In data martedì 10 aprile 2012 13:34:13, Nevil Amos ha scritto:
> How do I remove a "$" character from a string sub() and gsub() with "$" or
> "\$" as pattern do not work.
>
> > sub("$","","ABC$DEF")
>
> [1] "ABC$DEF"
>
> > sub("\$","","ABC$DEF")
>
> Error: '\$' is an unrecognized escape in cha
Thank you for the replies, Uwe and Marc. These are explanations that make
perfect sense. However, shouldn't the behavior of plot.factor include the
option of type = "n" for consistency with the default plot function?
Best,
Martin
On 21 Apr 2012, at 08:18 , Marc Schwartz wrote:
> On Apr 21,
On 12-04-21 9:21 PM, Stoch astic wrote:
First time user, so sorry if I don't understand protocol.. Anyway, I have
created a data frame consisting of pearson's R values at various x and y
coordinates and then plotted this using filled.contour. My data is similar
to fMRI data except that it is a su
i have uploaded file,but when i am opening it in R,using
> u<-file(file.choose(),"r")
>k<-readLines(u)
>k
> k[1:120]
is has all /t (tabs)& newlines, how to avoid it,
can i take first 3 columns only in table form (lines starts with # not
important for me)
uploaded file:-
http://r.789695.n4.nabble
i want to cut file from e.g. "abc" folder & put it into another location
with folder name e.g. "xyz"
how should i proceed?
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Hello,
I have tried obtaining the value of standard error from the code below but i
get different values when i compare it with the
standard error obtained from the hessian matrix. Can somebody help me out?
Thank you
n=100;rr=1000
p1=1.2;b=1.5
sq11=sq21=0
for (i in 1:rr){
t<-rweibull(n,shape=p1,
Why you need a double backslash is alluded
to in Circle 8.1.23 of 'The R Inferno'.
http://www.burns-stat.com/pages/Tutor/R_inferno.pdf
Pat
On 22/04/2012 10:18, Giuseppe Marinelli wrote:
In data martedì 10 aprile 2012 13:34:13, Nevil Amos ha scritto:
How do I remove a "$" character from a stri
I figured out something new that I would like to see if I can do this more
easy with R then Excel.
I have these huge files with data.
For example:
DataFile.csv
ID Name log2
1 Fantasy 5.651
2 New 7.60518
3 Finding 8.9532
4 Looeka -0.248652
5 Vani 0.3548
With like header1: ID, header 2:
On 22-04-2012, at 13:03, Yellow wrote:
> I figured out something new that I would like to see if I can do this more
> easy with R then Excel.
>
> I have these huge files with data.
> For example:
>
> DataFile.csv
> ID Name log2
> 1 Fantasy 5.651
> 2 New 7.60518
> 3 Finding 8.9532
> 4 Lo
I am also compairing 2 things with each other.
x = c(1, 5, 7, 9)
y = c(2, 7, 9, 10, 11)
intersect(x, y)
Output will be: 7, 9.
Hope it helped. :)
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?file.copy
Or ?system
From: sagarnikam123
Date: Sun, 22 Apr 2012 01:25:21 -0700 (PDT)
i want to cut file from e.g. "abc" folder & put it into another location
with folder name e.g. "xyz"
how should i proceed?
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"Quidvis recte factum, quamvis humile, praeclarum."
Hello,
Berend Hasselman wrote
>
> On 22-04-2012, at 13:03, Yellow wrote:
>
>> I figured out something new that I would like to see if I can do this
>> more
>> easy with R then Excel.
>>
>> I have these huge files with data.
>> For example:
>>
>> DataFile.csv
>> ID Name log2
>> 1 Fantasy
I have to agree that Excel is a poor tool for "serious scientific and
engineering data analysis" (love the phrase.) I too have spent way too
much time beating Excel files into submission, with workarounds and
manipulations, just to be able to do anything useful with them. I'm told
that one can
On Apr 22, 2012, at 1:25 AM, Martin Renner wrote:
> Thank you for the replies, Uwe and Marc. These are explanations that make
> perfect sense. However, shouldn't the behavior of plot.factor include the
> option of type = "n" for consistency with the default plot function?
>
> Best,
> Martin
How about, "don't avoid them, use them"?
dta <- read.table( " http://r.789695.n4.nabble.com/file/n4577757/rabata.txt
rabata.txt", as.is=TRUE, skip=4, sep="\t" )
---
Jeff NewmillerThe . .
Hi everyone!
I have to following question: I have three items that had
to be ordered (e.g. three persons were rating var1 on the
first rank):
var1 var2 var3
123
213
132
123
Now I'd like to have the data.frame "the other way round", so that
the ranks are in the col
Hello,
sagarnikam123 wrote
>
> i have uploaded file,but when i am opening it in R,using
>
>> u<-file(file.choose(),"r")
>>k<-readLines(u)
>>k
>> k[1:120]
>
> is has all /t (tabs)& newlines, how to avoid it,
> can i take first 3 columns only in table form (lines starts with # not
> important fo
The cut/copy/paste paradigm is not common in programmed file manipulation under
various operating systems... due to cross-platform compatibility, be prepared
to work on files with a copy(=duplicate)/remove approach.
?files
Dear R-Gurus
I have a data frame (from CSV file) which has its first column called Date.
The Date is in the format mm/dd/. I was trying to get the weekday for
these dates and I tried using wday() and day.of.week() functions and both
of them gave me precisely the wrong answers. I think the issu
Yes dput() for a reproducible example with some minimal
reproducible code (and the packages "day.of.week" and wday() come
from...)
x <- xts(10, Sys.Date())
wday(x)
seems fine for me.
"precisely the wrong answers" -- interesting turn of phrase.
Michael
On Sun, Apr 22, 2012 at 12:53 PM, Rag
On Sun, 22 Apr 2012, David Studer wrote:
Hi everyone!
I have to following question: I have three items that had
to be ordered (e.g. three persons were rating var1 on the
first rank):
var1 var2 var3
123
213
132
123
Now I'd like to have the data.frame "the other
Raghu,
On 22 April 2012 09:53, Raghuraman Ramachandran wrote:
> I have a data frame (from CSV file) which has its first column called Date.
> The Date is in the format mm/dd/. I was trying to get the weekday for
> these dates and I tried using wday() and day.of.week() functions and both
> of
O_o This is kinda interesting
I have 267 log2 values >= 7.
And 295 ID numbers.
I don't see any problems in my code also:
ID_Log2_Above_7 = DataFile[DataFile$log2 >= 7, c("ID", "Log2"]
# Take ID out.
ID_Above_7 = ID_Log2_Above_7$ID
# Only numbers, no na or inf.
ID_Above_7_NO_NA
On Sun, 22 Apr 2012, Hasan Diwan wrote:
Raghu,
On 22 April 2012 09:53, Raghuraman Ramachandran wrote:
I have a data frame (from CSV file) which has its first column called Date.
The Date is in the format mm/dd/. I was trying to get the weekday for
these dates and I tried using wday() and
Please provide self-contained, reproducible examples.
On Sun, 22 Apr 2012, Yellow wrote:
O_o This is kinda interesting
I have 267 log2 values >= 7.
And 295 ID numbers.
I don't see any problems in my code also:
ID_Log2_Above_7 = DataFile[DataFile$log2 >= 7, c("ID", "Log2"]
Missing a
I tried downloading using as.is and have also provided the dput below. The
date for example is 20/4/2012 and wday gives 2 instead of 6? Thanks for all
your help.
> str(test1)
'data.frame': 1825 obs. of 7 variables:
$ Date : chr "20/04/2012" "19/04/2012" "18/04/2012" "17/04/2012" ...
$ Op
sagarnikam123 writes:
> i want to cut file from e.g. "abc" folder & put it into another location
> with folder name e.g. "xyz"
> how should i proceed?
See
?files
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/how-to-cut-files-from-any-folder-to-another-folder-tp4577
I also tried:
> test$Date=as.POSIXct(test$Date,format="%m%d%y")
> test=cbind(test,day.of.week=format(test$Date,format="%A"))
> head(test)
Date Open High Low Close Volume Adj.Close day.of.week
1 2.33 2.34 2.31 2.31 5366000 2.31
2 2.35 2.36 2.33 2.35 5382000 2.35
On 22-04-2012, at 20:12, Raghuraman Ramachandran wrote:
> I tried downloading using as.is and have also provided the dput below. The
> date for example is 20/4/2012 and wday gives 2 instead of 6? Thanks for all
> your help.
dt <- "20/04/2012"
> as.Date(dt)
[1] "0020-04-20"
> as.Date(dt,format="
On Apr 22, 2012, at 2:12 PM, Raghuraman Ramachandran wrote:
I tried downloading using as.is and have also provided the dput
below. The
date for example is 20/4/2012 and wday gives 2 instead of 6? Thanks
for all
your help.
str(test1)
'data.frame': 1825 obs. of 7 variables:
$ Date :
On Apr 22, 2012, at 2:18 PM, Raghuraman Ramachandran wrote:
I also tried:
test$Date=as.POSIXct(test$Date,format="%m%d%y")
Well, as became apparent when you eventually offered an example, you
have dates in dd/mm/ format, so it's hardly surprising that "it
didn't work" with a format
I have created an S4 object type for conducting fire department data
analysis. The object includes validity check that ensures certain fields
are present and that duplicate records don't exist for certain combinations
of columns (e.g. no duplicate incident number / incident data / unit ID
ensures
Hello,
SMALL, reproducible examples...
Anyway, it's not that difficult. Try this
d.of.w <- as.integer(format(as.Date(test1$Date, format="%d/%m/%Y"), "%w"))
str(d.of.w)
head(d.of.w)
Note that the format '%w' gives days in 0-6, where Sunday == 0. See
?strftime.
Your Friday is therefore 5.
(Or us
The text below is a part of, some work I have to do, which is due in 2 days
and I am strung up with a lot of other stuff, so I was hoping someone would
take 5 mins and help me ??
Here is a part of my data.frame:
year country1 country2 contig comlangpop1gdp1
pop2
Thanks all (particularly to you, Berend) -- I'll push forward with these
solutions and integrate them into my code. I did come across geigen while
rooting around in the CCA code but its not formally documented (it just
says "for internal use" or something along those lines) and as you found
out ab
On 22-04-2012, at 21:08, Jonathan Greenberg wrote:
> Thanks all (particularly to you, Berend) -- I'll push forward with these
> solutions and integrate them into my code. I did come across geigen while
> rooting around in the CCA code but its not formally documented (it just says
> "for inter
Look at ?ifelse, a combination of logical subscripting and mean(), or even
better ?ave -- I can't say too much more; there's a no homework policy on this
list and I recognize that first solution as mine already... (I should have
noted that the first time)
Michael
On Apr 22, 2012, at 2:54 PM,
Hello,
phillip03 wrote
>
> The text below is a part of, some work I have to do, which is due in 2
> days and I am strung up with a lot of other stuff, so I was hoping someone
> would take 5 mins and help me ??
>
> Here is a part of my data.frame:
>
> year country1 country2 contig comlang
This looks like a perfect case for an RExcel solution.
RExcel is an addin that allows you, among other things, to place an
arbitrary R function inside the
Excel automatic recalculation mode. For details see
rcom.univie.ac.at
There are many references item listed on the wiki page in the left panel.
On Sun, Apr 22, 2012 at 7:03 AM, Yellow wrote:
> I figured out something new that I would like to see if I can do this more
> easy with R then Excel.
>
> I have these huge files with data.
> For example:
>
> DataFile.csv
> ID Name log2
> 1 Fantasy 5.651
> 2 New 7.60518
> 3 Finding 8.9532
> 4 Looek
Hi, all.
I've written a function that returns the survival function for a Gompertz
mortality model. I've specified the two model parameters. Using a simple
integration, I can calculate the life expectancy at any age. Is there a way
I can use a loop with the integration that will quickly return
I have tried ifelse:
> trade<-data.frame(avgflow,EMU,stringsAsFactors=FALSE)
> avgflowEURO<-rep(0,nrow(trade))
> trade1<-(for (i in
> 1:nrow(trade)){ifelse(EMU[i]==1,avgflowEURO[i]<-avgflow[i],NA)})
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Does mean(avgflow[EMU]) sum the avgflows for all countrypairs where
EMU[i]==TRUE and take the mean ? Practical question: is mean(avgflow[EMU]) =
mean(avgflow[EMU==TRUE]) ???
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phillip03 wrote
>
> Does mean(avgflow[EMU]) sum the avgflows for all countrypairs where
> EMU[i]==TRUE and take the mean ? Practical question: is mean(avgflow[EMU])
> = mean(avgflow[EMU==TRUE]) ???
>
Answer: yes.
Rui Barradas
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If I go to wiki -> "how to install" it looks like a rather complicated
installation that involves installing R followed by several command line
prompts.
It looks like it might be too much of an installation process to make sense
for a client to conduct a one-time data check.
Looks like a great to
On Apr 22, 2012, at 3:41 PM, piltdownpunk wrote:
Hi, all.
I've written a function that returns the survival function for a
Gompertz
mortality model. I've specified the two model parameters. Using a
simple
integration, I can calculate the life expectancy at any age. Is
there a way
I c
Dear List,
I built a package under both Mac and Win 7 (both on R 2.12.0) . One of the
functions in the package is set up to print a status message using the code
below:
if (verbose)
if ((i %% 10) == 0 && i < ntree) message( "", i, "out of", ntree,
"trees so far...")
This works perfectly o
On 23/04/12 09:36, Axel Urbiz wrote:
Dear List,
I built a package under both Mac and Win 7 (both on R 2.12.0) . One of the
functions in the package is set up to print a status message using the code
below:
if (verbose)
if ((i %% 10) == 0&& i< ntree) message( "", i, "out of", ntree,
"
Thank you Rui
Can you help me with my ifelse problem - I would like to add a list to my
data.frame where avgflow in those rows where ONLY my country pair both are
in euro
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CRAN (and crantastic) updates this week
New packages
* appell (0.0-3)
Maintainer: Daniel Sabanes Bove
Author(s): Daniel Sabanes Bove with
contributions by F. D. Colavecchia, R. C. Forrey, G.
Gasaneo, N. L. J. Michel, L. F. Shampine, M. V. Stoitsov
On 12-04-22 5:36 PM, Axel Urbiz wrote:
Dear List,
I built a package under both Mac and Win 7 (both on R 2.12.0) . One of the
functions in the package is set up to print a status message using the code
below:
if (verbose)
if ((i %% 10) == 0&& i< ntree) message( "", i, "out of", ntree,
I actually tried "robustPca" in "pcaMethods" on bioconductor.
It keeps giving me the warning "Input data is not complete"...
Reading into the function:
When there is no "NA"s, it will give this warning...
It seems that there is a bug in this code...
Is it reliable at all?
Any thoughts on this error in robustSVD?
Thanks a lot!
Error in if (!all(tmp)) { : missing value where TRUE/FALSE needed
Enter a frame number, or 0 to exit
1: #73: pca(dTmp, method = "robustPca", nPcs = nNumFactors, center = FALSE)
2: robustPca(prepres$data, nPcs = nPcs, ...)
3: robustSvd(Mat
On Sun, Apr 22, 2012 at 4:43 PM, Michael wrote:
> I actually tried "robustPca" in "pcaMethods" on bioconductor.
>
> It keeps giving me the warning "Input data is not complete"...
>
> Reading into the function:
>
> When there is no "NA"s, it will give this warning...
>
> It seems that there is a bu
Even in R, there are so many of "robust PCA"... any survey or review of all
these different methods?
On Sun, Apr 22, 2012 at 6:58 PM, Joshua Wiley wrote:
> On Sun, Apr 22, 2012 at 4:43 PM, Michael wrote:
> > I actually tried "robustPca" in "pcaMethods" on bioconductor.
> >
> > It keeps giving me
As I believe I already told you, look at the CRAN Robust task view.
-- Bert
On Sun, Apr 22, 2012 at 6:29 PM, Michael wrote:
> Even in R, there are so many of "robust PCA"... any survey or review of all
> these different methods?
>
> On Sun, Apr 22, 2012 at 6:58 PM, Joshua Wiley wrote:
>
>> On Su
I cleaned up my old benchmarking code and added checks for missing
data to compare various ways of finding OLS regression coefficients.
I thought I would share this for others. the long and short of it is
that I would recommend
ols.crossprod = function (y, x) {
x <- as.ma
Hello,
The Scopus bibliographic database allows one to manually download batches of
2000 publications. The data is rich but does not provide one with a field
containing the author id. However, author id's can be retrieved through the
hyperlinks on the Scopus website. I have two questions:
1. My i
Hi Eik or other who might help:
I got this error:
"Error in roc.formula(form = y1 ~ x + z, plot = "ROC") :
Invalid formula: exactly 1 predictor is required in a formula of type
response~predictor.
"
when I ran "out=ROC( form = y1 ~ x + z, plot="ROC") " from your code.
How to fix it?
Thanks.
-
boa.plot('trace')
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yes, but that is not a good Review or Survey... thx
On Sun, Apr 22, 2012 at 9:47 PM, Bert Gunter wrote:
> As I believe I already told you, look at the CRAN Robust task view.
>
> -- Bert
>
> On Sun, Apr 22, 2012 at 6:29 PM, Michael wrote:
> > Even in R, there are so many of "robust PCA"... any s
On Mon, Apr 23, 2012 at 12:01 AM, Michael wrote:
> yes, but that is not a good Review or Survey... thx
But the packages listed there do have their own documentation and
vignettes. For instance the rrcov package seems to have a nice
vignette about its design as well as methods it implements, and
r
Hi Barry,
Thanks so much for the Junk Charts link. Maybe it'll help me make my case
for why we shouldn't present our data like this.
Susanna
On Mon, Apr 9, 2012 at 1:07 PM, Barry Rowlingson <
b.rowling...@lancaster.ac.uk> wrote:
> On Mon, Apr 9, 2012 at 7:29 AM, Susanna Makela
> wrote:
> > Hel
Hi R users,
I am sort of new on those.
In the following logistic regression function "tigol( 0.3 + 3*x + 5*z + 7*w
) ", why the intercept was set 0.3, and the coefficients were set 3 ,5 and
7?
Thanks.
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Hello,
May i know whether it is possible to generate data twice from Weibull
distribution and use one as the start time and the
other as the end time, below is my code.
Any suggestion on how to estimate the parameters of Weibull distribution with
interval data will be highly appreciated.
Thank y
Hello,
I have tried obtaining the value of standard error from the code below but i
get different values when i compare it with the
standard error obtained from the hessian matrix. Can somebody help me out?
Thank you
n=100;rr=1000
p1=1.2;b=1.5
sq11=sq21=0
for (i in 1:rr){
t<-rweibull(n,shape=p1,
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