August 17, 2018 10:24 PM, "Rolf Turner" wrote:
> On 18/08/18 02:37, David L Carlson wrote:
>
>> Notice below that your message is substantially scrambled. R-Help is a
>> plain text only list so you should set your email client to produce plain
>> text messages.
Apologies, forgot to change the
August 19, 2018 4:58 AM, "Peter Langfelder" wrote:
> To the OP, try formatting the data to be plotted as a matrix, not as a
> vector
CSV data provided in a previous message; is not the data formatted as a matrix?
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R-help@r-project.org mailing list -
On Sun, Aug 19, 2018 at 7:15 AM wrote:
>
> August 19, 2018 4:58 AM, "Peter Langfelder"
> wrote:
>
> > To the OP, try formatting the data to be plotted as a matrix, not as a
> > vector
>
> CSV data provided in a previous message; is not the data formatted as a
> matrix?
I meant the data you giv
I have the following function
kdenor <- function(aa,q=NULL){
a=sample(aa,500,replace=F)
ab=quantile(a, p=0.75)-quantile(a, p=0.25)
h=(0.9*min(var(a),ab))/(1.34*n^(1/5))
if(is.null(q)) {
q = seq(min(a)-3*h, max(a)+3*h, length.out=length(a))
}
nx = length(a)
nq = length(q)
xmat = matrix(q,nq,nx) -
Actually the data you provided are a data frame and not a matrix as R uses the
term. Two columns of gceac are numeric and one is a factor. If we read your
data with read.csv() we get:
> str(gceac)
'data.frame': 35 obs. of 3 variables:
$ year : int 2014 2014 2014 2014 2014 2014 2014 201
Good evening,
I am attempting to download Genomic data from the GDC onto R for analysis
and am experiencing some difficulty. I have downloaded the GDC data into an
Excel, CSV, and notepad (.txt) file and implemented what I believe to be
the proper arguments, with every attempting failing to pro
The load() function is only used for binary files that R creates with the
save() function.
You are trying to assign the data to an object (variable) called LGG Drug. R
does not allow spaces in variable names. You could try LGGDrug, LGG_Drug, or
LGG.Drug. Same issue with GBM Drug.
David L. Car
On Sun, 19 Aug 2018, Spencer Brackett wrote:
I am attempting to download Genomic data from the GDC onto R for analysis
and am experiencing some difficulty. I have downloaded the GDC data into an
Excel, CSV, and notepad (.txt) file and implemented what I believe to be
the proper arguments, with e
Just a hunch, but I would recommend simplifying your filename: remove the
(CSV) portion. It could be confusing in R read syntax. Create a filename with
no unnecessary punctuation and no blank spaces.
--John Sparks
From: R-help on behalf of Spencer Brackett
Hello everyone!
Could anyone recommend a good way to learn about tidyverse, please? Is
there a book, please?
Thanks,
Erin
Erin Hodgess, PhD
mailto: erinm.hodg...@gmail.com
[[alternative HTML version deleted]]
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R-help@r-project.org mailin
https://www.tidyverse.org/learn/
On Sun, Aug 19, 2018 at 4:29 PM Erin Hodgess wrote:
>
> Hello everyone!
>
> Could anyone recommend a good way to learn about tidyverse, please? Is
> there a book, please?
>
> Thanks,
> Erin
>
>
>
> Erin Hodgess, PhD
> mailto: erinm.hodg...@gmail.com
>
> [[
Thanks so much
e
Erin Hodgess, PhD
mailto: erinm.hodg...@gmail.com
On Sun, Aug 19, 2018 at 2:42 PM Ista Zahn wrote:
> https://www.tidyverse.org/learn/
> On Sun, Aug 19, 2018 at 4:29 PM Erin Hodgess
> wrote:
> >
> > Hello everyone!
> >
> > Could anyone recommend a good way to learn about
I am having trouble with what must be a very simple problem. Here is a
reproducible example:
library(lubridate)
st <- c("1961-01","1961-04","1983-02")
print(st)
#[1] "1961-01" "1961-04" "1983-02"
st1 <- as.Date(st, format=("%Y-%m"))
print(st1)
#[1] NA NA NA
Why the heck am I getting three NAs
Hi Philip:
Here is something to consider:
> #potential solution:
> sta <- paste(st,"-01",sep="")
> st1 <- as.Date(sta, format=("%Y-%m-%d"))
> print(st1)
[1] "1961-01-01" "1961-04-01" "1983-02-01"
Hope this helps!
Erin
Erin Hodgess, PhD
mailto: erinm.hodg...@gmail.com
On Sun, Aug 19, 2018 at
On Sun, Aug 19, 2018 at 05:20:29PM -0400, phili...@cpanel1.stormweb.net wrote:
> Why the heck am I getting three NAs instead of three Dates?I have
> studied the R documentation for as.Date() and it has not turned on
> the light bulb for me.
I haven't encountered this problem before, but in my mind
I think this hunch is off the mark... the file name is fine as it is... if
anything will confuse R it would be that the data inside the file are not what
was expected.
If in fact the file is csv formatted then the function to read it would be
read.csv [1] or read.table [2]. Read the help pages
I agree with Jeff. The data type is the problem. I wrote what I wrote without
looking at the problem very carefully.
--JJS
From: Jeff Newmiller
Sent: Sunday, August 19, 2018 4:38 PM
To: r-help@r-project.org; Sparks, John; Spencer Brackett; r-help@r-project.o
Hi Phillip,
Jose has the correct answer. You probably missed this sentence in the
"Note" section of the help page:
"If the date string does not specify the date completely, the returned
answer may be system-specific."
In your case, the function throws up its hands and returns NA as you
haven't sp
See comment inline below:
On 8/18/2018 10:06 PM, Rui Barradas wrote:
Hello,
It also works with class "factor":
df <- data.frame(variable = c("12.6%", "30.9%", "61.4%"))
class(df$variable)
#[1] "factor"
as.numeric(gsub(pattern = "%", "", df$variable))
#[1] 12.6 30.9 61.4
This is because sub(
Thanks Erin and Jim. You have indeed solved my problem.
Philip
Quoting Erin Hodgess :
Hi Philip:
Here is something to consider:
#potential solution:
sta <- paste(st,"-01",sep="")
st1 <- as.Date(sta, format=("%Y-%m-%d"))
print(st1)
[1] "1961-01-01" "1961-04-01" "1983-02-01"
Hope this hel
Hello,
Inline.
On 20/08/2018 01:08, Daniel Nordlund wrote:
See comment inline below:
On 8/18/2018 10:06 PM, Rui Barradas wrote:
Hello,
It also works with class "factor":
df <- data.frame(variable = c("12.6%", "30.9%", "61.4%"))
class(df$variable)
#[1] "factor"
as.numeric(gsub(pattern = "%"
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