I was probably too vague. I meant that the group variable descirbes
the group (eg. different individuals) and val1 and val2 are just two
variables measured from eg. individual.
> mydata
val1 val2 group
1 1.1 4.2 0
2 3.2 5.3 1
3 4.1 3.4 0
4 2.5 2.6 1
5 6.2 5.3
Hi
r-help-boun...@r-project.org napsal dne 01.12.2009 04:42:31:
> length(unique(c(1,2,2)))==length(c(1,2,2))
>
> I use the above test to test if all the elements in a vector are
> unique. But I'm wondering if there is a convenient function to do so
> in R library.
maybe
any(duplicated(c(1,2,2)
It seems that it is not possible to color points that way using
stripchart. I found a workaround which solved the problem:
stripchart(values ~ ind,
data=mydata.stack,
vertical=T,
at=c(1.25, 1.75),
pch=15,
col="white")
points(rep(1.25, nrow(mydata)), mydata$v
Hi,
I have created a web interface to enable analysis for users without having
much to worry about the stats in the backend. In this particular case I have
reached a stage where I have finally created two arrays between which I want
to do an independant samples T Test. I have the arrays ready in a
Hi there,
I'm pretty sure that it's written down somewhere but I cannot find it so
far.
The little example shows different approaches to replace a substring.
Only the last one works. I think it has something to do with the fact
that "substr" is used on the left side. Can anybody refer to an
Hi,
I have created a web interface to enable analysis for users without having
much to worry about the stats in the backend. In this particular case I have
reached a stage where I have finally created two arrays between which I want
to do an independant samples T Test. I have the arrays ready in
RE: Compression
Hi R-Users,
You can deal with pretty decent size data sets in R on a relatively new
computer. I have one that I have been working with that is a nearly 100MB
plain text file. With storage as inexpensive as it is these days that's not
really all that much data and I could stor
Hi Stephen,
Option 2 I am not sure, but option 3 cannot be used because R is not an OLE
component (Microsoft-objects). You can call JMP and the functions from C#,
VB, Excel, etc. (all the Microsoft related stuff) but can't call R. You just
need to make sure that the common library JMP.TLB is lin
Hello Marcos,
When you use paste(.), it will return a String, and the first argument of
lda(.) does not read a string as formula.
>lda(Grupo~paste(names(cien[,3:80]),collapse="+"),data=cien)
Here's what I'd do:
colIndex <- c(1,2,4,5,...) #what ever index of your input data set that you
want t
hi, i am looking to reproduce a study done in stata in R, where a
regression was done while absorbing a categorical variable. i am new
to R, i've i installed the design package but haven't been able to
find an applicable function. thanks for any help.
Dear friends,
I have several sets of points in a transformed environmental space. Each set
of points can be represented as a cloud in the environmental space.
This space is spanned by n coordinates, corresponding to the first n PCs of 36
PCs of some environmental variables (12 monthly minimum t
Hi,
I just responded this post, then have just realised it was already
responded to last month with a similar answer.
I'm very sorry, I just started reading this mailing list a few days ago.
Should be more aware of the discussion in future.
--
Charlotte Maia
http://sites.google.com/site/maiagx
On 12/01/2009 03:49 PM, John Sorkin wrote:
R 2.9
Windows XP
Is there an R function that will compute a measure of agreement(e.g. Kappa)
among three or more observers?
Hi John,
There are several in the irr package.
Jim
__
R-help@r-project.org ma
On Mon, 2009-11-30 at 22:20 -0500, John K. Williams wrote:
> hi, i am looking to reproduce a study done in stata in R, where a
> regression was done while absorbing a categorical variable. i am new
> to R, i've i installed the design package but haven't been able to
> find an applicable function.
Well, here's another naive post from me (hopefully better than the last one).
Firstly I'm not sure computing euclidean distance is that simple. I
would assume temperatures and precipitation would need to be
standardised in some way.
I think the notion of how far away something is, and how distinc
silhouette coefficients?
It measure for each point how similar is to its cluster other points and how
dissimilar
from the points of other clusters.
P.N. Tam, M. Steinbach, V. Kumar, Introduction to data mining, Addison-Wesley,
2006 page 541
Hope it helps.
mario
Charlott
Amrit Nandan 01-Dec-09 08:27:
> I have created a web interface to enable analysis for users without having
> much to worry about the stats in the backend. In this particular case I have
> reached a stage where I have finally created two arrays between which I want
> to do an independant samples T
Thanks Mario! (Oppure grazie Mario?)
- Can those silhouette coefficients be used for distances between sets or only
for distances point to set?
- Where did you get the other post you attached? It did not come up when I
searched the mailing list!
Best,
On Tuesday 01 December 2009 10:31:47 Ma
This is to announce that we plan to release R version 2.10.1 on Monday,
December 14, 2009.
Release procedures start Friday, December 4.
Those directly involved should review the generic schedule at
http://developer.r-project.org/release-checklist.html
The source tarballs will be made available d
Hi every one,
I'm having some problems with the function read.table(clipboard). I got a
spread sheet in the Excel, and than I make a command+C in the Mac, but the R
returns the message that there is no object in the clipboard.
What could have happened?
Thanks,
Diogo
[[alternative HTML ver
Hi,
I'm trying to install R with atlas in ubuntu karmic 64. I do a lot of
matrix operations so I need performance.
Doing
grep sse2 /proc/cpuinfo
tells me tha my CPU supports SSE2.
But I don't see libatlas3gf-sse2 in the package repositories.
Also, there seem to be some gotchas on how to insta
Hi
did you put your spreadsheet to the clipboard? I am not sure if trick
with Ctrl-C followed by read.delim("clipboard") functions in Mac so maybe
you will need to try some more elaborated procedure which was suggested
several times here and I believe is also mentioned in Data import/export
m
Sorry i forget to paste it.
But it should be there in another mail.
Also, the suggested trick fixes the problem in with the given workspace,
but still fails in another one (where the kernel matrix IS positive
definite)
http://www-stud.uni-due.de/~sfhestra/freeze_on_pos_def_matrix.tar.gz
This is n
Hi Amrit,
I believe you can you use the PHP system command to call Rscript or R CMD. I
don't know much PHP but this page might be useful -
http://php.net/manual/en/function.system.php.
You might also want to look at rapache -
http://biostat.mc.vanderbilt.edu/rapache/
Good luck with your project
SJ Robson-Davis bristol.ac.uk> writes:
>
> I want to find the inverse of an integer k mod p (prime.) Is there a
> function that can do this for me? I know i could simply write (k^(p-2)) %%
> p, but i need to do this for large primes (above 100) and this gives the
> warning message:
> probabl
On 12/01/2009 12:48 PM, Hrishi Mittal wrote:
Hi Amrit,
I believe you can you use the PHP system command to call Rscript or R CMD. I
don't know much PHP but this page might be useful -
http://php.net/manual/en/function.system.php.
You might also want to look at rapache -
http://biostat.mc.vander
The rcom package allows you to access the Excel object model from within
R. So you can do essentially you can either do manually or by VBA from
within Excel also from R.
Formatting cells should not be too hard.
Hans-Peter Suter wrote:
> 2009/11/24 Kevin Wright :
>> If had done a little searchi
Dear R help community,
I have tumbleled across some problem quite often and could not find a
solution for it (or was not able to google the right terms).
I am wondering whether there is a way to tell R to assign a value of
parameter X to parameter B while the actual name of parameter X is given
On Tue, 01 Dec 2009 12:45:18 + Jannis wrote:
> I am wondering whether there is a way to tell R to assign a value of
> parameter X to parameter B while the actual name of parameter X is given
> by parameter C. Like this:
Yes. See ?get.
--
Karl Ove Hufthammer
On the Mac, reading from the the clipboard is:
pipe("pbpaste")
... and writing to the clipboard:
pipe("pbcopy", "w")
?pipe
--
David
On Dec 1, 2009, at 6:43 AM, Petr PIKAL wrote:
Hi
did you put your spreadsheet to the clipboard? I am not sure if trick
with Ctrl-C followed by read.delim("clip
Hello R-Helpers,
I am not sure if it is a very simple question but I would like to use two
(...) in a function, for example,
this is a script where I would like to input the variable names (in one of
the (...)) and the variances associated to those variables which are not
calculated in the script
isn't it simpler just to pass two vectors, say v1 and v2, in which one contains
the object names and the other has the associated variances? (btw, "data" isn't
a good function name)
myData <- function(v1, v2){
Vec <- matrix(v1)
varF <- v2
}
I may have misunderstood your question, but IMHO a
--
Best wishes,
Zhijiang Wang
PHD Student
Room 212, Science buliding,
The International WIC Institute,
College of Computer Science and Technology,
Beijing University of Technology,
Beijing, China.
__
R-hel
Seems pretty doubtful that a construction like (..., ...) is going to
be accepted by the R interpreter. However, if you construct your
function to handle two objects of equal length, one for the variable
names and the other for their variances, there should be no problem.
If yu want to hand
?plot.default
On Dec 1, 2009, at 8:39 AM, Zhijiang Wang wrote:
snipped
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide h
Hi everybody,
I have the following problem, the following code seems to run only once for
i and j and for k from one to M.
Doesn't R for increase the argument by itself?
for (i in 1:N){
for (j in 1:(Tk-1)){
if((XGrid[i] < Xk[j+1])&(Xk[j] <= XGrid[i])){
for (k in 1:M){
if ((R
You should learn to use search facilities in R, for example:
RSiteSearch("central moments")
Ravi.
Ravi Varadhan, Ph.D.
Assistant Professor,
Division of Geriatric Medicine and Gerontology
School of Medicine
Johns Hopkins Unive
Hi Maithili,
Here is a suugestion:
R> install.packages('fBasics')
R> require(fBasics)
R> set.seed(123)
R> x <- rnorm(100)
R> basicStats(x)
HTH,
Jorge
On Tue, Dec 1, 2009 at 2:08 AM, Maithili Shiva <> wrote:
> Dear R helpers
>
> If for a given data, I need to calculate Mean, Standard Deviation
Just pass a named vector
f <- function(vars) { nms <- names(vec); ... }
f(c(DAP = var1, ALT = var2))
2009/12/1 Márcio Resende
>
> Hello R-Helpers,
> I am not sure if it is a very simple question but I would like to use two
> (...) in a function, for example,
>
> this is a script where I would
help('rpart.object') will give you information on the return value from
rpart. I think you want the 'where' portion.
For new data help('predict.rpart') gives the predicted results.
Terry T
--
Hi,
I am building a regression tree (method=anova) by using rp
Hello everyone,
I have come across a bit of an odd problem: I am currently analysing data
PCR reaction data of which part is behaving exponential. I would like to fit
the exponential part to the following:
y0 + alpha * E^t
In which Y0 is the groundphase, alpha a fluorescence factor, E the
effic
HI,
As I'm trying to compute Taylor series, I'm having problems in adding and
multiplying unevaluated expressions. I searched for a solution but found none.
my Taylor function works fine for evaluating functions as you can see here:
rTaylorVal=function(exp,x0,dx,n) {
ls=list(x=x0)
newexp=eva
On Tue, Dec 1, 2009 at 2:01 PM, Trafim wrote:
> Hi everybody,
>
> I have the following problem, the following code seems to run only once for
> i and j and for k from one to M.
> Doesn't R for increase the argument by itself?
>
> for (i in 1:N){
> for (j in 1:(Tk-1)){
> if((XGrid[i] < Xk[j+1])&(
Thanks a lot!
I was afraid smth is wrong with my R syntaxis.
On Tue, Dec 1, 2009 at 3:58 PM, Barry Rowlingson <
b.rowling...@lancaster.ac.uk> wrote:
> On Tue, Dec 1, 2009 at 2:01 PM, Trafim wrote:
> > Hi everybody,
> >
> > I have the following problem, the following code seems to run only once
>
At 9:09 AM -0500 12/1/09, Jorge Ivan Velez wrote:
Hi Maithili,
Here is a suugestion:
R> install.packages('fBasics')
R> require(fBasics)
R> set.seed(123)
R> x <- rnorm(100)
R> basicStats(x)
HTH,
Jorge
or, try the describe function in psych.
However, neither fBasics nor describe will report t
Dear R gurus..
I had tried out some suggestions sent to me privately..and unfortunately,
they did not work..
To use a condiition in a subset, the associated dataframe needs to be
attached and detached, which I found cumbersome to use if using more than 1
dataframe (with different dimensions) with
Hi everybody
How do I do to calculate the median and average of a colum of time data like
this: "8:50:10". I also need to plot the time difference between two colums
Thanks a lot
--
View this message in context:
http://n4.nabble.com/median-for-time-data-tp932287p932287.html
Sent from the R help
On Dec 1, 2009, at 10:38 AM, Santosh wrote:
Dear R gurus..
I had tried out some suggestions sent to me privately..and
unfortunately,
they did not work..
To use a condiition in a subset, the associated dataframe needs to be
attached and detached, which I found cumbersome to use if using more
On Dec 1, 2009, at 10:55 AM, David Winsemius wrote:
On Dec 1, 2009, at 10:38 AM, Santosh wrote:
Dear R gurus..
I had tried out some suggestions sent to me privately..and
unfortunately,
they did not work..
To use a condiition in a subset, the associated dataframe needs to be
attached and
The delay that I observe is when I type ctrl+C after I str() a long
list. Since str() comes from the core R installation, maybe it should
be improved?
> R can or cannot response immediately depending on the underlying C sources.
> If the underlying source code is written carefully enough, there ar
On Dec 1, 2009, at 11:04 AM, David Winsemius wrote:
On Dec 1, 2009, at 10:59 AM, David Winsemius wrote:
On Dec 1, 2009, at 10:55 AM, David Winsemius wrote:
On Dec 1, 2009, at 10:38 AM, Santosh wrote:
Dear R gurus..
I had tried out some suggestions sent to me privately..and
unfortunat
On Dec 1, 2009, at 10:59 AM, David Winsemius wrote:
On Dec 1, 2009, at 10:55 AM, David Winsemius wrote:
On Dec 1, 2009, at 10:38 AM, Santosh wrote:
Dear R gurus..
I had tried out some suggestions sent to me privately..and
unfortunately,
they did not work..
To use a condiition in a sub
Hello,
I wrote a package, which in the NAMESPACE file exports functions like this:
exportPattern("^\\rh")
On R-2.8 (Linux, 64), upon loading the package I have the rh functions present.
On R-2.10, Mac OS X, (32 bit), it builds, loads, but the functions are not
loaded, i.e the only function is rh
As a followup, i can do things Package:::rh*, there just no exported.
On Tue, Dec 1, 2009 at 11:18 AM, Saptarshi Guha
wrote:
> Hello,
> I wrote a package, which in the NAMESPACE file exports functions like this:
>
> exportPattern("^\\rh")
>
> On R-2.8 (Linux, 64), upon loading the package I have
I saw different specifications for Random Effects and I'm confused about
the use of "/" and the use of "(0+...|)" .
Let say we have a nested structure where some countries have some
several plants in different states and we measure the reaction to a drug.
The list of Countries = USA, France, I
On 01/12/2009 11:18 AM, Saptarshi Guha wrote:
Hello,
I wrote a package, which in the NAMESPACE file exports functions like this:
exportPattern("^\\rh")
That's a very strange pattern to be using. Why do you want those
backslashes there? If you just want to export items whose names start
You probably just want : exportPattern("^rh")
What did you expect the backslash to do ?
On 12/01/2009 05:18 PM, Saptarshi Guha wrote:
Hello,
I wrote a package, which in the NAMESPACE file exports functions like this:
exportPattern("^\\rh")
On R-2.8 (Linux, 64), upon loading the package I hav
Dear all,
I want to compute the eigenvalues of a complex matrix for some statistics.
Comparing it to its matlab/octave sibling, I don't get the same eigenvalues
in R computing it from the exact same matrix.
In R, I used eigen() and arpack() that give different eigenvalues. In
matlab/octave I used
I have no idea why I used the \\, the perils of copy and pasting from
some other package or source .
So, heres the thing, did R regex interpreter change? How come my
export stopped working?
Thank you
Regards
Saptarshi
On Tue, Dec 1, 2009 at 11:28 AM, Romain Francois
wrote:
> You probably just wa
Dear All,
I am finding trouble trying to guild a Wrapper using random forest to
evaluate the subsets:
I do:
nombi <-
make_Weka_filter("weka/filters/supervised/attribute/AttributeSelection")
datbin<- nombi(gene ~., data=X1X2X4X5W, control =Weka_control(
S=list("weka.attributeSelection.Geneti
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Santosh
> Sent: Tuesday, December 01, 2009 7:39 AM
> To: r-help@r-project.org
> Subject: Re: [R] "subset" or "condition" as argument to a function
>
> Dear R gurus..
> I had trie
On Tue, 1 Dec 2009, Itziar Frades Alzueta wrote:
Dear All,
I am finding trouble trying to guild a Wrapper using random forest to
evaluate the subsets:
I do:
nombi <-
make_Weka_filter("weka/filters/supervised/attribute/AttributeSelection")
datbin<- nombi(gene ~., data=X1X2X4X5W, control =
Hi,
try to convert this to the R time format "POSIXct" or "POSIXlt" via
strptime(). Then you can simply substract them. I am not sure whether a
median can be calculated though (should be possible as POSIXct stores
the value as seconds since 1970)
Best
Jannis
uvilla schrieb:
Hi everybo
Dear All,
I am finding trouble trying to build a Wrapper using random forest to
evaluate the subsets:
I do:
nombi <-
make_Weka_filter("weka/filters/supervised/attribute/AttributeSelection")
datbin<- nombi(gene ~., data=X1X2X4X5W, control =Weka_control(
S=list("weka.attributeSelection.
Hi,
I've this time series:
> ts_evi
Time Series:
Start = c(2000, 4)
End = c(2002, 7)
Frequency = 23
[1] 0.1948306 0.1930461 0.1905792 0.1848909 0.1893624 0.1811400 0.1678140
[8] 0.1750714 0.3100132 0.3495946 0.4103353 0.4973740 0.4937490 0.4031435
[15] 0.3503787 0.2755022 0.2304617 0.2284854 0.
Dears,
is there any way to "switch off" or work around the error message that
pops up when I do something like:
A<-B['logical vector']
and when 'logical vector' only consists of FALSE values? My problem is
that this message always kicks me out of my loops and always testing via
an if clause
?try
On Tue, Dec 1, 2009 at 12:22 PM, Jannis wrote:
> Dears,
>
>
> is there any way to "switch off" or work around the error message that
> pops up when I do something like:
>
>
> A<-B['logical vector']
>
>
> and when 'logical vector' only consists of FALSE values? My problem is
> that this messa
Hi,
an alternative to parse() is to use quote and bquote,
set.seed(123)
d = data.frame(a=letters[1:5], b=1:10, c=sample(0:1, 10, repl=TRUE))
cond1 <- quote(a=="b")
cond2 <- quote(b < 6)
cond3 <- bquote(.(cond1) & .(cond2))
subset(d, eval(cond1))
subset(d, eval(cond2))
subset(d, eval(cond3))
HT
If you could reformulate your model as alpha * (y0 + E^t) then you could
use nls with alg="plinear" (alpha then would be eliminated from the
nonlinear param and treated as conditionally linear) and this would help
with convergence.
Else you can try package DEoptim to get the starting values; the a
Hi,
You haven't given us much information.
You might actually have the same eigenvalues, but don't recognize that due
to possibly different orderings. Complex numbers do not possess ordering.
Therefore, there is no natural way to report complex eigenvalues. In R, the
complex eigenvalues are o
In my Excel file, I have data in following format :
Feb-07 38.49
Mar-07 39.95
Apr-07 37.47
May-07 35.77
Jun-07 32.96
Jul-07 33.27
I tried to copy this data as a time series using following code :
library(zoo)
dat <- read.zoo(file="clipboard", format="%m-%y")
However getting following err
Thanks a lot for your answer Jannis.
Actually, I should have specified what I`m trying to do.
I have a datafame which 3 colums, one is the "person ID", second is "Anfag"
and third is "Ende". The two time colums are in this way: "8:50:10", so I
have to calculate the medan of the Anfag colum and to
# input
library(chron)
tt <- times(c("8:50:10", "9:40:20", "10:55:45"))
tt2 <- times(c("01:00:00", "02:00:00", "03:00:00"))
tt
tt2
# calc median and differences (although it will give results as fractions of
a day if there are negative results)
median(tt)
tt - tt2
tt2 - tt
On Tue, Dec 1, 2009 a
Dear all,
I want to determine if the slopes of the trends I have in my plot are
significantly different from each other (I have 2 time-series trends). What
statistical test is most suitable for this purpose and is it available in the R
base package?
Many thanks,
Steve
Specify that your input is of class yearmon (as opposed to Date class) and
also correct the format specification as per the percent codes in ?strptime
library(zoo)
z <- read.zoo("clipboard", FUN = as.yearmon, format = "%b-%y")
On Tue, Dec 1, 2009 at 12:55 PM, Megh wrote:
>
> In my Excel file,
Hi Julia:
I am sure that you will find many useful resources as you attempt to learn
R.
If time permits, please look at the Tegrity-based video that Ive prepared
for my students:
http://tegrity1.acast.nova.edu/tegrityUtils/GetCourseListing.aspx?Session_In
fo=7KmTs8Wkvvr0/Q0TsCfcur4RNGDvBGYk0jY+
I want to export a csv file so I can do other things with it.
I issue this command to break down years as to whether it was windy or not:
t<-tapply(TURB,list(year,windy),mean,na.rm=T)
which results in:
> t
no yes
1990 21.516514 39.86400
1991 13.580435 28.87500
1992 12.17142
uvilla schrieb:
When I use strptime() I just get NA NA NA
I`m new at using R, must finisth this work thoug
I guess Im doing totally wrong, actually everytime i try to use "POSIXct" it
doesn`t work
If you have a look at help(strptime) you find that you have to specify
the format in which yo
I am trying to plot data with multiple logical and physical groups using
R. Below is a sample of the kind of data I am working with and the desired
output. We have a jmp script that can do the same thing, but at ~$200 a
year the licensing is counterproductive. Thanks for any help.
Data inpu
Hello All,
I am trying to create a legend for a black-white graph. The package I
use is ggplot2. It can add colors to the legend key but not line types.
Can you please help?
# example from Wickman (2009, ggplot2 - elegant graphics for data
analysis, page 109)
library(ggplot2)
huron <-
Hello All,
I am trying to create a legend for a black-white graph. The package I use is
ggplot2. It can add colors to the legend key but not line types. Can you
please help?
# example from Wickman (2009, ggplot2 – elegant graphics for data analysis,
page 109)
library(ggplot2)
huron <- data.fram
Thanks for your feedback.
Actually Plant is nested since High and Low are qualitative relative
values (High in Michigan is not the same as High in Sienna).
S Ellison wrote:
The Plant classification is not nested; it's an effect across all
countires and states and probably a fixed effct (assum
Starting with the head of a 499 element matrix whose column names are
now the labels trom a cut() operation, I needed to get to a vector of
midpoints to serve as the basis for plotting a calibration curve
( exp(linear predictor) vs. :
> dput(head(dimnames(mtcal)[2][[1]])) # was starting po
On 1/12/2009, at 8:32 PM, Karl Ove Hufthammer wrote:
Exercise to the reader:
Note that
sapply(split(x, ff, drop=TRUE), sum)
gives you the values of (just) the non-empty levels.
Now, why does
sapply(split(x, ff), sum, drop=TRUE)
give the wrong value (1) for these levels, while
sa
I was messing around with some data in R and SAS (the reason is
unimportant) fitting a multiple linear regression and got a
curious discrepancy. The data set is too big to post, but if
someone wants it, I can send it.
So, here are the (partial) results:
From R:
Coefficients:
Estima
You also might want to look at
demo("gsubfn-cut")
On Tue, Dec 1, 2009 at 2:41 PM, David Winsemius wrote:
> Starting with the head of a 499 element matrix whose column names are now
> the labels trom a cut() operation, I needed to get to a vector of midpoints
> to serve as the basis for plotting
Hi,
I don't understand why you used scale_manual_colour if you want only
black lines. To have different line types in the legend you can map
the linetype to the data,
huron <- data.frame(year=1875:1972, level=LakeHuron)
ggplot(huron, aes(year)) +
geom_line(aes(y=level+5, linetype="above")) +
Thanks to an insightful comment from Jeremy Miles, who politely
pointed out my thick-headed moment, I know what happened.
The sex variable was coded as 1/2 in the SAS data, but was a factor
in the R data and so became a properly coded dummy variable.
Sorry for the obvious question and answer.
K
Perhaps this shoul work too:
sapply(strsplit(gsub("^\\W|\\W$", "", testvec), ","),
function(x)sum(as.numeric(x))/2)
On Tue, Dec 1, 2009 at 5:41 PM, David Winsemius wrote:
> Starting with the head of a 499 element matrix whose column names are now
> the labels trom a cut() operation, I needed to
Hello - Thank you so much for the help. It works perfectly. I guess that as
many have pointed out, ggplot is a great package but there is a lack of
documentation and examples.
Edwin Sun
baptiste auguie-5 wrote:
>
> Hi,
>
> I don't understand why you used scale_manual_colour if you want only
I'm sitting here chuckling. Your solution is just so "pure".
I would offer an enhancement. When I tested with my cuts that had "-"
before the digits, you solution dropped them, so my suggestion for the
pattern would be: "[-[:digit:].]+"
I will admit that I thought it might fail with posit
Thanks you both
Jannis now it is working!!. I just have one mor request, please!
How I'm suppose to make a boxplot with anfang, when working with times, it
just have on the y axis some decimal number which make no sense. i need the
time to appear in the y axis in order to see the median in the bo
Try this:
> library(gsubfn)
> strapply(testvec, "[-+.0-9]+", as.numeric, simplify = ~
colMeans(cbind(...)))
[1] -5.8500 -2.9800 -2.8160 -2.7120 -2.6325 -2.5680
On Tue, Dec 1, 2009 at 3:14 PM, David Winsemius wrote:
> I'm sitting here chuckling. Your solution is just so "pure".
>
> I would offer
Because of the combinatorial nature of ggplot2, it is simply not
possible to provide an example that illustrates every single
combination of options. There are already over 600 example graphics
in the package - if you can't find one that exactly meets your need,
you need to buy the book and learn
On Dec 1, 2009, at 3:28 PM, Gabor Grothendieck wrote:
> Try this:
>
> > library(gsubfn)
> > strapply(testvec, "[-+.0-9]+", as.numeric, simplify = ~
> colMeans(cbind(...)))
> [1] -5.8500 -2.9800 -2.8160 -2.7120 -2.6325 -2.5680
Very, nice. Also tried on some other valid ("200,2") and
invalid )
Could somebody recommend some textbook how to compute contrast when
there are interactions terms? "Applied Linear Regression Models"
(book) mentioned contrast, but I cannot extend it to the case where
there are interaction terms.
__
R-help@r-project.org
Hi,
I am using R 2.9.0. It seems the documentation for the calculation of
Canberra distance using stats::dist is ambiguous. Does anyone have the
original definition given in the Lance & Williams paper from Aust. Comput.
J. 1, 15-20, 1967?
When there are zeros at certain position in both vectors,
On Tue, 1 Dec 2009, Peng Yu wrote:
Could somebody recommend some textbook how to compute contrast when
there are interactions terms? "Applied Linear Regression Models"
(book) mentioned contrast, but I cannot extend it to the case where
there are interaction terms.
Textbook? Schmextbook!
You
Where does the table come from?
write.csv(t, file = "t.csv")
looks like it would work
--- On Tue, 12/1/09, ggraves wrote:
> From: ggraves
> Subject: [R] write.csv fails with $ operator invalid for atomic
> To: r-help@r-project.org
> Received: Tuesday, December 1, 2009, 1:36 PM
>
> I want
It was in some documentation along with using data.frame and other entries that
didn't work. Can't explain why I didn't try it "as is".
Gregory A. Graves
Lead Scientist
REstoration COoordination and VERification (RECOVER)
Restoration Sciences Department
South Florida Water Management District
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