Hi John,
I don't know how well it will handle your truncated left distribution, but I
use the function Mclust from package mclust to fit a mixture of normal
distribution and it works very well.
Denis
> Le 2015-06-30 à 22:22, John Sorkin a écrit :
>
> I am trying to model the mixture of two n
Hello,
I am trying to fit my data to the default autoregressive models in R. I'm
trying to apply the effectiveSize function from the coda package to a list of
data frames using;
sapply(splits, function(x) coda::effectiveSize(x["V5"]))
However when I do, I get the error;
Error in ar.yw.defa
Please help,I am spinning my wheels behind what should be a pretty simple
solution. I found a solution by asking another question on here but it seems to
not be effective on all my files of similar make up to the test case. I am
simply trying to read data into R, group/order it by chain and atom
Hello all,
I just installed "forecast" package but I have the following error when I
try to load the library:
> library("forecast")
Loading required package: zoo
Attaching package: ‘zoo’
The following objects are masked from ‘package:base’:
as.Date, as.Date.numeric
Loading required packa
Hi
Please no HTML posting. It is almost unreadable.
Do not post twice the same question, it is unnecessary.
I do not know coda package but without further info you probably do not get
sensible answer.
Is your splits data mcmc or mcmc.list object?
How does objects for which the function works
Hi
> -Original Message-
> From: Debra Ragland [mailto:ragland.de...@yahoo.com]
> Sent: Wednesday, July 01, 2015 4:53 PM
> To: PIKAL Petr
> Subject: Re: [R] applying coda package effectiveSize function to a list
>
> Hi Petr,
>
> How do I remove a post?
AFAIK, no way. Why?
Instead of remov
Indeed, this is OT. :-)
The way you have phrased your question, you are asking us for help to design
your study. Certainly very OT.
Once your study is designed, and it is of clear, potential benefit to the R
community, posting a concise _announcement_ here would not offend me.
Hope this helps
Hi All,
I have two datasets, vowels and qaaf, and both have 8 columns clarified as
follows:
1. convergence: DV (whether participants succeeded to use CA (Cairene
Arabic) or fail to do so; hence, they use MA (Minia Arabic)
2. speaker: 62 participants
3. lexical.item: as pronounced
4. style:
Thanks Thierry. Is it the longitude and latitude that need to have finite
values?
From: Thierry Onkelinx
Sent: Wednesday, July 01, 2015 2:50 AM
To: Chichi Shu
Cc: r-help@r-project.org
Subject: Re: [R] ggmap warning
Your data contains 4945 rows with missing or infinite values. These cannot b
Here's a partial answer to my own question. While I still don't know how to
get the arrow information out of a CCA plot, it is possible to reproduce the
arrows by first extracting the biplot data with scores (results.cca,
display="bp") and then using the ordiArrowMul function in vegan to rescale
th
All variables used in the plot must contain finite values. Without your
code we can only speculate about your code.
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie & Kwaliteitszorg / team Biometrics & Quality Assurance
Kliniekst
Dear Saudi Sadiq,
If you want answers to most of your questions, you'll likely have to provide
your data so that people can reproduce the errors. I can, however, answer part
of your last question without the data:
plot(allEffects(modelqaaf1)) fails because the data set is named q, and there
is
Dear list,
I have the following anova that I want to fit in R:
y_{ijk} = \mu + \alpha_i + \beta_{j(i)} + \epsilon_{ijk}
This is an application in biology, in which we are measuring a certain
(continuous) characteristic of a group of cells.
Hence y_{ijk} corresponds to the measurement on cell k o
I have 682 variables in a data frame , and a function that I should feed
682 variables in this function one by one and each time save the file as a
special name!
for emaple:
my data frame file includes 682 names :
1 aaa
2 bbb
3 dfdsfg
4 fghh
.
682 fgfhg
and a function like prep(Z, aaa, .)
Note that the toy example you provided is garbage. It has nothing to
do with contrasts (i.e. constraints) -- the DESIGN is singular: The
(2) - (1) difference for factor A is exactly the same as the (3,4,5)
average - (1,2)average for B. I suspect you need to use a mixed
effects model treating batch
Hi Bert,
I apologize for the HTML. I will pay more attention in the future.
I know that the lm() command of my toy example fits the wrong model
with a singular design, maybe I shouldn't have included it.
I believe that the model with the additional constraint(s) is not
garbage. But I don't know
You do not set constraints in R you set contrasts. See the relevant
sections of e.g. Venables and Ripley's MASS book.
?contrasts ## what else!
?C
for details.
Beyond this, I cannot help.
-- Bert
Bert Gunter
"Data is not information. Information is not knowledge. And knowledge
is certainly no
Here is a way to do case I. It uses the 'tidyr' package and produces
results like:
> case1[[1]]
YR JF-R_NINO1.2 MAM-R_NINO1.2 JJA-R_NINO1.2 OND-R_NINO1.2
1 1982 MLMLMESE
2 1983 SESESEME
3 1984
You never said how you wanted to save the data, so I will choose to use
'saveRDS' which should handle most anything.
for (i in name_file$names){
saveRDS(prep(z, i), file = paste0(i, '.RDS'))
}
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you
I forgot that you also wanted to change the variable name; I would suggest
that you don't use individual objects, but instead use a 'list'. Here is
how it would change
result <- lapply(name_file$names, function(.file){
result <- prep(z, .file)
saveRDS(result, file = paste0(.file, '.RDS'))
Update:
I was able to fit the desired model by manually specifying the proper
contrast for the second factor, i.e. (going on with my example).
mat <- matrix(c(1, -1, 0, 0, 0, 0, 0, 1, 0, -1, 0, 0, 0, 1, -1), ncol=3)
fit <- lm(y~a+b, contrasts = list(a=contr.sum, b=mat))
I guess that the proper w
for (var_name in names(z)) {
# assuming the prep function writes the content of z$var_name to the file
var_name.csv
prep(z, var_name)
}
On Wed, Jul 1, 2015 at 10:18 PM Lida Zeighami wrote:
> I have 682 variables in a data frame , and a function that I should feed
> 682 variables in this funct
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