use 'unlist'
> x <- list(1:10, 20:27, 30:50)
> x
[[1]]
[1] 1 2 3 4 5 6 7 8 9 10
[[2]]
[1] 20 21 22 23 24 25 26 27
[[3]]
[1] 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50
> quantile(unlist(x))
0% 25% 50% 75% 100%
1.0 15.0 31.0 40.5 50.0
>
On Thu, Mar 17, 2011
On Thu, Mar 17, 2011 at 4:54 PM, David Wolfskill wrote:
> On Thu, Mar 17, 2011 at 10:23:33AM -0400, Gabor Grothendieck wrote:
>> On Thu, Mar 17, 2011 at 9:38 AM, David Wolfskill wrote:
>> ...
>> > But the X-axis labels show up as "large integers" -- the POSIXct values
>> > are apparently treated
G'day Gabor,
On Thu, 17 Mar 2011 11:36:38 -0400
Gabor Grothendieck wrote:
> The idea is that if you have a positive quantity that can be broken
> down into two nonnegative quantities: X = X1 + X2 then it makes sense
> to ask what proportion X1 is of X. For example: 10 = 6 + 4 and 6 is
> .6 of
On Thu, Mar 17, 2011 at 07:52:29PM -0400, Gabor Grothendieck wrote:
> ...
> > I hope to learn what I'm misunderstanding.
> ...
>
> This line in the code above produces an invalid object:
> class(df$time) <- "POSIXct"
>
> It should be:
> class(df$time) <- c("POSIXct", "POSIXt")
Ah. Thank you, Si
On Thu, Mar 17, 2011 at 10:06:21PM +, Khanvilkar, Shashank wrote:
> Hello,
> Thanks in advance for any help,
>
> I have read a CSV file in which there is a column for an IP addr as in:
>
> tmpInFile$V2
> [1] "74.125.224.38" "74.125.224.38" "129.46.71.19" "129.46.71.19"
> [5] "129.46.71.1
On Thu, Mar 17, 2011 at 8:22 PM, Berwin A Turlach
wrote:
> G'day Gabor,
>
> On Thu, 17 Mar 2011 11:36:38 -0400
> Gabor Grothendieck wrote:
>
>> The idea is that if you have a positive quantity that can be broken
>> down into two nonnegative quantities: X = X1 + X2 then it makes sense
>> to ask wh
Hi!
Not an elegant solution, but seems to work:
date <- c(1:300)
flow <- sin(2*pi/53*c(1:300))
levels <- factor(rep(c("high","med","low"),100))
data <- cbind.data.frame(date, flow, levels)
colours <- as.numeric(levels)+1
# interpolate
resolution <- 0.001
appres <- approx(date,flow,seq(min(date
G'day Gabor,
On Thu, 17 Mar 2011 20:38:21 -0400
Gabor Grothendieck wrote:
> > Or am I missing something?
O.k., because the residuals don't add to zero, there may be a non-zero
correlation between residuals and fitted values, which messes up the
equation at the variance level.
> Try it on an ex
Hi,
because each colour is defined on non-consecutive points, you'll
probably need to cut the intervals to define segments around each
point. One approach might be the following,
d = transform(data, start = date - c(0, diff(date)/2), end = date +
c(0, diff(date)/2) )
d$start.y = approx(d$date, d
Hi:
Try this:
plot(ts(rnorm(100), start = 2004, freq = 12), xaxt = 'n', yaxt = 'n',
xlab = '', ylab = '')
axis(1, at = c(2004:2012), cex.axis = 0.7)
axis(2, cex.axis = 0.7)
title(xlab = 'My X lab', ylab = 'RQI', cex.lab = 0.1)
The illegible dots in the region where the axis labels would nor
Indeed, I forgot about the segments function.
with(d,plot(date,flow,type="n"))
with(d,segments(start,start.y,end,end.y,col=colour))
> Hi,
>
> because each colour is defined on non-consecutive points, you'll
> probably need to cut the intervals to define segments around each
> point. One approa
On 2011-03-17 16:37, Axel Urbiz wrote:
Dear List,
This is an embarrassing question, but I can seem to make this work…How do I
change the font size on the xlab and on the numbers shown in the x-axis on
the time series plot below. The arguments cex.lab and cex.axis do not seem
to be 'passing' to
This mostly seemed like a condensation of what had been said
before ... threads from the past which were readily available through
searching.
http://finzi.psych.upenn.edu/R/Rhelp02/archive/20370.html
http://finzi.psych.upenn.edu/R/Rhelp02/archive/73750.html
http://finzi.psych.upenn.edu/R/Rhe
names(which.max(table(x)))
This is a 'named' vector
On Thu, Mar 17, 2011 at 8:58 PM, Khanvilkar, Shashank
wrote:
> Thanks
>
>> which.max(table(x))
> 129.46.71.19
> 10
>
> How do I get only "129.46.71.19" back as a str...
>
>
> -Original Message-
> From: jim holtman [mailto:jholt
Taby,
At the end of your note are you referring to the bootstrap confidence
intervals in the "external validation" case, i.e., not corrrected for
overfitting? If so you can get that without the bootstrap (e.g., Hmisc
package rcorr.cens function).
You can get bootstrap overfitting-corrected ROC a
On Mar 17, 2011, at 5:44 PM, ufuk beyaztas wrote:
Hi dear all,
It may be a simple question, i have a list output with different
number of
elements as following;
[[1]]
[1] 0.86801402 -0.82974691 0.3974 -0.98566707 -4.96576856
-1.32056754
[7] -5.54093319 -0.07600462 -1.34457280 -1.04
On Mar 17, 2011, at 6:06 PM, Khanvilkar, Shashank wrote:
Hello,
Thanks in advance for any help,
I have read a CSV file in which there is a column for an IP addr as
in:
tmpInFile$V2
[1] "74.125.224.38" "74.125.224.38" "129.46.71.19" "129.46.71.19"
[5] "129.46.71.19" "129.46.71.19" "129
On Mar 17, 2011, at 6:33 PM, Pamela Allen wrote:
Hi All,
I'm trying to plot data that is a time series of flows that are
associated
with a specific level, and I would like each level to represent a
colour
in a line plot. Here is some data that approximates what I'm using:
date=c(1:300)
I read it but it said PDF file and Ps, didn´t specify which other files, so I
attached a csv file, which I thought would work.I have uploaded the file in
rapidhare (second option was putting on the
web):http://rapidshare.com/files/453101614/Coordinates_and_values.csv
Hope this works.Thanks for
Hi everyone,
Is there any command to identify the pattern of responses of a database
with this format:
year id
20081
20091
20082
20092
20083
20093
20084
20094
20104
I just need the frequency of the patterns grouped by id:
2008 2009 2010 = 80
2009
Hi,
I have been learning the quantmod package over the last several days. I
went to check some of my data pulls against other sources and was
surprised to find that a few tickers that have single characters do not
successfully scrape from Google Finance using getFin(). Particularly
require(quan
Hi all.
I'm having a little trouble with the function "texteval" (session package).
I have used "texteval" in the construction of the function "ExpandData1".
"ExpandData1" does not work as expected. However, when I run only the inside
code
of "ExpandData1" I get the right result. Apparently "te
Thanks
> which.max(table(x))
129.46.71.19
10
How do I get only "129.46.71.19" back as a str...
-Original Message-
From: jim holtman [mailto:jholt...@gmail.com]
Sent: Thursday, March 17, 2011 4:39 PM
To: Khanvilkar, Shashank
Cc: r-help
Subject: Re: [R] Histograms with strings,
Have timestamp in format HH:MM:SS.MMM.UUU and need to remove the last "." so
it is in format HH:MM:SS.MMMUUU.
What is the fastest way to do this, since it has to be repeated on millions
of rows. Should I use regex ?
Currently doing it with a string split, which is slow:
>head(ts)
[1] 09:30:00
Dear R community members
I have been struggling on this simple question, but never get appropriate
solution. So please help.
# my data, though I have a large number of variables
var1 <- rnorm(500, 10,4)
var2 <- rnorm(500, 20, 8)
var3 <- rnorm(500, 30, 18)
var4 <- rnorm(500, 40, 20)
datafr1 <- da
Does someone have confirmatory factor analysis program in R,which includes
factor loading and some tests?thank you!
--
View this message in context:
http://r.789695.n4.nabble.com/confirmatory-factor-analysis-program-in-R-tp3386133p3386133.html
Sent from the R help mailing list archive at Nabble.
Dear List,
First off, this is completely off topic, but I thought others might
find it interesting. The good people at IBM are apparently providing
written interpretations of results now. I was working with a student
the other day with simple nonparametric tests using SPSS, and under
the nonpara
Hi all.
I'm working on an assignment for a psychology class and I am not sure how to
adjust the y-axis so it displays the range: 0, 5, 10, 15
The code below is almost ideal:
lsd = c(3, 5, 13)
mar = c(1, 2, 3)
g_range <- range(0, lsd, mar)
plot(lsd, type="o", col="blue", ylim=g_range,
axes=FALSE,
Hi Caitlin,
You just need to set the ylim argument to plot (you already did but
g_range is 0, 13 not 0, 15. So...
On Thu, Mar 17, 2011 at 10:49 PM, Caitlin wrote:
> Hi all.
>
> I'm working on an assignment for a psychology class and I am not sure how to
> adjust the y-axis so it displays the ra
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