I guess your problem is that you cannot write toplevel into "c:\" with
your permissions?
Best,
Uwe Ligges
On 16.12.2013 16:40, John Karon wrote:
Thanks for pointing out my error after specifying the destination in the
file( ) function. What you proposed also did not work.
It turns out the s
Thanks for pointing out my error after specifying the destination in the
file( ) function. What you proposed also did not work.
It turns out the solution is to give the file name but not include the path;
the resulting file is written in the working directory.
The mystery is that including the
On Dec 15, 2013, at 4:46 AM, 水静流深 wrote:
> t<--4:4
> y<-c(5,7,10,13,15,16,14,12,11)
> plot(t,y,type="l")
>
> how can i add a curve y=0.83*t-0.44*t^2 in the graph?
> [[alternative HTML version deleted]]
t<--4:4
y<-c(5,7,10,13,15,16,14,12,11)
plot(t,y,type="l", ylim=c(-4,16))
curve( 0.83
Julio Sergio Santana gmail.com> writes:
>
> I have a data frame whose first colum contains the names of the variables
> and whose second colum contains the values to assign to them:
>
>: kkk <- data.frame(vars=c("var1", "var2", "var3"),
> vals=c(10, 20, 30), stringsAs
On Dec 16, 2013, at 8:39 AM, David Carlson wrote:
> This will create a simple plot using Windows enhanced metafile
> format:
>
>> win.metafile("TestFigure.emf")
>> plot(rnorm(25), rnorm(25))
>> dev.off()
> null device
> 1
>>
>
> Windows does not read pdf.
This is correct for Offi
Greetings, I'm working on some analyses where I need to calculate wilcox
tests for paired samples. In my current literature search I've found a
few papers on sample size determination for the wilcox test notably:
Sample Size Determination for Some Common Nonparametric Tests
Gottfried E. Noether
J
Hi,
What could the cause of
history()
Error in savehistory(file) : no history available to save
savehistory(file="myhist")
Error in savehistory(file) : no history available to save
save.image()
be?
I have the information in the attached gif
Cheers Christian
--
Christian W. Hoffmann,
C
Dear List members,
I am trying to map the habitat suitability of Nephrops and one of my predictor
is a categorical variable.
However when I utilised the command "as.factor" (before to create my rasters
stack) I get the error message "Error in 1:ncol(r) : argument of length 0".
Could anyone hel
On 16/12/2013 15:14, Lauria, Valentina wrote:
Dear List members,
I am trying to map the habitat suitability of Nephrops and one of my predictor
is a categorical variable.
However when I utilised the command "as.factor" (before to create my rasters stack) I get
the error message "Error in 1:nc
Let us suppose that we have a function foo(X) which is called inside
another function, bar(). Suppose, moreover, that the name "X" has been
assigned a value when foo is called.
I have noticed that many functions contain arguments with defaults of
the form X=X. Call this reflexive assignment. How i
> I have noticed that many functions contain arguments with defaults of
> the form X=X.
Can you show us one (one that 'works')?
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Beh
Hey,
I have had another idea since. Is it possible to join these points together
(by lines) and then created a polygon from them?
Thanks
On Wed, Dec 11, 2013 at 10:43 PM, Shane Carey wrote:
> Hey,
>
> Thanks for this. I think I need some way of transposing the data onto a
> horizontal plane a
On Dec 16, 2013, at 8:27 AM, Collin Lynch wrote:
> Greetings, I'm working on some analyses where I need to calculate wilcox
> tests for paired samples. In my current literature search I've found a
> few papers on sample size determination for the wilcox test notably:
>
> Sample Size Determinati
Sorry about omitting library(plyr).
It's really thanks to Hadley, of course. His contributions make us all (capable
of being) better.
Eric
- Original message -
From: Michael Friendly
To: rmail...@justemail.net, r-help@r-project.org
Subject: Re: extracting non-NA entries from a two-way f
Ista Zahn wrote
> This is the R-help mailing list. If your problem persists when using R
> from the command line or with the GUI shipped with R on your
> (unspecified) platform post back here. Otherwise the RStudio support
> forum is at https://support.rstudio.com
>
> Best,
> Ista
>
> On Sat, Dec
>> columns are "处理水平"，“组别”，"物种数"。 But when I read this file with function
>> "read.csv" and displayed, these Chinese characters are garbled like the
>> followings：
>>> x<-read.csv("richness.csv")
>>> x[1:5,]
>> X..理?? X.?? 物种数
>> 1CK总 34
You have to, at least, use the check.names
Dear Rxperts..
I recently received a data file with the extension ".slk". If I save the
file as MS Excel file, I am able to read in R without issues. Is it
possible to read this ".slk" file without converting into another
R-readable data format?
Regards,
Santosh
[[alternative HTML versi
Indeed, I presume something changed. I would get an error message with the
file(description=.) command. The mystery is that everything worked fine
before. Thanks for your comments. john karon
From: Uwe Ligges-3 [via R]
Sent: Monday, December 16, 2013 8:44 AM
To: J Karon
Subject: Re: In
On 16/12/13 20:59, Jeff Newmiller wrote:
This is not a statistics theory forum, but posting a solution to this
nonsensical problem would be irresponsible.
Fortune?
cheers,
Rolf
__
R-help@r-project.org mailing list
https://stat.et
Unfortunately the win.metafile() device does not support semi-transparent
colours, which I like using.
In my experience, the best way to get R graphics into Word is to use compressed
high-resolution tiff, like this:
word.tif = function(filename="Word_Figure_%03d.tif", zoom=4, width=17,
height=
> From: Duncan Murdoch...
> Don't use a bitmap format (png).
I disagree. Each vector format comes with its own problems.
> Don't produce your graph in one format (screen display), then convert to
> another (png). Open the device in the format you want for the final file.
Agreed.
> Use a vect
Thanks to everyone for the helpful suggestions. -- David.
On Mon, Dec 16, 2013 at 7:23 PM, Steve Taylor wrote:
> > From: Duncan Murdoch...
>
> > Don't use a bitmap format (png).
> I disagree. Each vector format comes with its own problems.
>
> > Don't produce your graph in one format (scree
Anyway, thanks for all your response. These two sets of data are similar.
let's assume them are obtained from two experimental setups but at
the situation, so they are more similar but not the same because measure
error may be involved. I hope I can chose a set of data with a better
normal feature
Mydata is as under.
dat=" salary ex
+ 1 1856 1799
+ 2 1856 1800
+ 3 1858 1800
+ 4 1858 1801
+ 5 1862 1803
+ 6 1862 1805
+ 7 1862 1810
+ 8 1865 1805
+ 9 1865 1808
+ 10 1865 1815
+ 11 1865 1820
+ 12 1870 1810
+ 13 1870 1830
+ 14 1880 1840
+ 15 1880 1845
+ 16 1880 1851
+ 17
On Dec 16, 2013, at 10:50 PM, wrote:
> Mydata is as under.
> dat=" salary ex
> + 1 1856 1799
> + 2 1856 1800
> + 3 1858 1800
> + 4 1858 1801
>
snipped
> + "
>
> data<-read.table(text=dat,header=TRUE)
>
> I want to get the result(please see the attatchment),the header is sal
Dear R-help,
We are conducting a distance-based redundancy analysis using capscale and
then testing for statistical significance for six terms in the model for the
constrained ordination using anova.cca in the vegan package. The
significance test is sequential, i.e., testing for significance of a
hello,
I have a project in dose response and I should fit some models on my data.
how can I fit linear and quadritic models on my data?
many thanks,
mahboobe
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.
Hi,
I try to install the XML package, but unfortunatelly I get an erroron
uncompressing it
'Fehler in untar2(tarfile, files, list, exdir, restore_times) :
incomplete block on file'
I tried it manually using WinZip and tra in a Cygwin shell and get also errors
there.
gzip: stdin: unexpected e
Your question as posed is incomplete, because you have not specified what the
mean and standard deviation are of the distribution that you wish to use as the
target. Two histograms may each have an excellent fit to different
distributions, such that neither can be faulted as a poor fit to a norm
On 16-12-2013, at 08:52, 水静流深 <1248283...@qq.com> wrote:
> input <- "
> ty
> 1 5.3
> 2 7.2
> 3 9.6
> 4 12.9
> 5 17.1
> 6 23.2"
>dat<-read.table(textConnection(input),header=TRUE,sep="")
>t<-dat[,1]
>y<-da
Read the examples section of
?nls
You probably need to provide a start list of values.
There are some points you should note from the Posting Guide mentioned in the
footer of emails on this list: this is not a homework help forum, you should
provide a reproducible example, and you should not p
Hi all,
I am applying a Presence/absence Generalized additive model to model the
distribution of marine algae species in R. I have found that log transforming
the environmental variables improves the explained deviance of the model
considerably. While log transforming is common practice in GLM,
Hi,
Try:
dat1 <- read.table(text="id cat val
1 A 2
1 C 4
3 B 1
5 A 2
6 A 3
6 B 5
6 C 2
8 B 5
8 D 2
9 D 3",sep="",header=TRUE,stringsAsFactors=FALSE)
library(reshape2)
res1 <- dcast(dat1,id~cat,value.var="val",fill=0)
colnames(res1)[-1] <- paste0("cat",colnames(res1)[-1])
#o
It doesn't break anything - you can transform the predictors pretty much
any way you like, and it is often sensible as a way of tackling very
uneven leverage. By transforming predictors, all you are changing in the
model is what "smooth" means. e.g. smooth w.r.t. log(x) is somewhat
different to s
Hi,
I also would like to use quarters. I think a work around would be to just label
each record in the dataframe by its quarter.
i.e. you add a factor called 'Quarter' with four levels (Q1 to Q4) for each row
and you assign the level based on the month of the date.
You can easily do this with as.
Hi,
try
x <- seq(as.Date("2001/1/1"),as.Date("2010/1/1"),"3 months")
best,
daniel
Feladó: r-help-boun...@r-project.org [r-help-boun...@r-project.org] ;
meghatalmazó: Pancho Mulongeni [p.mulong...@namibia.pharmaccess.org]
Küldve: 2013. december 16. 13:05
On Dec 15, 2013, at 6:11 AM, Duncan Murdoch wrote:
> On 13-12-15 6:43 AM, 水静流深 wrote:
>> seq(as.Date("2001/1/1"),as.Date("2010/1/1"),"years")
>> seq(as.Date("2001/1/1"),as.Date("2010/1/1"),"weeks")
>> seq(as.Date("2001/1/1"),as.Date("2010/1/1"),"days")
>>
>> why there is no
>> seq(as.Date("2001
That will only work if your starting date happens to be the first day of the
year:
x <- seq(as.Date("2001/1/1"), as.Date("2010/1/1"), "3 months")
> head(x)
[1] "2001-01-01" "2001-04-01" "2001-07-01" "2001-10-01" "2002-01-01"
[6] "2002-04-01"
Compare that to:
x2 <- seq(as.Date("2001/2/3"), as.
Hi,
Also,
library(zoo)
format.yearqtr(x)
identical(gsub("\\-"," ",xqq),format.yearqtr(x))
#[1] TRUE
A.K.
On Monday, December 16, 2013 8:01 AM, Marc Schwartz
wrote:
On Dec 15, 2013, at 6:11 AM, Duncan Murdoch wrote:
> On 13-12-15 6:43 AM, 水静流深 wrote:
>> seq(as.Date("2001/1/1"),as.Date("20
水静流深 wrote:
i have write a function to convert decimal number into binary number in R.
dectobin can get right result ,it is so long ,is there a build-in function to
do ?
Try the R.utils package:
> library(R.utils)
> intToBin(12)
[1] "1100"
> intToBin(255)
[1] ""
> intToBin(65535)
This will create a simple plot using Windows enhanced metafile
format:
> win.metafile("TestFigure.emf")
> plot(rnorm(25), rnorm(25))
> dev.off()
null device
1
>
Windows does not read pdf. It will offer to import an eps
(encapsulated postscript) file, but it only imports the bitmap
thu
Hello Dears.
I have a 2 questions about Discriminant Analysis in R.
1- In "ade4" package I perform this analysis for both quantitative and
qualitative variables using "discrimin" function.
R gives me "Canonical weights/ Loadings" and "Canonical scores" but doesn't
give "*F* or *t *or *X-square *
Also
> tbl <- xtabs(val~id+cat, dat1)
> tbl
cat
id A B C D
1 2 0 4 0
3 0 1 0 0
5 2 0 0 0
6 3 5 2 0
8 0 5 0 2
9 0 0 0 3
To get your column names
> dimnames(tbl)$cat <- paste0("cat", dimnames(tbl)$cat)
> tbl
cat
id catA catB catC catD
12040
3010
It must be the case that this issue has already been rised before,
but I did not manage to find it in past posting.
In some cases, optim() and nlminb() declare a successful convergence,
but the corresponding Hessian is not positive-definite. A simplified
version of the original problem is given
Hi everyone,
This may be very simple but I couldn't figure it out. I have this function
rsm.lm<-function(data,xvar='xCmin',yvar='yCmin') {
#some calculation..
recast(df, xvar~yvar, id.var=1:2, measure.var=3)
#some other operations
}
df is a dataframe defined internally within the functi
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