Hello Andrew,
as you are "clean slate" anyway in handling XML files, you could take a look to
XSLT processing -- also an off-topic area.
There are free tools available around, and many examples of "XML to CSV XSLT"
on StackOverflow.
HTH,
Gabriele
-Original Message-
On January 4, 2017
Hi
I am trying to build my own package. When I run in RStudio (R3.3.2, all
packages updated, Roxygen available, Windows 10 machine) build-document, I get
the following error message:
==> devtools::document(roclets=c('rd', 'collate', 'namespace', 'vignette'))
Fehler in check_dep_version(pkg, ver
Hello guys,
The context is ordinary multivariate regression with k (>1) regressors,
i.e. *Y = XB + Error*, where
Y = n X 1 vector of predicted variable,
X = n X (k + 1) matrix of regressor variables(including ones in the first
column)
B = (k+1) vector of coefficients, including intercept.
Say, I
> On Jan 5, 2017, at 5:35 AM, Renger van Nieuwkoop
> wrote:
>
> Hi
> I am trying to build my own package. When I run in RStudio (R3.3.2, all
> packages updated, Roxygen available, Windows 10 machine) build-document, I
> get the following error message:
>
> ==> devtools::document(roclets=c('r
Hi all,
Is anyone aware of a package, function, or general R trick that would make
generating histograms like the one in the attachment easy in R (i.e.,
without manually drawing each individual horizontal line and specifying the
coordinates for a textbox for each number)?
I need to make ~12 of th
I recommend the stem function.
> stem(wt)
The decimal point is 1 digit(s) to the right of the |
12 | 57
14 | 4902479
16 | 1233444349
18 | 002507
> stem(wt, 2)
The decimal point is 1 digit(s) to the right of the |
13 | 57
14 | 49
15 | 02479
16 | 1233444
17 | 349
18 | 00
Hi Dan,
I'd probably start by looking at the various examples for stem and
leaf plot in R.
stem() or aplpack::stem.leaf() might help you get started, or if you
don't need the fancy boxes, be sufficient.
Sarah
On Thu, Jan 5, 2017 at 11:01 AM, Dan Abner wrote:
> Hi all,
>
> Is anyone aware of a
On 05/01/2017 11:01 AM, Dan Abner wrote:
Hi all,
Is anyone aware of a package, function, or general R trick that would make
generating histograms like the one in the attachment easy in R (i.e.,
without manually drawing each individual horizontal line and specifying the
coordinates for a textbox
Re-sending help request, went to wrong addy first time.
r-help-requ...@r-project.org
Belated Happy new year to the Guru's:
I have a data frame with 570+ columns and in those column headers yours truly
has a few blunders. Namely somehow I managed to end some of them with both an
apostrophe '
> On Jan 5, 2017, at 10:09 AM, Carl Sutton via R-help
> wrote:
>
> Re-sending help request, went to wrong addy first time.
> r-help-requ...@r-project.org
>
> Belated Happy new year to the Guru's:
>
> I have a data frame with 570+ columns and in those column headers yours truly
> has a few
Hello everyone,
I tried to get the IRkernel going doing the following:
install.packages(c('repr', 'IRdisplay', 'evaluate', 'crayon', 'pbdZMQ',
'devtools', 'uuid', 'digest'))
then taking care of proxy settings by doing:
library(devtools)
library(httr)
set_config(use_proxy(url="",port=8080,user
Dear R Users,
I am having the following problem with rJava, on a Windows 10 machine with R
3.3.2:
> library(rJava)
Error : .onLoad failed in loadNamespace() for 'rJava', details:
call: fun(libname, pkgname)
error: JAVA_HOME cannot be determined from the Registry
Error: package or namespace lo
I would guess that you don't have the Java runtime installed, or that the
wordsize (32 or 64 bit) runtime you have installed is not compatible with the
wordsize of the version of R that you are using.
You really should read and heed the Posting Guide, which mentions things like
mentioning your
Many thanks and will post accordingly.
Tolga
> On Jan 5, 2017, at 3:08 PM, Jeff Newmiller wrote:
>
> I would guess that you don't have the Java runtime installed, or that the
> wordsize (32 or 64 bit) runtime you have installed is not compatible with the
> wordsize of the version of R that you
Here's a different approach using barplot() to draw the boxes. The first line
in the function sorts the values so that they are printed from lowest to
highest on the histogram. If you want them in the original sequence, comment
this line out. It also assumes you want intervals of 10:
set.seed(4
> On Jan 5, 2017, at 11:16 AM, Paul Bernal wrote:
>
> Hello everyone,
>
> I tried to get the IRkernel going doing the following:
>
> install.packages(c('repr', 'IRdisplay', 'evaluate', 'crayon', 'pbdZMQ',
> 'devtools', 'uuid', 'digest'))
>
> then taking care of proxy settings by doing:
>
> l
Hi Dan,
This may help if your data is in the format below:
waffle.mat<-matrix(c(rep(NA,14),137,135,rep(NA,6),144,149,
rep(NA,3),150,152,159,157,154,
NA,163,164,164,161,162,165,164,rep(NA,5),179,173,173,
rep(NA,4),182,180,185,180,
rep(NA,6),197,190,rep(NA,8)),ncol=9)
waffle.col<-matrix("lightbl
On 06/01/17 10:31, Jim Lemon wrote:
Hi Dan,
This may help if your data is in the format below:
waffle.mat<-matrix(c(rep(NA,14),137,135,rep(NA,6),144,149,
rep(NA,3),150,152,159,157,154,
NA,163,164,164,161,162,165,164,rep(NA,5),179,173,173,
rep(NA,4),182,180,185,180,
rep(NA,6),197,190,rep(NA,8
A worthy challenge, Rolf:
egdat <- c(137,135,144,149,150,152,159,157,154,163,164,164,
161,162,165,164,179,173,173,182,180,185,180,197,190)
egcut<-cut(egdat,breaks=seq(120,210,by=10),right=FALSE)
eglist<-vector("list",9)
for(egindex in 1:9) eglist[[egindex]]<-rev(egdat[as.numeric(egcut)=
On 05/01/2017 5:21 PM, Rolf Turner wrote:
On 06/01/17 10:31, Jim Lemon wrote:
Hi Dan,
This may help if your data is in the format below:
waffle.mat<-matrix(c(rep(NA,14),137,135,rep(NA,6),144,149,
rep(NA,3),150,152,159,157,154,
NA,163,164,164,161,162,165,164,rep(NA,5),179,173,173,
rep(NA,4),1
Thank you gentlemen, thank you! All worked as you said it would and my
headers are now error free.
And David, thanks for the reference material cite. I will looking at that this
weekend.
Carl Sutton
On Thursday, January 5, 2017 12:12 PM, David Winsemius
wrote:
> On Jan 5, 2017,
Can you please help me with this assignment. I am having trouble with inputting
the ID. At the moment, the function will calculate 1-the ID number you put in.
I am not sure how to make it so that you can put only one number in or a range
of your choosing (a range that doesn’t start with 1)
__
Dear Mrs/Mr
I am a meteorological engineer and currently I am a master of science
student in atmospheric science at Istanbul Technical University. I have
data analysis and visualization lesson and I am analyzing data in R
programming. I have to project in this lesson and I am working on wind
energ
You should read the Posting Guide.
> On Jan 5, 2017, at 10:56 AM, elif beyza çatalbaş
> wrote:
>
> Dear Mrs/Mr
>
> I am a meteorological engineer and currently I am a master of science
> student in atmospheric science at Istanbul Technical University. I have
> data analysis and visualization l
You should read the Posting Guide.
> On Jan 5, 2017, at 12:40 PM, Malvika Marathe wrote:
>
> Can you please help me with this assignment. I am having trouble with
> inputting the ID. At the moment, the function will calculate 1-the ID number
> you put in. I am not sure how to make it so that
Hi R users,
I'm trying to concatenate two strings, while each string has numbers.
For example, strings1 = c(1.2, 1.31, 1.4, 1.51, etc), strings2= c(2.1,
2.22, 2.3, 2.44, etc). I want to have all decimals for the two strings,
such as: strings1= c(1.20, 1.31, 1.40, 1.51, etc), string2 = c(2.10, 2.22
I found that the last column is the digits 2.00, so the problem is solved.
On Thu, Jan 5, 2017 at 10:42 PM, lily li wrote:
> Hi R users,
>
> I'm trying to concatenate two strings, while each string has numbers.
> For example, strings1 = c(1.2, 1.31, 1.4, 1.51, etc), strings2= c(2.1,
> 2.22, 2.3,
Sorry for the emails. I just checked and the problem is still there. Is
there a proper way to reformat the decimal places, such as three or four
decimal places? Thanks.
If maintain four decimal places, the numbers are: 1.2000, 1.3100, 1.4000,
etc.
On Thu, Jan 5, 2017 at 10:46 PM, lily li wrote:
Hi lily,
maybe this is what you want:
strings1<-c(1.2,1.31,1.4,1.51)
strings2<-c(2.1,2.22,2.3,2.44)
paste(formatC(strings1,digits=2,format="f"),
formatC(strings2,digits=2,format="f"),sep="-")
Jim
On Fri, Jan 6, 2017 at 4:56 PM, lily li wrote:
> Sorry for the emails. I just checked and the pro
Hi Malvika,
What David means is that we don't do people's homework for them. Have
a look at "An Introduction to R" that comes with the R distribution,
particularly about sequences and vectorization.
Jim
On Fri, Jan 6, 2017 at 7:40 AM, Malvika Marathe wrote:
> Can you please help me with this as
Hi
It strongly reminds me following fortune
library(fortunes)
fortune("surgery")
Along with Posting guide you should also look at chapter 7 of R intro manual.
Cheers
Petr
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of David
> Winsemius
> Sent: Fri
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