Hi,
I'm new to R and I have a file with many rows of values. Each row contains a
title and values for a contingency table
e.g.
row 1= title8 0 37796 47
which is a table called 'title'
with values
8 0
37796 47
I would like to know how I can import this using R and for each
On Thu, 4 Nov 2010, Noah Silverman wrote:
Hi,
I'm trying to figure out how to use capturing parenthesis in regular
expressions in R. (Doing this in Perl, Java, etc. is fairly trivial, but I
can't seem to find the functionality in R.)
For example, given the string:"10 Nov 13.00 (PFE1020
That's perfect!
Don't know how I missed that.
I want to start playing with some modeling of financial data and the
only format I can download is rather ugly. So my plan is to use a
series of Regex to extract what I want.
Noticed that you are a Prof. in applied stats. I'm at UCLA working on
an
Hello, Emily,
take a look at read.table() for importing (with or without header
depending on your file which holds the data). Maybe
X <- read.table( "yourfilename", header = FALSE, row.names = 1)
and then
pvalues <- apply( X, 1,
function( x)
fisher.test(
FWIW: It turns out I dove into a rabbit hole:
1. Though the gaps in my 3-axis accelerometer data represent 10% data
loss (OMG!), the number of gaps represents only 0.1% of the 3 million
data points (BFD).
2. The data is noisy enough that 0.1% discontinuity can't affect an
FFT. Each gap was
Dear all,
I've written a function and repeated it for 5000 times with loops with
different value, and the messages returned are the output I set and 15
warnings.
I would like to trace the warnings by stopping the loop when warning came
out.
Does anyone know how to make it?
Thanks a lot fo
Hi folks,
(Learning R)
5.1 Arrays
http://cran.r-project.org/doc/manuals/R-intro.html#Vectors-and-assignment
1)
If continued on previous example (3.1 Intrinsic attributes: mode and length),
> z <- 0:9
> dim(z) <- c(3,5,100)
Error in dim(z) <- c(3, 5, 100) :
dims [product 1500] do not match th
Hello,
One approach would be to fit your distribution using MCMC with, for
example, the rjags package. Then you can use the "zeroes trick" or
"ones trick" to implement your new distribution as described here...
http://mathstat.helsinki.fi/openbugs/data/Docu/Tricks.html
You will find a summary of
Penny,
The ?makeDepmix page has an example of how to add your own response
distribution model.
hth, Ingmar
On Fri, Oct 22, 2010 at 3:08 PM, Penny Adversario wrote:
> I am running a latent class regression with 3 nominal and 2 ordinal
> variables using depmixS4 but the available response models d
hey
I am trying to turn a dataframe into xts with the function:
as.xts,
but it returns the error:
Error in as.POSIXlt.character(x, tz, ...) :
character string is not in a standard unambiguous format
could someone give me some pointers please
the data is coming from a spreadsheet via the excel,
I was just thinking of a way to present data and if it is possible in R.
I have a data frame that looks as follows (this is just mockup data).
df
location,"species1","species2","species3","species4","species5"
"loc1",0.44,0.28,0.37,-0.24,0.41
"loc2",0.54,0.62,0.34,0.52,0.71
"loc3",-0.33,0.75,-0.
On Fri, 5 Nov 2010, Stephen Liu wrote:
[snip]
"0" is counted as 1 object.
Of course! It is a number like any other.
Does "object length" mean the total number of objects/entries?
Yes.
Please help me to understand follow;
"For example if the dimension vector for an array, say a, is c(3,4
> install.packages("fortunes")
> library(fortunes)
> fortune("yoda")
Evelyn Hall: I would like to know how (if) I can extract some of the
information from the summary of my nlme.
Simon Blomberg: This is R. There is no if. Only how.
-- Evelyn Hall and Simon 'Yoda' Blomberg
R-help (April 20
Hi Gerrit,
Thanks for your advice.
- snip -
> A[i, j, k] is the value of the element in position (i,j,k) of array A. In
> other words, it is the entry in row i, column j, and "layer" k (if one
> wants to think of A as a cuboidal grid).
Sorry I can't follow. Could you pls explain in more d
Like James Booth, I find the SSQ and MSQ in lmer output confusing. The
F-ratio (1.485) for Variety is the same for aov, lme and lmer, but
lmer's mean square for variety is 1.485 times the subplot residual mean
square. In the conventional anova table for a split-plot expt, the
variety mean square is
Dear list members,
I have been using filled.contour in order to plot EEG data. For the colors, I
used a conventional ramp from blue to red (blue - green - yellow - red), and
100 color levels to make the plot looking smooth:
(...) color.palette = colorRampPalette(c('blue','green', 'yellow','
On Fri, Nov 5, 2010 at 4:45 AM, fugelpitch wrote:
>
> I was just thinking of a way to present data and if it is possible in R.
>
> I have a data frame that looks as follows (this is just mockup data).
>
> df
> location,"species1","species2","species3","species4","species5"
> "loc1",0.44,0.28,0.37,
Dear R Users,
Tried to install RBloomberg with R-2.12.0 and appears RDComclient has not been
built for this version of R, so failed. I then tried to get RBloombergs' Java
API version to work, but ran into problems with RJava which does not appear to
exist for Windows. My platform is Windows XP
It would be very useful if you would post some information about what
exactly you are doing. There si something with the size of the data
object you are processing ('str' would help us understand it) and then
a portion of the script (both before and after the error message) so
we can understand th
Hi:
Look at the structure of the experiment.
The six blocks represent different replications of the experiment.
No treatment is assigned at the block level.
Within a particular block, there are three plots, to which each
variety is randomly assigned to one of them. Ideally, separate
randomization
?options
and then you will find the following:
warn:
sets the handling of warning messages. If warn is negative all
warnings are ignored. If warn is zero (the default) warnings are
stored until the top–level function returns. If fewer than 10 warnings
were signalled they will be printed otherwise
On Nov 5, 2010, at 7:36 AM, Gregor Volberg wrote:
Dear list members,
I have been using filled.contour in order to plot EEG data. For the
colors, I used a conventional ramp from blue to red (blue - green -
yellow - red), and 100 color levels to make the plot looking smooth:
(...) color.p
On 11/4/10 11:31 PM, sayan dasgupta wrote:
> Thanks a lot thats exactly what I was looking for
>
> Just a quick question I agree the form gets submitted to the URL
> "http://www.nseindia.com/marketinfo/indices/histdata/historicalindices.jsp";
>
> and I am filling up the form in the page
> "http
On 11/5/10 5:20 AM, Tolga I Uzuner wrote:
> Dear R Users,
>
> Tried to install RBloomberg with R-2.12.0 and appears RDComclient has not
> been built for this version of R, so failed. I then tried to get RBloombergs'
> Java API version to work, but ran into problems with RJava which does not
>
> Date: Fri, 5 Nov 2010 00:14:15 -0700
> From: flym...@gmail.com
> To: marchy...@hotmail.com
> CC: ggrothendi...@gmail.com; r-help@r-project.org;
> rpy-l...@lists.sourceforge.net
> Subject: Re: [R] NFFT on a Zoo?
>
> FWIW: It turns out I dove into a r
Hi,
On Fri, Nov 5, 2010 at 6:00 AM, Stephen Liu wrote:
[snip]
>> A[i, j, k] is the value of the element in position (i,j,k) of array A. In
>> other words, it is the entry in row i, column j, and "layer" k (if one
>> wants to think of A as a cuboidal grid).
>
> Sorry I can't follow. Could you pls
Hi folks,
Debian 600 64bit desktop
> sudo R
Password:
> install.packages("RBloomberg", repos="http://R-Forge.R-project.org";)
* DONE (zoo)
ERROR: dependencies ‘rcom’, ‘bitops’, ‘RUnit’ are not available for package
‘RBloomberg’
* removing ‘/usr/local/lib/R/site-library/RBloomberg’
Fai
Hi Steve,
> It's not clear what you're having problems understanding. By
> setting the "dim" attribute of your (1d) vector, you are changing
> itsdimenensions.
I'm following An Introduction to R to learn R
On
5.1 Arrays
http://cran.r-project.org/doc/manuals/R-intro.html#Vectors-and-assignment
Hello All,
I have a zoo structure as follows:
> dput(tMRet)
structure(c(0.00138742474397713, -0.0309023681475112, 0.0390276302410908,
0.0832282874685357, -0.00315002033871414, -0.0158548785709138,
-0.0410876001496389, -0.0503189291168807, 0.00229628598547049,
0.112348434473647, 0.07600046962546
Dear all,
I am using ubuntu linux 32 with 4 Gb. I am running a very small script and I
always got the same error message: CAN NOT ALLOCATE A VECTOR OF SIZE 231.8 Mb.
I have reading carefully the instruction in ?Memory. Using the function gc() I
got very low numbers of memory (please sea belo
On Fri, Nov 5, 2010 at 11:21 AM, Santosh Srinivas
wrote:
> Hello All,
>
> I have a zoo structure as follows:
>> dput(tMRet)
> structure(c(0.00138742474397713, -0.0309023681475112, 0.0390276302410908,
> 0.0832282874685357, -0.00315002033871414, -0.0158548785709138,
> -0.0410876001496389, -0.0503189
Hi,
On Fri, Nov 5, 2010 at 10:56 AM, Stephen Liu wrote:
> Hi Steve,
>
>> It's not clear what you're having problems understanding. By
>> setting the "dim" attribute of your (1d) vector, you are changing
>> itsdimenensions.
>
> I'm following An Introduction to R to learn R
>
> On
>
> 5.1 Arrays
>
Hi.
I have a coxph model of variables linked to survival in
medulloblastoma. The data were collated from various publications and
not all authors quoted all variables. I'd like to internally validate
the model and have tried bootstrapping it using boot.stepAIC but it
fails because of th
A "very small script" should fit just fine in an email: what are you
trying to do?
Likely, you are assigning many small variables in some loop. Even if you
have 4GB of RAM available, if R assigns 3.99 GB of it and then then a call
comes in to assign something of size .02, it will tell you it ca
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf Of Stephen Liu
> Sent: Friday, November 05, 2010 7:57 AM
> To: Steve Lianoglou
> Cc: r-help@r-project.org
> Subject: Re: [R] About 5.1 Arrays
>
> Hi Steve,
>
> > It's not clear what
Thanks Gabor for pointing in the right direction.
Looked up cycle and the doc is tough to understand " cycle gives the
positions in the cycle of each observation." ... how is cycle defined.
I just extended your idea to make it readable for an avg. user in the
following way
mRet[format(index(mRet),
Hi Ela,
as.xts() calls as.POSIXlt() to convert the dates to a date/time class.
Evidently, the the column that contains your times is not
"unambiguous" to POSIX, that is, the format is not clear. It is
really impossible to give you much more advice without having some
sample data or what you actu
On Fri, Nov 5, 2010 at 11:54 AM, Santosh Srinivas
wrote:
> Thanks Gabor for pointing in the right direction.
> Looked up cycle and the doc is tough to understand " cycle gives the
> positions in the cycle of each observation." ... how is cycle defined.
>
> I just extended your idea to make it read
HI, Phil,
I used the following codes and run it overnight for 15 hours, this morning,
I stopped it. It seems it is still not efficient.
>
matt<-read.table("/house/groupdirs/genetic_analysis/mjblow/ILLUMINA_ONLY_MICROBIAL_GENOME_ASSEMBLY/4083340/STANDARD_LIBRARY/GWZW.994.5.1129.trim_69.fastq.1962
Hi Daniel,
Thanks for your detail advice. I completely understand your explain.
But I can't resolve what does "a" stand for there?
a[1,1,1] is 1 * 1 * 1 = 1
a[2,1,1] is 2 * 1 * 1 = 2
a[2,4,2] is 2 * 4 * 2 = 16
a[3,4,2] is 3 * 4 * 2 = 24
?
B.R.
Stephen L
- Original Message
Fro
Hello,
I'm a new user of R. I've a very big table like the following structure
(suppose the variable name with "aa"). From this table I want to make a new
table which'll contain just two column with V2 and V6 with some particular
rows( Suppose, variable name with "bb"). I'd like to mention V2 colum
On 11/05/2010 09:13 AM, Changbin Du wrote:
> HI, Phil,
>
> I used the following codes and run it overnight for 15 hours, this morning,
> I stopped it. It seems it is still not efficient.
>
>
>>
> matt<-read.table("/house/groupdirs/genetic_analysis/mjblow/ILLUMINA_ONLY_MICROBIAL_GENOME_ASSEMBLY/4
On 11/05/2010 09:42 AM, Martin Morgan wrote:
> ## first time only
> source("http://bioconductor.org";)
oops, source("http://bioconductor.org/biocLite.R";)
> biocLite("IRanges")
>
> ##
> library(IRanges)
> contigs = IRanges(start=1, width=matt$reads)
> cvg = coverage(contigs) ## an RLE summarizi
On Fri, Nov 5, 2010 at 9:17 AM, Stephen Liu wrote:
> Hi Daniel,
>
> Thanks for your detail advice. I completely understand your explain.
>
> But I can't resolve what does "a" stand for there?
the "a" just represents some vector. It is the name of the object
that stores your data. Like you migh
Continuing with Daniel's example, but with different data values
a <- sample(24)
a
dim(a) <- c(3,4,2)
a
as.vector(a)
## for an array with
## dim(a) == c(3,4,2)
## a[i,j,k] means select the element in position
##i + (j-1)*3 + (k-1)*3*4
index <- function(i,j,k) {
i + (j-1)*3 + (k-1)*3*4
}
Thanks Martin! I will try it and will let your guys know how it goes.
On Fri, Nov 5, 2010 at 9:42 AM, Martin Morgan wrote:
> On 11/05/2010 09:13 AM, Changbin Du wrote:
> > HI, Phil,
> >
> > I used the following codes and run it overnight for 15 hours, this
> morning,
> > I stopped it. It seems
The following cover_per_3 uses sorting to solve
the problem more quickly. It still has room
for improvement.
cover_per_3 <- function (data)
{
n <- length(data)
o <- rev(order(data))
sdata <- data[o]
r <- rle(sdata)$lengths
output <- numeric(n)
output[o] <- rep(cumsum(r),
Hi Mauluda,
Next time, please read the posting guide- helping you is made alot easier if
you provide the code that didn't work.
It sounds like you might want something like this?
#make a data frame, with some column names assigned...
aa<-data.frame(c(rep("a",5), rep("c",3)),c(rep(7,5), rep(2,3))
Thanks, William. It gave me a lesson.
On Fri, Nov 5, 2010 at 9:58 AM, William Dunlap wrote:
> The following cover_per_3 uses sorting to solve
> the problem more quickly. It still has room
> for improvement.
>
> cover_per_3 <- function (data)
> {
>n <- length(data)
>o <- rev(order(data)
There was a numerical typo below, I said
the sample sizes were 5 and 10 thousand,
I should have said 10 and 20 thousand
(the size argument to sample()).
Also, I timed cover_per_2 and _3 for size
200,000 and gots times of 338 and 0.12 seconds,
respectively. Growing the problem by a factor
to 10 ma
Hi Jim an Petr,
Both of your solutions do what i want. Thanks for the help,
Regards, m
-Original Message-
From: Petr PIKAL [mailto:petr.pi...@precheza.cz]
Sent: Friday, November 05, 2010 6:49 AM
To: Matevž Pavlič
Cc: jim holtman; r-help@r-project.org
Subject: RE: [R] Loop
Hi
the lis
On 11/5/2010 12:09 AM, Prof Brian Ripley wrote:
On Thu, 4 Nov 2010, Noah Silverman wrote:
Hi,
I'm trying to figure out how to use capturing parenthesis in regular
expressions in R. (Doing this in Perl, Java, etc. is fairly trivial,
but I can't seem to find the functionality in R.)
For example
2010/11/5 Brian Diggs :
> Is there a standard, built in way to get both (all) backreferences at the
> same time with just one call to sub (or the appropriate function)? I can
> cobble something together specifically for 2 backreferences (not extensively
> tested):
>
> both_backrefs <- function(patt
Hello,
I spent quite some time now searching for any hint that R can also be
used to address the interfaces of a computer (i.e. RS232 or USB) to
acquire data from measurement devices (like with the - I think it is the
- devices or serial toolbox of Matlab).
Is there any package available or
On Fri, Nov 5, 2010 at 6:00 AM, wrote:
> Send R-help mailing list submissions to
> r-h...@r-project.org
>
> To subscribe or unsubscribe via the World Wide Web, visit
> https://stat.ethz.ch/mailman/listinfo/r-help
> or, via email, send a message with subject or body 'help' to
>
Hi guys,
I have the following problem : when plooting using the X11() device, the
output I get is different from the output I get when I use pdf().
For instance the title font size in a pdf seems to be proportionnaly bigger
that in a x11...
I tryed to set pdf.options() egal to x11.options(), but
Hi,
I have a question about %in% and subsettin data frames.
Say I need to keep ID 1,2,4,5, 10 from the data frame dat. I can do:
dat <- data.frame(ID = 1:10, var = 1:10)
someID <- c(1,2,4,5,10)
subset(dat, dat$ID %in% someID)
Is there a quick way to do the opposite, ie to do a subset that conta
I am new to Using R for data analysis. I have an incomplete time series
dataset that is in daily format. I want to extract only Friday data from it.
However, there are two problems with it.
First, if Friday data is missing in that week, I need to extract the data of
the day prior to that Friday
Well, %in% returns a logical vector...
So
subset(dat, ! ID %in% someID)
Also, from ?subset:
Note
that ‘subset’ will be evaluated in the data frame, so columns can
be referred to (by name) as variables in the expression
Thus, you don't need 'dat$ID', bur just 'ID' in the subset argum
Any logical value can be negatively compared using !
does:
subset(dat, !(dat$ID %in% someID))
provide what you need?
--
Jonathan P. Daily
Technician - USGS Leetown Science Center
11649 Leetown Road
Kearneysville WV, 25430
(304) 724-4480
"Is the room still a room
Hi MP,
Try
subset(dat, ! dat$ID %in% someID) # ! symbol
HTH,
Jorge
On Fri, Nov 5, 2010 at 10:13 AM, <> wrote:
> Hi,
>
> I have a question about %in% and subsettin data frames.
>
> Say I need to keep ID 1,2,4,5, 10 from the data frame dat. I can do:
>
> dat <- data.frame(ID = 1:10, var = 1:10)
> Say I need to keep ID 1,2,4,5, 10 from the data frame dat. I can do:
> dat <- data.frame(ID = 1:10, var = 1:10)
> someID <- c(1,2,4,5,10)
> subset(dat, dat$ID %in% someID)
> Is there a quick way to do the opposite ...
>
Two operators spring to mind: ! and %nin
subset(dat, !(dat$ID %in% so
Dear Jonathan,
It is not small, I passed the wrong information. I am running a geostatistic
analysis with geoR that is computational intense. At the end my analysis I call
the function krige.control and krige.conv. However, what call my attention is
that I have a friend that was able to run
Dear Jim,
Thanks for your attention. I am running a geostatistic analysis with geoR that
is computational intense. At the end my analysis I call the function
krige.control and krige.conv. Do you have any idea how to improve the memory
allocation in Linux?
Thanks,
Ricardo
De: jim holtman
A
Apologies if this is the wrong place to ask. I'm not aware of a
mail list devoted to database interfaces. Please direct me if
so.
I am trying to use TSMySQL. It loads RMySQL, and apparent the
CRAN version has an .onLoad script which seeks out the local
MySQL server. If that fails, the package f
library(RMySQL)
conn <- dbConnect(MySQL(), user = 'user', password = 'password', host = '
your_host.com')
Look at http://biostat.mc.vanderbilt.edu/RMySQL for more information
On Fri, Nov 5, 2010 at 5:04 PM, Jan Theodore Galkowski <
bayesianlo...@acm.org> wrote:
> Apologies if this is the wrong p
Yes, what happens when I do that is:
R version 2.11.1 (2010-05-31)
Copyright (C) 2010 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
[snip]
> Sys.getenv("MYSQL_USER")
MYSQL_USER
"mf1"
> # As an example. Other env vars are defined.
> library(RMySQL)
Loading required package: DBI
Erro
Hey,
This should work, but after you read in your data make sure that your day,
date and time are separate, this should work just fine, or something like
it.
> testdata
views number timestamp day date time
1 views 910401 1246192687 Sun 6/28/2009 12:38
2 views 921537 124627891
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf Of Jan Theodore Galkowski
> Sent: Friday, November 05, 2010 12:05 PM
> To: R Project
> Subject: [R] connecting to remote database using RMySQL
>
> Apologies if this is the wrong plac
R implements (almost) all IO through its 'connections'. Unfortunately,
there is no API (public or private) for adding connections, and
therefore no packages that implement connections. You will find more
discussion of connections and hardware (serial, USB) interface in the
R-devel list archives.
T
Hi all,
I have a dataframe (df1) that I am trying to select values from to a second
dataframe that at the current time is only for the selected items from df1
(df2). The values that I am trying to save from df1 are factors with
alphanumeric names
df1 looks like this:
'data.frame': 3014 obs. o
Could you give a small reproducible example please?
It is not clear to me what your looping structure is
doing, or what your goal here is.
There may be a much simpler method than introducing
subscripts.
--Erik
Wade Wall wrote:
Hi all,
I have a dataframe (df1) that I am trying to select values
Your example looks like you are assigning back to the first column of
df2 (Num). Is this what you are really doing in your code?
You need to follow the posting guide:
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, repr
Perhaps this will help:
> test1 <- test2 <- data.frame(col1=factor(c(1:3), labels=c("a", "b", "c")))
> test3 <- data.frame(col1 = 1:3)
Now:
> test2[2,1] <- test1$col1[1]
> test2$col1
[1] a a c
Levels: a b c
vs
> test3[2,1] <- test1$col1[1]
> test3$col1
[1] 1 1 3
Because test3's first column,
I would do some monitoring (debugging) of the script by placing some 'gc()'
calls in the sequence of statements leading to the problem to see what the
memory usage is at that point. Take a close look at the sizes of your
objects. If it is happening in some function you have called, you may have
t
Hi Wade,
Try (untested):
df2[j,1] <- as.character(f2$Site)[i]
If that does not work, which is very likely, could you please provide
commented, minimal, self-contained, reproducible code?
HTH,
Jorge
On Fri, Nov 5, 2010 at 3:54 PM, Wade Wall <> wrote:
> Hi all,
>
> I have a dataframe (df1) tha
Hello,
I have problems with 'lars' package. I found the previous post of the person
who had the same issue, but the suggested solution in that post did not help
me.
I created the matrices:
ResponseMatrix <- data.frame (GAOdecision=GAOdecision)
PredictorsMatrix <- data.frame (WeaponvsNon = Weapon
Hi everyone,
I wonder if there is a package or functions to visualize data structures in R?
For example I have a list with a lot of data frames - is there a function which
plots the elements of the list?
Thanks!
Best,
Friedericksen
__
R-help@r-proje
Thank you very much. It worked great with the testdata. I have one more
questionto to ask. As my data is incomplete, sometimes Thu is also missing,
then I have no other options but to pick Sat instead, and if Sat is also
missing, then my best possible option is to pick Wed, and etc. Bascially I
ha
There is the TkListView function in the TeachingDemos package for looking at
list structures. It gives you a view of the list structure with nested
elements available to be expanded by clicking on the little plus sign. You can
view or run code on the selected piece, which could help create som
Hi,
On Fri, Nov 5, 2010 at 4:14 PM, Vladimir Subbotin
wrote:
> Hello,
>
> I have problems with 'lars' package. I found the previous post of the person
> who had the same issue, but the suggested solution in that post did not help
> me.
>
> I created the matrices:
>
> ResponseMatrix <- data.frame
Hi all,
Thanks for the help. Jeffrey was right; my initial dataframe did not have
the columns defined for factors. I solved it using Jorge's example of using
as.character.
Sorry for not being more clear before.
Wade
On Fri, Nov 5, 2010 at 4:12 PM, Jeffrey Spies wrote:
> Perhaps this will he
Hello,
I have fitted a Poisson Process model in spatstat using
>fit1<-ppm(points, ~elevation, covariates=list(elevation=elevation.im))
This far, everything went well, but I try to simulate the fitted model using
the function:
>sim1<-rmh(fit1)
But I get the error message:
"Extracting model infor
On Fri, Nov 5, 2010 at 1:22 PM, thornbird wrote:
>
> I am new to Using R for data analysis. I have an incomplete time series
> dataset that is in daily format. I want to extract only Friday data from it.
> However, there are two problems with it.
>
> First, if Friday data is missing in that week,
Dear Rhelp,
Â
I did a daisy on 5 lifestyle variables, 3 of which were nominal and 2 were
ordinal and assigned types ânominalâ and âordinalâ for the variables,
respectively. I got an output indicating their types as âIâ for
interval(?). Doing it on the Rdata example âflowerâ ga
Hi,
I have a problem with the appearance of legend in my plots. If I specify the
legend positions in characters like "topright"..etc, it appears, if i specify
it in terms of coordinates like "-1, 1" .. etc, it does not appear. Can anyone
help me with this?
script -
x.date <- as.Date(past
On Fri, Nov 5, 2010 at 8:24 PM, Gabor Grothendieck
wrote:
> On Fri, Nov 5, 2010 at 1:22 PM, thornbird wrote:
>>
>> I am new to Using R for data analysis. I have an incomplete time series
>> dataset that is in daily format. I want to extract only Friday data from it.
>> However, there are two prob
On Nov 5, 2010, at 6:59 PM, govin...@msu.edu wrote:
Hi,
I have a problem with the appearance of legend in my plots. If I
specify the legend positions in characters like "topright"..etc, it
appears, if i specify it in terms of coordinates like "-1, 1" ..
etc, it does not appear.
Is -
I have a data structure that is fast to dput(), but very slow to dget(). On
disk, the file is about 35MB.
> system.time(dget("r.txt"))
user system elapsed
142.931.27 192.84
The same data structure is fast to save() and fast to load(). The .RData file on
disk is about 12MB.
> system.t
Glad you figured it out, but just be aware that if you set one value
of the column to be a character, it will make the whole vector
characters. This could cause issues for analysis if you need numerics
or factors. If the column is supposed to be a factor to begin with,
set it to be so; if you hav
Dear All
--
Jumlong Vongprasert Assist, Prof.
Institute of Research and Development
Ubon Ratchathani Rajabhat University
Ubon Ratchathani
THAILAND
34000
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Dear All
I have 2 value assume 2.4 and 2.9 and mean = 2 variance = with n = 10
I want to find probability = 2.4 and 2.9.
How I can do this.
Many Thanks.
Jumlong
--
Jumlong Vongprasert Assist, Prof.
Institute of Research and Development
Ubon Ratchathani Rajabhat University
Ubon Ratchathani
THAILAN
Dear Jumlong,
Perhaps look at ?pnorm
I am not really certain what you want to do. Are 2.4 and 2.9 scores
or means? Is the variance 2? What distribution are you assuming
these values come from? If you explain a bit more what you are after,
we can help more.
Cheers,
Josh
On Fri, Nov 5, 2010
Hi Jumlong,
Is this what you want?
> pnorm(q = c(2.4, 2.9), mean = 2, sd = 1)
[1] 0.6554217 0.8159399
HTH,
Josh
On Fri, Nov 5, 2010 at 9:57 PM, Jumlong Vongprasert
wrote:
> Dear Joshua Wiley
> 2.4 and 2.9 are score, and mean = 2 variance = 1 n = 10 with normal
> distribution.
> Many Thanks.
dput/dget were not intended to save/restore large objects. Understand
what is happening in the use of dput/dget. dput is creating a text
file that can reconstitute the object with dget. dget is having to
read the file in and then parse it:
> dget
function (file)
eval(parse(file = file))
This
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