Hey List,
does anyone know how I can generate a vector of random numbers from a
given distribution? Something like "rnorm" just for non normal
distributions???
Thanks a lot!
Anna
--
Der Inhalt dieser E-Mail ist vertraulich. Sollte Ihnen die E-Mail
irrtümlich zugesandt worden sein, bitte ich
Hi,
I have a stupid and simple question.
Please forgive me.
In an example below, please tell me how to call "1947" in mydata.
Thank you in advance.
Wonjae
> mydata
[[1]]
[1] "1947""83" "234.289" "235.6" "159" "107.608" "1947"
[8] "60.323"
> mydata[[1],1]
error:unex
Hi,
I have some problems with as.Date function.
After I applied as.Date for my data, "2010" changed to "2020" as below
Where am I wrong?
Thanks
Wonjae
> x=c("11/16/2010","11/17/2010","11/18/2010","11/19/2010")
> x=as.Date(x,"%m/%d/%y")
> x
[1] "2020-11-16" "2020-11-17" "2020-11-18" "2020-11-19"
Thank you for replying the as.Date error question.
I have one more question as below.
I used cbind command, and data x changed, 2010-11-16 to 14929, 2010-11-17 to
14930.
What happened to them?
What should I do to see -mm-dd format data?
> x=c("11/16/2010","11/17/2010","11/18/2010","11/19/201
Dear list,
I'm trying to fit a chapman-richards equation to my data, only I
cannot interpret the parameters a, b and d. I know that the parameter
b denotes the asymptote, but for the others I couldn't figure out. But
I do need to know this in order to set my starting values. Here's the
model:
mod
Dear list,
I'm trying to fit a chapman-richards equation to my data, only I
cannot interpret the parameters a, b and d. I know that the parameter
b denotes the asymptote, but for the others I couldn't figure out. But
I do need to know this in order to set my starting values. Here's the
model:
mod
Dear list,
I'm trying to fit a chapman-richards equation to my data, only I
cannot interpret the parameters a, b and d. I know that the parameter
b denotes the asymptote, but for the others I couldn't figure out. But
I do need to know this in order to set my starting values. Here's the
model:
mod
I have spent hours on this ---looked through the quantreg manual and r-help
site--- still couldn't figure out the answer. Can someone please help me on
this?
I plot the result from quantile regression and want to change the variable
labels:
temp<-rq(dep~inc+age50, data=newdata, tau=1:9/10)
Hi Roger,
Maybe I'm missing a clue. Here's an example:
x<-rnorm(50)
x1<-rnorm(50)
y<-x+x1+rnorm(50)
out<-rq(y~x+x1, tau=1:9/10)
plot(summary(out))
plot.out<-plot(summary(out))
#I change the variable names
dimnames(plot.out)<-list(c("intercept", "sex", "inc"))
#Look at the plot
#it's ONE si
Why not just change the names of the variables before invoking the call to
rq, and its formula?
Because I won't be able to do longer label e.g. 'Population Density Per Square
Mile'.
I actually found the solution by accident---
x<-rnorm(50)
x1<-rnorm(50)
y<-x+x1+rnorm(50) out<-rq(y~x+x1, tau=1:9/
Hi,
I work in a kitchen production factory and I try to predict sales of kitchen
for an horizon of 12 weeks, and I have to turn into account promotions. My
sales are express in number of command, my promotion are express with dummy
variables. (1 if promotion, 0 else).
The first problem is that my
Dear list,
Hi, I am emailing to see if it would be possible to get some help on
running MCMCfactanal on R. I am trying to derive a single score measuring a
likelihood to recieve IMF loans from 8 different variables related to IMF
representation but for reason, my codes do not seem to take me to wh
Hi all-
I fit a zero-inflated Poisson model to model bycatch rates using an offset term
for effort. I need to apply the fitted model to a datasets of varying levels of
effort to predict the associated levels of bycatch. I am seeking assistance as
to the correct way to code this.
Thanks in adva
Thanks for your reply. I do have a copy of "Zero Inflated Models and
Generalized Linear Mixed Models with R" and have been using that as a guide.
I applied the predict function (type="count") to the dataset for which I
built the model to compare the predicted bycatch numbers to the observed to
ensu
012 5:20 PM
To: Lee, Laura
Subject: Re: Predicted values for zero-inflated Poisson
Laura Lee laura.lee at ncdenr.gov
Mon Jul 9 22:51:40 CEST 2012
Previous message: [R] Predicted values for zero-inflated Poisson
Next message: [R] Lavaan Package - How to Extract Residuals in Data V
led effort), would
I use sum(predict(ZIP,newdata=effort,type="response"))? I want to be certain
I am understanding the coding--this is my first time using the predict
function.
Thanks,
Laura
-
Laura M. Lee
Senior Stock Assessment Scientist
North Carolina Division of Marine Fis
5n4636025...@n4.nabble.com]
Sent: Tuesday, July 10, 2012 1:52 PM
To: Lee, Laura
Subject: Re: Predicted values for zero-inflated Poisson
*Laura Lee* laura.lee at ncdenr.gov
<mailto:r-help%40r-project.org?Subject=Re%3A%20%5BR%5D%20Predicted%20values%20for%20zero-inflated%20Poisson&In-Reply-To=%3
Hi all!
I have built a model to predict interactions with turtles and the model
includes an offset for effort:
ZIP<-zeroinfl(Sturgeon~fMesh+fSeason+offset(LogEffort),dist="poisson",link="logit",data=data)
I wasn't clear about one aspect of the response to a similar question I
recently posted..
ge
4a blink
4a orange
4a bedroom
4acurb
4abowl
Some of the words are presented to multiple participants others are not. I am
trying to get an index of 1) which words are repeated and 2) how many times
they are repeated. Any suggestion
RT for each word and add
that as a column in the second data frame.
Any help would be appreciated
Cheers
Lee
Data frame 1
> head(alldat)
s expt session cycle trial left.right freq concrword rt resp
Response correct corrResp
121 1aa 1C1 1 1 lfhc pian
Hi, all
Here is what I tried to do.
> strptime('20110101 0900',"%Y%m%d %H%M")
[1] "2011-01-01 09:00:00"
> strptime('20110101 900',"%Y%m%d %H%M")
[1] NA
If I have a 3-digit hour like '900', please show me how to convert it to
09:00:00.
Thank you in advance.
Wonjae
--
View this message in co
I used matplot to plot multiple lines (over 300 lines). I'd like to draw a
polygon and shade the area between upper and lower boundary.
I know the plot function works pretty well with polygon(). How about matplot? I
have too many lines and my upper/lower boundaries are formed by many different
Hi all,
I'm just having trouble getting row means of a matrix which
contain zero.
For example.
m=matrix(c(1:4, c(0, 0, 0, 0), c(1, 0, 1, 1)), nc=4, byrow=TRUE)
I want to be able to calculate means for non-zero elements for each row.
## what i have is this
apply((m[apply(m != 0, MARGIN
I came across the package 'ineq' that computes a variety of inequality measures
(e.g. gini, theil etc). I want to compute the Theil index (racial segregation)
and decompose the total into sub-components (by geog levels). I think the
package doesn't report the decomposition (correct me if I'm wro
Hello,
I have a matrix
animaltime A01 A02
A d0 -5.4 2.7
A d1124.6 5.9
A d224 3.96.3
B
nt here).
Thank you in advance,
Lee
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide c
Hello everyone!
I work with a german excell version which uses commas instead of
points for seperating decimal places. R work with points so in order
to be able to save my excell tables without changing the commas to
points, whenever I load a table I type in: read.table(..., dec = ",")
only R puts
Sorry guys, I allready found the solution. Excell showed some of the
numbers in the format: 1,90053-E05 and R interpreted it as 1.9... I
changed that in Excel
Cheers, Anna
Am 6. Oktober 2011 17:48 schrieb Uwe Ligges :
>
>
> On 06.10.2011 17:39, Anna Lee wrote:
>>
>> Hello e
e still
there, because if I edit a pgAdmin-created file in Notepad or gedit, then
save and read into R with readLines, they are there.
Best,
--Lee
--
Lee Hachadoorian
PhD, Earth & Environmental Sciences (Geography)
Research Associate, CUNY Center for U
Hello everyone,
I have a data frame (tt), see below (I only show 2 genes, actually I have a
lot):
groupgene1 gene2 Control 28.9776 9.9355
Control 28.9499 10.0997 Control 29.5468 14.2995 Control 29.5246 13.9561
Test1 29.1864 9.7718 Test1 29.2048 10.0388 Test1 34.95
Hello everyone,
I posted a question this morning, when I got replies, I realized that the
data I posted was messy. So I am going to re-post it.
Here is my data frame:
groupgene1 gene2
Control 28.9776 9.9355
Control 28.9
On 04/14/2012 09:37 AM, Duncan Murdoch wrote:
sql <- sub("\uFEFF", "", sql)
Thank you, this worked exactly.
Best,
--Lee
--
Lee Hachadoorian
PhD, Earth& Environmental Sciences (Geography)
Research Associate, CUNY Center for Urban Research
http://f
Hello. I am using the zeroinfl package to fit a zero-inflated negative
binomial. The explanatory variables are Year and Depth x STemp (interaction). I
am in need of guidance for extracting the year effect and the associated
precision.
Thank you for your time.
Cheers,
Laura
Hi
I have a data table matrix,"data" which looks like below:-
V1V2 V3
1 -6382.719 -1096.554 6998994
2 -some values-
3 -some values-
4 -some values-
5 -some values-
Querying dim of "data" gives me 3 columns and 5 rows.
And currently I want to plot "V1" against "V2" with the
00), ncol=3)
> plot(x[,1], x[,2], type='l')
> points(x[5,1], x[5,2], pch=17, cex=3, col='red') # plot point #5
>
> On Fri, May 23, 2008 at 8:50 AM, Jason Lee <[EMAIL PROTECTED]> wrote:
>
>> Hi
>>
>> I have a data table matrix,"data
Hi,
I have a couple of text and would like to automate of reading these multiple
files using
(namely; text1.txt, text2.txt)
for(y in 3:10){
data$y<-read.table('text$y.txt')}
But it seems not allow. Any idea?
Thanks.
[[alternative HTML version deleted]]
___
Hi,
I have a data frame which format is like below:-
X Y Z
131 22.2 3.4 4.4
150 20.0 12.2 4.5
etc...
And I have sorted the data frame. However, I would like to grab one of these
elements in the data frame. Also, i would like to number these rows so that
when i grab a particul
e calculation?
On Tue, Jun 3, 2008 at 12:02 AM, Marc Schwartz <[EMAIL PROTECTED]>
wrote:
> on 06/02/2008 08:45 AM Jason Lee wrote:
>
>> Hi,
>>
>> I have a data frame which format is like below:-
>>
>>X Y Z
>> 131 22.2 3.4 4.4
>
Hi R-listers,
I have problem in executing my R on server. It returns me
Error: cannot allocate vector of size 15.8 Mb
each time when i execute R on the server. But it doesnt give me any problem
when i try executing on my own Pc (except it runs extremely slow).
Any pointers to this? I tried to r
I am running on Sun Solaris server.
Please advise.
Thanks.
On Fri, Jun 6, 2008 at 11:50 AM, Erik Iverson <[EMAIL PROTECTED]>
wrote:
>
>
> Jason Lee wrote:
>
>> Hi R-listers,
>>
>> I have problem in executing my R on server. It returns me
>>
>&g
<[EMAIL PROTECTED]>
wrote:
>
> On 6/06/2008, at 1:36 PM, Jason Lee wrote:
>
> Hi R-listers,
>>
>> I have problem in executing my R on server. It returns me
>>
>> Error: cannot allocate vector of size 15.8 Mb
>>
>> each time when i execute
d in your Sun Solaris server? How much RAM is
> installed on your PC?
>
> Jason Lee wrote:
>
>> Hi,
>>
>> I am actually trying to do some matrix multiplications of large datasets
>> of 3000 columns and 150 rows.
>>
>> And I am running R version 2.7.0.
t;
wrote:
> And what is your sessionInfo() in each case!
>
> Jason Lee wrote:
>
>> Hi,
>>
>> I query free -m,
>>
>> On my server it is,
>>
>> total used free sharedbuffers cached
>> Mem: 321
. Thanks.
On Fri, Jun 6, 2008 at 2:49 PM, Ray Brownrigg <[EMAIL PROTECTED]>
wrote:
> What does the limit (or "ulimit -a" in sh or bash) command (outside of R)
> respond with?
>
> In Solaris, there can be per-user limits to memory use.
>
> HTH,
> Ray Brownrigg
0.1
year 2004
month11
day 15
language R
Any help to this query would be very much appreciated. Cheers.
Sincerely
- Derrick
Derrick Lee, MSc Candidate
Department of Statistics
The University of British Columbia
LSK-314A | 604 - 822 - 1299 x532
d.lee at stat dot ubc dot ca | dgylee
month11
day 15
language R
Any help to these queries would be very much appreciated. Cheers.
Sincerely
- Derrick
Derrick Lee, MSc Candidate
Department of Statistics
The University of British Columbia
LSK-314A | 604 - 822 - 1299 x532
d.lee at stat dot ub
rrick!
Is your subroutine named "chol"?
There is a function in R by the name of chol.
You might be having a problem with that.
thanks,
Erin
On Wed, Jun 11, 2008 at 2:39 PM, Derrick Lee <[EMAIL PROTECTED]> wrote:
Dear Fellow R-Users,
I am having some difficulties loading a For
month11
day 15
language R
Any help to these queries would be very much appreciated. Cheers.
Sincerely
- Derrick
Derrick Lee, MSc Candidate
Department of Statistics
The University of British Columbia
LSK-314A | 604 - 822 - 1299 x532
d.lee at
Hi,
Currently I have a dataset of 2400*408. And I would like to apply PCR method
to study the any correlation between the tests.
My current data is in data.frame and I have formed horizontal(1-407) to be
the exact data, and (408) to be my results data(Yes and No)
I have also binarized these Yes an
Hi,
Currently I have a data set of 2 classes and I am interedted to use emerging
patterns algorithm. I wondered if there is any packages or recommended code
available for this?
Please advise.Thanks.
[[alternative HTML version deleted]]
__
R-h
Hi,
Thanks for the reply.
Basically I dont have any label for my data except column 1 which is labeled
with Sample1, Sample2...etc...(vertical).
My cancerv1 data is data.frame.
So, I used df <- data.frame( x=I(coef(cancerv1(,2:407))),
y=cancerv1[,408])before feeding to PCR.
However, I get the b
Hi,
Recently I try to install Biobase component using the tutorials from
cran.r-project.org/doc/Rnews/Rnews_2006-5.pdf
I tried
u <- "http://bioconductor.org/biocLite.R";
> source(u)
> biocLite("pkgDepTools", dependencies=TRUE)
Running biocinstall version 2.0.8 with R version 2.5.1
Your version o
Hi,
I am aware this is somehow FAQ question but I ve been searching from R-cran
archive about the related matter and could not find anything closer to this.
I want to upgrade my R version from 2.5.1. to 2.7.1. What is the best way to
load the latest one apart from installing the packages (tar.gz)
I checked from Ubuntu distro and the latest package only show 2.5.1. Anyone
has the similar problem too?
On Mon, Jul 7, 2008 at 11:39 AM, Jason Lee <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I am aware this is somehow FAQ question but I ve been searching from R-cran
> archive about
Hi R-listers,
I would like to know how can i extract component no. when the RMSEP is
lowest?
Currently, I only plot it manually and then only feed the ncomp to the jack
knife command. However, I would like to automate
this step.
Please let me know. Many thanks.
Rgrds,
[[alternative HTM
Hi
You can try using the ctc package to export your dendrogram objects and use
Cluster to open them.
This package is part of biocondutor.
>>source("http://bioconductor.org/biocLite.R";)
>>biocLite('ctc')
regards
Julian Lee
- Original Message -
From: Ji
Hi!
I'm having a trouble changing font size of histogram label.
I have tried help(hist), but I couldn't find anything explain how to fix
label's font size.
Could you help me please?
Thank you.
_
Going green? See the top 12 foods t
cerely
- Derrick
Derrick Lee, MSc Candidate
Department of Statistics
The University of British Columbia
LSK-314A | 604 - 822 - 1299 x532
d.lee at stat dot ubc dot ca | dgylee at mun dot ca
www.stat.ubc.ca/~d.lee/ | www.math.mun.ca/~derrick0/
__
R-
Hi,
I have a data file which is named test.txt as below. Prior to that, I have
converted the last row from nominal to numeric using as.integer.
Statement T1001 T1002 T1003 T1004 T1005 T100 T1014 T1021 T1022 T1023
1 0 0 0 0 0 00 0 1 0 0
20
Hi,
I just started using R for about one week and I have few problems.
i)I have a problem in finding right function to convert a table of natural
numbers to bitwise. For a simple example;
I have the below table:-
Column Col1 Col2 Col3
Sample1 57 10
Sample2 02 1
S
Dear R-users,
I use R to run spatial stuff and it takes up a lot of ram. Runs can take hours
or days. I am thinking of getting a new desktop. Can R take advantage of the
dual-core system?
I have a dual-core computer at work. But it seems that right now R is using
only one processor.
The new
Dear users,
I try to follow the instruction on this page to install R on 4.4BSD network.
http://cran.r-project.org/doc/manuals/R-admin.html#Using-make
I can unpack the file but the system can't recognize the command:
./configure
make
Any ideas what should be the right command?
Thanks!!
K.
Thanks to Saeed Abu Nimeh. I used pkg_add to install R package on 4.4BSD.
My directory now has the following:
BUILDDIRMakefrag.cc_lo config.log m4 tests
MakeconfMakefrag.cxxconfig.status po tools
MakefileR-2.6.1 doc
Dear members,
I was trying to simulate W which is iid and depends on X and Y.
Here are 2 methods:
Method 1:
x<-rnorm(100)
y<-rnorm(100)
w<-rnorm(100, 2x+y,1)
Method 2:
x<-rnorm(100)
y<-rnorm(100)
w<-2x+y+rnorm(100,0,1)
Are these methods comparable?
Since x and y are vectors, the term 2x
Hello,
I'd like to pass a column name as the argument for a function, but I'm
getting "NULL" as a return value. Any suggestions? Thanks.
> d <- data.frame(cbind(x=1, y=1:10))
> d
x y
1 1 1
2 1 2
3 1 3
4 1 4
5 1 5
6 1 6
7 1 7
8 1 8
9 1 9
10 1 10
> testing <- function(var) {
Hello,
I'm trying to use tapply to find group means in a function. It works
outside of a function, but I get the error message from the following code:
"Error in tapply(index, cluster, mean) : arguments must have same length."
Any suggestions? Thanks.
eric
d <- data.frame(cbind(cluster=1:2, va
Hi,
How do I get labels onto the output from tapply? I need the labels to merge
the output with another data frame. Thanks.
eric
d <- data.frame(cbind(x=1:3, y=1:10))
a <- with(d, tapply(y, x, sum))
[[alternative HTML version deleted]]
__
R
Hi R-list,
I would like to know how to perform any elimination of attribute (column) in
R.
E.g I have:-
20,21,22,23,24,25,normal
1,2,3,4,5,5,normal
0,1,0,2,3,4,abnormal
...
I intend to do a checking on each column:-
If the column sum of abnormal is 0 but the column sum of normal is nonzero,
i
Hi,
I'd like to merge the following list and data frame by matching the first
column in the data frame to the first number in each object of the list.
I'd also like the merged object to be a list. Any suggestions? Thanks.
eric
a <- list(c(1,11), c(2,12), c(3,13), c(4,14), c(5,16))
b <- data.f
Hi. I have a list where each object in the list has multiple parts. I'd
like to take the mean of just one part of each object. Is it possible to do
this with lapply? If not, can you recommend another function? Thanks.
eric
> x1 <- c(0,1,2,3)
> x2 <- c(7,8)
> x3 <- c(2,6,6,8)
> x4 <- c(4,8)
>
Hi,
I came across the below error when I try to do ifelse condition:-
Error in "[<-"(`*tmp*`, test, value = rep(yes, length = length(ans))[test])
:
incompatible types
What I am trying to accomplish is :-
for(x in 1:ncol(filterpred)){
sumno<-sum(filterpred[no,x])
sumyes<-sum(filterpred[
ing.
When I put that on a loop, it gives me the above error.
Please advise. Thanks.
On Fri, Oct 3, 2008 at 1:57 PM, Duncan Murdoch <[EMAIL PROTECTED]> wrote:
> On 02/10/2008 10:07 PM, Jason Lee wrote:
>
>> Hi,
>>
>> I came across the below error when I try to do
Hi,
I have data for one dependent variable and multiple independent variables
y = b0 + b1*x1 + b2*x2 + ...
I want to a list of all models that have some subset of the independents
(just x1 x2, and not x3, etc.) and their corresponding BIC values. Is there
a pre-existing function that does this?
Hi,
I'm trying to use ad.test or ad2.test to test whether a given data set is
exponential. I see that one of the function inputs is "distn", but I try
"exponential" and 5 other variants, but I still get the error message:
ad.test(test2, distn="exponential", fit=list(estimate = 0.167685), H=NA,
s
Hi. This may be a straight-forward question...
I have a time series from 1950 to 2000 (by year) with missing values.
Sometimes only a year has value and the adjacent years have missing data, e.g.
1950 2.7
1951
1952
1953 3.4
1954
1955
1956 2.9
1957 3.6
1958 2.7
When I use plot (type='l'), the
Hi.
I have two variables, x and y, that are each normally distributed with
mean 0 and have known standard deviations. The variables also have a
known correlation, so I can represent their correlations in a matrix
like so:
a <- array(c(0.3,0.1,0.1,0.2),c(2,2))
a
Is there an R function that gener
Hi all,
I have modeled my observations/data,say, D=y(i) (i=1,2,...,2), as a
univariate non-gausian distribution, gamma distribution y(i)~gamma(a,b) for
example, and I have also obtained N samples of a, b via WinBUGS(Gibbs
sampling), my question is: how to calculate the marginal density of D,
m
Hi. I'm trying to run the elliptic package on my computer (windows
platform, version 2.7.2). I downloaded the elliptic package zip file
from
http://lib.stat.cmu.edu/R/CRAN/
and installed it, but it says that it needs the "emulator" package.
Can you tell me where to download this? The only simi
n port 80.
I assume it's something on my end because I've been having
connectivity issues here.
Thanks again for your help.
eric
On Thu, Feb 26, 2009 at 11:22 AM, Duncan Murdoch wrote:
> On 2/26/2009 11:08 AM, eric lee wrote:
>>
>> Hi. I'm trying to run the elliptic
Thanks, Duncan. The BACCO package worked.
On Thu, Feb 26, 2009 at 11:22 AM, Duncan Murdoch wrote:
> On 2/26/2009 11:08 AM, eric lee wrote:
>>
>> Hi. I'm trying to run the elliptic package on my computer (windows
>> platform, version 2.7.2). I downloaded the ellipti
I have a puzzle
When I include an interaction in the model, many predicted probabilities are
above 1. Is that a problem with my model? I thought the predicted prob can't be
bigger than 1...
Any help would be really appreciated! Thanks!
K.
reg1<-glm(pyea~male+edu+married+inc+relig+factor(
Hi,
I'm trying to calculate p-value to findout definitely expressed genes
compare A to B situation.
I got this data(this is a part of data) from whole organism , and each
number means each expression values (that means, we could think 'a' gene
is 13 in A situation, and it turns 30 in B situation)
ew = TRUE, las=1)
> axis(2,at = axTicks(4), labels = as.character(kwResults[,2]))
but the axis on side 2 is never scaled as the first axis on side 4. I've
also checked par(), and the ylim for the graph is the same as what I set
with at in the call to axis(). Can anyone shed some light
Hi,
I'm trying to get the p-value from the 'lm' regression function as a list
object. For example, I can get r^2 from the following code by entering
summary(fm)$r.squared. Is there a way to get the p-value? If not, is there
a function where I can enter the f-value and degrees of freedom to get
Hi. I'm trying to plot two ecdf's on the same graph using two
different colors. I can plot using the same color, but it doesn't
work when I change colors? Any suggestions? Thanks in advance for
your help.
x <- c(0.80, 0.83, 1.89, 1.04, 1.45, 1.38, 1.91, 1.64, 0.73, 1.46)
y <- c(1.15, 0.88, 0.9
Hi. I have built a levelplot with 3 variables, X, Y, and Z where X and Y are
the two axes and Z represents the intensity (i.e. Z~X*Y).
Now I want to adjust the size of the grid (like a mosaic plot) where the size
of each grid is weighted by a variable, W.
Just wonder how can I do that with lev
Hi. I'm trying to take the difference in days between two times. Can
you point out what's wrong, or suggest a different function? When I
try the following code, The following code works fine:
a <- strptime(1911100807,format="%Y%m%d%H",tz="GMT")
b <- strptime(1911102718,format="%Y%m%d%H",tz="GM
Bioconductor,
* Bioconductor software packages
<http://www.bioconductor.org/packages/bioc/>
Under the section 7.39 How do I create a plot with two y-axes?,
* http://rwiki.sciviews.org/doku.php?id=tips:graphics-base:2yaxes
I appreciate your helps!
Chel Hee Lee
_
http://windowsvistablog.com/blogs/windowsvista/archive/2007/01/23/security-features-vs-convenience.aspx
I appreciate your help!
Chel Hee Lee
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do re
Thank you so much, Jim. Yes, I also see that the wiki
(rwiki.sciviews.org) is not found.
Chel Hee Lee
On 15-06-25 04:54 AM, Jim Lemon wrote:
Hi Chel Hee,
The last link (for FAQ 7.39) is dead and the domain
(rwiki.sciviews.org) is not there either.
Jim
On Thu, Jun 25, 2015 at 3:45 AM, Chel
Thank you so much, David! I also confirmed that the link moved is not
found.
Chel Hee Lee
On 15-06-24 04:15 PM, David Winsemius wrote:
On Jun 24, 2015, at 10:52 AM, Chel Hee Lee wrote:
Could you also kindly check the following links in the rw-FAQ manual at
<http://cran.r-project.org/
this project. Please
contact me if you voluntarily participate in or offer your help with
this project of translating R manuals. Comments and corrections is of
course most welcome.
Chel Hee Lee
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Hello,
I'm following previous threads on the use of varimp in the R "party" package.
I'm running up against similar problems to that described here (and the thread
referenced therein):
https://stat.ethz.ch/pipermail/r-help/2011-October/292897.html
Specifically, I'm running cforest and then varim
class
[1] "rowwise_df" "tbl_df" "tbl""data.frame"
$row.names
[1] 1 2 3 4 5 6 7
> attributes(new2)
$names
[1] "id" "mrjdate" "cocdate" "inhdate" "haldate" "oiddate"
$row.names
[1] 1 2 3
1.65
2 1 3.3 1.65
3 1 3.3 1.65
4 2 10.0 5.00
5 2 10.0 5.00
6 3 30.0 15.00
7 4 40.0 20.00
>
Is this what you are looking for? I hope this helps.
Chel Hee Lee
On 12/03/2014 03:14 PM, Brock Huntsman wrote:
I apologize if this is
tX = rbind(tX, as.data.frame(cbind(GId =0,Grp = 0,
S = fm, T = fm)))
Of course you have to do little more works with this change in order to
get final bar plots. I hope this helps.
Chel Hee Lee
On 12/03/2014 12:29 PM, Charles R Parker wrote:
I am trying to create groups of barplot
This question seems to be the problem specific to Ubuntu. What if you
post the message to ?? I hope you get
answers from that mailing list.
Chel Hee Lee
On 12/02/2014 11:10 AM, VG wrote:
Hi everyone,
I was having trouble with R i installed some time ago on my local ubuntu
machine. So i
0,19.0,24.0),right=FALSE)
> levels(achtergrond$spits) <-
c("between","morning","between","evening","between")
> table(achtergrond$spits)
between morning evening
1636 579 142
>
You can also use function 'findInterval()
example_02.dat" "new_example_03.dat"
[4] "new_example_04.dat" "new_example_05.dat" "new_example_06.dat"
>
> file.rename(from=file_names, to=new_names)
[1] TRUE TRUE TRUE TRUE TRUE TRUE
> list.files(pattern="*.dat")
[1] "new_ex
I see that a function 'format()' is used in your code.
> format(c(1,5,32,100), width=3, flag="0")
[1] " 1" " 5" " 32" "100"
> formatC(c(1,5,32,100), width=3, flag="0")
[1] "001" "005" "032&quo
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