On Wed, Apr 21, 2010 at 6:50 PM, Michael Hosack wrote:
>
>
> I provided a minimized version of my dataframe at the bottom of this message
> containing the results of David's code in variable ('wkoffset') and Jeff
> Hallman's code in ('WEEK'). Jeff's code produced the correct results (thank
> yo
There are at least two functions that
may be of interest to you in this regard:
'head' (there is also 'tail')
'page'
On 21/04/2010 23:01, Mingfeng Lin wrote:
Hello all:
Is there a way to set up R such that, when you have a very long output
from a command, it will pause when it has displayed on
A similar problem was mentioned before:
https://stat.ethz.ch/pipermail/r-sig-mixed-models/2008q3/001425.html
There appears to be a bug in the C code leading to memory corruption.
Best,
--
Wolfgang Viechtbauerhttp://www.wvbauer.com/
Department of Methodology and Statistic
Dear all,
Thank you very much for your replies and help. I will try to work with
your suggestions and come back to you if I need something more.
Kind regards,
Stella Pachidi
On Thu, Apr 22, 2010 at 5:30 AM, kMan wrote:
> You set records to NULL perhaps (delete, shift up). Perhaps your system is
?strptime
Read the documentation and you will find reference to "%OSn"
> x <- strptime('13:45:34.123', format="%H:%M:%OS")
> x
[1] "2010-04-22 13:45:34"
> format(x, format="%H:%M:%OS3")
[1] "13:45:34.123"
>
On Thu, Apr 22, 2010 at 2:58 AM, Carol Gao wrote:
> Hi,
>
> Does anyone know how to ta
I am working with time series and I have encountered a problem with R not
recognizing a series properly. I can do the tests and fitting, but when I
want to decompose the series I got a message:
d<-decompose(data)
Error in decompose(dane) : time series has no or less than 2 periods
Maybe I have ma
Dear all,
I have several character strings with a high number of different levels.
unique(x) gives me values in the range of 100-200.
This creates problems as I would like to use them as predictors in a coxph
model.
I therefore would like to convert each of these strings to a new string
(x_new).
I've rolled up R-2.11.0.tar.gz a short while ago. This is a development
release which contains a number of new features.
Also, a number of mostly minor bugs have been fixed. See the full list
of changes below.
NOTE: The build platform has been changed for this release. Please watch out
extra car
Carol Gao gmail.com> writes:
>
> Hi,
>
> Does anyone know how to take a time difference when the format of the time
> is as 13:22:23.586? I am trying to take the difference of time between stock
> transactions and need to keep the three decimal places for seconds. I have
> tried *diff(strptime(
Thanks for the suggestions Unfortunately contour won't in this case as it
expects the x,y values to be in an ascending sequence.
--
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Sent from the R help mailing list ar
Hello Peter,
Thank you, and the R core team, for the new release.
I see that in R 2.11.0 there is now support for rendering of raster (bitmap)
images through rasterImage().
I am wondering - can this be used to create a texture/fill-pattern for
hist()/barplot() ?
(A request made several times th
Hi,
Is an R package built under Unix (package.tar.gz) could be installed on other
platforms like windows or Mac? The compressed tar file (.tar.gz) built under
Unix doesn't seem to be uncompressed under windows (unzip under windows instead
of gunzip). How to proceed?
Look forward to your reply,
Hi,
I try to create a data.frame from results of a tapply.
I have this results from tapply:
--
, , tapinom sp 1
1 2 3 4 5 6 7 8 9 10
1 NA NA NA NA NA NA NA NA NA NA
4 NA NA NA NA NA NA NA NA NA 4
5 NA NA NA NA NA NA NA NA NA NA
6 NA NA NA NA NA NA NA NA NA NA
On Apr 22, 2010, at 5:16 AM, Michael Haenlein wrote:
Dear all,
I have several character strings with a high number of different
levels.
unique(x) gives me values in the range of 100-200.
This creates problems as I would like to use them as predictors in a
coxph
model.
I therefore would
Try this:
as.vector(tapply(...))
On Thu, Apr 22, 2010 at 9:47 AM, Ronaldo Reis Junior wrote:
> Hi,
>
> I try to create a data.frame from results of a tapply.
>
> I have this results from tapply:
> --
> , , tapinom sp 1
>
>1 2 3 4 5 6 7 8 9 10
> 1 NA NA NA NA N
--- Begin included message
I have attempted to email the author of this package without success,
just wondering if anybody else has experienced this.
I am having an using rpart on 4000 rows of data with 13 attributes.
I can run the same test on 300 rows of the same data with no issue.
When I run
On Apr 22, 2010, at 8:09 AM, carol white wrote:
Hi,
Is an R package built under Unix (package.tar.gz) could be installed
on other platforms like windows or Mac? The compressed tar file
(.tar.gz) built under Unix doesn't seem to be uncompressed under
windows (unzip under windows instead of
On Apr 22, 2010, at 5:33 AM, Simon Goodman wrote:
Thanks for the suggestions Unfortunately contour won't in this
case as it
expects the x,y values to be in an ascending sequence.
?order
David Winsemius, MD
West Hartford, CT
__
R-help@r
I wonder if there is a more efficient way to do this task. Suppose I have two
data frames, such as
d1 <- data.frame(x = c(1,2,3), y = c(4,5,6), z = c(7,8,9))
d2 <- d1[, c('y', 'x')]
The first dataframe d1 has more variables than d2 and the variable columns are
in a different order.
So, what I
Jun,
I created a function called "pageNum" that does exactly what you want for
both 'base' and 'lattice' graphics. You can find it here:
http://ryouready.wordpress.com/2009/02/17/r-good-practice-adding-footnotes-to-graphics/
Kevin
On Wed, Apr 21, 2010 at 7:23 PM, Jun Shen wrote:
> David, Dun
Hi,
This idea was also discussed when Paul Murrell first announced the
grid.raster function to R-devel,
http://tolstoy.newcastle.edu.au/R/e8/devel/09/12/0912.html
My personal conclusion was that vector fill patterns are generally
better in terms of resolution and speed. Of course the situation mi
On Apr 22, 2010, at 9:41 AM, Doran, Harold wrote:
I wonder if there is a more efficient way to do this task. Suppose I
have two data frames, such as
d1 <- data.frame(x = c(1,2,3), y = c(4,5,6), z = c(7,8,9))
d2 <- d1[, c('y', 'x')]
The first dataframe d1 has more variables than d2 and the
On 22.04.2010 15:34, David Winsemius wrote:
On Apr 22, 2010, at 8:09 AM, carol white wrote:
Hi,
Is an R package built under Unix (package.tar.gz) could be installed
on other platforms like windows or Mac? The compressed tar file
(.tar.gz) built under Unix doesn't seem to be uncompressed unde
On 22/04/2010 8:09 AM, carol white wrote:
Hi,
Is an R package built under Unix (package.tar.gz) could be installed on other
platforms like windows or Mac? The compressed tar file (.tar.gz) built under
Unix doesn't seem to be uncompressed under windows (unzip under windows instead
of gunzip). H
Hi Kate,
the function does not directly return the calculated density values, however
those can be recomputed through the internal function .smoothScatterCalcDensity
This function is not exported from the grDevices name space, so you need to use
the full qualifier:
dat <- cbind(rnorm(100), rnorm
I am unfamiliar with how to use coin, but it looks like it should be doable -
the vignette in coin.pdf does a Page test. The wikipedia page for Page's
test explains how this is related to the Jonckheere-Terpstra test, which
seems to suggest if it can do one it should be able to do the other. Add t
Thanks a lot for the help, but it’s not what I needed.
--
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Sent from the R help mailing list archive at Nabble.com.
__
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https:/
...that this Danish movie would have an official release today:
http://www.imdb.com/title/tt1434443/
http://filmz.dk/film/r/trailers/24836
--
Peter Dalgaard
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Email: pd@cbs.dk
Hi!
I have v1, v2 and v3 (data in v. ranges 1 to 4)
v1
[1] 1 1 1 1 NaN 1 1 4 1 1 3
v2
[1] 1 1 1 1 1 1 1 1 1 1 1
v3
[1] 1 1 1 1 1 1 1 1 1 1 1
I want R to compare entries in v1,v2,v3 and in v4 to put largest value
(NA=0).
For
On 22/04/2010 11:07 AM, Vlatka Matkovic Puljic wrote:
Hi!
I have v1, v2 and v3 (data in v. ranges 1 to 4)
v1
[1] 1 1 1 1 NaN 1 1 4 1 1 3
v2
[1] 1 1 1 1 1 1 1 1 1 1 1
v3
[1] 1 1 1 1 1 1 1 1 1 1 1
I want R to compare entrie
Hi
I'm looking for a package to perform quality control, normalization and
analysis of high throughput cell-base chemical screens. I know that the
cellHTS2 package provides this for siRNA screens.
Does anybody know if something like what I'm looking for exists?
Thank you!
Gabriele Zoppoli,
Thanx a lot! That's it!
2010/4/22 Duncan Murdoch
> On 22/04/2010 11:07 AM, Vlatka Matkovic Puljic wrote:
>
>> Hi!
>>
>> I have v1, v2 and v3 (data in v. ranges 1 to 4)
>>
>> v1
>> [1] 1 1 1 1 NaN 1 1 4 1 1 3
>> v2
>> [1] 1 1 1 1 1 1 1 1 1 1 1
>> v3
>
On Thu, Apr 22, 2010 at 3:27 PM, peter dalgaard wrote:
> ...that this Danish movie would have an official release today:
>
> http://www.imdb.com/title/tt1434443/
Does it have music by this composer:
http://www.imdb.com/name/nm1731203/
and stills photography by:
http://www.imdb.com/name/nm208
Hi all,
I would like to get the array index for a range of values, say 0 < x <
1.5. I'm wondering if there is an alternative for the following which
I've done
x0 <- rnorm(100)
x1 <- ifelse(x0 > 0 & x0 < 1.5,"t","f")
x2 <- which(x1=="t",arr.ind=TRUE)
x0[x2]
Thanks.
--
Muhammad
___
Only thing that when I put na.rm=FALSE,
R is puting in v4 NA (as is largest)
and I want to see NA as zero (0, smallest value)
2010/4/22 Vlatka Matkovic Puljic
> Thanx a lot! That's it!
>
> 2010/4/22 Duncan Murdoch
>
> On 22/04/2010 11:07 AM, Vlatka Matkovic Puljic wrote:
>>
>>> Hi!
>>>
>>> I h
On 22-Apr-10 15:19:45, Barry Rowlingson wrote:
> On Thu, Apr 22, 2010 at 3:27 PM, peter dalgaard
> wrote:
>> ...that this Danish movie would have an official release today:
>>
>> http://www.imdb.com/title/tt1434443/
>
> Does it have music by this composer:
>
> http://www.imdb.com/name/nm1731203
Hi,
On Thu, Apr 22, 2010 at 11:21 AM, Muhammad Rahiz
wrote:
> Hi all,
>
> I would like to get the array index for a range of values, say 0 < x < 1.5.
> I'm wondering if there is an alternative for the following which I've done
>
> x0 <- rnorm(100)
> x1 <- ifelse(x0 > 0 & x0 < 1.5,"t","f")
> x2 <
On Apr 22, 2010, at 11:39 AM, Steve Lianoglou wrote:
Hi,
On Thu, Apr 22, 2010 at 11:21 AM, Muhammad Rahiz
wrote:
Hi all,
I would like to get the array index for a range of values, say 0 <
x < 1.5.
I'm wondering if there is an alternative for the following which
I've done
x0 <- rnorm(
On Apr 22, 2010, at 11:21 AM, Muhammad Rahiz wrote:
Hi all,
I would like to get the array index for a range of values, say 0 <
x < 1.5. I'm wondering if there is an alternative for the following
which I've done
x0 <- rnorm(100)
x1 <- ifelse(x0 > 0 & x0 < 1.5,"t","f")
x2 <- which(x1=="t"
I need to create 10 matrices. say matrix 1-10.
matrix_1 is 1 by 1
matrix_2 is 2 by 2
matrix_3 is 3 by 3
.
.
.
matrix_10 is 10 by 10
I am just wondering if there are some functions in R that are similar to the
macro variables in SAS. so I can create these 10 matrices by doing:
for (i in
Dear R-users, the problem I'm facing today is to write a
multicolor main title in a plot.
I would like to have 3/4 colors to help people in the
audience to visually realize what is what in a 4x2 plot array
On top of each plot I would like to have two lines.
The 1st line will indicate what is plo
Why don't use a list?
m <- list()
for(i in 1:10) {
m[[i]] <- matrix(NA, i, i)
}
then access them as m[[7]][1,6]
Ciao!
mario
On 22-Apr-10 18:08, karena wrote:
I need to create 10 matrices. say matrix 1-10.
matrix_1 is 1 by 1
matrix_2 is 2 by 2
matrix_3 is 3 by 3
.
.
maybe
for (i in 1:10) assign(paste("matrix", i, sep="_"), matrix(nrow=i, ncol=i))
suffices?
On Thu, Apr 22, 2010 at 5:08 PM, karena wrote:
>
> I need to create 10 matrices. say matrix 1-10.
>
> matrix_1 is 1 by 1
> matrix_2 is 2 by 2
> matrix_3 is 3 by 3
> .
> .
> .
> matrix_10 is 10 by 1
Hi,
On Thu, Apr 22, 2010 at 12:08 PM, karena wrote:
>
> I need to create 10 matrices. say matrix 1-10.
>
> matrix_1 is 1 by 1
> matrix_2 is 2 by 2
> matrix_3 is 3 by 3
> .
> .
> .
> matrix_10 is 10 by 10
>
> I am just wondering if there are some functions in R that are similar to the
> macr
You did not give a good description of your problem, or what you wanted as a
solution (what is a 'button'), or a reasonable idea of what you data is.
Here is one solution
x <- read.table(textConnection("Deafness, EYA4, DIAPH1, MYO7A, TECTA,
COL11A2, POU4F3, MYH9, ACTG1, MYO6"),
as.is=TRUE, se
I'd like to have an online horizon=k forecast with Arima, something like:
library(forecast)
air.model = Arima(AirPassengers[0:100], c(1,0,1),
seasonal=list(order=c(0,1,1), period=12))
for(i in 0:(length(AirPassengers)-100)) {
air.model2 = Arima(AirPassengers[0:(100+i)], model=air.model)
Hello everyone,
I'm trying to draw the non-linear regression curve to look at the
distance decay relationship between distance and correlation values. But
I'm not able to plot the curve as I'm struggling with the following
error ("parameters without starting value in 'data': x") and found no
On Apr 22, 2010, at 12:24 PM, Steve Lianoglou wrote:
Hi,
On Thu, Apr 22, 2010 at 12:08 PM, karena wrote:
I need to create 10 matrices. say matrix 1-10.
matrix_1 is 1 by 1
matrix_2 is 2 by 2
matrix_3 is 3 by 3
.
.
.
matrix_10 is 10 by 10
I am just wondering if there are some function
Hi Uwe,
I downloaded R 2.11.0 and the latest version of nlme. I am still getting the
problem. I should also note that I got a message from Viechtbauer Wolfgang
saying that he had experienced a similar problem using nlme.
I have pasted the code below. (The data is generated in the first ~15
lines)
Hi
how can I find, in a vector of characters, which is the most frequent one?
Thanks
Gabriele Zoppoli, MD
Ph.D. Fellow, Experimental and Clinical Oncology and Hematology, University of
Genova, Genova, Italy
Guest Researcher, LMP, NCI, NIH, Bethesda MD
Work: 301-451-8575
Mobile: 301-204-5642
Em
On 2010-04-22 11:09, Muhammad Rahiz wrote:
Hello everyone,
I'm trying to draw the non-linear regression curve to look at the
distance decay relationship between distance and correlation values. But
I'm not able to plot the curve as I'm struggling with the following
error ("parameters without sta
On Apr 22, 2010, at 10:34 AM, Ted Harding wrote:
> On 22-Apr-10 15:19:45, Barry Rowlingson wrote:
>> On Thu, Apr 22, 2010 at 3:27 PM, peter dalgaard
>> wrote:
>>> ...that this Danish movie would have an official release today:
>>>
>>> http://www.imdb.com/title/tt1434443/
>>
>> Does it have musi
Hello,
What about
test <- c(rep(c("A","C","G","T"), 20),"C")
table(test)
I am not sure that is an apt representation of the data and problem
you are trying to solve. It also occurred to me that each character
may not be its own element in the vector. If that is so, you would
need to do somethi
Hi Gabriele,
This is one way but I'm sure that there is an optimal way of doing so...
x <- c("A","B","C","C","C","C","C","B","B")
name <- unique(x) # get unique characters
freq <- c()
for (a in 1:length(name)){
freq[a] <- sum(x==name[a])}# get frequency
out <- cbind(name,freq)
On Apr 22, 2010, at 1:36 PM, Zoppoli, Gabriele (NIH/NCI) [G] wrote:
Hi
how can I find, in a vector of characters, which is the most
frequent one?
> a <- sample(letters[1:10], 100, replace=TRUE)
> table(a)
a
a b c d e f g h i j
10 7 7 13 7 12 1 14 15 14
> max(table(a))
[1] 15
It now works. Thanks both.
Muhammad
Peter Ehlers wrote:
On 2010-04-22 11:09, Muhammad Rahiz wrote:
Hello everyone,
I'm trying to draw the non-linear regression curve to look at the
distance decay relationship between distance and correlation values. But
I'm not able to plot the curve a
Gabriele -
How about this:
> data<-c("A","A","A","B","B","C","D")
> data
[1] "A" "A" "A" "B" "B" "C" "D"
> table(data)
data
A B C D
3 2 1 1
Thanks,
Lee
". . . people who focus only on 'what is' will create more of 'what is.'
People who focus mostly on 'what could be' will begin to create 'wh
Mixing base/lattice graphics can be tricky, but is possible.
http://www.bioconductor.org/CRAN/web/packages/gridBase/vignettes/gridBase.pdf
Also, did you look at Chapter 13 of the lattice book?
http://lmdvr.r-forge.r-project.org/figures/figures.html
Kevin
On Wed, Apr 21, 2010 at 2:08 PM, David
Try this:
apply(replace(v <- rbind(v1, v2, v3), is.nan(v), 0), 2, max)
On Thu, Apr 22, 2010 at 12:24 PM, Vlatka Matkovic Puljic <
v.matkovic.pul...@gmail.com> wrote:
> Only thing that when I put na.rm=FALSE,
> R is puting in v4 NA (as is largest)
> and I want to see NA as zero (0, smallest val
Perhaps this helps?
http://blog.revolution-computing.com/2009/01/multicolor-text-in-r.html
Kevin
On Thu, Apr 22, 2010 at 11:18 AM, Ottorino-Luca Pantani <
ottorino-luca.pant...@unifi.it> wrote:
> Dear R-users, the problem I'm facing today is to write a
> multicolor main title in a plot.
>
> I w
Hi All,
I apologize if this is not the right forum for this question.
I know there used to be a package for R that connected to opentick's (open
source) stock market data. However, opentick closed up about a year ago.
Does anyone know of a similar package that connects to IQfeed's stock market
On Apr 22, 2010, at 2:24 PM, Kevin Wright wrote:
Mixing base/lattice graphics can be tricky, but is possible.
http://www.bioconductor.org/CRAN/web/packages/gridBase/vignettes/gridBase.pdf
That could be quite useful in the future. Thanks for that.
Also, did you look at Chapter 13 of the la
Hello Everyone,
My company purchased S-Plus before it was bought out by Tibco. My understanding
is that we own version 7.0 outright.
So far, I've been learning in R but thought I might also try working in S-Plus.
My understanding is that S-Plus has some useful extra features. Another
potent
Hi I'm trying to import a large csv file without quotes around each field.
This creates some problems when there are "#" characters in certain strings
as R understands its comment field and ignores the rest of the line.
Here's an example:
var1, var2, var3, var4
one, two, three, four
Use this
On Apr 22, 2010, at 2:05 PM, Jack T. wrote:
>
> Hi I'm trying to import a large csv file without quotes around each field.
> This creates some problems when there are "#" characters in certain strings
> as R understands its comment field and ignores the rest of the line.
>
> Here's an example:
On Apr 22, 2010, at 3:05 PM, Jack T. wrote:
Hi I'm trying to import a large csv file without quotes around each
field.
This creates some problems when there are "#" characters in certain
strings
as R understands its comment field and ignores the rest of the line.
Here's an example:
var1
Oh man, totally missed that one! Thanks so much for the reminder.
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Sent from the R help mailing list archive at Nabble.com.
___
Hi All,
I built a mixed model with subject-specific variance structure in SAS and it
works quite well. Now I intended to implement the same model in R using lme
with "weights" option. Following is the SAS code and the corresponding R code:
SAS:
proc mixed data=source;
class id trial group valen
Hi,
The permutation test for two samples in R is function perm.test(). I could
not figure out what is the statistics it estimate and how many permutation
it did in default?
Thanks,
[[alternative HTML version deleted]]
__
R-help@r-project.org m
Hi All!
I have a problem that I do not know it how it is necessary to query an index
belonging to a given value.
Somebody would help?
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listin
On Apr 22, 2010, at 3:45 PM, tamas barjak wrote:
Hi All!
I have a problem that I do not know it how it is necessary to query
an index
belonging to a given value.
I bit hard to tell without an example but suspect you want:
?which
--
David Winsemius, MD
West Hartford, CT
___
Hi
Sounds like the 'compare' package might do some of what you want.
Paul
On 23/04/2010 1:41 a.m., Doran, Harold wrote:
I wonder if there is a more efficient way to do this task. Suppose I
have two data frames, such as
d1<- data.frame(x = c(1,2,3), y = c(4,5,6), z = c(7,8,9))
d2<- d1[, c('y'
Hi
On 23/04/2010 12:10 a.m., Tal Galili wrote:
Hello Peter,
Thank you, and the R core team, for the new release.
I see that in R 2.11.0 there is now support for rendering of raster (bitmap)
images through rasterImage().
I am wondering - can this be used to create a texture/fill-pattern for
hi
Ah.
Close to what David suggested...
Try:
?which.max
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English
Paul
Just as in your implied analogy there are significant differences
beneath the surface between these programs despite superficial
similarities.
You will soon get frustrated trying to use both simultaneously as you
will not be sure that the critical step you've discovered in one will
wor
Thanks for those pointers making some progress now
The following will put the levelplot on to the map, but the not with the
co-ordinates aligned...
The level plot appears on a slightly larger scale compared to the underlying
map.
In both the map and levelplot, the coordinates are in lon, lat
Why does:
nm <- intersect(names(d1),names(d2))
identical(d1[,nm], d2[,nm])
not do it?
-- Bert
Bert Gunter
Nonclinical Biostatistics
467-7374
http://devo.gene.com/groups/devo/depts/ncb/home.shtml
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-proje
Greetings.
How can I insert gridlines
in the following density plot call?
Must one compose a panel function?
'data.frame': 46 obs. of 2 variables:
$ fallrates: num 5.2 7.1 7.1 9.8 3.7 7.5 5 6.2 1.5 2.9 ...
$ prepost : Factor w/ 2 levels "post","pre": 2 2 2 2 2 2 2 2 2 2 ...
library(latt
Dear R users,
I have been plotting several graphics in only one page. I intend to plot
only one legend in each page.
Since the graphics are inside a loop I have to do it automatically.
The main problem is that inside the loop I work with differente types of
variables, I mean , the range is differe
" Must one compose a panel function?"
Depending on what you want exactly, no. Add the argument
type="g"
to your call.
(e.g.
densityplot(~fallrates, groups = prepost,type="g",...
)
See ?panel.xyplot and recall that lattice passes down arguments that it
does not know what to do with to the p
Another solution (whether this is better/worse, prettier/uglier, etc./etc. is
in the eye of the beholder):
library(TeachingDemos)
x0 <- rnorm(100)
x0[ 0 %<% x0 %<% 1.5 ]
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.40
On Apr 22, 2010, at 4:52 PM, Bert Gunter wrote:
" Must one compose a panel function?"
Depending on what you want exactly, no. Add the argument
type="g"
to your call.
(e.g.
densityplot(~fallrates, groups = prepost,type="g",...
)
See ?panel.xyplot and recall that lattice passes down argum
Thank you Burt Gunter and David Winsemius,
I confirmed David's comment.
One must use type=c("p","g")
in order to get both the grid and points.
So, to use densityplot well,
we must be quite aware of the options
for panel.xyplot!
Cordially,
Giles Crane
You don't have to use map() to draw the map.
m <- map(..., plot = FALSE)
xyplot(y ~ x, m, type = "l", aspect = "iso",
par.settings = list(axis.line = list(col = "transparent")))
or inside a panel function, assuming appropriate scales:
panel.xyplot(m$x, m$y, ...)
On 23 April 2010 04:38, David
I'm using randomSurvivalForest to predict survival from a rather small
sample. As it's not enough data to have training and validation set, I
rely on the "Estimate of error rate" computed by the randomForest. If I
understand the method correctly, it repeatedly partitions the data into
varying t
I am sorry if this is documented in apply's dcumentation or completely
obvious, I could not find or work it out.
Given an matricies Q: 2x3, R:1x3 and S:1x2
apply(Q, 1, '-', R) is 3x2 and apply(Q, 2, '-', S) is 2x3
Why?
cheers
Worik
> Q
[,1] [,2] [,3]
[1,]123
[2,] 10 11 1
Or use this handy-dandy function:
smode<-function(x){
xtab<-table(x)
modes<-xtab[max(xtab)==xtab]
mag<-as.numeric(modes[1]) #in case mult. modes, this is safer
themodes<-names(modes)
mout<-list(themodes=themodes,modeval=mag)
return(mout)
}
On 2010-04-21 21:13, zhenjiang xu wrote:
R experts,
Is there anyway to reorder inside each group? In the following example, the
bar of year 1932 is always plotted before the bar of year 1931, may I change
the order inside each groups of bars?
Do you mean a different order in different panels?
Hi
I'm looking for a package to perform quality control, normalization and
analysis of high throughput cell-based chemical screens. I know that the
cellHTS2 package provides this for siRNA screens.
Does anybody know if something like what I'm looking for exists?
Thank you!
Gabriele Zoppoli,
You are plotting the entire lattice plot (including axes, margins etc)
in the grid viewport. What you want to do is to call the panel
function, panel.levelplot(), instead.
However, why not just
mm <- map('worldHires', plot = FALSE)
levelplot(z~x+y,xyz, mm = mm, panel = function(..., mm) {
pan
Dear all,
I have a couple of short noob questions for whoever can take them. I'm
from a very non-stats background so sorry for offending anybody with
stupid questions ! :-)
I have been using logistic regression care of glm to analyse a binary
dependent variable against a couple of independent var
Hi ,
This maybe a bug. I checked my another package, the same problem occurred.
See below for detailed information.
##check log##
* using log directory 'D:/StatSoft/R/MyPackage/sbar.Rcheck'
* using R version 2.10.1 (2009-12-14)
* using session charset: ISO8859-1
* checking for file 'sbar/DESCRIPT
Hi all,
I have a dataset similar to the following
NameDateValue
A 1/01/2000 4
A 2/01/2000 4
A 3/01/2000 5
A 4/01/2000 4
A 5/01/2000 1
B 6/01/2000 2
B 7/01/2000 1
B 8/01/2000 1
I would like R
Thank you very much Dieter and Don. This solves my problem. :)
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R-help@r-project.org mailing l
confusionMatrix in the caret package can be used to replace your
manual procedure.
You could try using RWeka, the R interface to the java Weka software.
Once you have it working you could then directly interface your java
program to Weka without involving R.
On Thu, Apr 22, 2010 at 9:29 PM, Claus
thank you! this really helps!
On Thu, Apr 22, 2010 at 7:00 PM, jim holtman wrote:
> ?strptime
>
> Read the documentation and you will find reference to "%OSn"
>
> > x <- strptime('13:45:34.123', format="%H:%M:%OS")
> > x
> [1] "2010-04-22 13:45:34"
> > format(x, format="%H:%M:%OS3")
> [1] "13:45
Dear R-list members,
I have just downloaded R version 2.11.0. Then I installed
package gdata. At the end of the installation, a warning message
said that package gtools could not be found. Package gdata
was, after the installation, included in the "Package Index"
in the help files. Messages duri
Claus O'Rourke wrote:
Dear all,
I have a couple of short noob questions for whoever can take them. I'm
from a very non-stats background so sorry for offending anybody with
stupid questions ! :-)
I have been using logistic regression care of glm to analyse a binary
dependent variable against a c
Hello everyone,
I'm trying to plot the initial and final size of some tadpoles and look at
their growth rates (slope of line). They are divided into 6 densities, and
so far I have plotted the initial and final sizes (these are means for a
pool), and color coded for the 6 densities, but I want a l
Dear fellow R-help members,
I hope to seek your advice on how to parse/manage a dataset with hundreds of
columns. Two examples of these columns, 'cancer.problems', and
'neuro.problems' are depicted below. Essentially, I need to parse this into
a useful dataset, and unfortunately, I am not familiar
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