ce
of the two.
Thanks for any help or leads.
Bill Shipley
bill.ship...@usherbrooke.ca
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and pr
know how to specify the model in
lme but I don't know how to set up the inferential test that b_j=Kj for all
j groups versus the alternative hypothesis that b_j is not equal to Kj for
at least one group. Any help in explaining how to do this using the mle
function in R is appreciated.
Tha
different scales to define the numerical y values for each subgroup.
This graph would have one scale on the left-hand y-axis and a second scale
on the right-hand y-axis.
I cannot simply superimpose two bar plots because I have to make sure that
the subgroup bars are beside each other.
Bill Shipley
ink) give the same
output since they correspond to Type I and III sums of squares in the SAS
terminology. At least, this is the case with normal (i.e. not mixed) linear
models. However, he finds very different results of these two types of
ANOVA tables. Why?
Bill Shipley
North American Edi
Yesterday I posted the following question to the help list. Thanks to John
Fox (copied below) who pointed out the solution.
Original question:
I have come across a result that I cannot explain, and am hopingthat someone
else can provide an answer. A student fitted a mixed model usingthe
function from stopping when this happens, so that the
loop can continue?
Bill Shipley
North American Editor, Annals of Botany
Département de biologie
Université de Sherbrooke
Sherbrooke (Québec) J1K 2R1
Canada
(819) 821-8000, poste 62079
(819) 821-8049 FAX
http://pages.usherbrooke.ca/jship
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