Hi All,
I thought I’d try to get a function working instead of block copying code and
editing. My backorund is more SAS, so using a SAS Macro would be easy, but not
so lucky with R functions.
R being used on Mac Sierra 10.12.4:
R version 3.3.1 (2016-06-21) -- "Bug in Your Hair"
Copyright (C)
ong ago that attach() should be avoided to avoid name
> conflicts. Also, it makes it difficult to figure out which data is actually
> being used.
>
> HTH
> Ulrik
>
> On Tue, 9 May 2017 at 06:44 Gerard Smits <mailto:smits.gerar...@gmail.com>> wrote:
> Hi All,
>
ot;, n1, ")"), paste0("Low Dose (N=", n2, ")"),
> paste0("High Dose (N=", n3, ")"))
> should do it.
>
> I was taught a long ago that attach() should be avoided to avoid name
> conflicts. Also, it makes it difficult to figure out which dat
a and fig_descrip in the function
> body, call your function with:
>
> plot_f1(indata=v5, n1=114, n2=119, n3=116, fig_descrip="Figure 2a\nChange in
> Composite Score at Visit 5 (Day 31)\nPer Protocol Population")
>
> and you should be fine.
>
> HTH
>
>
All,
I am trying to put a few special symbols into a string to place on a graph
(e.g., >= and superscript 2).
This clearly works, but does not look good: text<-c("x2", "A>=B")
I tried pasting in the >= symbol, but just comes out as an =.
I have tried expression() with no luck: text<-c("x2
Hi All,
I have a number of plots to run and was hoping to use a function instead of
bock copying my code and retyping my parameters.
I am using R 3.0.0 on a mac.
My code is as follows:
library (car)
cres<-read.csv("//users//smits//r_work//cres.csv", header = TRUE)
attach(cres);
run_plots <- f
Dumb error. Thanks for letting me know. Gerard
On Aug 15, 2013, at 11:38 AM, "Richard M. Heiberger" wrote:
> typo
>
> run_plots <- functon()
>
>
> On Thu, Aug 15, 2013 at 1:10 PM, Gerard Smits wrote:
> Hi All,
>
> I have a number of plots to run
Hi All,
I'm using R 3.0.0. I'm trying to add the sample size of the paired data
(calculated by a function n(), which returns a value of 70, correctly).
My main title works fine except that the '70' appears far to the right on the
line as in:
at Month 18 (N=
(N=",.(ss),")"))),
xlab="Baseline xyz",
ylab="Month 18 DAS28",
legend.plot=F)
Prior, related post:
On Aug 29, 2013, at 2:00 PM, Gerard Smits wrote:
> Hi All,
>
> I'm using R 3.0.0. I'm trying to add the sample size of the pa
That explains it. Thanks for the info. Gerard
On Aug 30, 2013, at 8:42 AM, Marc Schwartz wrote:
>
> On Aug 30, 2013, at 10:26 AM, Gerard Smits wrote:
>
>> Hi All,
>>
>> This is a variant of a problem I posted yesterday (see below) where I found
>> I had
references to font
size in the code. Digitize changes the number size on the x-axis, but dont
see a corresponding way of making the labeling size smaller.
Using R 3.0.2
Any suggestions appreciated.
Gerard Smits
fplot=function (labeltext, mean, lower, upper, align = NULL, is.summary =
FALSE
Hi David,
That worked perfectly. I had tried something like that, but obviously messed
up the change.
Thanks for your help. Much appreciated.
Gerard
On Jan 19, 2014, at 2:16 PM, David Winsemius wrote:
>
> On Jan 19, 2014, at 1:13 PM, Gerard Smits wrote:
>
>> Hi All,
>&
Hi All,
I am running a scatter plot and trying to add a best fit line. I use an abline
function, but get no line drawn over the points. I also get no error. I arm
using V 2.10.0 on Windows 7.
Here is my code, including the SAS transport file import:
require (foreign)
require (chron)
require
Hi David,
Just changed to the standard plot from xyplot and it worked fine. I'll check
out panel.lmline.
Thanks for your help.
Gerard
On Oct 6, 2010, at 3:27 PM, David Winsemius wrote:
>
> On Oct 6, 2010, at 5:56 PM, Gerard Smits wrote:
>
>> Hi All,
>>
>>
Hi All,
I am using the package, cmprisk, to plot competing risks. In my case, I have
four lines showing risk of going on dialysis (by a lab test [fgf-23] in
quartiles), where the 4 lower lines are for the competing risk of death.
I am trying to edit the function to just plot the upper curves (
Hi All,
I'm trying to label my plot axis with times (HH:MM) that correspond to a
numeric index (values 0:6) for my time variable. I'd like to plot "08:00",
"12:00", and so on, instead of 0 through 6.
I have used the following line of code:
axis(1, 0:6, labels=c("08:00", "12:00", "16:00", "2
uot;24:00",
>> "04:00", "08:00"), cex=0.8)
>>
>
> You need the xaxt="n" in the plot statement, and the correct form is at=0:6
>
> Sarah
>
> On Mon, Feb 20, 2012 at 6:39 PM, Gerard Smits wrote:
>> Hi All,
>>
>
Hi All,
I have a small dataset named das (43 cases) in which I am trying to
create a binary outcome (1/0) based on the following code:
if (das$age>65 && das$bmi>30) {das$danger<-1} else das$danger<-0
I am setting a flag called 'danger' to 1 of the subject is over 65
and has a BMI > 30.
I fin
mp; bmi>30, 1, 0))
>
>HTH
>
>-Christos
>
> > -Original Message-
> > From: [EMAIL PROTECTED]
> > [mailto:[EMAIL PROTECTED] On Behalf Of Gerard Smits
> > Sent: Tuesday, January 01, 2008 5:04 PM
> > To: r-help@r-project.org
> > Subject: [R] i
e are accepted with a warning, but only
> the first element is used. Other types are coerced to
> logical if possible, ignoring any class.
>...
>
>The ifelse statement check the condition for each element of your
>input (returning
>a value with the same shape
All,
I would like to find a simper method that I now have to find the
product of all elements in a vector:
#get product of vector elements: (1,2,3,4,5)
vec.product <- exp(sum(log(c(1,2,3,4,5
I have not found a vector product function, if one has been written.
Thanks,
Gerard
[[al
Thanks for cumprod() and prod().
I should have tried the help.search first. Next time
Gerard
At 04:55 PM 1/12/2008, Gabor Grothendieck wrote:
>help.search("product")
>
>On Jan 12, 2008 7:38 PM, Gerard Smits <[EMAIL PROTECTED]> wrote:
> > All,
> >
>
I am a reasonable programer (other than with R), but have not been
able to decipher what I should be modifying. Any suggestions will be
appreciated.
Thanks,
Gerard Smits
At 02:32 PM 9/7/2007, Gerard Smits wrote:
>Hi R users,
>
>I have a test dataframe ("file1," shown below) f
It seems that SAS is willing to offer this interface if you are
willing to purchase one of their expensive add-on packages. Not surprising.
Gerard Smits
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
https
Hi All,
I have been able to modify the x-axis to start at zero by adding xlow
and xhigh parameters; that was pretty simple. I have been unable to
find the location of the code that would turn off the information
weighting of the box size (I have smaller randomized trials getting
less weight t
Hi David,
I just checked to make sure I had the latest version. I see no
boxsize option in the forestplot function parameters or any other
place in the code.
function (labeltext, mean, lower, upper, align = NULL, is.summary = FALSE,
clip = c(-Inf, Inf), xlab = "", zero = 0, graphwidth =
ices utils datasets
>methods base
>other attached packages:
>[1] rmeta_2.15 zoo_1.5-5
>loaded via a namespace (and not attached):
>[1] lattice_0.17-20 tools_2.8.1
>--
>David Winsemius, MD
>Heritage Laboratories
>West Hartford, CT
>On Mar 21, 2009, at 2:01 PM, Gerard S
hed packages:
>[1] rmeta_2.15 zoo_1.5-5
>loaded via a namespace (and not attached):
>[1] lattice_0.17-20 tools_2.8.1
>--
>David Winsemius, MD
>Heritage Laboratories
>West Hartford, CT
>On Mar 21, 2009, at 2:01 PM, Gerard Smits wrote:
>
>>Hi David,
>>
>>I just c
Yes, my R is a few versions old. I did not realize that the package
version was dependent on the R version. Thanks. Gerard
PS was able to apply the code suggested by David W. to the 2.14
version and got it to work.
At 12:32 AM 3/22/2009, Thomas Lumley wrote:
>On Sat, 21 Mar 2009, Ger
Hi all,
Thanks for the suggestions. I have not yet tried the apply ()
approach, but have tried to get the indexed version working, so far
with limited success. I realize that a transpose, as suggested,
would work, but want to avoid that for something simpler.
To repeat, the task is to perform
Hi Stephen,
Not responding to the R memory question, but to the racing.
I worked on this many years ago and found no way of overcoming the
19% or so paramutual take. That being said, I suggest you take class
into account (based on purse, type of race (maiden claiming, claiming
$, NWxx allowan
Hi All,
There are a variety of functions that can be applied to a variable
(column) in a data frame: mean, min, max, sd, range, IQR, etc.
I am aware of only two that work on the rows, using q1-q3 as example
variables:
rowMeans(cbind(q1,q2,q3),na.rm=T) #mean of multiple variables
rowSums (cbi
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