On Aug 26, 2010, at 1:35 PM, Marlin Keith Cox wrote:
I need the parameters estimated for a non-linear equation, an
example of the
data is below.
# rm(list=ls())I really wish people would add comments to
destructive pieces of code.
Time<-c( 0, 0, 0, 0, 0, 2, 2, 2, 2, 2, 3, 3, 3, 3,
Please correct the following
> sqldf("update esc left join forwagg on esc.ym=forwagg.Date set
> esc.ri2=forwagg.N1 where esc.age=12","select * from main.esc")
Error in sqliteExecStatement(con, statement, bind.data) :
RS-DBI driver: (error in statement: near "left": syntax error)
Thanks.
Step
Thanks, David.
I did try to use predict() to obtain the graph, but it somehow looks
different from the one generated by "plot" command. So, I was
wondering if there is any way that I can get the one generated by
"plot" so that I can compare. Thank you.
Le
On Wed, Aug 25, 2010 at 11:15 PM, David
On Aug 26, 2010, at 2:35 PM, Le Wang wrote:
Thanks, David.
I did try to use predict() to obtain the graph,
"Try"? How? Code?
( predict() is used to obtain numbers, not to do graphing. )
but it somehow looks
different from the one generated by "plot" command.
I have no idea what you actu
Hello all-
Just wondering if anyone has heard of a package performing latent factor
analysis, similar to what is done with LatentGold. I know that PoLCA does
latent class analysis, but I don't think it can accomodate latent factor
models.
Thanks,
David Joubert
Dept Criminology
University of
I have a dataset of multiple variables and a response. For example,
> str(x)
'data.frame': 3557238 obs. of 44 variables:
$ response : Factor w/ 2 levels
$ var2: Factor w/5000 levels
If var2 for example is a factor with 5000 levels, what is the best
approach to determine which of these level
No need to do that. They have some instances that run 64-bit ubuntu.
If I remember correctly we had to install 64-bit R from the debian
packages on the ubuntu instance.
On Wed, Aug 25, 2010 at 6:12 PM, noclue_ wrote:
>
>
>>> You have a 64 bit Linux? If so...
>
>>>Dowload the sources
>
> Do you m
Exact, "efficiency", I didn't see that. Thank you very much.
2010/8/26 Gavin Simpson :
> On Thu, 2010-08-26 at 10:42 +0200, David Hajage wrote:
>> Hello useRs and guRus,
>>
>> I was trying to add the support of str() in the ascii package, and I
>> realized that str() does not have a print method.
On Aug 26, 2010, at 1:48 PM, David Winsemius wrote:
On Aug 26, 2010, at 1:35 PM, Marlin Keith Cox wrote:
I need the parameters estimated for a non-linear equation, an
example of the
data is below.
# rm(list=ls())I really wish people would add comments to
destructive pieces of code.
On Thu, Aug 26, 2010 at 2:31 PM, Bond, Stephen wrote:
> Please correct the following
>
>> sqldf("update esc left join forwagg on esc.ym=forwagg.Date set
>> esc.ri2=forwagg.N1 where esc.age=12","select * from main.esc")
> Error in sqliteExecStatement(con, statement, bind.data) :
> RS-DBI driver:
I created a small example to show something that I do a lot of. "scale"
data by month and return a data.frame with the output. "id" represents
repeated observations over "time" and I want to scale the "slope"
variable. The "out" variable shows the output I want. My for..loop
does the job but is
Thx... The following seems to work. However I´m sure there is a more elegant
solution to it
tre<-dat
b<-length(dat)
attr(dat,"label.table")->a
for (i in 1:b){
if(!is.null(a[[i]]) &
length(levels(as.factor(dat[,i])))==length(a[[i]]))
{
tre[,i]<-factor(dat[,i
On Aug 26, 2010, at 3:33 PM, Bos, Roger wrote:
> I created a small example to show something that I do a lot of. "scale"
> data by month and return a data.frame with the output. "id" represents
> repeated observations over "time" and I want to scale the "slope"
> variable. The "out" variable sh
It looks like you have found a bug, I can confirm that with your data on my
computer that I am getting nonsense results for some cases. I even found that
when calling the function on element 164 of the input vector that I don't even
get consistent results, I ran it several times and many times
On Aug 26, 2010, at 3:40 PM, Marc Schwartz wrote:
> On Aug 26, 2010, at 3:33 PM, Bos, Roger wrote:
>
>> I created a small example to show something that I do a lot of. "scale"
>> data by month and return a data.frame with the output. "id" represents
>> repeated observations over "time" and I wa
On Thu, Aug 26, 2010 at 4:33 PM, Bos, Roger wrote:
> I created a small example to show something that I do a lot of. "scale"
> data by month and return a data.frame with the output. "id" represents
> repeated observations over "time" and I want to scale the "slope"
> variable. The "out" variabl
A ddply solution is
dat.out <- ddply(dat, .(time), transform, slope = scale(slope))
but this is not faster than the loop, and slower than the ave() solution:
> system.time(
+ for (i in 1:3) {
+mat <- dat[dat$time==i, ]
+outi <- data.frame(mat$time, mat$id, slope=scale(mat$slope))
+if
I installed MySQL 5.0.67 and R. I installed RMySQL and added env variable
MYSQL_HOME. But R still does not want to load the library. It says
Error : .onLoad failed in loadNamespace() for 'RMySQL', details:
call: NULL
error: MYSQL_HOME was set but does not point to a directory
Error: package/n
On 26/08/10 18.42, Martin Morgan wrote:
On 8/26/2010 8:43 AM, Niels Richard Hansen wrote:
setGeneric("myplus",function(x,y,...) standardGeneric("myplus"))
setMethod("myplus",c(x="numeric",y="numeric"),
function(x,y,z=0) x+y+z
)
setMethod("myplus",c(x="numeric",y="list"),
function(x,y,...) call
Dear Anderson,
please see
http://lists.nongnu.org/archive/html/igraph-help/2007-07/msg00010.html
for the solution of the 'postscript font not included' problem.
Best,
Gabor
On Wed, Aug 25, 2010 at 11:50 PM, anderson nuel wrote:
> Dear r-help,
>
> I took your advice into consideration and i trie
The background you requested are energetic level (joules) in a group of
starved fish over a time period of 45 days. Weekly, fish (n=5) were removed
killed and measured for energy. This was done at three temperatures. I am
comparing the rates at which the fish consume stored body energy at each o
OK, I think that I figured out what is going on. You have some of your x
values that are very close to each other in value, but not exactly the same.
If we look at how many unique x values you have we get:
> length(unique(approx.data$x))
[1] 901
But inside the approxfun function the tapply fu
My opinions only below; consume at your own risk.
On Thu, Aug 26, 2010 at 2:20 PM, Marlin Keith Cox wrote:
> The background you requested are energetic level (joules) in a group of
> starved fish over a time period of 45 days. Weekly, fish (n=5) were removed
> killed and measured for energy. Th
Thank you. Could you lastly help me with this error. I was trying to use a
self starting function (Weibull).
model<-nls(Level~ SSweibull(Time,Asym,Drop,lrc,pwr))
Error in qr.default(.swts * attr(rhs, "gradient")) :
NA/NaN/Inf in foreign function call (arg 1)
On Thu, Aug 26, 2010 at 1:42 PM, D
I have a dataset I need to sort:
test.df<-data.frame(Zone=c("Floodplain", "Lake",
"Shoreline"),Cover=c(50,60,70))
However, I don't want it sorted ascending/descending but in an order that I
define via a vector:
sort.v<-data.frame(c("Lake","Shoreline","Floodplain"))
I realize I could probabl
Hi Chipper,
Try
test.df[unlist(sort.v),]
HTH,
Jorge
On Thu, Aug 26, 2010 at 5:59 PM, chipmaney <> wrote:
>
> I have a dataset I need to sort:
>
> test.df<-data.frame(Zone=c("Floodplain", "Lake",
> "Shoreline"),Cover=c(50,60,70))
>
> However, I don't want it sorted ascending/descending but in
Here's one possibility:
sort.v<-c(Lake=1,Shoreline=2,Floodplain=3)
test.df[order(sort.v[as.character(test.df$Zone)]),]
Zone Cover
2 Lake60
3 Shoreline70
1 Floodplain50
- Phil Spector
Sta
Hi Christian!
Sorry for being late.
David Winsemius wrote:
On Aug 18, 2010, at 2:58 PM, christiaan pauw wrote:
Hi Ricardo and everybody
In this old post to rhelp you say that the problem was solved but not
what
the sollution was. I have the same problem now. I want to read a Excel
file
fr
On Aug 26, 2010, at 6:10 PM, Jorge Ivan Velez wrote:
Hi Chipper,
Try
test.df[unlist(sort.v),]
That does work, and I suspect it is because data.frame converts
character vectors to factors by default. So this also works:
test.df[factor(c("Lake","Shoreline","Floodplain")), ]
But why? I mu
On Aug 26, 2010, at 5:20 PM, Marlin Keith Cox wrote:
> The background you requested are energetic level (joules) in a group
> of starved fish over a time period of 45 days. Weekly, fish (n=5)
> were removed killed and measured for energy. This was done at three
> temperatures. I am compa
I agree. I typically do not use non-linear functions, so am seeing the
"art" in describing functions of non-linear plots. One last thing. I tried
to use a self-starting Weibull function with the posted data and received
the following error.
model<-nls(Level~ SSweibull(Time,Asym,Drop,lrc,pwr))
E
A factor with 5000 levels looks like it may be a numeric variable that was
accidently coded as a factor (functions like read.table will do this if there
is a non numeric character in with the numbers).
If you really have a 5000 level factor, which levels can be discarded or
combined is a questi
Hi all
I was playing with termplot(), and came across what appears to be an
inconsistency.
It would appreciate if someone could enlighten me:
> # First, generate some data:
> y <- rnorm(100)
> x <- runif(length(y),1,2)
> # Now find the log of x:
> logx <- log(x)
>
> # Now fit two models that a
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of chipmaney
> Sent: Thursday, August 26, 2010 3:00 PM
> To: r-help@r-project.org
> Subject: [R] Non-standard sorts on vectors
>
>
> I have a dataset I need to sort:
>
> test.df
There is a graphical parameter that controls whether a plot is square or takes
up the maximum amount of room (rectangle), see ?par and look at the entry for
pty.
It is possible that you set pty='s' or it may be that the plot method sets it,
without us knowing what type of object Date and Test0
Hi,
I am writing a function that requires a specific package to be installed.
Is there a way of checking if the package is installed and returning a TRUE
/ FALSE result so my function can return an appropriate error message and
exit the function gracefully rather than just bombing out?
I'm thi
Hi pdb,
Take a look at
http://r.789695.n4.nabble.com/test-if-a-package-is-installed-td1750671.html#a1750674
HTH,
Jorge
On Thu, Aug 26, 2010 at 9:07 PM, pdb <> wrote:
>
> Hi,
>
> I am writing a function that requires a specific package to be installed.
>
> Is there a way of checking if the pac
On Aug 26, 2010, at 9:07 PM, pdb wrote:
Hi,
I am writing a function that requires a specific package to be
installed.
Is there a way of checking if the package is installed and returning
a TRUE
/ FALSE result so my function can return an appropriate error
message and
exit the functio
Dear list members,
I'm trying to use JAGS 2.1.0 from within R but every time I try to load the
rjags package I receive the following message:
Loading required package: coda
Loading required package: lattice
Error : .onLoad failed in loadNamespace() for 'rjags', details:
call: dyn.load(file, DL
Hi Greg,
Thanks for your advice.
I'm not prepared altering the shape of the graphs to be plotted. What I'm
trying to do is to pop up a rectangle layout window with following command.
The command;
layout(matrix(1:2, nrow=1))
pop up a square window. What I need is a rectangular window for the
Ruben Garcia Berasategui binus.ac.id> writes:
>
> Dear list members,
> I'm trying to use JAGS 2.1.0 from within R ...
Just a guess: are you using an up-to-date version of R?
I think you might be picking up an older version of rjags
which in turn is looking for an older version of JAGS ...
Ben Bolker gmail.com> writes:
>
> Ruben Garcia Berasategui binus.ac.id> writes:
>
> >
> > Dear list members,
> > I'm trying to use JAGS 2.1.0 from within R ...
>
Sorry, didn't see the subject line ("R 2.11.0") but still
worth posting sessionInfo()
___
When you run any graphics command (layout in this case) and there is not a
current graphics device (more technically only the null device) then a default
graphics device is opened, that is what you are seeing. What you need to do
instead is open the device yourself before calling layout. Which
Hi Greg,
Test01 was created with;
> Test01=read.table(file=file.choose(), header=TRUE)
the file selected was a .txt file.
DayMonthMo.NumberDay_of_yearDraft_No.
1Jan11305
2Jan12159
3Jan13251
4Jan14215
..
1Fe
On 26/08/10 19:48, David Winsemius wrote:
On Aug 26, 2010, at 1:35 PM, Marlin Keith Cox wrote:
I need the parameters estimated for a non-linear equation, an example
of the
data is below.
# rm(list=ls()) I really wish people would add comments to destructive
pieces of code.
Time<-c( 0, 0,
On Fri, 27 Aug 2010, Ruben Garcia Berasategui wrote:
Dear list members,
I'm trying to use JAGS 2.1.0 from within R but every time I try to
load the rjags package I receive the following message:
Which version of 'the rjags package' and where did you get it from?
I have 2.1.0-6, installed as
require() does what you want. Run "?require" for details.
require() returns 'FALSE' and gives a warning (rather than an error as
'library()' does by default) if the package does not exist.
'require' returns (invisibly) a logical indicating whether the required
package is available. (You can c
On Thu, 26 Aug 2010, Jorge Ivan Velez wrote:
Hi pdb,
Take a look at
http://r.789695.n4.nabble.com/test-if-a-package-is-installed-td1750671.html#a1750674
You are citing yourself with a poor solution (calling
installed.packages()) -- so please don't.
The help page for installed.packages in R
I am not sure whether you are working under windows. Hope the following
message helps.
Using the RMySQL package under Windows
http://www.stat.berkeley.edu/users/spector/s133/RMySQL_windows.html
On 2010-8-27 5:03, quant wrote:
I installed MySQL 5.0.67 and R. I installed RMySQL and added env var
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