Hi Roy,
Thank you, I’m sorry — I couldn’t resist fitting in a little dig there because
that’s one of my main frustrations with actually using R, and to me it seemed
to make some sort of sense because I was complaining about backwardness in a
way (so a steep learning curve seemed to fit in). The
Dear ggplot2 experts,
I'm struggling to make a plot having family id in x-axis and female id
below that family id where each 4 families have a single female id.
I also need to add male id on top of each bar which I can do before
grid.arrange, but fail after doing it. So, any suggestions?
Please
Thanks Rishi,
Please find attached the data herewith.
On Fri, Sep 20, 2019 at 5:48 PM ঋষি ( ऋषि / rIsHi )
wrote:
> There are no attached data .
>
> On Fri, Sep 20, 2019 at 11:40 AM Moshiur Rahman
> wrote:
>
>> Dear ggplot2 experts,
>>
>> I'm struggling to make a plot having family id in x-ax
Not being a jerk is a good thing.
Unthinking political correctness is not the same thing at all.
The point has already been made that the relationship between
a "master" process or cylinder and a "slave" one is intrinsically
a dominance relation where the "master" tells the "slave" what to
do. No
Hi Richard,
Sure, it's a silly example, but it makes about as much sense as using
"slave" to mean "quiet". Also, there is no "--master" option so it's not
exactly the master/slave terminology here either.
My only point is that I think it's very distasteful to give such a
needlessly awful name to
Thanks a lot Rishi for your very cordial effort and great help. But still I
need some help to improve it as the plot doesn't clearly depict which
female belongs to which family and this can be detected by drawing a line
from 1-4 for F1, 5-8 for F2
Another problem I can see that the position of
There are no attached data .
On Fri, Sep 20, 2019 at 11:40 AM Moshiur Rahman
wrote:
> Dear ggplot2 experts,
>
> I'm struggling to make a plot having family id in x-axis and female id
> below that family id where each 4 families have a single female id.
>
> I also need to add male id on top of ea
Here is the solution inspired by this post
https://stackoverflow.com/questions/18165863/multirow-axis-labels-with-nested-grouping-variables
> data$Female <- factor(data$Female, levels =
c("F1","F2","F3","F4","F5","F6","F7","F8","F9","F10"))
>
ggplot(data,aes(x=family,y=offs.surv.perct,fill=treat
Using this list as a labor pool to procure code for generating
publication-quality plots is abuse. Please read the Posting Guide and the
documentation for the ggplot package or go pay someone offlist for their
services.
On September 20, 2019 4:15:18 AM PDT, Moshiur Rahman
wrote:
>Thanks a lot
> Sure, it's a silly example, but it makes about as much sense as using
> "slave" to mean "quiet".
It doesn't. It's a set of options chosen for when R is called as a slave
process from a controlling process, and in that it is a reasonable description
of the circumstance.
--quiet is a separate c
Hi,
I'm trying to create a simple function that takes a dataframe as its only
argument. I've been using gmodels::CrossTable, but it requires a lot of
arguments, e.g.:
#this runs fine
CrossTable(data$col1, data$col2, prop.chisq = FALSE, prop.c = FALSE, prop.t =
FALSE, format = "SPSS")
Moreover
With the data snippet below I’m trying to increment the “count” vector by one
each time the date changes.
Date count
1 2018-03-29 1
2 2018-03-29 1
3 2018-03-29 1
81 2018-03-30 1
82 2018-03-30 1
83 2018-03-30 1
165 2018-03-31 1
166 2018-03-31 1
1
On 20/09/2019 11:30 a.m., Zachary Lim wrote:
Hi,
I'm trying to create a simple function that takes a dataframe as its only
argument. I've been using gmodels::CrossTable, but it requires a lot of
arguments, e.g.:
#this runs fine
CrossTable(data$col1, data$col2, prop.chisq = FALSE, prop.c = FAL
Hi Phillip,
This can be done in several ways as most things in programming. Here is one
posible solution:
dates <- c("2018-03-29", "2018-03-29", "2018-03-29",
"2018-03-30", "2018-03-30", "2018-03-30",
"2018-03-31", "2018-03-31", "2018-03-31")
dates <- as.data.frame(as.Dat
Hello,
Maybe I am not understanding but isn't this what you have asked in your
previous question and my 2nd post (adapted) does?
If not, where does it fail?
Hope this helps,
Rui Barradas
Às 18:46 de 20/09/19, Phillip Heinrich escreveu:
With the data snippet below I’m trying to increment the
Hello,
Something like this?
ctab <- function(data) {
gmodels::CrossTable(as.matrix(data), prop.chisq = FALSE, prop.c =
FALSE, prop.t = FALSE, format = "SPSS")
}
mtcars %>% select(cyl, gear) %>% ctab()
Hope this helps,
Rui Barradas
Às 16:30 de 20/09/19, Zachary Lim escreveu:
Hi,
I'm t
Ah, *now* we're getting somewhere. There is something that *can* be
done that's genuinely helpful.
>From the R(1) manual page:
-q, --quiet
Don't print startup message
--silent
Same as --quiet
--slave
Make R run as quietly as possible
Thanks everyone especially Rishi to solve
this issue
Regards,
Moshichi
On Fri, Sep 20, 2019 at 22:26 Jeff Newmiller
wrote:
> Using this list as a labor pool to procure code for generating
> publication-quality plots is abuse. Please read the Posting Guide and the
> documentation for the ggplot
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