On Fri, 11 Jul 2014 12:19:39 PM Ryan de Vera wrote:
> Hello all,
>
> I have a data frame filled with senders and recipients. Some of the
senders
> have multiple rows with different recipients and I want to merge
those
> rows. For example I have
>
> a...@email.com b...@email.com
> a...@email
Hi Jeff,
Yes, I searched that but it comes out "zeta-squared coefficient" instead of
transformation method.
I hope if there is someone have the experience in applying "zeta-squared
transformation" in R?
Appreciate any help on this.
Regards,
miles
On Sat, Jul 12, 2014 at 4:01 PM, Jeff Newmille
Dear all,
I have a list of arrays :
foo<-list(A = c(1,3), B =c(1, 2), C = c(3, 1))
> foo
$A
[1] 1 3
$B
[1] 1 2
$C
[1] 3 1
> if( foo$C[1] == 1 ) foo$C[1]
> lapply(foo, function(x) if(x[1] == 1 ) x )
$A
[1] 1 3
$B
[1] 1 2
$C
NULL
I don't want to list $C NULL in the output. How I can
On 12.07.2014 15:25, ce wrote:
Dear all,
I have a list of arrays :
foo<-list(A = c(1,3), B =c(1, 2), C = c(3, 1))
foo
$A
[1] 1 3
$B
[1] 1 2
$C
[1] 3 1
if( foo$C[1] == 1 ) foo$C[1]
lapply(foo, function(x) if(x[1] == 1 ) x )
$A
[1] 1 3
$B
[1] 1 2
$C
NULL
I don't want to lis
This is a (very) slightly modified version of Jim's reply that takes the
sender's email our of the list element and uses it as the name so it can
be accessed as newdat$'senders email' or newdat[['senders email']]
newdat<-list()
for(sndr in unique(rdvdf$sender)) {
newvec<-
as.character(unique
Hello,
Try the following.
res <- lapply(foo, function(x) if(x[1] == 1 ) x )
res[!sapply(res, is.null)]
Hope this helps,
Rui Barradas
Em 12-07-2014 14:25, ce escreveu:
Dear all,
I have a list of arrays :
foo<-list(A = c(1,3), B =c(1, 2), C = c(3, 1))
foo
$A
[1] 1 3
$B
[1] 1 2
$C
[1
I think that removing them is something the OP doesn't understand how to do.
The lapply function ALWAYS produces an output element for every input element.
If this is not what you want then you need to choose a looping structure that
is not so tightly linked to the input, such as a for loop (unt
Thanks Jeff et. all,
This is exactly what I needed.
-Original Message-
From: "Jeff Newmiller" [jdnew...@dcn.davis.ca.us]
Date: 07/12/2014 10:38 AM
To: "Uwe Ligges" , "ce" ,
r-help@r-project.org
Subject: Re: [R] lapply returns NULL ?
I think that removing them is something the OP doesn'
Another option is
Filter(function(x) x[1] == 1, foo)
Best,
luke
On Sat, 12 Jul 2014, ce wrote:
Thanks Jeff et. all,
This is exactly what I needed.
-Original Message-
From: "Jeff Newmiller" [jdnew...@dcn.davis.ca.us]
Date: 07/12/2014 10:38 AM
To: "Uwe Ligges" , "ce" ,
r-help@r-proj
Hi,
I'm quite new to R and currently trying to use lm to fit linear models but I am
currently stuck my code is as follows:
Model1 = function(meth_matrix,exposure, X1, X2, X3, batch) {
mod = lm(meth_matrix[, methcol]~exposure+X1+X2+X3+batch)
res = summary(mod)$coef[2,]
system.time(in
Hi,
I am currently trying to build a regression model for calibration of
HPLC outputs. I decided to use a multiplicative error model:
Y_i = (a*X_i + b)*eps_i
where the eps_i ~ iid N(0, s^2). Now I am having a hard time estimating
my parameters ;) So the idea was to apply log() to both sides:
Dear R group,
I am trying to update Negative Binomial distribution parameters using MCMC
(Metropolis-within Gibbs sampling) method with Gamma prior.
Can someone direct me to where i can get some R codes for this?
Kind regards
Zakir
[[alternative HTML version deleted]]
_
Try this:
mod = lm(methcol ~ exposure+X1+X2+X3+batch, data = meth_matrix)
res=coef(summary(mod))[2,]
It will good if you give a subset of data you are working on by dput.
Raghu
On Sat, Jul 12, 2014 at 3:11 PM, Jessica Timms
wrote:
> Hi,
>
>
>
> I'm quite new to R and currently trying to use
Hi,
I'm working on a new set of simple, ecological modeling exercises for our
campus' undergraduate Introductory Biology lab series. The students work
with simple population models by looking at graphs and seeing how changing
parameter values and initial population sizes changes how the population
There are probably several solutions to what you want to do, but you might look
at Shiny as one possibility:
http://shiny.rstudio.com
-Roy M.
On Jul 12, 2014, at 1:47 PM, Louise Stevenson
wrote:
> Hi,
>
> I'm working on a new set of simple, ecological modeling exercises for our
> campus' und
I recommend RExcel.
RExcel is an add-in for Windows Excel that gives complete access to
the entirety of R
from Windows Excel. It is free for educational use.
The program by Erich Neuwirth is at http://rcom.univie.ac.at
Our book, designed as a supplement to any text, is at
http://www.springer.com/
On Jul 12, 2014, at 4:25 AM, Kevin Kunzmann wrote:
> Hi,
>
> I am currently trying to build a regression model for calibration of HPLC
> outputs. I decided to use a multiplicative error model:
>
> Y_i = (a*X_i + b)*eps_i
>
> where the eps_i ~ iid N(0, s^2). Now I am having a hard time estimat
Hi,
I was wondering if it's possible in R to do a canonical correlation with
only one dependent variable and several independent variables.
I've tried using cc(X,Y) but I got an error message. In this case I had 1
dependent variable and 10 independent variables.
Error in cor(X, use = "pairwise")
Hi Louise,
I tried using Deducer (graphical frontend to R) in my introductory
class (Stat 105 at Iowa State University) for civil and construction
engineers and this was a roaring success this year. The class itself
has a wee bit of software experience, which has previously been done
using JMP. M
Hello,
I'm running R.3.1.1 on Mac OS X 10.6.8 with gamm4 version 0.2-2 and lme4
version 1.1-7. I get the following error when trying to fit the simplest model
I can think of:
> fit = gamm4( y ~ s(x))
Warning message:
In deviance.merMod(ret$mer) :
deviance() is deprecated for REML fits; use R
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