how to do it faster?
thank you kindly,
Matthew Finkbeiner
"Sample""C1""C2""PermN"
158perm1
143perm1
164perm1
226perm1
231perm1
274perm1
1
how to do it faster?
thank you kindly,
Matthew Finkbeiner
"Sample" "C1" "C2" "PermN"
1 5 8 perm1
1 4 3 perm1
1 6 4 perm1
2 2 6 perm1
2 3
Yes, I suspect that I will end up using a sampling approach, but I'd
like to use an exact test if it's at all feasible.
Here are two samples of data from 3 subjects:
Sample SubjC1 C2
44 1 0.0093 0.0077
44 2 0.0089 0.0069
44 3 0.051 0.0432
44 4
I'm sorry for what I'm sure is a terribly simple question. I have a large
dataframe along these lines:
S<- 1:3
d<- data.frame(cbind(S=rep(paste('S',S,sep=""),each=30),
trial=rep(1:3,each=10),
FactorA=rep(paste('L',1,sep=""),each=30), Acc=
c(rep(1,each=20),rep(0,each=10)),
Sample=rep(1:10,
Hi Daniel, thanks for your reply. Unfortunately, that is not doing what I
need. In the example I sent, there are three subjects (S1, S2 & S3). Each
subject has 3 trials worth of data and each trial has 10 samples. What I
want to return is the accuracy rate for each subject. The answer is 66.6
I don't have enough RAM for this problem, so I need a work around. This is
what I want to do:
y<- sample(2^32, 10, replace=FALSE)
but my machine won't let me do that. so I now do this:
x<- seq(1,2^32, by=100)
y<- sample(x, 10, replace=FALSE)
this works fine, but by selecting every 100
I am trying to interpolate missing values using spline and am running
into some strange problems.
first, this works just fine:
x<- c(1:10, rep(NA, 3), 14:20)
y<- c(rnorm(10), rep(NA,3), rnorm(7))
s<- spline(x,y, n=length(x))
plot(x,y)
lines(s, col="blue")
but look at what happens with my real d
s under
> the impression that for a hermite spline fit the xs had to be strictly
> increasing (as in your toy example) whereas in your actual data the x
> values increase then decrease.
>
> Michael
>
> On 2 October 2010 11:59, Matthew Finkbeiner
> wrote:
>> I am trying
I have a list of data frames like this:
a<- data.frame(x=runif(10), y = runif(10), Acc = 1)
b<- data.frame(x=runif(10), y = runif(10), Acc = 0)
ls<- list(a,b)
and I want to remove the data frames from ls that have Acc values other than 1.
How do I do that?
Thanks for any help!
Matthew
___
90820779 0.3841037 1
> 5 0.20168193 0.7698414 1
> 6 0.89838968 0.4976992 1
> 7 0.94467527 0.7176185 1
> 8 0.66079779 0.9919061 1
> 9 0.62911404 0.3800352 1
> 10 0.06178627 0.7774452 1
>
>>
>
> On Sun, Nov 7, 2010 at 6:07 AM, Matthew Finkbeiner
> wrote:
Hi, I am trying to scramble items in a matrix so that no item repeats on
consecutive rows. This generates the matrix:
LevelsOfA = 2
LevelsOfB = 2
LevelsOfC = 3
Items = 10
FactorA = rep(1:LevelsOfA, each=(LevelsOfB*LevelsOfC*Items))
FactorB = rep(rep(1:LevelsOfB, each=(LevelsOfC*Items)),LevelsOfA
I have a list of data frames like the following:
set.seed(123)
a<- data.frame(x=runif(10), y = runif(10), sample = seq(1,10))
b<- data.frame(x=runif(10), y = runif(10), sample = seq(1,10))
L<- list(a,b)
All data frames in the list have the same dimensions. I need to calculate
the sample means fo
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