On 2014-09-15 14:22, David L Carlson wrote:
I think switch() should work for you here, but it is not clear how
much flexibility you are trying to have (different tests based on the
first response; different tests based on first, then second response;
different tests based on each successive respo
There was indeed a bug in rmh() w.r.t. the "new.coeff" argument.
The bug has been fixed and will not be present in the next release of
spatstat.
cheers,
Rolf Turner
On 16/09/14 16:30, Sebastian Schutte wrote:
Thanks so much for your comments. Sorry for not having sent a running
example from
Hi
> Selection: 1
> Error in if (menu1 == 1) menu1a <- menu(c("1a", "2a", "3a", "4a"),
> graphics = FALSE, :
> argument is of length zero
>
> How to correct this error please, for this zero length argument?
Instead of writing functions which you are unable to debug and resolve look
what e
Is there a way to get around R’s memory-bound limitation by interfacing
with a Hadoop database or should I look at products like SAS or JMP to work
with data that has hundreds of thousands of records? Any help is
appreciated.
--
__
*Barry E. King, Ph.D.*
Analytics Modeler
On Tue, Sep 16, 2014 at 6:40 AM, Barry King wrote:
> Is there a way to get around R’s memory-bound limitation by interfacing
> with a Hadoop database or should I look at products like SAS or JMP to work
> with data that has hundreds of thousands of records? Any help is
> appreciated.
> __
On 2014-09-16 10:50, PIKAL Petr wrote:
switch(menu(c("List letters", "List LETTERS")) + 1,
cat("Nothing done\n"), letters, LETTERS)
why is the result changed if ' + 1,' removed?
Because +1 belongs to switch not to menu. You can translate above to:
The help pages ?switch, ?menu do no
If you need to start your question with a false dichotomy, by all means choose
the option you seem to have already chosen and stop trolling us.
If you actually want an answer here, try Googling on the topic first (is "R
hadoop" so un-obvious?) and then phrase a specific question so someone has a
Hi
One comment: I never used menu or switch, this is just how I understand its
function. So you probably are on a wrong track and do not understand what are
objects and functions in R languange.
menu
Description
menu presents the user with a menu of choices labelled from 1 to the number of
ch
Not sure trolling was intended here.
Anyways:
Yes, there are ways of working with very large datasets in R, using databases
or otherwise. Check the CRAN task views.
SAS will for _some_ purposes be able to avoid overflowing RAM by using
sequential file access. The biglm package is an example o
Hundreds of thousands of records usually fit into memory fine.
Hadley
On Tue, Sep 16, 2014 at 12:40 PM, Barry King wrote:
> Is there a way to get around R’s memory-bound limitation by interfacing
> with a Hadoop database or should I look at products like SAS or JMP to work
> with data that has h
You should use:
plot(density(rmh(mod,new.coef=c(1,200
Sorry, my bad, typo in the example code.
(2) However, even when the correct call is given you still wind up
with identical densities!!!
Hm. I think this may be a bug; I'll will check with the other
authors of spatstat and repor
Hello,
In my script I have one list of 1,132,533 vectors (each vector contains
381 elements).
When I use "write" to save this list in a flat text file (I unlist my
list, separate by tabs, and set ncol to 381), I end up with a file of
1,132,535 lines (2 additional lines). I checked back, my R li
Hello,
I have a file "x.mtx" stored as a array format MatrixMarket file.
The header says "%%MatrixMarket matrix array real general"
However when I do readMM("x.mtx"), it raises an error saying Error in
scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, :
scan() expected 'an int
On 16/09/2014 13:56, peter dalgaard wrote:
Not sure trolling was intended here.
Anyways:
Yes, there are ways of working with very large datasets in R, using databases
or otherwise. Check the CRAN task views.
SAS will for _some_ purposes be able to avoid overflowing RAM by using
sequential fi
Thanks, Ista. I think RFacebook package is using HTTR to get access token too.
So I don’t have to use it separately to get access token.
Once someone creates an app ID and secret, do they ever expire? I can’t find
any information online about the expiration of App ID and App secret so I’m
assum
Sure, here it is. Thanks for any help with this Dr. Pierce:
# Exporting to NETCDF files
#
# define the netcdf coordinate variables
library(ncdf)
dim1 = dim.def.ncdf( "Nodes","", seq(1,19000))
dim2= dim.def.ncdf( "Time","Hours s
> [*] I recall a student fitting a GLM with about 30 predictors to 1.5m
> records: at the time (ca R 2.14) it did not fit in 4GB but did in 8GB.
You can easily run out of memory when a few of the variables are
factors, each with many levels, and the user looks for interactions
between them. This
On Tue, Sep 16, 2014 at 11:36 AM, Hernan A. Moreno Ramirez
wrote:
> Sure, here it is. Thanks for any help with this Dr. Pierce:
>
>
> # Exporting to NETCDF files
> #
> # define the netcdf coordinate variables
> library(ncdf)
...
Remember, you have to *also* set force_v4=TRUE in the nc_create() call.
Regards,
--Dave
On Tue, Sep 16, 2014 at 2:01 PM, Hernan A. Moreno Ramirez
wrote:
> Hi Professor,
>
> Thanks for you valuable help. I did change my code to use ncdf4 package and
> still I get the same error:
>
> # Expor
Hi Professor,
Thanks for you valuable help. I did change my code to use ncdf4 package and
still I get the same error:
# Exporting to NETCDF files
#
# define the netcdf coordinate variables -- note these have values!
library(ncd
I'm trying to set up an AR(2) model in the dlm context. I've generated a time
series utilizing the code:
am = 800; #sample size
des = 200; #initial values to be discarded
V = 0.5
v = rnorm((am+des+1),0,sqrt(V))
W = 0.9
w = rnorm((am+des+1),0,sqrt(W))
U = 0.9
Hello,
I would like to evaluate the relationship between flows and phytoplankton
abundance (or Chlorophyll a concentrations) using a changepoint analysis.
Specifically, I have two study questions:
Study Question 1: Are there certain flow thresholds that result in spikes in
phytoplankton abun
Hi everyone,
Could there be an error in the predict() function in R for models
without intercepts which include one or more predictors? When using
the predict() function to obtain the standard errors of the fitted
values produced by a linear model (lm), the behaviour of the s
Hi Antonio,
I've just sent an e-mail to the r-help list with some R code which
shows that the standard errors of the fitted values are indeed
computed incorrectly by R (please see below). Let's hope that there
will be at least one helpful answer to the question.
B
This is primarily a statistical issue and is offtopic here.
I would strongly suggest that you consult with a local statistical
expert. The answer is almost certainly yes: this is regression
(perhaps quantile regression) in which the error structure is not iid
(the response is an autocorrelated tim
Hi,
Your example didn't come through, probably because you sent your message in
HTML. Please re send it in plain text (messages sent to this list should
always be plain text, as explained in the posting guide).
Best,
Ista
Hi everyone,
Could there be an error in the predict() fu
Hi everyone,
It appears my R code didn't come through the first time (thanks for letting me
know, Ista). Here is my message again:
Could there be an error in the predict() function in R for models without
intercepts which include one or more predictors?
When using the predict() function to
When I run your code (in the single predictor case) I get exactly what I
would expect. In particular the standard errors are indeed proportional
to the (absolute) value of x, and the standard error is indeed 0 at x = 0.
The proportionality constant is exactly what it should be, explicitly
s/
Hello R users,
I'm writing a brief tutorial of getting statistical measures by splitting
according strata and over columns. When I used plyr::ddply I got and
unexpected result, with NA/NaN for non existing cells. Below is a minimal
reproducible code with the result that I got. For comparison, the
Hi Rolf,
BODY { font-family:Arial, Helvetica, sans-serif;font-size:12px; }
Thanks very much for your response. You are right - my simulated
example works as intended, so it can't be used to get to the bottom of
this problem (if it is a problem at all).
Here is
Dear r Users,
I am new in r. I am trying to estimate regression quantiles in complex
surveys.I used these commands.
mydesign
<-svydesign(ids=~IDSCHOOL,strata=~IDSTRATE,data=TUNISIA,nest=TRUE,weights=~TOTWGT)
bootdesign <- as.svrepdesign(mydesign,type="auto",replicates=150)
fit+dictionary+in
I need to create a color vector with 4000 colors, and I have another
variable, it contains 4000 element. If my variable is number of bed, and I
want the color corresponds to the number of bed in this variable. How should
I do?
--
View this message in context:
http://r.789695.n4.nabble.com/How-
I answered this question which was part of the online course correctly by
executing some commands and guessing.
But I didn't get the gist of this approach though my R code works.
I have a training and test dataset.
> nrow(training)
[1] 251
> nrow(testing)
[1] 82
> head(training1)
diagnos
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