Hi Jose,
You're referring to your response variable when you're saying it's missing
some of the choices, right? Are your response choices ever known or do they
just occur with extremely low frequency? Either way, I think the mlogit
package would be inappropriate for you. I imagine you would have m
This might be useful: http://adv-r.had.co.nz/
On Tue, Apr 5, 2016 at 10:31 AM, Francisco Banha wrote:
> Dear All,
>
> I'm currently working on a project with
> the purpose of remotely executing R code, which requires me to have to
> work with the code of R itself. I've searched the Internet for
Hi,
I have 45 models that I have named: 1, 2, 3, ... , 45 and I am trying to
plot them in order of ascending BIC values. I am however unclear as to
how I can get the models to line up on the x-axis by BIC and not by
numeric order. For example, if model 5 has a lower BIC than 1, I want it
to be
ley wickham wrote:
> Hi Chris,
>
> Try this:
>
> qplot(reorder(model, delta), delta, data = growthm.bic)
>
> Hadley
>
> On Sun, Jun 28, 2009 at 9:53 AM, Christopher
> Desjardins wrote:
>
>> Hi,
>> I have 45 models that I have named: 1, 2, 3, ... , 45 an
n, Jun 29, 2009 at 10:39 AM, Christopher
> Desjardins wrote:
>
>> Hi Hadley,
>> Thanks for the reply and the great graphing package. That code is giving me
>> the following error:
>>
>>
>>> qplot(reorder(model,delta),delta,data=growthm.bic)
>>
Hi,
I am trying to combine two data frames by ID. The first data frame is
the whole data set and the second data frame is a subset of the first.
What I would like to do is take the values from variable, p1, from the
second data frame and merge them back into that variable in the first
data fr
Hi,
I am trying to do run the following model saved in "C:/bugs/sus.bug"
model {
for (i in 1:n){
y[i] ~ dpois(lamdba[i])
log(lambda[i]) <- mu+bmale[male[i]]+bschn[schn[i]]+epsilon[i] #
epsilon[i] ~ dnorm(0,tau.epsilon)
}
mu ~ dnorm(0,.0001)
bmale ~ dnorm(0,.0001)
tau.epsilon
Hi,
How can I perform the following
y1y2y3y4
1 0 3 2
0 1 2 1
3 2 0 1
0 5 1 0
into ...
> y
1 0 3 2 0 1 2 1 3 2 0 1 0 5 1 0
Please cc me on reply as I subscribe to the digest.
Thanks!
Chris
___
0 1 0 5 1 0
>
>
>
>
> On Sun, Jul 19, 2009 at 7:25 PM, Christopher
> Desjardins wrote:
>
>> Hi,
>> How can I perform the following
>>
>> y1y2y3y4
>> 1 0 3 2
>> 0 1 2 1
>> 3 2
Hi,
When I zoom into a graph created in ggplot2 with the
coord_cartesian(ylim=c(0,5)) option, I have no values labelled on my y-axis.
For this graph ggplot2 only puts labels the y-axis at intervals of 10 (i.e.
0, 10, 20, ...). However, the major portion of the graph I am interested in
is located be
Hi,
I have the following data.
> set.seed(6245)
> data <- data.frame(x1=rnorm(5),x2=rnorm(5),x3=rnorm(5),x4=rnorm(5))
> round(data,digits=3)
x1 x2 x3 x4
1 0.482 1.320 -0.859 -0.142
2 -0.753 -0.041 -0.063 0.886
3 0.028 -0.256 -0.069 0.354
4 -0.086 0.475 0.244 0.781
5 0.69
on(x){x1<-
> match(x,sample(unlist(data2[,3:4]),round(0.8*length(unlist(data2[,3:4]);x[
> is.na(x1)]<-NA;x})
> data2
> # x1 x2 x3 x4
> #1 0.482 1.320 -0.859 -0.142
> #2 -0.753 -0.041 NA NA
> #3 0.028 -0.256 -0.069 0.354
> #4 -0.0
Does this do what you want?
library(Amelia)
library(Zelig)
library(stargazer)
library(xtable)
data(africa)
m = 10
imp1 <- amelia(x = africa,cs="country",m=m)
imp2 <- amelia(x = africa,cs="country",m=m)
lm.imputed1 <- zelig(infl ~ trade + civlib, model="ls",data = imp1)
lm.imputed2 <- zelig(infl
SE)
> but then I get my error:
> Error: Unrecognized object type.
>
> Even though your example is insightful, I can't figure out how to solve
> my problem.
> Any advice is very welcome.
> Regards,
> f.
>
>
> On 17 August 2013 17:02, Christopher Desjardins
Oh and are you looking for just the summarized results over all the imputed
runs? i thought you wanted them from each iteration.
On Sat, Aug 17, 2013 at 11:38 AM, Christopher Desjardins <
cddesjard...@gmail.com> wrote:
> What do you mean by results? Do you want just the estimated p
Seems you're after the pooled results. Would the following work?
library(Amelia)
library(Zelig)
library(xtable)
data(africa)
m = 10
imp1 <- amelia(x = africa,cs="country",m=m)
imp2 <- amelia(x = africa,cs="country",m=m)
lm.imputed1 <- zelig(gdp_pc ~ trade + civlib, model="ls",data = imp1)
lm.i
do by hand in the tex code.
> Is it possible that there is no way to get nicely latex formatted tables
> concerning multiply imputed data-set?
> But maybe I should open a separate thread on this.
> Thanks a lot for your kind and patient help.
> Best regards,
> f.
>
>
> fsumstatZINB=paste("/Users/chris/Dropbox/phd/analysis/Simulation/zinbmodels/summaries/zinbsumstat-",j,k,l,m,".rdata",
> sep="")
> load(fsumstatZINB)
> print(zinbMeans[,1])
> result[[paste(j,k,l,m)]] <- zinbMeans
>
Hi,
I want to submit a package to CRAN and I am getting the following Note:
* checking CRAN incoming feasibility ... NOTE
New submission
How can I take care of this? And/or is it a big deal?
Thanks and sorry if this is something that I easily overlooked I have
googled this topic for a while and
Hi,
I have the following data:
> data[1:20,c(1,2,20)]
idr schyear year
1 80
1 91
1 10 NA
2 4 NA
2 5 -1
2 60
2 71
2 82
2 93
2 104
2 11 NA
2 126
3 4 NA
3 5 -2
3 6 -1
3
gt; 3.13 3 4 -3
> 3.14 3 5 -2
> 3.15 3 6 -1
> 3.16 3 70
> 3.17 3 81
> 3.18 3 92
> 3.19 3 103
> 3.20 3 114
> >
> >
>
>
> On Sat, Nov 3, 2012 at 1:14 PM, Christopher Desjardi
flag changes for an idr. Which it shouldn't.
Thanks,
Chris
On Sat, Nov 3, 2012 at 5:50 PM, Christopher Desjardins <
cddesjard...@gmail.com> wrote:
> Hi Jim,
> Thank you so much. That does exactly what I want.
> Chris
>
>
> On Sat, Nov 3, 2012 at 1:30 PM, jim holtman w
721
> #5 2 900
> #6 2 1010
> #7 2 1120
>
>
> A.K.
>
>
>
>
>
>
> - Original Message -
> From: William Dunlap
> To: arun ; Christopher Desjardins <
> cddesjard...@gmail.com>
&g
Hi,
I am running the following code based on the cpm vignette's code. I believe
the code is syntactically correct but it just seems to hang R. I can get
this to run if I set the sims to 100 but with 2000 it just hangs. Any ideas
why?
Thanks,
Chris
library(cpm)
cpmTypes <- c("Kolmogorov-Smirnov","M
Hi,
I am wondering if there is a way to call Gnuplot from R and/or if anyone can
recommend a package on CRAN capable of doing this?
Thanks,
Chris
PS - Please cc me on the response.
[[alternative HTML version deleted]]
__
R-help@r-project.org mai
Hi,
I am curious if the status of RWinEdt and WinEdt 6.0 has changed since this
thread
http://r.789695.n4.nabble.com/RWinEdt-in-WinEdt-6-td2174285.html
Thanks for the help (especially Uwe Ligges for writing RWinEdt).
Chris
[[alternative HTML version deleted]]
Hi,
I am wondering if there is a way to change the pattern of the fill in
histogram in ggplot2? By default the fill is solid and I'd like to add some
sort of pattern to make it more visible that these are different levels of a
factor.
Thanks!
Chris
[[alternative HTML version deleted]]
__
Hi I am running the following code:
sym <- c(sym1,sym2,sym4)
lifedxm <- c("O-BD","O-WELL","O-UNI")
life <- c(lifedxm,lifedxm,lifedxm)
tp <- c("TP-ANY","TP-ANY", "TP-ANY", "TP-SUB", "TP-SUB", "TP-SUB", "TP-CLIN"
, "TP-CLIN", "TP-CLIN")
data <- data.frame(sym,life,tp)
qplot(life,geom="bar",w
Hi,
I am trying to get TextWrangler to work with LaTeX and Sweave. Ideally
I would call a script from TextWrangler that would run Sweave on a
document, then LaTeX (using SyncTeX), and finally
open the corresponding pdf in Skim. Of course I don't always need to
run Sweave and would be looking for th
I have 3 vectors: p1, p2, and p3. I would like each vector to be any
possible value between 0 and 1 and p1 + p2 + p3 = 1. I want to graph these
and I've thought about using scatterplot3d(). Here's what I have so far.
library(scatterplot3d)
p1 <- c(1,0,0,.5,.5,0,.5,.25,.25,.34,.33,.33,.8,.1,.1,.9,.
generally you can generate n-tuples that sum to unity as:
> > >
> > > diff(c(0, sort(runif(n-1)), 1))
> > >
> > >
> > > Ravi.
> > >
> > >
> > >
> > > Ravi
Hi,
I am trying to write a loop to recode my data from -999 to NA in R. What's
the most efficient way to do this? Below is what I'm presently doing, which
is inefficient. Thanks,
Chris
dat0 <- read.table("time1.dat")
colnames(dat0) <- c("e1dq", "e1arcp", "e1dev", "s1prcp", "s1nrcp", "s1ints",
x27;t at the time of my question or
script writing.
Thanks,
Chris
>
> On Wed, Mar 30, 2011 at 10:15 AM, Christopher Desjardins
> wrote:
> > Hi,
> > I am trying to write a loop to recode my data from -999 to NA in R.
> What's
> > the most efficient way to do this?
On Wed, Mar 30, 2011 at 10:51 AM, peter dalgaard wrote:
>
> On Mar 30, 2011, at 16:05 , Christopher Desjardins wrote:
>
> >>
> >> dat0 <- read.table('tim1.dat', na = -999)
> >>
> >
> > Ah ... yes. I knew that but clearly didn
Hi,
I have longitudinal school suspension data on students. I would like to
figure out how many students (id_r) have no suspensions (sus), i.e. have a
code of '0'. My data is in long format and the first 20 records look like
the following:
> suslm[1:20,c(1,7)]
id_r sus
11 0
15 10
16
On Wed, Apr 6, 2011 at 4:03 PM, Douglas Bates wrote:
> On Wed, Apr 6, 2011 at 3:44 PM, Christopher Desjardins
> wrote:
> > Hi,
> > I have longitudinal school suspension data on students. I would like to
> > figure out how many students (id_r) have no suspensions (sus), i
rote:
> Hi Chris,
>
> Sorry I did not see your email before ;-) Here is one option:
>
> > r <- with(d, tapply(sus, id_r, function(x) any(x > 0)))
> > r
>111516181920212224252630
> 31 32
> FALSE TRUE FALSE FA
On Thu, Apr 7, 2011 at 8:07 AM, Christopher Desjardins <
cddesjard...@gmail.com> wrote:
> Hi Jorge,
> I want to make sure this does what I want.
>
> So I want to get a count of students that never get a suspension. Once a
> student has a non-zero I don't want to count
Hi,
I am using ggplot2 to with the following code:
gmathk2 <-
qplot(time,math,colour=Kids,data=kids.ach.lm.k5,geom="smooth",method="lm",formula=y~ns(x,1))
+ opts(title="Smoother Plot: Math K-5") + xlab("Time") + ylab("Math") +
scale_colour_brewer(pal="Set1"); gmathk2
This plots all the smoother f
Hi,
Let's say I have the following data:
> a=matrix(c(1,2,4,4,2,1,1,2,4),nrow=3,byrow=T)
> a
[,1] [,2] [,3]
[1,]124
[2,]421
[3,]124
What syntax should I use to get R to tell me the column that corresponds to
the maximum value for each row?
For my exa
Hi,
I have the following data management issue. I am trying to combine multiple
years of ethnicity data into one variable called ethnic. The data looks
similar to the following
idethnic07ethnic08 ethnic09ethnic10
1 1 1 11
2 1
Hi,
I have the following data:
> est
sch190 sch107 sch290 sch256 sch287 sch130
sch139
4.16656026 2.64306071 4.22579866 6.12024789 4.49624748 11.12799127
1.17353917
sch140 sch282 sch161 sch193 sch156 sch288
sch352
3.
', colour='red') +
> geom_pointrange(aes(x=as.factor(sch), y=est, ymin=lower.95ci,
> ymax=upper.95ci))+
> xlab('School') + ylab("Value-added")+theme_bw()
>
>
>
>
> On 07/07/2011 05:55 PM, Christopher Desjardins wrote:
>> Hi,
&
Hi,
I have the follow ggplot2 code I am running:
ggplot(data=bb.res.math,aes(x=factor(id.bb),y=bb.math.comb,fill=BB)) +
geom_bar() + facet_grid(BB~.) + scale_fill_brewer(pal="Set1") + ylab("Average
Student Residual (Math)") + xlab("Student ID")
The number of unique id.bb is 2207 and so my X-axi
Hi,
I have my data the following way:
y A B C
0 11 2
0 12 1
1 11 2
0 11 2
1 11 2
1 12 1
0 12 2
.
.
.
And so on. How can I make my data look like the following:
y A B C
2 1 1 2
1 1 2 1
0 1 2 2
.
.
.
---
> David L Carlson
> Associate Professor of Anthropology
> Texas A&M University
> College Station, TX 77843-4352
>
> > -Original Message-----
> > From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> > project.org
12
0 1 2 2 1
.
.
.
So I would know there were 2 successes out of 4.
Thanks!
Chris
On Fri, Jul 20, 2012 at 10:41 AM, Christopher Desjardins <
cddesjard...@gmail.com> wrote:
> Thanks the aggregate() command is what I was looking for.
> Chris
>
>
> On Thu, Ju
Hi,
I am wondering if there is an easy way to access the hat matrix for
zeroinfl and hurdle objects in the pscl library?
Thanks,
Chris
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https://stat.ethz.ch/mailman/listi
Hi,
I am wondering if anyone knows how to perform an F-test on the change in R
square between hierarchical models in R? SPSS provides this information and
a researcher that I am working with is interested in getting this
information. Alternatively, if someone knows how I can calculate the test
sta
Hi,
I have a pretty simple problem. Here is the code:
dat1=complete(dat.mice,1)
dat2=complete(dat.mice,2)
dat3=complete(dat.mice,3)
dat4=complete(dat.mice,4)
dat5=complete(dat.mice,5)
dat6=complete(dat.mice,6)
dat7=complete(dat.mice,7)
dat8=complete(dat.mice,8)
dat9=complete(dat.mice,9)
d
Hi,
I am having trouble with syntax for a for loop. Here is what I am trying to
do.
class=c(rep(1,3),rep(2,3),rep(3,3))
out1=rnorm(length(class))
out2=rnorm(length(class))
out3=rnorm(length(class))
data=data.frame(class,out1,out2,out3)
dat.split=split(data,data$class)
for(i in 1:3){
sub[i]=da
Hi,
I am trying to replicate Lambert (1992)'s simulation with zero-inflated
Poisson models. The citation is here:
@article{lambert1992zero,
Author = {Lambert, D.},
Journal = {Technometrics},
Pages = {1--14},
Publisher = {JSTOR},
Title = {Zero-inflated {P}oisson regression, with an application to d
On Fri, Apr 27, 2012 at 1:53 AM, Achim Zeileis wrote:
> On Thu, 26 Apr 2012, Christopher Desjardins wrote:
>
> Hi,
>> I am trying to replicate Lambert (1992)'s simulation with zero-inflated
>> Poisson models. The citation is here:
>>
>> @article{la
Hi,
I am a little confused at the output from predict() for a zeroinfl object.
Here's my confusion:
## From zeroinfl package
fm_zinb2 <- zeroinfl(art ~ . | ., data = bioChemists, dist = "negbin")
## The raw zero-inflated overdispersed data
> table(bioChemists$art)
0 1 2 3 4 5 6
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