advantage of this approach is that you don't have to list each
question individually, in case you have lots.
Sarah
On Tue, Aug 16, 2016 at 2:51 PM, Lauren Bolger wrote:
> M
> y dataset includes a survey comp
make sense, then you should definitely go read
some of the great introductory material on R out there.
Sarah
On Tue, Aug 23, 2016 at 1:54 PM, André Luis Neves wrote:
> Hi, There!
>
> I have this data frame:
>
>> plotdat2
> FirmicutesLowerUpper fTissue2
> 1 63.480
0)
z <- rnorm(10) + atan2(x, y)
# version one: text only
plot3d(x, y, z, type="n")
text3d(x, y, z, text=letters[1:10], cex=2)
# version two: colored symbols
data.groups <- sample(1:3, size=10, replace=TRUE)
data.colors <- c("red", "purple", "blue")
You could take a look at ?identify3d
You should probably also read
https://cran.r-project.org/web/packages/rgl/vignettes/rgl.html
Beyond that, if it's difficult to see what you're looking for, maybe
you should rethink your approach.
Sarah
On Wed, Aug 24, 2016 at 1:21 PM, LMH wrot
The help isn't particularly helpful, but you need to play with the
scale argument.
The range of your first dataset is long enough that you're getting
only even-numbered stems by default.
Try these:
x1 <- c(479,482,487,493,494,494,495,496,497,498,498,499,503,504,507,507,508,
510,511,512,514,516,
If it doesn't do ANYTHING, you may have failed to save the file.
Unless that file contains a function, in which case it isn't supposed
to do anything except load the function into your global environment.
But it should have thrown an error in that case, as Duncan said.
On Wed, Aug 31, 2016 at 11:
on Mac. All of the OS problems
I've run into tend to be problems with Windows. It's a bit harder to
get some geospatial stuff working on Mac, but that's unlikely to be a
problem with your elementary stats students.
Sarah
--
Sarah Goslee
http://www.functionaldiversity.org
_
un on other systems.
Sarah
On Thu, Sep 1, 2016 at 11:34 AM, Franklin Bretschneider
wrote:
> Dear Tom Mosca,
>
> Re:
>
>> Using a PC I have written the R code for my elementary statistics students.
>> One of the students has a Mac. Should the same lines of code work on
t; cleanBetweenBrackets(Str)
[1] "The cat is crazy "
The trailing space is left as an exercise for the reader.
Sarah
On Tue, Sep 6, 2016 at 2:56 AM, Audrey Riddell wrote:
> Hello,
>
>
> I am trying to remove brackets and the text contained in brackets. I tried
&g
>
> $Station_RM
> [1] "integer"
>
> $Sensor_RM
> [1] "integer"
>
> $Place_RM
> [1] "character"
>
> $Y_init_RM
> [1] "integer"
>
> $M_init_RM
> [1] "integer"
>
> $D_
> # lets the user decide how to handle the missing data, rather than making
> # assumptions.
>
> Again, sorry for my question
> Stefano
>
>
> Da: Sarah Goslee [sarah.gos...@gmail.com]
> Inviato: mercoledì 7 settembre 2016 15.11
> A:
ent withoutdata? Obviously I am missing thepoint. My own created
> function makes a new environment, but I onlycreated it to crunch numbers. If
> it doesn't crunch numbers it's useless. The point is, I do not understand the
> definitionof "with" and thus have no ide
Hi Carl,
The duplicate names were to demonstrate the difference in search path
and environment, since you appeared to be confused.
If you dislike with, don't use it.
On Fri, Sep 9, 2016 at 5:20 PM, Carl Sutton wrote:
> Hi Sarah
>
> I see the difference, but pardon the big ya
data that contain NA values (pcaMethods), but wasn't able
to get the code to work...
(I understand that this isn't strictly an R question, but any help would be
appreciated.)
2. Does my code look correct for the PCA and visualization (see below)?
Thanks in advance,
Sarah
#rea
re it says "The - operator
removes the specified terms".
Sarah
On Wed, Sep 21, 2016 at 10:19 AM, mviljamaa wrote:
> So I found out that to remove the (Intercept) term from lm's model one can
> add -1 to the predictors. I.e. do lm(resp ~ x1 + x2 - 1)
>
> Another way is
caMethods), but wasn't able
to get the code to work...
(I understand that this isn't strictly an R question, but any help would be
appreciated.)
2. Does my code look correct for the PCA and visualization (see below)?
Thanks in advance,
Sarah
#read data
mesocleaned <- read.csv("Meso
The only google hit appears to be that paper, which is a 2014 PhD
dissertation, and states that the author will be uploading it on CRAN.
Since that hasn't been done, the only thing you can do is try to track
down the author and ask.
Sarah
On Tue, Sep 27, 2016 at 4:45 AM, stud1830153714
or constructing packages. Though on linux, I use a local
.Rprofile if I need per-session options, because I often don't have a saved
.RData file.
Sarah
--
Sarah Goslee
http://www.stringpage.com
http://www.sarahgoslee.com
http://www.functionaldiversity.o
ng list as r-help_AT_stat.math.ethz.ch.
>
> Are these different mailing lists?
They are the same. r-help@r-project.org is the preferred address, but the
mailserver is run out of stat.ethz.ch.
Sarah
Useful info
> __
> R-help@r-project
down.
Sarah
On Mon, Apr 20, 2015 at 12:33 PM, Sonia Amin wrote:
> Dear All,
>
> I have written the following lines:
>
>
> data<-read.table("C:\\Users\\intel\\Documents\\SIIID\\datamultiplereg.txt",header
> = FALSE, sep = "")
> colnames(d
On Mon, Apr 20, 2015 at 12:56 PM, Sonia Amin wrote:
> Sorry Sarah for my basic question: what does "a column was read as factor"
> mean?
A factor is one of the basic types of data in R, and in statistics
generally, eg M/F or red/white/blue - a predetermined set of
categories tha
0,0,1,0,0), Camp3 = c(0,1,0,1,0))
aggregate(rowSums(testdata[, -1] == 0), list(testdata$EmpSize), FUN="sum")
--
Sarah Goslee
http://www.functionaldiversity.org
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.
data$Type_Desc), 1, 0)
test1.rle <- rle(test1)
test0.rle <- rle(test0)
if(any(test1.rle$lengths >= 5 & test1.rle$values == 1))
cat("Type_high\n")
if(any(test0.rle$lengths >= 5 & test0.rle$values == 1))
cat("Type_low\n")
ussions of that very topic on this mailing list, and other useful
information.
Sarah
On Thu, May 14, 2015 at 6:50 AM, Preethi Balaji
wrote:
> Dear R users,
>
> I am new to R and trying to learn raster image processing in R.
>
> I have a tiff image with pixel values and I am trying
tp://cyclismo.org/tutorial/R/
Sarah
--
Sarah Goslee
http://www.functionaldiversity.org
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-projec
;, ylim = c(0,9000), cex.axis=0.6,
xaxt="n")
axis(1, (0:23)+.5, 1:24, cex.axis=.6)
text((0:23)+.5, aaa.hist$counts-150, aaa.hist$counts, cex=.6)
Sarah
--
Sarah Goslee
http://www.functionaldiversity.org
__
R-help@r-project.org mailing lis
16
4 4 4 10 17
5 5 1 8 18
6 6 1 12 26
head(ids4)
id v1 v2 v3
1 1 1 2 8
2 2 2 19 22
3 3 3 21 16
4 4 4 10 17
5 5 1 8 18
6 6 1 12 26
Kate, if you're getting all zeros, check str(yourdataframe) - it's
likely that when you imported your data into R the strings were
alre
s? That is, what is the result you expect to obtain
for the sample data you provided?
What code have you tried? I would think table() might be involved, and
possibly strsplit(), but will refrain from putting more time into this
until you provide a reproducible dataset with dput() and some clearer
i
1111
411 0000
510 0000
>
On Fri, May 29, 2015 at 4:58 PM, Bogdan Tanasa wrote:
> Hi Sarah,
>
> thank you for your help. I have simplified the example, by read
LMGTFY:
http://stackoverflow.com/questions/11433432/importing-multiple-csv-files-into-r
On Fri, May 29, 2015 at 5:58 PM, Bogdan Tanasa wrote:
> Dear Sarah,
>
> thank you very much, it is very helpful. please may I ask one more question
> about a quick and easy tutorial about
ems to work on the first element of the vector.
>
> I.E.
> scale
> function(x,mn,max){
> if (x==min(x)) 0
>
> if (x==max(x)) 10
> else x=max-min/10
> }
>
> where x is the numeric column of the dataframe.
>
> Thank you.
>
>
>
--
the code you used, and some clear idea of what output you
expect, it's impossible to figure out how to help you. Here are some
suggestions for creating a good reproducible example:
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
Sarah
On Tue, Jun 2, 2015 a
The first line tells you that your matrix is numeric (matrices can
only contain elements of one type), that it has 64 rows and 6 columns,
and a bit of what the contents look like.
The second line tells you that your matrix has as attributes a list of
two dimnames, and the subsequent lines tell yo
The dangers of HTML: > should be > a greater than symbol.
grecent <- subset(gtemp, subset = Year >= 1995,select = c(Year, Annual))
I've copied Gavin so he can decide whether to fix it.
Sarah
On Thursday, June 4, 2015, Jackson Rodrigues
wrote:
> Hi,
>
>
>
> I
Easiest? Use sub() to replace the periods after the fact.
You can also use the check.names or the col.names arguments to
read.table() to customize your import.
Sarah
On Mon, Jun 8, 2015 at 10:15 AM, John Sorkin
wrote:
> I am reading a csv file. The column headers have spaces in them.
I've taken the liberty of copying this back to the list, so that others can
participate in or benefit from the discussion.
On Mon, Jun 8, 2015 at 10:49 AM, John Sorkin
wrote:
> Sarah,
> I am not sure how I use check.names to replace every space in the names of
> my variables wit
ame format with % that is
>
>
>> dd<-c("21/01 11:11:11")
>> strptime(dd,"%d/%m H:M:S")
> [1] NA
>
>
> it is giving NA.
>
>
>
--
Sarah Goslee
http://www.functionaldiversity.org
__
R-help@r-p
explore a little bit and found
>
>> as.character(dgrid)
> [1] "0.101" "0.2"
> [3] "0.0996" "0.101"
> [5] "0.0996"
>
> which shows the absolute values of
ot
> found:
>
> for (i in 1:nrow(df)) {
> df[i,"htn"] <- any(sapply('410', function(x) which( grepl(x, df[i, 2:4],
> fixed = TRUE) )))
> }
>
> Thanks in advance. I never fail to learn new things from this list.
>
--
Sarah Goslee
http://www.funct
", 4/2, ifelse(mydata$Color ==
> "<5", 5/2, as.numeric(mydata$Color)))
> mydata
Color Unit NewColor
1:2 5 Hazen 5.0
1:3<4 Hazen 2.0
1:4 5 Hazen 5.0
1:5<5 Hazen 2.5
1:6 5 Hazen 5.0
This will throw a warning message that y
and BH(FDR) as
genes there are.
the same I would need to do for the sensitivity... and so on.
Do you think this is doable? I am not at all a bioinformatic expert, so all
help is very welcome.
Thank you very much!
Kind regards,
Sarah
--
Sarah Bazzocco, PhD student
Group
1 - 100 of 1933 matches
Mail list logo
