Hi ,
When using errorest on a large dataset (12000 variables) it performs
very slow. By looking at the randomforest package it says that for
largedatasets the use of the formula is discouraged.
So it's better to use the x and y terms as the example below:
rf<-randomForest(x=df[trainindices,-1]
Hi,
I'm newbie with R and don't really know how to add a median line to each
of the groups that is not all the plot long.
Here is a small working code that i have adapted for my purpose. If
somebody could tell me how to draw median lines on each group and not
all plot long.
ctl <- c(4.17,5
thanks !!!
On 12/08/10 17:49, William Dunlap wrote:
segments(x0=ix-w, x1=ix+w, y0=mediansByGroup, col=ix)
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> str(data)
'data.frame': 250 obs. of 3 variables:
$ student: chr "A" "B" "C" "D" ...
$ data : num 20.2 20.4 22.5 22.1 23.3 ...
$ param : Factor w/ 4 levels "AGE","SCHOOL",..: 1 1 1 1 1 1 1 1 1 1
Hi , i would like to split the dataframe so that each level of param is
a column
At th
24.1
33 22.0 23.5 24.4
44 23.3 22.8 23.2
55 23.1 25.3 22.4
66 22.5 31.4 27.1
77 21.8 18.8 24.6
88 23.9 23.0 24.8
99 25.2 28.0 22.5
10 10 22.8 21.5 21.3
HTH,
Dennis
On Fri, May 20, 2011 at 2:49 AM, David martin w
Hello,
Sorry if this question has been posted before but could't find out
exactly an answer to the question
I'm doing bioinformatics and doing small RNA sequencing that make use of
packages such as DESeq and EDGE. For those familiar with this data you
will notice that you end up having la
Hey,
Here is a snippet that generated a boxplot and separates points so that
they do not overlap. I have a problem to avoir text overlapping. Any
help would be helpful.
>
attach(InsectSprays)
boxplot(count ~ spray, data = InsectSprays, outpch = NA)
stripchart(count ~ spray, data = InsectSpray
Hello,
I have done a stepwise analysis to determine the best model fitting my data.
data <- stepAIC( aov (Group)~ . , data=mydata)
data
> summary(data)
Df Sum Sq Mean Sq F valuePr(>F)
`a` 1 1.9829 1.98290 11.176 0.0011824 **
`b` 1 2.6606 2.66064 14.996 0.0001967 ***
Hi,
I'm trying to select the best model for a particular problem. So far i
have managed to identify a set of variables that woudl explain my model
lm1 <- lm(Group ~ . , data=dataf))
> summary(lm1)
Df Sum Sq Mean Sq F valuePr(>F)
`A` 1 2.3963 2.3963 24.0390 7.328e-06
Here is a snippet to show what i'm trying to do.
library(randomForest)
library(ROCR)
library(caret)
data(iris)
iris <- iris[(iris$Species != "setosa"),]
fit <- randomForest(factor(Species) ~ ., data=iris, ntree=50)
train.predict <- predict(fit,iris,type="prob")[,2]
plot(performance(prediction(t
Hi,
is it possible to export the LDA model into a file so that it can be
reused in R afterwards ?
I have already checked the package "pmml" but does not seem to export
LDA models.
thanks,
david
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Hi,
I haven't found in R a possibility to draw a boxplot with a diamond
shape (means and CI).
Does anyone know how to plot it ?
thanks,
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;ei=ySEUT_rlOMnsObn0rIQE&usg=AFQjCNFmhzo48CvMLH7YRFCXVPpoDmIfOg&cad=rja
That would be be extremely useful to draw using the boxplot function.
Hope helps.
thansk,
david
On 01/16/2012 12:25 PM, Jim Lemon wrote:
On 01/16/2012 10:07 PM, David martin wrote:
Hi,
I haven't found in R a possibili
Here is a working snippet.
library(epitools)
mat <- matrix(c(10,15,60,25,98, 12,10,70,28,14, 9,11,68,10,12
,8,13,20,11,58) ,ncol=2)
colnames(mat) <- c("treatmentA","treatmentB")
row.names(mat) <- paste("Cond",rep(1:10,1))
dimnames(mat) <- list("Condition" = row.names(mat), "instrument" =
colna
Here is a working snippet.
library(epitools)
mat <- matrix(c(10,15,60,25,98, 12,10,70,28,14, 9,11,68,10,12
,8,13,20,11,58) ,ncol=2)
colnames(mat) <- c("treatmentA","treatmentB")
row.names(mat) <- paste("Cond",rep(1:10,1))
dimnames(mat) <- list("Condition" = row.names(mat), "instrument" =
colna
Here is a working snippet.
library(epitools)
mat <- matrix(c(10,15,60,25,98, 12,10,70,28,14, 9,11,68,10,12
,8,13,20,11,58) ,ncol=2)
colnames(mat) <- c("treatmentA","treatmentB")
row.names(mat) <- paste("Cond",rep(1:10,1))
dimnames(mat) <- list("Condition" = row.names(mat), "instrument" =
colna
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