Dear all,
I am trying to draw a weighted cumulative distribution (as defined
here http://rss.acs.unt.edu/Rdoc/library/spatstat/html/ewcdf.html)
with ggplot2
however the syntax
temp<-qplot(X,weight=weight,data=data,stat = "ecdf", geom =
"step",colour=factor(year))
seems not to produce exactly th
I think I have my answer... ggplot2 uses ecdf which does NOT allow
weightings...
so there is no warning or error, but still the resulting plot do not
take into account the command weight=weight
Hope that helps someone, just in case ;-)
On 8 October 2012 15:40, Francesco wrote:
> Dear all,
&g
thank you very much David, I will have a look at your idea
Best,
On 8 October 2012 19:24, David Winsemius wrote:
>
> On Oct 8, 2012, at 10:12 AM, David Winsemius wrote:
>
>>
>> On Oct 8, 2012, at 9:18 AM, David Winsemius wrote:
>>
>>>
>>> On Oct 8,
Dear R-help
Î would like to know if there is a short solution in R for this
merging problem...
Let say I have a dataset A as:
TYPE DATE
A2
A5
A20
B10
B2
(there can be duplicates for the same type and date)
and I have another dataset
me", row.names = c(NA, -5L))
>
> Now all we have to do is run the statement A <- structure(... etc...) to
> have an exact copy of the data example.
> Anyway, your example with input and the wanted result was very welcome.
>
> Hope this helps,
>
> Rui Barradas
>
&g
combination of TYPE and DATE.
>
> Replace this
>
> x[which(min(a) == a), ]
>
> by this
>
> x[which.min(a), ]
>
> Rui Barradas
>
> Em 19-08-2012 12:00, Francesco escreveu:
>
>> Dear Riu, Many thanks for your suggestion
>>
>> However thes
---Original Message-
> > From: Rui Barradas [mailto:ruipbarra...@sapo.pt]
> > Sent: Sunday, August 19, 2012 3:54 PM
> > To: William Dunlap; Francesco
> > Cc: r-help
> > Subject: Re: [R] merging and obtaining the nearest value
> >
> > Hello,
> >
>
Dear Andrew,
Thanks for your suggestion.
I will indeed have a look at Allison's booklet...
Best,
On 7 February 2012 23:39, Andrew Miles wrote:
> Based on Paul Allison's booklet "Fixed Effect Regression Models" (2009), the
> FE model can be estimated by person-mean centering all of your variable
Dear Giovanni,
I recalled the procedure and here is the output :
Erreur : impossible d'allouer un vecteur de taille 39.2 Mo
De plus : Messages d'avis :
1: In structure(list(message = as.character(message), call = call), :
Reached total allocation of 12279Mb: see help(memory.size)
2: In structu
Dear R help,
I am using Stata, and I use a Stata ado file (Rsource) to run R in batch
mode within Stata
Everything works fine except for the fact that I cannot export the
graphics that I obtain with my computations written in my R source file
I believe this is related to the global Rterm_opt
Dear Peter,
You are absolutely right... I did not know that
;-)
What to say ? Many thanks for your right answer to my "silly" question ;-)
Best Regards
On 25 May 2012 15:19, peter dalgaard wrote:
>
> On May 25, 2012, at 14:46 , Francesco wrote:
>
> > Dear R help,
>
Dear all,I want to create a routine to generate an object for different value
of val:
z <- c(1,2,3,4,5,6,7,8,9)
for (val in z) {
neighbors.knn <- knn2nb(knearneigh(coord, val, longlat=F),
row.names=cod_pro,sym=F)
}
However, it seems it does not work.
How to store the neighbors.knn created
Sema, E is just a computer way of saying 0. For the purpose of statistical
analysis, if you can't compute a calculation with E values (i.e. 0),
substitute all E values with a usable constant, say 50. I stumbled across a
few websites lately that did this.
Frank Romano Ph.D.
*Academia.edu*
https://
lated comment to my
repository at:
https://github.com/contefranz/msmtools/issues
or contact me at francesco.grosse...@polimi.it
Thanks!
Francesco
--
Francesco Grossetti
Ph.D. Student
MOX - Modeling and Scientific Computing
Dipartimento di Matematica “F. Brioschi"
Politecnico di Milano
Via
honen says about the trainY parameter:
"Values for the dependent variable for the training data."
Anybody understands what does it mean?
thanks,
Francesco Stablum
--
The generation of random numbers is too important to be left to chance
- Robert R. Coveyou
an RBF network for a classification task? I've also looked on
CRAN but couldn't find any.
Thank you for your help,
Francesco.
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-/.
I'm sure I'm missing something because my neurons stick with Matlab
behaviour. Can you help me to understand what's wrong with my reasoning?
Thank you very much,
Francesco.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/
So I see from help([[) what's happening: thank you very much.
Il giorno mer, 23/12/2009 alle 18.59 -0800, Henrik Bengtsson ha scritto:
> Use
>
>submat <- data[1:i,, drop=FALSE]
>
> /H
>
> On Wed, Dec 23, 2009 at 6:46 PM, Francesco Napolitano
> wrote:
&
ab. In the real code I need to store
the partial sums (the example overwrites them, so it looks like wasted
loops).
Francesco.
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However, I gave information only about what I
was interested in and I got my answer immediately.
Cheers,
Francesco.
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PLEASE do
nsity like it is a
1-dimensional casual variable.
I have looked at the documentation of density, but I was not able to do it.
I have also spent quite a lot time looking in the internet for similar
issues, but found nothing helpful.
any suggestions?
thanks
-Francesco Stablum
P.S. sorry for my poor en
re are the
critical points for every X point.
Should I create a density matrix and then apply some kind of
transformation to it or is there a more direct way to plot it?
thanks,
Francesco Stablum
P.S. sorry for my poor english
--
The generation of random numbers is too important to be left
Sorry for the dumb question, but I couldn't figure this out myself.
Consider the following:
> str <- c("abc","def")
> array(str, c(2,1))
[,1]
[1,] "abc"
[2,] "def"
How can i obtain the outcome of the second instruction without
specifyin
On Fri, Sep 20, 2019 at 03:14:44PM +1200, Richard O'Keefe wrote:
> The one thing "slave" does not mean in technology is any kind of human
> being.
At risk of repeating what someone else said, we are most likely
not dealing with a human but with a "supernatural being, often
represented as of diminu
Dear R users/developers,
while ploughing through "An Introduction to R" [1], I found the
expression "static scope" (in contraposition to "lexical scope").
I was a bit puzzled by the difference (since e.g. Wikipedia conflates the
two) until I found this document [2].
Maybe the Introduction should
Hello everyone again,
I much appreciated the explanations.
On Wed, Sep 25, 2019 at 11:02:42AM +0200, Francesco Ariis wrote:
> Maybe the Introduction should link to it (or similar page) with text
> "In case you are interest in the difference between static and lexical
> sco
What is the function to do the truncation to a certain decimal digit of a
number. And the function approximation?
Thanks.
Francesco M
[[alternative HTML version deleted
Dear listers,
I am running some OLS on multiply imputed data using Amelia.
I first imputed the data with Amelia.
than I run a OLS using Zelig to obtain a table of results accounting for
the multiply imputed data-sets. And I'd like to do this for various models.
Finally, I want to output all the mo
> }
>
> # xtable
> for(i in 1:m){
> print(xtable(summary(lm.imputed1[[i]])))
> print(xtable(summary(lm.imputed2[[i]])))
> }
>
>
> On Sat, Aug 17, 2013 at 6:37 AM, Francesco Sarracino <
> f.sarrac...@gmail.com> wrote:
>
>> Dear listers,
>>
>
estimated parameters
>> from all imputation runs?
>>
>> Chris
>>
>>
>> On Sat, Aug 17, 2013 at 11:18 AM, Francesco Sarracino <
>> f.sarrac...@gmail.com> wrote:
>>
>>> Hi Christopher,
>>> thanks for your reply. Unfortunate
;*",sep=" "),
> ifelse(lm2[,4]<.1,paste(lm2[,2],".",sep="
> "),lm2[,2]
>
> ## ONE OPTIONS ##
> lms <- as.data.frame(cbind(lm1[,1],lm2[,1],lm1[,2],lm2[,2]))
> rownames(lms) <- rownames(lm1)
> colnames(l
how can i calculate the probability of occurrence of an event and the
probability of an event upon the occurrence of another event.
P (A) and P (A | B) ..
[[alternative HTML version deleted]]
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How to calculate the probability P (xt https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Dear R-listers,
I am a newbie with R and I am struggling with something I consider very
basic. I wish to produce a table (to import in a latex file) of summary
statistics, but for as much as I've been looking around and trying various
alternatives (plyr, reporttools, pastecs and Hmisc) I haven't f
levels option I lost the initial information.
Can you help figuring out what I am doing wrong?
thanks in advance,
f.
--
Francesco Sarracino, Ph.D.
https://sites.google.com/site/fsarracino/
[[alternative HTML version deleted]]
__
R-help@r-pro
ber of dimensions
Any ideas about what am I doing wrong?
Thanks in advance,
f.
--
Francesco Sarracino, Ph.D.
https://sites.google.com/site/fsarracino/
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https://stat.ethz.ch
the level (the value label - in
Stata dictionary). Moreover, the little "hat" in "o.particip^4" drives
latex nuts. Any ideas on how to fix these things?
Thank you very much for your kind help,
f.
--
Francesco Sarracino, Ph.D.
https://sites.google.com/site/fsarracino/
nderstand what's going on. Does anybody have any ideas about
what is going on?
Thanks in advance for your help ,
f.
--
Francesco Sarracino, Ph.D.
https://sites.google.com/site/fsarracino/
[[alternative HTML version deleted]]
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R-h
Dear R helpers,
I am currently having hard time fixing the values on the x-axis of a plot
with ggplot: even though I have 12 years, ggplot plots only 3 of them.
Here is my example:
library(ggplot2)
ii <- 2000:2011
ss <- rnorm(12,0,1)
pm <- data.frame(ii,ss)
tmpplot <- ggplot(pm, aes(x = ii, y = s
; plot <- tmpplot + geom_line()+scale_x_continuous(breaks=ii)
>
>
> Yao He
>
>
> 2013/1/8 Francesco Sarracino :
> > Dear R helpers,
> >
> > I am currently having hard time fixing the values on the x-axis of a plot
> > with ggplot: even though I have
Dear R helpers,
I am using knitr to run analysis with R and edit my document with Latex. I
am wondering whether there is a way to include 2 or more pictures per chunk
and being able to refer them in the text independently and eventually
whether it is possible to give them different captions. Let m
Dear R-listers,
does anybody know of any package developed to implement the Oaxaca-Blinder
decomposition in R?
I've been googling around and my reserch has been unfruitful. The latest
news I've found were 1 year old. Does anybody know of any recent
development?
Has R ever been employed to run a Oa
r.com/4lKpw.png
>
> Regards,
> Yihui
> --
> Yihui Xie
> Phone: 515-294-2465 Web: http://yihui.name
> Department of Statistics, Iowa State University
> 2215 Snedecor Hall, Ames, IA
>
>
> On Tue, Jan 8, 2013 at 4:17 AM, Francesco Sarracino
> wrote:
> > Dear
. Indeed, the result is 1.5 and not 0.5 as expected.
What am I doing wrong?
Thanks in advance for your kind support,
f.
--
Francesco Sarracino, Ph.D.
https://sites.google.com/site/fsarracino/
[[alternative HTML version deleted]]
__
R-help@r
the output is a vector of NA.
Any ideas?
f.
On 23 January 2013 10:39, D. Rizopoulos wrote:
> Check R FAQ 7.10: How do I convert factors to numeric?
>
>
> I hope it helps.
>
> Best,
> Dimitris
>
>
> On 1/23/2013 10:33 AM, Francesco Sarracino wrote:
> > Dear R li
t; check also
>
> pp <- rep(0:1, 10)
> pp <- factor(pp, levels=(0:1), labels=c("no","yes"))
>
> unclass(pp)
> unclass(pp) - 1
>
>
> Best,
> Dimitris
>
>
> On 1/23/2013 10:48 AM, Francesco Sarracino wrote:
> > Dear Dimitris,
> &g
urner wrote:
>
> Given that your labels are "no" and "yes", what do you expect R to
> do? To quote a well-known fortune, "R is lacking a mind_read() function!"
>
> cheers,
>
> Rolf Turner
>
>
> On 01/23/2013 10:58 PM, Frances
Dear Ellison,
thanks a lot for your reply. Your explanation makes things much clearer.
Sincerely,
f.
On 24 January 2013 05:58, S Ellison wrote:
>
>
> On 23 Jan 2013, at 21:36, "Francesco Sarracino"
> wrote:
>
> > what I meant refers to the fact that I&
t \. but it
does not work.
> grepl("\.",string)
Error: '\.' is an unrecognized escape in character string starting "\."
Thank you very much for your help
Francesco
[[alternative HTML version deleted]]
__
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Thanks so much for your help, now I could solve the problem (using [.])!
2013/5/13 arun
> You may also try:
> grepl("[.]",c("ad.1","ads","ad.2"))
> #[1] TRUE FALSE TRUE
> A.K.
>
>
>
> - Original Message -
> From: Fra
Hello,How do I extract only the value from the quantile
function?example:quantile (x, probs = 0.10) 10%-1.83442I want to add salt
only the number -1.83442
SincerelyFrancesco Miranda
[[alternative HTML version deleted]]
<>
what kind of error? how to solve it?
[[alternative HTML version deleted]]
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PLEASE do read the posting guide http://www.
Hello,I was trying to enter commands input messages or error within a
routin.for example : msg (consistency error: at the time ( j : generic time )
the lower quantile is not less than the upper quantile)
thanks in advanceFrancesco Miranda
[[alterna
at you're looking for.
>
> Sarah
>
> On Mon, Jun 24, 2013 at 4:50 PM, Francesco Miranda
> wrote:
> > Hello,I was trying to enter commands input messages or error within a
> > routin.for example : msg (consistency error: at the time ( j : generic
> > ti
Hi all,
I'm new to R and to this mailing list,
I'd need to display, in a 2x2 window (mfrow = c(2, 2)), a graph that is 2 rows
tall (so with 2 other graphs at his right).
Here is an example of what I mean
http://www.stefandahlen.com/pictures/rowspan.gif
in html there is an attribute called rowspa
n x.i.e. in this
example only the -10 in position y[3] satisfies the criteria, because x has in
position x[2]the figure 1.
Thank in advance for you help,Francesco
[[alternative HTML version deleted]]
__
uestion does not seem to make sense - there is no value of -500
> in Y (did you mean -10?). Anyway, I think this might work:
>
> which(y==-10 & (x==1 | c(0, x[-length(x)]) == 1 | c(x[-1], 0) == 1))
>
> ... though one would think there is a more elegant way
>
>
> O
conditions
on y must be true":
which(x==1 & (c(0,y[1:12])==-10 |c(0,0, y[1:11])==-10|
c(0,0,0, y[1:10])==-10))
thank in advance for you help,
Francesco
> Date: Wed, 17 Oct 2012 10:36:46 +1100
> Subject: Re: [R] vectors comparison
> From: sleepingw...@gmail.c
, gamma = 1.5)
?
It fails with:
Error in rainbow(100, s = 1, v = 0.75, start = 0, end = 0.75, gamma = 1.5)
:
unused argument (gamma = 1.5)
Calls: nmfconsensus ... matrix.abs.plot -> image -> image.default -> rainbow
Execution halted
Thanks
~ Francesco Brundu
[[alternative HTM
Hi Boris,
yes I tried this way and it worked. The fact is that I wanted to be
compliant with the old code, I did not want to change anything. So I wanted
to find a new way to rewrite the code.
Thanks
~ Francesco Brundu
On 19 April 2014 23:18, Boris Steipe wrote:
> Have you looked at ?rain
Thanks Boris for the detailed answer. I thought to make it backward
compatible because I did not know if gamma parameter would change the
result if absent. As far as I can see changes in my results are not
relevant, so I think to follow your advice to update the old code.
Thanks
~ Francesco
, length.out= 50)
data <- data.frame(var, dim1, dim2, dim3)
I am trying to build a fifth one (let's say: group_id) to uniquely identify
groups of observations as defined by dim1, dim2 and dim3, i.e. 30 groups.
can you please help me figuring out how to do it?
thanks in advance,
f.
--
F
Nice job Nicholas!thanks for the e-mail.
Regards,
Francesco
---
Francesco Nutini
CNR-IREA
Institute for Electromagnetic Sensing of the Environment
Via Bassini 15, 20133 Milano (Italy)
Tel: +39-02 23699 297
www.irea.cnr.it
nutin
Hi,
I was wondering if it would be possible to print the counts of common
items in the venneuler() diagrams.
Anybody knows a straightforward idea?
I can always count things from the data matrix, but I have vectors with
50 thousands elements.
thanks
Francesco
t the significativity of the variable.
I mean, variables that appear correlated with dependent variable in the matrix
result not correlated in the summary of linear model, and vice versa. Have I
made a mistake in the interpretation of the result, or not?
Thank you in advance,
Francesco
#command for m
0.2339
---
Signif. codes: 0 *** 0.001 ** 0.01 * 0.05 . 0.1 1
If I read the line "var_indipendent:factor" can I understand if the factor
influence significatvly the regression between dependent-indipendent variable?
Thanks a lot!
Francesco Nutini
P.S. numbers have
near model. But if I made a scatterplot the r2 is
very low.
How can I interpretate the information of command summary()?
Thank you in advance,
Francesco
#command for summary() of linear model
>summary(model_example)
Call:
lm(formula = dmp ~
Latitude + Longitude + Year + Tot.Prod + RFE.Cu
dear [R] users,
is there a way to plot different data (but with the same x-variables) in the
same xyplot window?
There are already a similar question, but the answer is not enought
explanatory...
Thanks a lot,
Francesco
[[alternative HTML
n the
dataset, but it's a factorial variables.
How can I use your method?
sorry for my ignorance!
Francesco Nutini
> Date: Fri, 10 Dec 2010 10:13:00 -0800
> From: ehl...@ucalgary.ca
> To: nutini.france...@gmail.com
> CC: r-help@r-project.org
> Subject: Re: [R] [r] overlap diffe
> From: fe...@nfrac.org
> Date: Sun, 12 Dec 2010 11:47:55 +1100
> Subject: Re: [R] overlap different line in a xyplot (lattice)
> To: ehl...@ucalgary.ca
> CC: nutini.france...@gmail.com; r-help@r-project.org
>
> On 12 December 2010 00:08, Peter Ehlers wrote:
> > On
ce the correlation?
Any suggestions how to perform post-hoc comparions?
Thanks a lot!
Francesco Nutini
P.S. numbers have no significance, it's just an example
[[alternative HTML version deleted]]
?
I wanna start with 2D set of points, but the real case scenario is
with a 5D set of points.
Thanks,
Francesco
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(from smaller to bigger) and
order the correspondent row to the new position.
Is it possible (apart from looping on the index) to do this with some
predefined R function?
Thanks,
Francesco
__
R-help@r-project.org mailing list
https://stat.ethz.ch/ma
ommand "summary", and
generically about the finest post-hoc test for implemented model with the code
"lm()". I think that R-help is quite insufficient...
Which command did you use normally?
Thanks a lot,
Francesco Nutini
__
R-he
if (x*y>0) {...}
On Mon, Jan 24, 2011 at 1:27 PM, Rainer Schuermann
wrote:
> On Monday, January 24, 2011 07:18:03 pm Alaios wrote:
>> Hello :)
>> I wanted to right an expression to check when x and y have the same sign
>> and I wrote the following:
>>
>> if ((x<0 && y<0) || (x>0 && y>0))
>>
>> w
this information with excel, but the factor have 68
levels...maybe [r] have a useful command.
Thanks,
Francesco Nutini
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318801 y
So, I would like to know the r2 for a~b for every factors levels.
Off course I can made the regression separately for every factors, but my
dataset have 68 factors...
--
Francesco Nutini
PhD student
CNR-IREA (Institute for Electromagnetic Sensing of the Environment)
Milan
tors
> From: dimitri.liakhovit...@gmail.com
> To: nutini.france...@gmail.com
> CC: rb...@atsu.edu; r-help@r-project.org
>
> Francesco, do you just want a separate regression for each level of
> your factor c?
> You could write a loop - looping through levels of c:
>
> for(i in levels(c))
y elements as there are
> levels in c) and extract the coefficients.
> Dimitri
>
>
> On Fri, May 20, 2011 at 9:57 AM, Francesco Nutini
> wrote:
> > Yes Dimitri that's what I mean!
> > Something like this?
> >
> > for(i in levels(c)) { lm(a ~ b * c
In fact "temp.data$" is not necessary, but the command still not run.
Thanks for your response, I'm also tring other point of view (suggested by
r-helpers).
For example ?ddply and ?lmList.
If you are interested I will keep you updated.
Francesco
> Date: Fri, 20 May 2
ce of graphs?
1998 1999 2000 2001 2002 2003 2004 2005 2006 2007 2008 2009 2010
I have tried with "par" code but it's doesn't work.
Thanks for help,
Francesco Nutini
[[alterna
Hello everybody,
is there a way to tell Sweave to skip the R code and process only the
LaTeX part?
I know it sounds a little bit weird, but the R code of my document is
complete and _slow_ and I need to add the LaTeX part.
Thanks,
franZ
__
R-help@r-p
Thanks Dennis,
I have used the codes as.table = TRUE and aspect = 1 to obtain what i needed.
Maybe I'll ask you more about xyplot, is very powerfull tool!
Cheers,
Francesco
Date: Mon, 31 Jan 2011 04:33:27 -0800
Subject: Re: [R] [r] align xyplot
From: djmu...@gmail.com
To: nutini.f
Hi Dennis and [R]users!
as I said last week, I need more info about xyplot.
Is it possible to change the color of the intestation of xyplot? By default is
pale-pink, but light-gray is better for a paper.
Thanks,
Francesco
From: nutini.france...@gmail.com
To: djmu...@gmail.com
CC: r-help@r
default is
pale-pink, but light-gray is better for a paper.
Thanks,
Francesco
From: nutini.france...@gmail.com
To: djmu...@gmail.com
CC: r-help@r-project.org
Subject: RE: [R] [r] align xyplot
Date: Thu, 3 Feb 2011 10:58:35 +
Thanks Dennis,
I have used the codes as.table = TRUE and
Sorry, I mean "heading".
Thanks for the tip.
Francesco
> CC: djmu...@gmail.com; r-help@r-project.org
> From: dwinsem...@comcast.net
> To: ui...@hotmail.it
> Subject: Re: [R] [r] align xyplot
> Date: Tue, 22 Feb 2011 08:33:07 -0500
>
> I don't know the ter
: |_|_|_|
what i want: | | | |
|_|_|_|
I tried to use the command "par", but it's doesn't work with xyplot. The two
plot have, by default, the same x-axis scale.
I know it's just a "visual solution", but it could be nice for a paper!
Did you mean this?
http://rgm2.lab.nig.ac.jp/RGM2/func.php?rd_id=latticeExtra:c.trellis
In fact I'm already using latticeExtra package because my xyplot is little bit
complicated...
So, I'm tring, thanks fro tricks baptiste!
Francesco
> Date: Thu, 14 Apr 2011 08:52:45 +1200
>
yplot
Date: Thu, 14 Apr 2011 07:46:31 +
Did you mean this?
http://rgm2.lab.nig.ac.jp/RGM2/func.php?rd_id=latticeExtra:c.trellis
In fact I'm already using latticeExtra package because my xyplot is little bit
complicated...
So, I'm tring, thanks fro tricks baptiste!
Franc
3, grid=T, par.settings =
list(strip.background = list(col = c("gray90"
enclose (?c.trellis):
c( z,double, x.same = TRUE, y.same = T, layout = c(13,2))
Maybe there is no solution but, anyway, thanks for help!
francesco
From: nutini.france...@gmail.com
To: baptiste.aug...@
Dear R-users,
I need to produce a histogram where for every breaks there are the mean of the
data.
I tried tu use the function >hist(x, break=20 ... ) but this return the
numerosity for every breaks, not the mean.
Any hint?
Thanks in advance,
france
.23 859.0167 945.4912
1046.917 1147.703 1249.375 1359.794 1447.518
1553.838 1649.231 1735.217 1850.617 1957.85
2031.329 2156.8 2247.55 2340.6 2822.1
Thank you very much.
francesco
From: michael.weyla...@gmail.com
Date: Tue, 23 Aug 2011 11:27:13 -
ound
we cannot understand what's wrong and where R searches for the mylib.so files.
Any suggestion?
Thanks,
Michela and Francesco
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the postin
Dear all,
I am a stata user and I am moving my first steps in R.
I am dealing with a silly issue concerning looping over variables. I read
previous posts on similar topics in the R help archive, but I did not find a
solution.
Here is my case:
I run a simple bivariate linear regression saving the
eep track of.
>>
>> The two documents mentioned in my signature
>> may help you get up and running in R. Since
>> you are coming from Stata, you should also
>> look at http://r4stats.com
>>
>>
>> On 18/09/2011 17:05, Francesco Sarracino wrote:
>>
&g
Dear R-Users, I'd like to have some tips for a ternaryplot ("vcd").
I have this dataframe:
a<- c (0.1, 0.5, 0.5, 0.6, 0.2, 0, 0, 0.00417, 0.45) b<- c
(0.75,0.5,0,0.1,0.2,0.951612903,0.918103448,0.7875,0.45)c<- c
(0.15,0,0.5,0.3,0.6,0.048387097,0.081896552,0.20833,0.1)
t).How can I print more than one graph per page, when I work with
this "elaborated" graph?Many thanks!Francesco
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
Thank you Brian! So, that's why sometimes I can't use the par()
Now I'm using the ternaryplot in [vcd]. Then, I have to read the vcd help to
looking for a function similar to par().
Many thanks.
Francesco
> Date: Tue, 5 Jun 2012 19:01:25 +0100
> From: rip..
Oh thank you Carlos!I wasted a lot of time formatting my xyplot by
powerpoint.Did you used a similar tips for ternaryplot (vcd)?
Many thanks.Regards,Francesco
Date: Wed, 6 Jun 2012 17:08:39 +0200
Subject: Re: [R] [r] par and complex graph
From: c...@qualityexcellence.es
To: nutini.france
Dear R listers,
I am trying to be a new R user, but life is not that easy.
My problem is the following one: let's assume to have 3 outcome variables
(y1, y2, y3) and 3 explanatory ones (x1, x2, x3).
How can I run the following three separate regressions without having to
repeat the lm command thre
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