Hello,
First of all use ?dput to post a data example.
dput(head(x, 20)) # paste the output of this in a post
Now, without a reproducible example it's difficult to say but maybe ?%in%
x[x$Species %in% names(sp)[1:2],]
Hope this helps,
Rui Barradas
Em 09-02-2014 00:03, Yuanzhi Li escreveu:
Many thanks, Peter. Creating a wrapper function for integrand using
Vectorize, and then integrating the wrapper, does indeed solve the
problem. I tried your final suggestion, but the variable x still gets
passed into pmvnorm inside the new mean and variance matrix, leading
to the same prob
Hi,
Try:
x[x$Species%in%names(sp)[1:2],]
A.K.
On Saturday, February 8, 2014 10:21 PM, Yuanzhi Li
wrote:
Hi, everyone
I met a small problem when I want take a subset from a data frame. The
data frame(x) looks like the followings(10 species with 3 measured
traits):
Species trait1 tra
Dear All,
I am Nasim Hasan a CS Student of New Mexico State
University(NMSU). I am using R for my course work on the topics of Big-Data. My
OS is Windows Seven and I using R's windows version of 3.0.2 along with the
R-Studio of version 0.98.495.
The problem is that,
Hello all,
To set options in a package I'm putting together I'd like to write a
function like options, that is:
my.options <- function(...) {
# ...
}
Now I'd like to access the named arguments that were passed to my
funtion within that function. How does that work? formals() doesn't do
it, neith
You seem to be under the impression that prettyTree() is something to do
with package rpart: it is not.
You need to ask the person who told you about prettyTree() where to find it.
On 09/02/2014 07:49, Nasim Hasan wrote:
Dear All,
I am Nasim Hasan a CS Student of New Mexico Stat
Hello,
Inside the function try
dots <- list(...)
Hope this helps,
Rui Barradas
Em 09-02-2014 12:14, Robert Latest escreveu:
Hello all,
To set options in a package I'm putting together I'd like to write a
function like options, that is:
my.options <- function(...) {
# ...
}
Now I'd like t
On 09/02/2014 12:14, Robert Latest wrote:
Hello all,
To set options in a package I'm putting together I'd like to write a
function like options, that is:
my.options <- function(...) {
# ...
}
Now I'd like to access the named arguments that were passed to my
funtion within that function. How do
On Sun, 09 Feb 2014 12:28:11 +
Rui Barradas wrote:
> Hello,
>
> Inside the function try
>
> dots <- list(...)
Hi guys,
thanks a lot. I knew it HAD to be something ultra-simple, like most
things in R.
Regards,
robert
__
R-help@r-project.org mai
On Sun, Feb 9, 2014 at 7:20 AM, Prof Brian Ripley wrote:
> You seem to be under the impression that prettyTree() is something to do
> with package rpart: it is not.
>
> You need to ask the person who told you about prettyTree() where to find it.
OR:
install.packages("sos")
library(sos)
findFn("p
On 09/02/2014 15:52, Ista Zahn wrote:
On Sun, Feb 9, 2014 at 7:20 AM, Prof Brian Ripley wrote:
You seem to be under the impression that prettyTree() is something to do
with package rpart: it is not.
You need to ask the person who told you about prettyTree() where to find it.
OR:
install.pac
Hello: I’m having troubles with plotting a barchart with percentages rather
than counts in ggplot2. I’m aware that others have a problem with this, but
cannot get this to work as I wish. At the end, I’d like a facetted barchart
with percentages rather than with counts. Thank you for any assist
I don't know why want to use Rstudio on the server, not the R itself.
If you use putty and do not need a GUI, I think R is enough.
If you really want to use Rstudio on your server, you can try Rstudio
server http://www.rstudio.com/ide/server/
On Sat, Feb 8, 2014 at 3:56 PM, Qike Li wrote:
> H
In the lubridate vignette
(http://cran.r-project.org/web/packages/lubridate/vignettes/lubridate.html)
setdiff(auckland, jsm)
results in
## [1] 2011-06-04 12:00:00 NZST--2011-07-20 NZST
But if Hadley's mentor had been called away earlier, say, July 31st,
wouldn't the set difference have resulted
On Feb 8, 2014, at 2:57 PM, Benjamin Ward (ENV) wrote:
> Hi, fellow R users,
>
> I've been asked to make a plot with two datasets each with a different x
> axis, and it's been suggested one be at the top and the other at the bottom
> of the graph. I normally use ggplot2, and I know how to plot
Hi all, first thanks for a so useful package! I have a question about
"gpagen". I understand that the resulting coordinates of this command are
in shape space, so for statistical analisys one must project them to
tangent space. But the command "plotTangetSpace" runs "prcomp" directly
over gpagen's
Hi everyone,
I previously posted this question but my message was not well written and did
not contain any code so I will try to do a better job this time.
The goal is to perform a non-linear regression on complex-valued data.
I will first give a short description of the data and then describe t
Hi,
Minor Additions:
The original file was as follows:
## ---
GunPos RaceNo Name Gender Cat Club GunTime ChipPos ChipTime
1 10038 Carl Allwood M Sutton & Ashfield Harriers 02:38:40 1 02:38:40
2 10098 Adam Holland M Votwo/USN 02:41:2
On 14-02-09 5:56 PM, Burhan ul haq wrote:
Hi,
Minor Additions:
The original file was as follows:
## ---
GunPos RaceNo Name Gender Cat Club GunTime ChipPos ChipTime
1 10038 Carl Allwood M Sutton & Ashfield Harriers 02:38:40 1 02:38
On Feb 9, 2014, at 2:48 PM, Burhan ul haq wrote:
> Hi,
>
> I am trying to read in a file, which is not delimited by any specific
> characters.
>
> Something as follows:
> ## ---
Lines <- readLines(textConnection("GunPos RaceNo Nam
Based on the data.
vec1 <- c(56,98,15)
vec2 <- sort(vec1,decreasing=TRUE)
vec2[1]-vec2[2]
#[1] 42
A.K.
Hi,
I need some help in a simple thing
If I have 3 classes like 56 98 15, I need do max1-max2
where the max 1 is the maximun (98) and the max2 is the second maximun
(56)...
Hello,
I am trying the ifelse command for imputing a variable based on a
conditional statement, but the NAs do not transform. The code I am trying
is:
ifelse (x==1, y=="NO", y=="YES"). However, the number of NAs remains the
same after the attempt. I would like to turn all Y (NAs included) int
On 02/10/2014 03:03 PM, Ana Genkova wrote:
Hello,
I am trying the ifelse command for imputing a variable based on a
conditional statement, but the NAs do not transform. The code I am trying
is:
ifelse (x==1, y=="NO", y=="YES"). However, the number of NAs remains the
same after the attempt.
On Feb 9, 2014, at 8:03 PM, Ana Genkova wrote:
> Hello,
>
> I am trying the ifelse command for imputing a variable based on a
> conditional statement, but the NAs do not transform. The code I am trying
> is:
>
> ifelse (x==1, y=="NO", y=="YES"). However, the number of NAs remains the
> same a
Hello Ana,
The syntax is:
y <- ifelse(x==1, 'YES', 'NO')
Hope this helps,
Pascal
On 10 February 2014 13:03, Ana Genkova wrote:
> Hello,
>
> I am trying the ifelse command for imputing a variable based on a
> conditional statement, but the NAs do not transform. The code I am trying
> is:
>
> if
... Well, the syntax is corrected, but it doesn't solve her problem:
ifelse() leaves NA's as NA's.
"But:, you ask, "what should NA's become?" As the OP does not tell
us, we are left to read tea leaves: only the Shadow knows...*
Cheers,
Bert
* The Shadow also knows about ?is.na, which the OP sh
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