Hi:
I am trying to map column names of a matrix to another data frame and
get values in a different column of data frame
I have a matrix m.
> my.numeric vec <- m[1,]
> my.numeric.vec
a b cd ef
2 1 49 10 3
## my data frame = df1
> df1
fileNametype sta
Dear Rui,
1) With test subject I mean each file (I have posted three similar files
above (2, 50 and 1112), but each test subject has one exact file (which
differs of course! --> 2, 50 an 1112 are the same file but I renamed it for
the problem described ans solved above). In this file the vpNum is
combined <- data.frame(mnv=my.numeric.vec[df1$fileName], type=df1$type)
sorted <- combined[order(rownames(combined)),]
On Wed, Jul 11, 2012 at 8:38 AM, Adrian Johnson
wrote:
> Hi:
> I am trying to map column names of a matrix to another data frame and
> get values in a different column of data
That is silly, but I have learned something. Thanks.
Though honestly, I've never seen the advantage of read.csv() over the more
versatile read.table().
Sarah
On Tuesday, July 10, 2012, peter dalgaard wrote:
>
> On Jul 10, 2012, at 21:44 , Sarah Goslee wrote:
> >
> > But note that if sep=";" the
On Jul 11, 2012, at 01:24 , Sarah Goslee wrote:
> That is silly, but I have learned something. Thanks.
>
(The silliest bit was when someone decided that numeric data files should use
locale-dependent conventions, notably decimal separators...)
> Though honestly, I've never seen the advantage o
I'm sure this is easy, but I'm new to R and can't find any example of
the following.
Here's what I'm trying to do in pseudo-code.
data$newvar <- ifelse(data$oldvar1 == 8, 1,data$oldvar2)
In other words, if the existing variable equals 8, then the new
variable should equal 1, otherwise the n
Seems to work for me:
> x <- data.frame(old1 = sample(c(1,2,8), 10, TRUE), old2 = 1:10)
> x$new <- ifelse(x$old1 == 8, 1, x$old2)
> x
old1 old2 new
1 11 1
2 22 2
3 23 3
4 84 1
5 15 5
6 86 1
7 87 1
8 28 8
9 2
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Jeff
> Sent: Tuesday, July 10, 2012 5:26 PM
> To: r-help
> Subject: [R] ifelse help
>
>
> I'm sure this is easy, but I'm new to R and can't find any example of
> the following.
At 07:41 PM 7/10/2012, you wrote:
Seems to work for me:
> x <- data.frame(old1 = sample(c(1,2,8), 10, TRUE), old2 = 1:10)
> x$new <- ifelse(x$old1 == 8, 1, x$old2)
> x
Thanks Jim and Dan. The problem ended up with a missing values issue
that threw me off. When your post confirmed that my co
You failed to tell us any of: the actual code you used, the data you were
working with, or the actual error you got. Your "pseudo-code" looks okay to me,
so I suggest you read the Posting Guide and try again. (Anything other than a
complete reproducible example of your problem is unlikely to eli
german "Null" == english "zero" :-)
2012/7/10 Rolf Turner
>
>
> In addition to taking cognisance of Richard Heiberger's reply you
> should also learn to distinguish between the concept of "null" and
> "zero". They are not at all the same thing.
>
> cheers,
>
> Rolf Turner
>
>
> On 1
Try putting the data into some kind of object. I'm not sure what R does with
the data from read.csv. I always
1) read the data into an object
2) print the data out
3) attach the data so that the headers become objects that contain the data
4) and yes, print the data out using ls
5) check the ou
Well I've figures out a painful way of doing it with triangles 3d, as
suggested in another post by Duncan Murdoch.
The code is disgusting, but it works.
x <- c(0,0.75,75.75,150.75,225.75,300.75,375.75,450.75,525.75,600.75,675.75,
675.75,0,
0,0.5,50.5,100.5,150.5,200.5,250.5,300.5,350.5,4
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--
Message: 2
Date: Tue, 10 Jul 2012 06:58:20 -04
Hi Try this:
df1<-read.table(text="
fileName type status
b N alive
a T dead
d N alive
c T dead
f N alive
e T dead
",sep="",header=TRUE)
mynumeric.vec<-c(a=2,b=1,c=4,d=9,e=10
Hi,
Perl:
perl -e 'print -1.1-0.1+1.2. "\n";'
-2.22044604925031e-16
perl -e 'print -1.2-0.2+1.4. "\n";'
0
A.K.
- Original Message -
From: massimodisasha
To: ollestrat ; r-help@r-project.org
Cc:
Sent: Tuesday, July 10, 2012 6:23 PM
Subject: Re: [R] -1.1 - 0.1 + 1.2 is NOT null! Why?
Hi, I'm currently having some problem connect .mdb file into R.
I've installed the RODBC packages and I do the code this way:
channel <- odbcConnectAccess("C:/Users/Documents/XYZ")
channel
and it gave me this :
RODBC Connection 3
Details:
case=nochange
DBQ=C:\USers\JieYi\Documents\NYP\IPP\GCR
D
Hi HJ,
No problem.
By changing the order of numbers in both perm and dim, you can create different
combinations
A.K.
- Original Message -
From: "yhj...@googlemail.com"
To: arun
Cc:
Sent: Tuesday, July 10, 2012 7:25 PM
Subject: Re: [R] Read vector as multi-dimensional data in R by r
Hi,
I need to position arrow according to content of data dynamically. let's say
i have vector c(2,3,56,9) and i need to put arrow at 56 dynamically. How
can i use above method.
Regards
--
View this message in context:
http://r.789695.n4.nabble.com/How-to-use-external-image-with-R-plot-tp4635
My apologies in advance as this seem like an easy thing to fix.
I am quite new to using R. I am doing my thesis at the moment and I am
trying to use the extremes package. However, when I try to access it I get
this message:
The following object(s) are masked from ‘package:stats’:
> library( extRe
David,
That message is not an error. It is simply telling you that there are
functions named qqnorm an qqplot in the extRemes package that are "masking"
functions of the same name in the stats package. Functions in a package
being loaded with the same names as functions in a package already loaded
On Tue, Jul 10, 2012 at 4:23 PM, FJ M wrote:
> 3) attach the data so that the headers become objects that contain the data
> attach(v_data)
This is a discouraged practice as it leads to difficult to trace
errors and non-local effects. Some "big names" of the R universe
suggest it [I think V of V
Are you sure XYZ is the name of the MDB file? Perhaps you are being fooled by
the default filename display that omits the extension?
---
Jeff NewmillerThe . . Go Live...
DCN:B
Hello,
Here are two ways of doing it.
df1 <- read.table(text="
fileNametype status
b N alive
a Tdead
d N alive
c T dead
f Nalive
e Tdead
", header=TRUE)
df1
my.num
Dear Rui,
1) With test subject I mean each file (I have posted three similar files
above (2, 50 and 1112), but each test subject has one exact file (which
differs of course! --> 2, 50 an 1112 are the same file but I renamed it for
the problem described ans solved above). In this file the vpNum is
imnew writes:
> Hi, I'm currently having some problem connect .mdb file into R.
> I've installed the RODBC packages and I do the code this way:
>
> channel <- odbcConnectAccess("C:/Users/Documents/XYZ")
>
> I have a total of 5 tables in the .mdb database. any one can help me with
> how to get t
On 10/07/2012 17:35, stanislas rebaudet wrote:
Hello,
I run [R] 2.14 on Mac OS 10.6 and I've been desperately trying to install rpy2
in order to compute spatial statistics on QGIS 1.7.3.
rpy2 is dependent upon the rgdal [R]package that I've been unable to install in
spite of up to date version
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