created variables with names
one_df, two_df and three_df earlier in the same script which I want to
reference inside the for loop. Is there a more elegant way to do this?
Best Regards,
Michael Bach
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for its functional style.
> hth.
It did, thanks.
Kind Regards,
Michael Bach
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Kenn Konstabel writes:
> Another way (not elegant but better and shorter than the eval-parse
> way) is to use get. ?get
This one is handy for interactive use, thanks for the hint.
Kind Regards,
Michael Bach
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27;s own plot method where mfrow(4,1) etc. is
defined. Now suppose I wanted to wrap those mfrow(4,1) into my own
mfrow(2,2) layout. How could I achieve this? Is there a general way to
handle these cases? Something like a "meta" par(mfrow())?
Best Reg
Uwe Ligges writes:
> On 29.04.2011 17:10, Michael Bach wrote:
>> Dear R Users,
>>
>> I am doing stats::decompose() on 4 different time series. When I issue
>>
>> csdA<- decompose(tsA)
>> plot(csdA)
>>
>> I get a summary plot for observed,
Prof Brian Ripley writes:
> On Mon, 2 May 2011, Michael Bach wrote:
>
>> Uwe Ligges writes:
>>
>>> On 29.04.2011 17:10, Michael Bach wrote:
>>>> Dear R Users,
>>>>
>>>> I am doing stats::decompose() on 4 different time serie
something wrong /
addtitional config needed?
Thanks in advance,
Michael Bach
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Dear All,
I was wondering why the forecast for an additive HoltWinters model is given
by Yhat[t+h] = a[t] + h * b[t] + s[t + 1 + (h - 1) mod p].
I am a student and new to time series analysis and forecasting. That said, I
considered t = 13 and h = 1: Yhat[13+1] = a[13] + b[13] + s[13 + 1]
It see
attach my csv file?
Best Regards,
Michael Bach
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and
column headers. This caused M[[x]] to evaluate to NULL which in
turn triggered the "scales of x and y are too dissimilar" since there is
indeed no scale whatsoever in NULL.
On Fri, Mar 18, 2011 at 1:21 PM, Duncan Murdoch wrote:
> On 18/03/2011 6:37 AM, Michael Bach wrote:
>
>>
e following work?
14 > as.POSIXlt(dx)$hour & as.POSIXlt(dx)$hour < 10
Is there something I miss about subset()? Or is there even another way of
aggregating over an hourly time interval in a nicer way?
Best Regards,
Michael Bach
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s?
Thanks for your help David.
On Thu, Mar 24, 2011 at 3:44 PM, David Winsemius wrote:
>
> On Mar 24, 2011, at 9:29 AM, Michael Bach wrote:
>
> Dear R users,
>>
>> Given this data:
>>
>> x <- seq(1,100,1)
>> dx <- as.POSIXct(x*900, origin="
@Kenn: Yeah I have a way of loosing concentration when fiddling around and
trying to get it work. Thanks for pointing out that I supplied a third
argument when I wanted an additional test in the second argument instead.
Also my selection choices indeed do not make any sense, no wonder your
"parser"
bset(dfx, dx > ymd("2007-06-01") & hour(dx) > 10 & hour(x) < 14)
>
>
You are certainly right about that...
Best Regards,
Michael Bach
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Hi there,
I was doing great with R, ggplot and tikzDevice, when suddenly it stopped
working.
I can do a plot just fine on the R online graphics device. I can also open a
tikzdevice via tikz(). However, the plot (both ggplot and R graphics plot)
call leads to the error:
"createLockFile(lockname):
lly specify
nrow=2. It behaves as if I had not given the ncol argument. Any hints
on what might be borked up here?
R.Version()$ver
[1] "R version 2.10.1 (2009-12-14)"
Thanks in advance,
Michael Bach
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Hi Adrian,
thanks for the hint. The problem was that it showed me help for matrix
when I did ?as.matrix. I thought it was some kind of convention that
data type conversion functions start with "as.", so now I will take more
care in the future.
With matrix() it works as expected, thanks again.
es it? All searches I did pointed me to data
type frame to matrix conversion...
Kind Regards,
Michael Bach
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David Winsemius writes:
> Perhaps but only if the third row of your example was incorrectly constructed:
>> dta <- rd.txt(" x y z
> 1 1.00 5 0.5
> 2 1.02 5 0.7
> 3 1.04 7 0.1
> 4 1.06 9 0.4")
> #rd.txt() is a combo fn of read.table and textConnection
>
>> mat <- matrix(NA, ncol=NROW(dta)+1,
Petr PIKAL writes:
> Hi
>
> r-help-boun...@r-project.org napsal dne 19.04.2011 09:46:47:
>
>> Dear R Users,
>>
>> Lets assume I have this data frame:
>>
>> x y z
>> 1 1.00 5 0.5
>> 2 1.02 5 0.7
>> 3 1.04 7 0.1
>> 4 1.06 9 0.4
>>
>> x and y columns are sorted and the values not necessari
David Winsemius writes:
> On Apr 19, 2011, at 8:16 AM, Michael Bach wrote:
>
>> David Winsemius writes:
>>
>>> Perhaps but only if the third row of your example was incorrectly
>>> constructed:
>>>> dta <- rd.txt(" x y z
>>>
Dear R Users and Developers,
I am trying to do the equivalent of
v <- c(1,2,3,3,2,1,)
vu <- unique(v)
for a vector such as
v2 <- c(1.02, 2.03, 1.00, 3.04, 3.06)
vut <- ...
As indicated in the subject, we need approximately unique values with a defined
tolerance, i.e. for the v2 vector the resu
Thanks to both of you for suggestions.
I settled for the round() approach.
much obliged,
Michael Bach
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On 9/6/2012 7:24 PM, Bert Gunter wrote:
... and if it Duncan's suggestion won't do, maybe approaching it via
clustering might be useful.
But do note that, as stated, the problem is not well defined, because
transitivity fails: consider
v <- c(1,2,3,4,5,10)
with a tolerance of <=2. Then 1 is the
s the subject
states, I need a way of inserting this word field from R2wd -
something along the lines of:
> wdField("<>= plot(1:100)")
sadly, I did not find that in the documentation. Any ideas or hints?
Best Regards,
Michael Bach
[1] http://cran.r-project.org/web/packages/R2wd/inde
ion (x) { return (x*x) }
w <- applyfun(v, mysquare, 2)
then w should be c(1, 4, 3, 16)
Thanks for your time,
Michael Bach
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Thank you very much for your comments Ista and David! I will
experiment and see which one serves my needs best.
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