WRAY NICHOLAS [2015.11.18] wrote:
>
> I'd like to get shot of the junk files, but I can't distinguish them by
> names/label from the ones I want to keep -- the only criterion is the date of
> making them, but I cannot see a way of telling R to look at the date rather
> than
> the name/label Ob
s cucullatus, herb, 19
Mauritius , 1874 , Circus alphonsi, carn, 0.63
Mallorca , 3667 , Myotragus balearicus, herb, 40
Mallorca , 3667 , Aquila chrysaetos, carn, 4.2
Kreta , 8259 , Elephas creutzburgi, herb, 3200
...
/Par
--
Par Leijonhufvud p...@hunter-gath
line from the latter,
but (no surprise) none from the former. Now I just need to fix my
assumptions such that I produce a line that is an actual regession
line...
Thanks for making me think it through!
/Par
--
Par Leijonhufvud p...@hunter-gatherer.org
The best com
I'm working on a quick tutorial for my students, and was planning on
using Mann-Whitney U as one of the tests.
I have the following (fake) data
grade <- c("MVG", "VG", "VG", "G", "MVG", "G", "VG", "G", "VG")
sex <- c( "male", "male", "female", "male", "female", "male", "female",
"male", "ma
Steven McKinney [2010.10.29] wrote:
> You can set up the data as
>
> > grade <- ordered(c("MVG", "VG", "VG", "G", "MVG", "G", "VG", "G", "VG"),
> > levels = c("G", "VG", "MVG"))
> wilcox.test(as.integer(grade) ~ sex, data = gradesbysex)
Thanks, this solved my problems. I'll just explain the pr
Peter Dalgaard [2010.10.30] wrote:
> I wouldn't bother with that. The p-value is based on the correct
> covariance matrix of the rank sums, tie-breaking just adds noise to the
> analysis.
Good to know.
> If you really want an exact p-value, package exactRankTests is
In this case I suspect that
6 matches
Mail list logo