Hi Mates,
I have a very long R code that needs to go to production but my portfolio
managers do not use R language and the software is not supported by my bank.
Is there any way I can compile the code to an executable file and make it
usable to my portfolio managers who have no knowledge at al
A = read.table("clipboard", header=TRUE)
> A
sex age region no_of_accidents
1 F young north 10
2 F young south 12
3 F old north 5
4 F old south 7
5 M young north 24
6 M young south 30
7 M o
> letters
[1] "a" "b" "c" "d" "e" "f" "g" "h" "i" "j" "k" "l" "m" "n" "o" "p" "q"
"r" "s" "t" "u" "v" "w" "x" "y" "z"
> LETTERS
[1] "A" "B" "C" "D" "E" "F" "G" "H" "I" "J" "K" "L" "M" "N" "O" "P" "Q"
"R" "S" "T" "U" "V" "W" "X" "Y" "Z"
>
Hope that will help.
Mama
-
Mama Attiglah, PhD
Adva
Hi all,
I am struggling to compile a massive R code that I have written through
some years, aiming to provide automated investment strategies to my
Portfolio Managers. You may ask me why do I not rewrite the code in C or
C++; the answer is it is really massive and that will take me lots of
time.
Try this
X = rbind(y1, y2)
colnames(X) = as.character(x)
barplot( X, density=c(35,40), col=c("red","blue"), beside=FALSE)
barplot( X, density=c(35,40), col=c("red","blue"), beside=TRUE)
Alternatively,
barplot( y1, ylim = c(0, max(y1,y2)), col="blue", beside=FALSE)
par(new=TRUE)
barplot( y2
Ret= matrix(sample( 1:1000, 500*9), nrow=500, ncol=9)
Pos= c( 2593419 ,2130220, 6198197, 1673888, 198 , 1784732 ,
2052120 ,-7490228 ,-5275000)
Solution = Ret * matrix( rep(Pos, 500), nrow=500, byrow=TRUE)
Use the element-wise multiplication rather than a matrix multiplication.
Hope th
Attiglah, Mama
Sent: 30 January 2008 11:32
To: Megh Dal; [EMAIL PROTECTED]
Subject: Re: [R] Multiplying each row of a big matrix with a vector
Ret= matrix(sample( 1:1000, 500*9), nrow=500, ncol=9)
Pos= c( 2593419 ,2130220, 6198197, 1673888, 198 , 1784732 ,
2052120 ,-7490228 ,-5275000
Hi room,
Is there any R package that solves a non linear objective pb, with
linear equality constraint?
A simple example
a =c (2, 5, 6, 7, 2)
b = c (7, 1, 4, 5, 6)
a and b are vectors of length 5
minimise f(x, a) = sum( (x-a)^2) such that sum( x*b) = 50.
where x is the control varia
Hi room,
Is there any R package that solves a non linear objective pb, with
linear equality constraint?
A simple example
a =c (2, 5, 6, 7, 2)
b = c (7, 1, 4, 5, 6)
a and b are vectors of length 5
minimise f(x, a) = sum( (x-a)^2) such that sum( x*b) = 50.
where x is the control var
Let's A = expand.grid(xk1=xk1,xk2=xk2)
B = A[A[,1] %in% x1 & A[,2] %in% x2, ]
Should in principle produce the desired result.
Mama
-
Mama Attiglah, PhD
Advanced Research Center
Quantitative Research Analyst
State Street Bank
+44(0)20 7698 6290 (Direct Line)
+44 (0)207 004 2968 (Direct Fax
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