Prof Brian Ripley stats.ox.ac.uk> writes:
> Basically Remote Desktop restricts the number of colours when connecting
> to a Windows Server machine, and interpolating rasters needs a lot of
> colours.
Hi Brain,
I looked into this further and have a solution.
1. On the server launch Remote Des
Dear all,
Could someone please point me to the definitive list of valid
characters that are allowed in object names in R? I believe that the
following list covers them:
_.abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789
but I would like to make sure.
Thank you,
Liviu
--
Do you kn
Hello,
(Apologies for the repost, but it appears that the original text was
garbled.)
I have recently discovered the modeest library, and am trying to understand
how to use it with non-numeric data (e.g. determining the most common last
name, or analysing customer demographics by zip code).
I ha
Hi
Quick question. I am running a multiple regression function for each column of
two data sets. That means as a result I get several coefficients. I have a
problem because data that I use for regression contains NA. How can I ignore NA
in lm function. I use the following code for regression:
On 13-07-27 7:36 AM, Liviu Andronic wrote:
Dear all,
Could someone please point me to the definitive list of valid
characters that are allowed in object names in R? I believe that the
following list covers them:
_.abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789
but I would like to
On Sat, Jul 27, 2013 at 3:08 PM, Duncan Murdoch
wrote:
> Your question is a little ambiguous. All characters are allowed in object
> names, but the parser will only recognize some of them if they are quoted in
> backticks.
>
> The ones it recognizes without the backticks are ones that the C isaln
So, I downloaded the source files of Hmisc and changed in the file latex.s line
688 'rotate' to 'sideways'. This does the work for landscape ctables in Latex.
I also wrote an email to the package maintainer. I consider this thread as
solved.
Best
Simon
On Jul 26, 2013, at 5:34 PM, Simon Ze
I did indeed install the r-base-dev.
However, I did not send to the Debian mailing list.
Thanks,
Erin
On Sat, Jul 27, 2013 at 12:27 AM, David Winsemius wrote:
>
> On Jul 26, 2013, at 9:45 PM, Erin Hodgess wrote:
>
> > Hello!
> >
> > I have just installed R on an Ubutnu machine (13.04)
>
> Did
HI,
set.seed(28)
dat1<- as.data.frame(matrix(sample(c(NA,1:20),100,replace=TRUE),ncol=10))
set.seed(49)
dat2<- as.data.frame(matrix(sample(c(NA,40:80),100,replace=TRUE),ncol=10))
lapply(seq_len(ncol(dat1)),function(i) {lm(dat2[,i]~dat1[,i])}) #works bcz the
default setting removes NA
Regarding
I have not tried anything like that but have a look at
www.google.ca/url?sa=t&rct=j&q=&esrc=s&source=web&cd=3&ved=0CDkQFjAC&url=http%3A%2F%2Fstackoverflow.com%2Fquestions%2F7476022%2Fgeom-point-and-geom-line-for-multiple-datasets-on-same-graph-in-ggplot2&ei=MfHzUej7FoSergG1_ICYAw&usg=AFQjCNH2b72a6
I have searched the r-help archive and saw only one unanswered post related
to mine.
My design is as follows.
- y is Bernoulli response
- x1 is continuous variable
- x2 is categorical (factor) variable with two levels
The experiment is completely within subjects. That is, each subject
r
Stanislav Aggerwal gmail.com> writes:
>
> I have searched the r-help archive and saw only one
> unanswered post related
> to mine.
Take a look at the r-sig-mixed-models (@r-project.org)
mailing list and archive ...
>
> My design is as follows.
>
>- y is Bernoulli response
>- x1 is
Hi
Thanks for your hints. I would like to describe my problem better and give an
examle of the data that I use.
I conduct the event study and I need to create abnormal returns for the daily
stock prices. I have for each stock returns from time period of 8 years. For
some days I don't have the
HI,
I couldn't get any error message with the data you provided.
return<- read.table(text="
ATI AMU
-1 0.734 9.003
0 0.999 2.001
1 3.097 -1.003
2 NA NA
3 NA 3.541
",sep="",header=TRUE)
median<- read.table(text="
ATI AMU
-1 3.224
Hi.
I've been puzzling about how to replace the nested loops below. The idea
is that the B dataframe has rows with a posix datetime and the C
dataframes has posix Start and End times. I want to assign a value to
the observations in B based in intersecting the appropriate
time-interval in C.
Dear R-helpers,
I compared various programs for cubic spline smoothing, and it appeared
that smooth.spline ( stats version 3.0.1) seems to behave surprisingly.
For enough long series and low values of lambda (or spar), the results
of smooth.spline seem to be different from those of sreg ( packa
On 13-07-27 2:50 PM, Jean-Luc Dupouey wrote:
Dear R-helpers,
I compared various programs for cubic spline smoothing, and it appeared
that smooth.spline ( stats version 3.0.1) seems to behave surprisingly.
For enough long series and low values of lambda (or spar), the results
of smooth.spline see
Perhaps: ?findInterval
(you may need to do some type conversion first)
-- Bert
On Sat, Jul 27, 2013 at 3:28 PM, John Helly wrote:
> Hi.
>
> I've been puzzling about how to replace the nested loops below. The idea is
> that the B dataframe has rows with a posix datetime and the C dataframes has
Dear all,,
thank you all for your help..Its been such a help but its not really
exactly what I am looking for. Apparently I havent explained the condition
very clearly. I hope this can works.
If the data on column product is duplicated from the previous row, (its
applied for response==buy and ==sa
HI,
May be this is what you wanted.
#using tt1
indx<-which(tt1$response=="buy")
tt1$newcolumn<-0
tt1[unique(unlist(lapply(seq_along(indx),function(i){x1<-if(i==length(indx))
seq(indx[i],nrow(tt1)) else if((indx[i+1]-indx[i])==1) indx[i] else
seq(indx[i]+1,indx[i+1]-1);x2<-
tt1[unique(c(indx[1:i]
If you wanted to wrap it in a function:
fun1<- function(dat,colName,newColumn){
indx<- which(dat[,colName]=="buy")
dat[,newColumn]<-0
dat[unique(unlist(lapply(seq_along(indx),function(i){
x1<- if(i==length(indx)){
seq(indx[i],nrow(dat))
}
All,
What is the current method for installing tikzDevice in R version 3.0.1? I'd
like to use it with knitr and RStudio.
Thanks.
D.
--
View this message in context:
http://r.789695.n4.nabble.com/tikzDevice-tp4672523.html
Sent from the R help mailing list archive at Nabble.com.
_
It seems I can still install from source under Ubuntu:
install.packages('tikzDevice', repos='http://r-forge.r-project.org',
type='source')
If you are under Windows, I think you have to install RTools.
I'm cc'ing its author to see if there is still hope to get it back to
CRAN, or if someone else
I am using a MacBook Pro, 10.6.8, R version 3.0.1. and RStudio 0.97.551. I
entered your command in the Console Window in RStudio and got the following
reply:
> install.packages('tikzDevice', repos='http://r-forge.r-project.org',
> type='source')
Warning in install.packages :
package ‘tikzDevice’
The following minimal example Sweave file compiled properly in RStudio.
\documentclass{article}
\begin{document}
Example text outside R code here; we know the value of pi is \Sexpr{pi}.
<>=
set.seed(1213) # for reproducibility
x = cumsum(rnorm(100))
mean(x) # mean of x
plot(x, type = 'l') # B
Dear Vanessa,
Glad to know that it works.
Sorry, I misunderstood ur question initially because there were no duplicates
for "product" from response=="buy" in your initial dataset (tt).
Regarding the code: what i did in brief is:
1. Find the rows with response=="buy
indx<- which(dat[,colName]=="bu
26 matches
Mail list logo
