Thank you very much!
Eleni
On Fri, Dec 11, 2009 at 7:19 PM, Steve Lianoglou <
mailinglist.honey...@gmail.com> wrote:
> Hi Eleni,
>
> On Dec 11, 2009, at 12:04 PM, Eleni Christodoulou wrote:
>
> > Dear R users,
> >
> > I am trying to apply SVM regression for a set of microarray data. I am
> usin
On Fri, 11 Dec 2009, Xiongqing Zhang wrote:
Hello all, I am Xiongqing Zhang, come from Beijing of China. I know you from
the web site: http://finzi.psych.upenn.edu/Rhelp08/2008-February/154627.html.
I am not very clear about the R-project software.
Look at
http://www.R-project.org/
especia
> Datum: Fri, 11 Dec 2009 21:52:30 -0500
>
> On Dec 11, 2009, at 11:08 AM, Tom Knockinger wrote:
>
> > Hi,
> > i am new to the R-project but until now i have found solutions for
> > every problem in toturials, R Wikis and this mailing list, but now i
> > have some problems which I can't solve
Dear list,
I have a file that is comma delimited but contains some erroneous
non-delimiter commas. I would like to replace these commas with
semicolons and then read the correct file into R as a data frame.
I want to do this from within R, without changing the original data
file.
My current idea
Dear R developers,
is that right?
> -27^(1/3)
[1] -3
> c(-27,27)^(1/3)
[1] NaN 3
i'm using sign( c(-27,27) ) * abs( c(-27,27)) ^(1/3) ,
thanks
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/m
On Dec 12, 2009, at 9:31 AM, Rodrigo Tsai wrote:
Dear R developers,
is that right?
-27^(1/3)
[1] -3
library(fortunes)
> fortune("^")
Thomas Lumley: The precedence of ^ is higher than that of unary minus.
It may be surprising, [...]
Hervé Pagès: No, it's not surprising. At least to me...
I am using SWord from statconn: http://rcom.univie.ac.at/download.html
It allows you to put r-commands into Word (similar to odfWeave). Output
is directed to Word including figures and tables. It is still a
beta-version but works fine.
Frank Bloos
>>> Wenjie Lee 12.12.2009 00:28 >>>
Hi R Exper
On Dec 12, 2009, at 7:54 AM, Marianne Promberger wrote:
Dear list,
I have a file that is comma delimited but contains some erroneous
non-delimiter commas. I would like to replace these commas with
semicolons and then read the correct file into R as a data frame.
I want to do this from within
On 12/12/09 11:02, David Winsemius wrote:
>
> On Dec 12, 2009, at 7:54 AM, Marianne Promberger wrote:
>
> > Dear list,
> >
> > I have a file that is comma delimited but contains some erroneous
> > non-delimiter commas. I would like to replace these commas with
> > semicolons and then read the cor
Thanks for both replies.
Let me start by giving a better minimal example, although indeed the
regex replacement is not my problem.
system("echo \"var1,var2,var3\none,two,three\none,this is a comment,with
commas.,three\" > file.csv")
> On 12/12/09 11:02, David Winsemius wrote:
> >
> > You ne
On Dec 12, 2009, at 12:01 PM, Marianne Promberger wrote:
Thanks for both replies.
Let me start by giving a better minimal example, although indeed the
regex replacement is not my problem.
system("echo \"var1,var2,var3\none,two,three\none,this is a
comment,with commas.,three\" > file.csv")
David Winsemius 12-Dec-09 17:12:
> > txt <- gsub("( [A-Za-z]+),","\\1;",readLines("file.csv"))
> > read.csv(textConnection(txt), header=TRUE)
>var1 var2 var3
> 1 onetwo three
> 2 one this is a comment;with commas. three
Wonderful, tha
Hi, ALL,
Is there any function in R that does the exact test for the matched pair
proportions (one sided), which I assume is binomial(b+c, .5).
Thanks,
Annie
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://st
*
I have a simple question regarding plots of time series in R.
I have to plot "conc" against "time" **for each individual and display in
the same panel for the in-built dataset "Indometh" in R.
*
***I have six time series, say subject1.ts, subject2.ts, .,
subject6.ts.
The observation
*Respected Sir,
I have a simple question regarding plots of time series in R.
I have to plot "conc" against "time" **for each individual and display in
the same panel for the in-built dataset "Indometh" in R.
*
*I have six time series, say subject1.ts, subject2.ts, .,
subject6.ts.
Th
Thanks for all the help, They all worked, But I'm stuck again.
I've tried searching, but I not sure how to word my search as nothing came
up.
Here is my new hurdle, my data has 7 abservations and my results have 2
answers:
Here is my data
LEAID ratio
3 6307 0.720
1 6307
*
I have a simple question regarding plots of time series in R.
I have to plot "conc" against "time" **for each individual and display in
the same panel for the in-built dataset "Indometh" in R.
*
*I have six time series, say subject1.ts, subject2.ts, .,
subject6.ts.
The observation
annie Zhang wrote:
Hi, ALL,
Is there any function in R that does the exact test for the matched pair
proportions (one sided), which I assume is binomial(b+c, .5).
binom.test should fit nicely, I think.
Thanks,
Annie
[[alternative HTML version deleted]]
Dear all,
here my problem my be somone can help to solve this.
I have tow timeseries from different stock market with different length
(diff ca. 4000 )
Now I would to add the missing times of the one of this series with proper
time (they are minute data) and set the value to 0 since I need to hav
Hi,
I had a question regarding the rpart command in R. I used seven continuous
predictor variables in the model and the variable called "TB122" was chosen
for the first split. But in looking at the output, there are 4 variables
that improve the predicted membership equally (TB122, TB139, TB144,
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of L.A.
> Sent: Saturday, December 12, 2009 12:39 PM
> To: r-help@r-project.org
> Subject: Re: [R] by function ??
>
>
>
> Thanks for all the help, They all worked, But I'm stuck a
RV> I would be very grateful if you could help me with:
RV> Given the regularized gamma function Reg=int_0^r
RV> (x^(k-1)e^(-x))dx/int_0^Inf (x^(k-1)e^(-x))dx ; 0 (which is eventually the ratio of the Incomplete gamma
RV> function by the gamma function),
and which is exactly what
saveObject() and loadObject() are using save() and load() in base.
The default is to compress the data when saving, which take some time.
Using saveObject(..., compress=FALSE) is probably faster, but takes
up more disk space. ...and make sure you don't work towards a file
system over a network,
On Dec 12, 2009, at 3:38 PM, L.A. wrote:
Thanks for all the help, They all worked, But I'm stuck again.
I've tried searching, but I not sure how to word my search as
nothing came
up.
Here is my new hurdle, my data has 7 abservations and my results
have 2
answers:
Here is my data
*Respected Sir,
I have a simple question regarding plots of time series in R.
I have to plot "conc" against "time" **for each individual and display in
the same panel for the in-built dataset "Indometh" in R.
*
***I have six time series, say subject1.ts, subject2.ts, .,
subject6.ts.
Dear R Users,
Do you know whether is there any way of calling STATA from within R
(possibly in a similar way that is possible to call WinBUGS from within R
using the function "Bugs")??
Thanks,
Manuel
--
View this message in context:
http://n4.nabble.com/Call-STATA-code-from-within-R-tp961885p9
How can I create the following without the 'for' loop?
start=c(1,10,20)
end=c(4,15,27)
out=c()
for (i in 1:length(start)) {
out=c(out,start[i]:end[i])
}
out
[1] 1 2 3 4 10 11 12 13 14 15 20 21 22 23 24 25 26 27
I know there must be an easier (and, hopefully, faster) way.
Hi Kevin,
Here is a suggestion using mapply():
start <- c(1,10,20)
end <- c(4,15,27)
do.call(c, mapply( seq, start, end))
See ?mapply and ?do.call for more information.
HTH,
Jorge
On Sat, Dec 12, 2009 at 2:27 PM, Kevin Ummel <> wrote:
> How can I create the following without the 'for' loop?
Also what about
c(seq(1,4,1),seq(10,15,1),seq(20,27,1))
Joe King
j...@joepking.com
"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
Hi Philip,
I must confess that I not understood what is the problem.
Could you clarify it a little bit more?
Cheers
miltinho
brazil=toronto
On Sat, Dec 12, 2009 at 12:39 AM, philip robinson wrote:
>
> I am trying to graphically represent a large set of data who's result is
> not
> strictly un
Hi,
Is it possible to assign to an array with different dimensions?
That is to say, supposing a three dimensional array,
the third dimension of the array has matrices of different sizes?
> array
, , 1
[1] [2] [3]
[1] 111
, , 2
[1] [2] [3]
[1] 111
[2] 11
Dear all,
I'm stuck in a seemingly trivial task that I need to perform for many
datasets. Basically, I want to replace NA with 0 in a specified range of
columns in a dataframe. I know the first and last column to be recoded
only by its name.
I can select the columns starting like this
a[match
hi Michael,
the following code should work
b <- a[match('first',names(a)): match('last',names(a))]
b[is.na(b)]<-0
a[match('first',names(a)): match('last',names(a))] <- b
cheers,
Patrizio
2009/12/13 Michael Scharkow :
> Dear all,
>
> I'm stuck in a seemingly trivial task that I need to perform f
Yes, thanks. It's exactly what I want.
Annie
On Sat, Dec 12, 2009 at 12:46 PM, Peter Dalgaard
wrote:
> annie Zhang wrote:
>
>> Hi, ALL,
>>
>> Is there any function in R that does the exact test for the matched pair
>> proportions (one sided), which I assume is binomial(b+c, .5).
>>
>
> binom.te
On Dec 12, 2009, at 5:36 PM, parkbomee wrote:
Hi,
Is it possible to assign to an array with different dimensions?
That is to say, supposing a three dimensional array,
the third dimension of the array has matrices of different sizes?
Use a list. Or populate with NA's
array
, , 1
[1
On Sat, 12 Dec 2009, Jorge Ivan Velez wrote:
Hi Kevin,
Here is a suggestion using mapply():
start <- c(1,10,20)
end <- c(4,15,27)
do.call(c, mapply( seq, start, end))
...which is what I would usually do.
But for heavy duty applications, the IRanges package and function may be
worth study
On Dec 12, 2009, at 6:15 PM, Patrizio Frederic wrote:
hi Michael,
the following code should work
b <- a[match('first',names(a)): match('last',names(a))]
b[is.na(b)]<-0
This might not throw an error:
b <- apply(a[match('first',names(a)): match('last',names(a))], 1:2,
fun
Farrel Buchinsky wrote:
> It Works! Thanks a lot! Its great.
Thanks for letting me know. Glad that fixed things for you.
>
> What were your "few minor, but important, changes" - in a nutshell. I will
> not understand unless you describe it as high level issues.
Basically, recognizing the type
Dear list,
I am trying to make a contingency table with xtabs but I am getting
a 0 where I expect a 'NA'. Here is a simple example:
options(stringsAsFactors = FALSE)
rn <- LETTERS[1:4]
df1 <- data.frame(r07 = rep(rn, each=4),
r08 = rep(rn, 4), value = 1:16)
xtabs(value ~ r07 +
Hi,
I am trying to fit a non-linear model for a parasite dataset. Initially, I
tried log-transforming the data and conducting a 2-way ANCOVA, and found
that the equal variance of populations and normality assumptions were
violated. Gaba et al. (2005) suggests that the Weibull Distribution is be
for an example,
counts <- c(18,17,15,20,10,20,25,13,12)
outcome <- gl(3,1,9); treatment <- gl(3,3)
glm.D93 <- glm(counts ~ outcome + treatment, family=poisson())
confint(glm.D93)
confint.default(glm.D93) # based on asymptotic normality
to verify the confidence interval (confint.default(glm.D93
Dear R family
When I run the command below, the error message came up. It seems like
the problem is about computer capacity.
It would be appreciated if anyone could give me a solution.
###
> N <- 415884
> tau <- diag(1, N)[c(N, 1:(N - 1)),]
Error in array(0, c(n, p)) : 'dim' specifies too
Hi all, i am still using the Hmisc package and I like the filled bands part,
is there a way though to have different groups have different color of
bands, maybe a lighter version of the color of the line that is used?
---
Joe King, M.A.
Ph.D. Student
I'm facing this problem on R GUI version 2.10.0 on Windows Vista. I have not
changed Windows settings or R GUI settings much except to change from MDI to
SDI.
Someone else reported this problem a few months ago:
https://stat.ethz.ch/pipermail/r-help/2009-April/195714.html
but it wasn't followed
Hi Viju,
Here is a suggestion:
R> options(width = 80)
R> 1:120
HTH,
Jorge
On Sat, Dec 12, 2009 at 10:34 PM, Viju Moses <> wrote:
> I'm facing this problem on R GUI version 2.10.0 on Windows Vista. I have
> not
> changed Windows settings or R GUI settings much except to change from MDI
> to
>
Is there an easy way to switch between R GUI and R terminal? I'm currently
using R GUI 2.10.0 on Windows Vista and would like to see something like the
R terminal found in Linux. But I may also want to switch back to GUI. I
don't remember seeing the terminal option at the R download site, or during
Dear Jorge, Thanks.
But.
(My R console width is set by default at 91, which is fine.
Output for R>1:120 wraps correctly already. )
The problem is that when I am typing a command, it does not wrap like it
does in this email while typing. As I am reach the right border, a
horizontal scroll
On Dec 12, 2009, at 8:31 PM, Moohwan Kim wrote:
Dear R family
When I run the command below, the error message came up. It seems like
the problem is about computer capacity.
It would be appreciated if anyone could give me a solution.
You would want to just store such an object but also to man
On Dec 12, 2009, at 8:19 PM, casperyc wrote:
for an example,
counts <- c(18,17,15,20,10,20,25,13,12)
outcome <- gl(3,1,9); treatment <- gl(3,3)
glm.D93 <- glm(counts ~ outcome + treatment, family=poisson())
confint(glm.D93)
confint.default(glm.D93) # based on asymptotic normality
to verify
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