Hello,
unfortunately I haven't gotten an answer up to now. You can see my
question/problem below in the first mail.
Is the given extract too unspecific?
I haven't solved the problem but I think that it's in the
handler.Berechnung function. Maybe I'm using wrong data-types (there are
vectors define
On Sun, Aug 8, 2010 at 2:01 AM, steven mosher wrote:
> In the real data the months are all complete, but the years can be missing.
> So years can be missing up front, in the middle, at the end. but if a year
> is present than every month has a value or NA.
> To create regular R ts I had to plow th
Dear Wolfgang,
Is there any way for rma to add random effects only to each treatment arm,
but not to the control one?
Many thanks,
Angelo
On Thu, August 5, 2010 6:21 pm, Viechtbauer Wolfgang (STAT) wrote:
> Dear Angelo,
>
> rma(yi=o, sei=se, mods=~s+t-1, method="REML")
>
> is *a* way to run the
Dear Ben,
thanks a lot! This did the trick (after adding "install" behind apt-get).
Regards,
Christian
On Fri, 6 Aug 2010, Ben Bolker wrote:
Christian Hennig stats.ucl.ac.uk> writes:
LaTeX errors when creating PDF version.
This typically indicates Rd problems.
LaTeX errors found:
! Font T1
Hello Andy,
Thank you for your quick and helpful reply. I will try to follow your
suggestions.
Also, thank you for the R implementation of random forest. It is very
useful for our work.
Best,
Pierre
Liaw, Andy wrote:
From: Pierre Dubath
Hello,
I am using the R randomForest package to c
QUESTION:
Is there a way of passing arguments from an external file to a script so
that they can be used directly by functions within the script?
I have a series of interdependent functions. I wish to test the time for
processing various datasets.
I was initially doing something along the lines o
How can I get a substring based on the index into the string?
strM <- c("abcde", "cdefg")
ind <- c(1,3,5)
I want to use ind to index into the strings so the result is:
strMind <- c("ace", "ceg")
__
R-help@r-project.org mailing list
https://stat.ethz.c
> I am thinking about using 'predict' command to generate the prediction of z
> with the new data.frame but there should be a better way.
I'm puzzled. Why would you think that? This is the canonical way to do
predictions in R.
Bert Gunter
Genentech Nonclinical Statistics
How can I get a substring based on the index into the string?
strM <- c("abcde", "cdefg")
ind <- c(1,3,5)
I want to use ind to index into the strings so the result is:
strMind <- c("ace", "ceg")
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R-help@r-project.org mailing list
https://stat.ethz.c
On Aug 8, 2010, at 9:50 AM, david h shanabrook wrote:
> How can I get a substring based on the index into the string?
>
> strM <- c("abcde", "cdefg")
> ind <- c(1,3,5)
>
> I want to use ind to index into the strings so the result is:
>
> strMind <- c("ace", "ceg")
Here is one way:
> apply(s
Ok,
I'm a bit confused by what you mean by "regularly spaced"
After I do the do.call I do get a data structure with all the times present
and every time has a NA or a data value.
Steve
On Sun, Aug 8, 2010 at 2:46 AM, Gabor Grothendieck
wrote:
> On Sun, Aug 8, 2010 at 2:01 AM, steven mosher
>
Hi there,
After many attempts at trying different methods I have used the Tps package
to interpolate between a number of measurements of field data, in this case
thickness of a sedimentary deposit. My input values are Longitude, Latitude
and Thickness and I have produced a valid contour map base
On Sun, Aug 8, 2010 at 11:21 AM, steven mosher wrote:
> Ok,
> I'm a bit confused by what you mean by "regularly spaced"
> After I do the do.call I do get a data structure with all the times present
> and every time has a NA or a data value.
> Steve
>
regularly spaced means that every observation
On Sun, Aug 8, 2010 at 11:55 AM, Gabor Grothendieck
wrote:
> On Sun, Aug 8, 2010 at 11:21 AM, steven mosher wrote:
>> Ok,
>> I'm a bit confused by what you mean by "regularly spaced"
>> After I do the do.call I do get a data structure with all the times present
>> and every time has a NA or a da
There is a MethComp package from Bendix Carstensen that does not seem
to be on CRAN yet.
http://staff.pubhealth.ku.dk/~bxc/MethComp/
But it is on R-Forge:
https://r-forge.r-project.org/R/?group_id=364
--
David.
On Aug 7, 2010, at 4:50 PM, Christos Argyropoulos wrote:
I believe there was
I would like to bootstrap the difference between two mean costs (I have a
different number of observations in the two group costs under
consideration).
So, this is my script:
x <- datos$direct_costsUS
fun <- function(x){m=(mean(x[63:136])-mean(x[1:62]))
}
boot.x<- boot(x,
statis
Hi,
I am trying to create a treemap for a non-symmetric tree where some
branches have more sub-branches than others. I have tried tools in two
packages, but have encountered some problems that I hope more
experienced users on this list can help address.
The PORTFOLIO package offers MAP.MARKET, b
Hi,
I assume you used boot package. Try this:
library(boot)
x <- rnorm(136)
fun <- function(x,ind){
x <- x[ind]
m <- mean(x[63:136])-mean(x[1:62])
m
}
boot.x<- boot(x, fun, R = 5000, sim = "ordinary")
-
A R learner.
--
View this message in context:
http:/
Dear list,
I'm trying to Sweave with localized characters in graph titles and axis
labels through a pdf device. I set pdf encoding through pdf.options(encoding
= "CP1250"). When I run my script through the command line like so: R CMD
Sweave report.Rnw, the localized characters turn into two dots.
Hi All,
I am plotting vertical lines using xyplot in lattice and type="h".
It works well, but the problem is that the tops of the lines are convex and the
bottoms are concave.
Is there a way to flatten the tops and bottoms?
Here's my code:
Source<-matrix(1:30,10,3)
colnames(Source)<-c("x","y1",
Hello,
I am not sure about the p.adjust( , fdr). How do these adjusted p-values
get?
I have read papers of BH method. For independent case, we compare the
ordered p-values with the alfa*i/m, where m is the number of tests. But I
have checked that result based on the adjusted p-values is different
Hi
On 9/08/2010 7:49 a.m., George Chen wrote:
Hi All,
I am plotting vertical lines using xyplot in lattice and type="h".
It works well, but the problem is that the tops of the lines are convex and the
bottoms are concave.
Is there a way to flatten the tops and bottoms?
You want to control th
Dear friends,
I am having problem with installing some packages in R in Ubuntu like
"ISwR". Bellow is the outcome. Anybody can help me to solve this problem.
Thanks a lot and sorry if it is very simple question.
install.packages("ISwr")
Loading Tcl/Tk interface ... done
trying URL 'http://pro
On Sun, 8 Aug 2010 13:55:28 -0700 (PDT)
gagea wrote:
> ERROR: failed to lock directory
> ‘/home/ubuntu/R/i486-pc-linux-gnu-library/2.9’ for modifying
> Try removing ‘/home/ubuntu/R/i486-pc-linux-gnu-library/2.9/00LOCK’
>
Are you installing from user? Perhaps try from root.
Liviu
___
Thanks again,
They worked for me as well. I did a simpler example with fewer years just to
show that it worked...( shorted here for display)
f <- function(x) {
+dat <- x[-(1:2)]
+tim <- as.yearmon(outer(x$Year, seq(0, length = ncol(dat))/12,
"+"))
+zoo(c(as.matrix(dat)),
On Sun, Aug 8, 2010 at 5:54 PM, steven mosher wrote:
> z<-as.zooreg(as.ts(g))
>> z
> X12345 X34567 X56789
> 1989(1) NA 3 6
> 1989(2) NA 3 6
> 1989(3) NA 3 6
> 1989(4) NA 3 6
> 1989(5) NA 3 6
> 1989(6) NA
On Sun, 08-Aug-2010 at 12:49PM -0700, George Chen wrote:
|> Hi All,
|>
|> I am plotting vertical lines using xyplot in lattice and type="h".
|> It works well, but the problem is that the tops of the lines are
|> convex and the bottoms are concave. Is there a way to flatten the
|> tops and bottoms
CRAN (and crantastic) updates this week
New packages
* cumSeg (1.0)
Vito M.R. Muggeo
http://crantastic.org/packages/cumSeg
Estimation of number and location of change points in mean-shift
(piecewise constant) models. Particularly useful to model genomic
sequences of contin
Hi Qing.
I believe what you are referring to is:
p.adjust(..., "BH")
The "fdr" option uses the method of Benjamini, Hochberg, and Yekutieli.
(Not the original Benjamini, Hochberg article)
It might be the method described here:
http://www.math.tau.ac.il/~ybenja/MyPapers/benjamini_yekutieli_ANNSTAT2
It is a simple problem in that I simply want to convert the For loop to a more
efficient method. It simply loops through a large vector checking if the
numeric element is not equal to the index of that element. The following
example demonstrates a simplified example:
> rows <- 10
> collusionM
Try this:
Matrix(diag(duplicated(matchM)), sparse = TRUE)
On Sun, Aug 8, 2010 at 9:43 PM, david h shanabrook
wrote:
> It is a simple problem in that I simply want to convert the For loop to a
> more efficient method. It simply loops through a large vector checking if
> the numeric element is no
Hi folks,
I am new to the R software. I have been going through different materials to
know more about R.
I have the R software installed on my windows machine.I would like to know
the R source code for the following problems on iris flower data set.
I need to do the cluster analysis project wit
Hi all,
>From a list of strings, I desire to filter out the followings:
1. Digits at the beginning of the strings
2. Character "SPE" following the digits (if it exists)
3. Any characters followed by hyphen
The following produces the desired result, but would like to know whether
this can be done
Hi folks,
> x
[1] 1 2 3 4 5
> y
[1] 6 7 8 9 10
> plot(x,y, type = "1" )
Error in plot.xy(xy, type, ...) : invalid plot type '1'
I looked on man plot but unable to resolve. Please help. TIA
B.R.
Stephen L
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R-help@r-project.org mailing list
On 08/08/2010 08:36 PM, meetsiddu1 wrote:
Hi folks,
I am new to the R software. I have been going through different materials to
know more about R.
I have the R software installed on my windows machine.I would like to know
the R source code for the following problems on iris flower data set.
I
On 08/08/2010 08:47 PM, Stephen Liu wrote:
Hi folks,
x
[1] 1 2 3 4 5
y
[1] 6 7 8 9 10
plot(x,y, type = "1" )
Error in plot.xy(xy, type, ...) : invalid plot type '1'
I looked on man plot but unable to resolve. Please help. TIA
You never say what you expect type = "1" (that's the
gsub(pattern = "^[0-9]+ (SPE )*(\\w+) - .*$", "\\2", dat)
-
A R learner.
--
View this message in context:
http://r.789695.n4.nabble.com/Regular-Expression-tp2318086p2318101.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r
Hi Erik,
I followed following video;
Statistics with R (part 3: plot and history tutorial)
http://www.youtube.com/watch?v=NfH5peM1RtI&feature=related
It is type = "1".
A graph was generated there. But I got an error msg
B.R.
Stephen
- Original Message
From: Erik Iverson
To: St
How about
a <- which(row(matchM)!=matchM)
b <- matchM[a]
diag(collusionM[a,b]) <-1
Nikhil Kaza
Asst. Professor,
City and Regional Planning
University of North Carolina
nikhil.l...@gmail.com
On Aug 8, 2010, at 8:43 PM, david h shanabrook wrote:
It is a simple problem in that I simply want to
On 08/08/2010 09:14 PM, Stephen Liu wrote:
Hi Erik,
I followed following video;
Statistics with R (part 3: plot and history tutorial)
http://www.youtube.com/watch?v=NfH5peM1RtI&feature=related
It is type = "1".
A graph was generated there. But I got an error msg
No, it was type = "l" (the
Was going to suggest gsub("^[0-9]+ (SPE )?([^ -])( -.*)?", "\\3", s)
but I see Wu Gong beat me to the punch with a nicer one :)
On 9 August 2010 12:13, Wu Gong wrote:
>
> gsub(pattern = "^[0-9]+ (SPE )*(\\w+) - .*$", "\\2", dat)
>
__
R-help@r-project.o
And my \\3 should have been a \\2 anyway !
On 9 August 2010 12:23, Michael Bedward wrote:
> Was going to suggest gsub("^[0-9]+ (SPE )?([^ -])( -.*)?", "\\3", s)
> but I see Wu Gong beat me to the punch with a nicer one :)
>
> On 9 August 2010 12:13, Wu Gong wrote:
>>
>> gsub(pattern = "^[0-9]+ (
Hello all,
I need to imitate the 'q' function (qnorm, qweibull, etc) for Clark's 2Dt
distribution model. I'm not skilled enough in R to code it myself, so I
thought I could find the base code for one of the existing 'q' functions and
just modify it. However, I'm having trouble navigating throug
Hi Erik,
I got it. Thanks
On
R-Project
The R Manuals
http://www.r-project.org/
There are several manuals.
Whether I should follow:-
An Introduction to R
http://www.r-project.org/
B.R.
Stephen L
- Original Message
From: Erik Iverson
To: Stephen Liu
Cc: r-help@r-project.org
Dear R users,
I'm hoping to get a few suggestions about which books are good to follow along
and learn R.
I'm hoping to spend the summer going through a good R book as it is applied in
linear regression.
Thanks!
__
R-help@r-project.org mailing list
h
Using R, I would like to find out which Samples (S1, S2, S3, S4, S5) fulfill
the following criteria:contain minimally one value (x, y or z) bigger than
4. Any ideas? Thanks, Alex.
> data
Sample xy z
1S1 -0.35.32.5
2S20.40.2 -1.2
3S3
On 08/09/2010 01:16 AM, Alexander Eggel wrote:
Using R, I would like to find out which Samples (S1, S2, S3, S4, S5) fulfill
the following criteria:contain minimally one value (x, y or z) bigger than
4. Any ideas? Thanks, Alex.
data
Sample xy z
1S1 -0.35.3
On Aug 9, 2010, at 2:16 AM, Alexander Eggel wrote:
Using R, I would like to find out which Samples (S1, S2, S3, S4, S5)
fulfill
the following criteria:contain minimally one value (x, y or z)
bigger than
4. Any ideas? Thanks, Alex.
data
Sample xy z
1S1 -0.3
gagea wrote:
> Dear friends,
>
> I am having problem with installing some packages in R in Ubuntu like
> "ISwR". Bellow is the outcome. Anybody can help me to solve this problem.
> Thanks a lot and sorry if it is very simple question.
>
>
> install.packages("ISwr")
...ISwR..., I presume.
> Lo
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