Subscribers,
apply block of if statements with menu function
Subscribers,
For a menu:
menu(c('a','b','c','d'))
How to create a function that will apply to specific menu choice
objects? For example:
object1<-function (menuifchoices) {
menu1<-menu(c('a','b','c','d'))
if (menu1==1)
Dear list
Version 3.0-1 of the Lahman package was recently submitted to CRAN. It
contains the
the tables from Sean Lahman's Baseball Database,
http://www.seanlahman.com/baseball-archive/statistics/
as a set of R data.frames with examples of use.
V 3.0 provides the updated data on pitching, hi
Leif Ruckman Ruckman.se> writes:
>
> I am going to buy a new computer ( Dell workstation T5810 - Windows 8)
> to work with simulatons in R.
>
> Now I am asked what kind of processor I like and I was given two choices.
>
> 1. Intel Xeon E5-1620 v3 - 4 cores 3.7 GHz Turbo
> 2. Intel Xeon E5-264
On 15/09/2014 11:21, Ben Bolker wrote:
Leif Ruckman Ruckman.se> writes:
I am going to buy a new computer ( Dell workstation T5810 - Windows 8)
to work with simulatons in R.
Now I am asked what kind of processor I like and I was given two choices.
1. Intel Xeon E5-1620 v3 - 4 cores 3.7 GHz T
Dear R and spatstat developers,
Thanks so much for the time and effort that you invest into this awesome
software. I have a problem simulating from a Point Process Model in
spatstat. In summary, the option "new.coef" should allow me to use a
fitted model and change its beta coefficients before
Thanks - I ended up getting our linux admin to let the server connect to the
internet and got it working.
Mark Ewing
From: ray48 [via R] [mailto:ml-node+s789695n4696884...@n4.nabble.com]
Sent: Friday, September 12, 2014 8:51 AM
To: Ewing, Mark
Subject: [I] Re: Installing nloptr in UNIX environ
Hello all,
I have a table like this, with ~300 individuals:
Famid Id Faid Moid CohortSex Survival Event SNP1 SNP2 SNP3
11000010 1010
22001120 1000
23000025 1010
4
hello everybody,
I have been trying to run "dbscan" algorithm on my data, my data round
4 records which each of them has 3 attributes + plus the ID for each
record.
the interesting thing is that when I run the "dbscan just on 3 attributes"
R gives me an ERROR regarding "stackoverflow" but when
I think switch() should work for you here, but it is not clear how much
flexibility you are trying to have (different tests based on the first
response; different tests based on first, then second response; different tests
based on each successive response).
?switch
For the second question ju
On 2014-09-15 14:22, David L Carlson wrote:
I think switch() should work for you here, but it is not clear how
much flexibility you are trying to have (different tests based on the
first response; different tests based on first, then second response;
different tests based on each successive respo
Dear useRs of R,
I have two datasets (TT and SS) and i wanted to to see if my data is uniformly
distributed or not?I tested it through chi-square test and results are given at
the end of it.Now apparently P-value has a significant importance but I cant
interpret the results and why it says that
On 09/15/2014 10:57 AM, eliza botto wrote:
Dear useRs of R,
I have two datasets (TT and SS) and i wanted to to see if my data is uniformly
distributed or not?I tested it through chi-square test and results are given at the end
of it.Now apparently P-value has a significant importance but I cant
I am learning to use sqldf() to read in very large fixed width files that
otherwise do not work efficiently with read.fwf. I found the following example
online and have worked with this in various ways to read in the data
cat("1 8.3
210.3
319.0
416.0
515.6
719.8
", file = "fixed")
fixed <- file
I'm in a similar situation and am looking seriously at a pair of E5-2643v3
(6 cores each-hyperthreaded).
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air Quality Modeler INTERNET: cl...@math.utah.edu
Department of Ecology VOICE: (360) 407-
Dear R and spatstat developers,
Thanks so much for the time and effort that you invest into this awesome
software. I have a problem simulating from a Point Process Model in
spatstat. In summary, the option "new.coef" should allow me to use a
fitted model and change its beta coefficients before
Dear all,
I have discovered a bug in the standard rep() function: At certain
values, rep() does not replicate the element by the proper number of times:
> a <- (1-0.9)*100
> a
[1] 10
> length(rep(1,times=a))
[1] 9
> length(rep(1,each=a))
[1] 9
As shown, this happens as well for the times= as
All,
I’ve attached the actual benchmark TACC and I used. I’ve also attached a paper
I wrote covering this in a little more detail. The paper specifies the
hardware configuration I used. Let me know if you have any other questions.
Regards,
Jonathan Anspach
Sr. Software Engineer
Intel Corp.
j
No, actually you've discovered FAQ 7.31.
> a <- (1-0.9)*100
> a
[1] 10
> print(a, digits=20)
[1] 9.9982236
In combination with the description in ?rep:
Non-integer values of ‘times’ will be truncated towards zero. If
‘times’ is a computed quantity it is prudent to add a sma
On 15/09/2014 16:30, Samuel Knapp wrote:
Dear all,
I have discovered a bug in the standard rep() function: At certain
Not so:
> a <- (1-0.9)*100
> trunc(a)
[1] 9
As the help says
Non-integer values of ‘times’ will be truncated towards zero. If
‘times’ is a computed quantity it is
On Mon, Sep 15, 2014 at 12:09 PM, Doran, Harold wrote:
> I am learning to use sqldf() to read in very large fixed width files that
> otherwise do not work efficiently with read.fwf. I found the following
> example online and have worked with this in various ways to read in the data
>
> cat("1 8.
Thank you, Gabor. This has seemingly resolved the issue. Perhaps a quick follow
up. Suppose I know that the 1st variable I am reading in is to be numeric and
the second is character. Can that be specified in the substr() argument?
sqldf("select substr(V1, 1, 1) f1, substr(V1, 2, 4) f2 from fixed
On Mon, Sep 15, 2014 at 3:23 PM, Doran, Harold wrote:
> Thank you, Gabor. This has seemingly resolved the issue. Perhaps a quick
> follow up. Suppose I know that the 1st variable I am reading in is to be
> numeric and the second is character. Can that be specified in the substr()
> argument?
>
Rick's question is a good one. It is unlikely that the results will be
informative, but from a technical standpoint, you can estimate the p value
using the simulate.p.value=TRUE argument to chisq.test().
> chisq.test(TT, simulate.p.value=TRUE)
Pearson's Chi-squared test with simulated p
I would have caught this tomorrow (I read the digest).
Some thoughts:
1. Skip the entire step of subsetting the death.kmat object. The coxme function knows how
to do this on its own, and is more likely to get it correct. My version of your code would be
deathdat.kmat <- 2* with(deathdat, ma
Your example is not reproducible. We don't have "cshape" or "im.pop"
(and are possibly lacking other bits and pieces; I didn't check the
details since the example fails to run from the get-go). Please provide
a *reproducible* example.
Also I am puzzled by the line
mod <- ppm (ppp, ~ pop
Thank you.
I got the point with non-integer values in rep(). I also red FAQ 7.3:
"The only numbers that can be represented exactly in R’s numeric type
are integers and fractions whose denominator is a power of 2."
But then I still don't understand:
> for (b in seq(0.2,0.8,0.2))
+ {
+ a <- (1
Hi, I want to use the quantile function, the example shown under "help"
x <- rnorm(1001)
quantile(x <- rnorm(1001)) # Extremes & Quartiles by default
quantile(x, probs = c(0.1, 0.5, 1, 2, 5, 10, 50, NA)/100)
I get the following error:
Error in quantile(x, probs = c(0.1, 0.5, 1, 2, 5, 10, 50, NA)
Hi all,
It is my pleasure to announce new members to R Core and to the R
Foundation
whose efforts will be most appreciated as R continues to evolve and
advance.
There are 2 new R core members: Martin Morgan and Michael Lawrence.
In addition Stefano Iacus has decided to step down from R
Hi I need help for plotting efficient frontier, I have expected return and
covariance matrix. I am using tseries and downloaded portfolio package too. The
suggestion says to use efficient.frontier, but it looks you replaces it by
something in R 3.1.1 as it says this is not available. At current
Hi I am using both ncdf and ncdf4 libraries and with both I keep getting the
same error: Error in R_nc_enddef: NetCDF: One or more variable sizes violate
format constraints. Error in R_nc_sync: NetCDF: Operation not allowed in
define mode. This happens when I try to create.ncdf() a file with more
hello everybody,
I have been trying to run "dbscan" algorithm on my data, my data round
4 records which each of them has 3 attributes + plus the ID for each
record.
the interesting thing is that when I run the "dbscan just on 3 attributes"
R gives me an ERROR regarding "stackoverflow" but when
On Mon, Sep 15, 2014 at 4:20 PM, Hernan A. Moreno Ramirez
wrote:
>
> Hi I am using both ncdf and ncdf4 libraries and with both I keep getting the
> same error: Error in R_nc_enddef: NetCDF: One or more variable sizes violate
> format constraints. Error in R_nc_sync: NetCDF: Operation not allowed i
On Sep 15, 2014, at 11:17 AM, Felix Dietrich wrote:
> Hi, I want to use the quantile function, the example shown under "help"
>
> x <- rnorm(1001)
> quantile(x <- rnorm(1001)) # Extremes & Quartiles by default
> quantile(x, probs = c(0.1, 0.5, 1, 2, 5, 10, 50, NA)/100)
>
> I get the following
> Why are the first two yielding an integer after multiplying, and the last two
> don't?
> Apparently, c(0.8,0.6,0.4,0.2) can't be represented exactly.
Most fractions cannot be represented exactly. Also, you cannot depend
on the third element of seq(.2,.8,by=.2) being equal to .6 (it is
slightly
Instead of repeating yourself, please do some research. There is a Posting
Guide mentioned at the bottom of this message. One of the things it mentions is
making a reproducible example. (You might find [1] helpful in that regard.)
Another thing it mentions is posting in plain text, which does no
Please read the posting guide (link at bottom of message) to learn how
to post coherently to get a useful response. I, at least, found your
post to be unintelligible gibberish.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
"Data is not information. Information is no
Thanks so much for your comments. Sorry for not having sent a running
example from the start. Here it is:
library (spatstat)
#Load example data
data(demopat)
#Generate a random point pattern within the polygon
set.seed(12345)
pdat <- rpoint(200,win=demopat$window)
#Generate a distmap, which wi
OK. Two things are going wrong.
(1) There is an error in your code. You are passing the new.coef
argument to density() and not to rmh(). The function density() has no
such argument, but has a "..." argument, so "new.coef" simply gets ignored.
You should use:
plot(density(rmh(mod,new.coef=
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