Dear all,
I encountered a problem that has been bugging me for some hours now,
and I still can't come up with a viable solution. I tried searching
the archives, but to no avail, so here I am sending my first e-mail to
the list!
I am estimating a binary spatial autoregressive model via a Gibbs
samp
Hi Nia,
Many ways to do something like this, for example:
N<-6
sapply(1:N,function(x) return(sample(1:10,x,TRUE)))
I'll let you work out how to generalize this.
Jim
On Sun, Jun 14, 2015 at 3:06 PM, Bert Gunter wrote:
> Is this homework? Homework is deprecated here.
>
> ?lapply
>
> is one of m
On Jun 13, 2015, at 11:04 PM, Berend Hasselman wrote:
>
>> On 14-06-2015, at 06:25, Ramnik Bansal wrote:
>>
>> Thanks. But it seems to be an R 3.2.0 specific problem.
>>
>
> I replied with the following to a similar message on R-devel.
There was no error either with using help() or using th
Hi,
Just do the following:
> tran<-c(7.2)
> tgrid<-c(7.1,7.4,7.3,7.1,7.3)
> tgrid<-tgrid-tran
> tgrid
[1] -0.1 0.2 0.1 -0.1 0.1
> abs(tgrid[tgrid>0.1])
[1] 0.2
Andrés
> El 12/06/2015, a las 11:01, Jeff Newmiller
> escribió:
>
> FAQ 7.31
> ---
Dear group,
I have the following integer object
> a
3 4 6
3 3 6
how to get the most frequent value (it should be 3)
and get nothing if no frequent one and all is equal
3 4 6
3 4 6
Thanks in advance
Ragia
[[alternative HTML version deleted
Hi Ragia,
The basic method is to use "table" and examine the result:
> a<-matrix(c(3,3,4,3,6,6),nrow=2)
> b<-matrix(c(3,3,4,4,6,6),nrow=2)
> table(a)
a
3 4 6
3 1 2
but you can get the modal value directly like this:
library(prettyR)
Mode(a)
[1] "3"
Mode(b)
[1] ">1 mode"
Jim
On Mon, Jun 15, 201
Is this what you want:
> x1 = structure(list(Subject = c("x1", "x2"), A = c(1.5, -1.2), B = c(-1.3,
+ -0.3), C = c(0.4, 0.3), D = c(-0.2, -0.1)), .Names = c("Subject",
+ "A", "B", "C", "D"), class = "data.frame", row.names = c(NA,
+ -2L))
>
> x2 = structure(list(Subject = c("x1", "x2"), A = c(4.3,
check out the 'hexbin' package for making scatter plots that have a lot of
points overlapping in a small area.
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
On Tue, Jun 2, 2015 at 9:51 AM, Adams, Jean wrot
On Wed, Jun 10, 2015 at 8:05 PM, Joshua Ulrich wrote:
>
> This is known behavior with how POSIXt objects are printed. See the
> discussion on StackOverflow:
> http://stackoverflow.com/questions/7726034/how-r-formats-posixct-with-fractional-seconds
>
To summarize the relevant portion of the disc
Terry - your example didn't demonstrate the problem because the variable
that interacted with strata (zed) was not a factor variable.
But I had stated the problem incorrectly. It's not that there are too
many strata terms; there are too many non-strata terms when the variable
interacting with
Thank you very much. It worked!
On Sun, Jun 14, 2015 at 8:00 PM, jim holtman wrote:
> Is this what you want:
>
>> x1 = structure(list(Subject = c("x1", "x2"), A = c(1.5, -1.2), B = c(-1.3,
> + -0.3), C = c(0.4, 0.3), D = c(-0.2, -0.1)), .Names = c("Subject",
> + "A", "B", "C", "D"), class = "dat
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