Hello together,
In the package 'Matching' there ist a possibility to determine balance
statistics after Matching with the function 'MatchBalance'.
In this function there has a formula 'formul' to be given.
I'm wondering how I can implement all two-way interactions, without
specifying them explicit
Jorge Ivan Velez wrote:
And if you want to replace both "+" and "?", here is a suggestion:
x <- "asdf+,jkl?"
gsub("[?]|[+]", "", x)
# [1] "asdf,jkl"
Once you're into character classes ([]), you might as well go all
the way:
> gsub("[?+]", "", x)
[1] "asdf,jkl"
--
O__ Peter D
On Sun, 22 Nov 2009, zubin wrote:
Hello, can one use predict, as you can with other model objects like lm,
with dynlm to predict a new data set that is identical in field names,
just a different time period.
Be nice if you could, I don't really want to create a new data set with
all the lags, h
Hi All,
I am currently doing the following to compute summary statistics of
aggregated data:
a = aggregate(warpbreaks$breaks, warpbreaks[,-1], mean)
b = aggregate(warpbreaks$breaks, warpbreaks[,-1], sum)
c = aggregate(warpbreaks$breaks, warpbreaks[,-1], length)
ans = cbind(a, b[,3], c[,3])
Thi
Hi all,
I am relatively a new user of R. I need assistance on how to download and
install the clim.pact_2.2-39.zip. I am running R on Windows.
--
ZABLONE OWITI
GRADUATE STUDENT
Nanjing University of Information, Science and Technology
College of International Education
Deal list,
I have a data frame (birth) with mixed variables (numeric and
alphanumeric). One variable "t1stvisit" was originally coded as
numeric with values 1,2, and 3. After attaching the data frame, this
is what I see when I use str(t1stvisit)
$ t1stvisit: int 1 1 1 1 1 1 1 1 2 2 ...
On 11/23/2009 07:15 PM, utkarshsinghal wrote:
Hi All,
I am currently doing the following to compute summary statistics of
aggregated data:
a = aggregate(warpbreaks$breaks, warpbreaks[,-1], mean)
b = aggregate(warpbreaks$breaks, warpbreaks[,-1], sum)
c = aggregate(warpbreaks$breaks, warpbreaks[
Erin Hodgess wrote:
Hello again.
I did the update and it worked well, except for one thing: the Rcmdr
doesn't work anymore.
Has that come up before please?
Not that I know. But what does "doesn't work anymore" mean precisely?
Uwe
Thank you for all of your help.
Sincerely,
Erin
Li
Hi
r-help-boun...@r-project.org napsal dne 23.11.2009 09:15:02:
> Hi All,
>
> I am currently doing the following to compute summary statistics of
> aggregated data:
> a = aggregate(warpbreaks$breaks, warpbreaks[,-1], mean)
> b = aggregate(warpbreaks$breaks, warpbreaks[,-1], sum)
> c = aggregate
masterinex wrote:
Hi Hadley ,
I really apreciate the suggestions you gave, It was helpful , but I still
didnt quite get it all. and I really want to do a good job , so any
comments would sure come helpful, please understand me .
Well, we try to understand you, but we do not either. I th
On Sun, 22 Nov 2009, Ravi Varadhan wrote:
Hi Torsten,
Hi Ravi,
It would be useful to "warn" the users that the multivariate normal probability
calculated by "pmvnorm" using the GenzBretz algorithm is "random", i.e.
the result can vary between repeated executions of the function.
only i
masterinex wrote:
this is how my data matrix looks like . This is just for the first 10
observations , but the pattern is similar for the other observations.
112.3 154.25 67.75 36.2 93.1 85.2 94.5 59.0 37.3 21.9 32.0
27.4 17.1
2 6.1 173.25 72.25 38.5 93.6 83.0 98.7
ZABLONE OWITI wrote:
Hi all,
I am relatively a new user of R. I need assistance on how to download and
install the clim.pact_2.2-39.zip. I am running R on Windows.
See the manual "R Installation and Administration" and afterwards read
?install.packages
Uwe Ligges
__
Dear R-ers,
I don't understand the following, maybe someone will help me
explain:
> setClasss('A')
[1] "A"
> new('a')
Error in new("a") :
trying to generate an object from a virtual class ("a")
> setClass('b', contains='a')
[1] "b"
> new('b')
An object of class “b”
In what way is B more co
Thanks a lot for the hint!
Antje
Duncan Murdoch wrote:
On 20/11/2009 7:11 AM, Antje wrote:
Hey there,
I'm running R 2.10 on Windows XP (Professional) and I was wondering
where the HTML help window disappeared?
With earlier versions everything was fine. Now I get only this
old-fashioned te
PS. All class names were upper-case, I messed up while copying the
code, but it has no effect on the result. Thanks for help.
--Hun
On Mon, 23 Nov 2009 10:28:37 +0100 "Hun S. Tesatte"
wrote:
>Dear R-ers,
>
>I don't understand the following, maybe someone will help me
>explain:
>
>> setClasss
The Rcmdr menu does not appear.
However, I tried an experiment: I downloaded the R-2.10.0.tar.gz file
and installed via ./configure, make, and all was well for Rcmdr.
Thanks,
Erin
2009/11/23 Uwe Ligges :
>
>
> Erin Hodgess wrote:
>>
>> Hello again.
>>
>> I did the update and it worked well, exc
Peter Ehlers wrote:
If there's been an answer to this, I've missed it.
Here's my take.
Antje wrote:
Hi there,
I was wondering if anybody can explain to me why the boxplot ends up
with different results in the following case:
I have some integer data as a vector and I compare the stats of
b
Readers,
I have tried to use the zoo package to merge datasets and then use the
coplot function, but the graph is not fully created. Only the panel
data is shown. Command terminal output below, with csv files. What is
the meaning of the warning message? Can anyone help please?
rhelpatconference.j
Hi Torsten,
Thanks for you comment.
If you have some free time to spare, partial derivatives with respect
to bounds and correlation coefficients would be great for pmvnorm! In
complex problems, optim is not very good at estimating the hessian
numerically and first order derivatives help to build
On 11/23/2009 1:06 AM, ashok varma wrote:
> hello,
>
> i am fitting a Linear model using R. I have to fit the model considering all
> the interaction effects of order 1 of the independent variables. But I have
> 9 variables. So, it will be difficult for me to write all the 36
> combinations in the
Hi, Im new to R and having some trouble with my code - it works, its just
very slow! Ive tried lots of things, but nothing quite seems to work, so any
help and suggestions would be really appreciated!
I want to calculate the marginal likelihood for every element of a row of a
matrix and the corre
Loops tend to dramatically increase computation time. You may re-write
a vectorized version of your code if possible, i.e. use matrix
algebra. Calculus is a lot faster if one can avoid loops (at least
some of them) .
Best,
Stephane
2009/11/23 AnnaFowler :
>
> Hi, Im new to R and having some troub
Good afternoon!
I need to evaluate the goodness-of-fit (aka calibration) for survival
probability estimates from a Cox model.
I tried to use 'calibrate' in the Design package but I'm not sure if it
should/would produce what I need (ie a chi-sq type statistic with a table of
expected vs observ
The NEWS of the randomForest R library mention that version 4.5-13
fixed a bug in predict.randomForest() when newdata is a matrix with no
rownames.
Can anyone explain what were the consequences of this bug in the predictions?
I think the bug was fixed with the new line
if (is.null(rn)) rn <- kee
Alan Kelly wrote:
Deal list,
I have a data frame (birth) with mixed variables (numeric and
alphanumeric). One variable "t1stvisit" was originally coded as numeric
with values 1,2, and 3. After attaching the data frame, this is what I
see when I use str(t1stvisit)
actually, str(birth), I s
On Sun, Nov 22, 2009 at 11:15 PM, David Winsemius wrote:
>
> On Nov 22, 2009, at 4:45 PM, stephen's mailinglist account wrote:
>
> On Sun, Nov 22, 2009 at 11:14 AM, frenchcr
>> wrote:
>>
>>
>>>
>>> Please help me persuade IT to install R on my computer!
>>>
>>> All suggestions welcome.
>>>
>>> Ou
Antje wrote:
Peter Ehlers wrote:
If there's been an answer to this, I've missed it.
Here's my take.
Antje wrote:
Hi there,
I was wondering if anybody can explain to me why the boxplot ends up
with different results in the following case:
I have some integer data as a vector and I compare
On Nov 23, 2009, at 7:34 AM, Peter Ehlers wrote:
Alan Kelly wrote:
Deal list,
I have a data frame (birth) with mixed variables (numeric and
alphanumeric). One variable "t1stvisit" was originally coded as
numeric with values 1,2, and 3. After attaching the data frame,
this is what I s
The dyn package has a predict method that can typically be used to
predict one step ahead (and you can use a loop to get multiple steps).
To use just preface lm (or glm or any model fitting function in R
that uses model.frame in the same way as lm). It works with zoo,
zooreg, ts, its and irts cla
Eleni Rapsomaniki wrote:
Good afternoon!
I need to evaluate the goodness-of-fit (aka calibration) for survival probability estimates from a Cox model.
I tried to use 'calibrate' in the Design package but I'm not sure if it should/would produce what I need (ie a chi-sq type statistic with a tabl
On Nov 23, 2009, at 7:47 AM, stephen's mailinglist account wrote:
>
> On Sun, Nov 22, 2009 at 11:15 PM, David Winsemius > wrote:
>
> On Nov 22, 2009, at 4:45 PM, stephen's mailinglist account wrote:
>
> On Sun, Nov 22, 2009 at 11:14 AM, frenchcr
> wrote:
>
>
>
> Please help me persuade IT to
simona.racio...@libero.it wrote:
> It works! But Once I have the square root of this matrix, how do I convert it
> to a real (not imaginary) matrix which has the same property? Is that
> possible?
No. That is theoretically impossible.
If A = B'B, then x'Ax = ||Bx||^2 >= 0
for any x, which impl
You have no complete rows so how could it plot anything?
If you had some complete rows then this should work:
coplot(z1 ~ z2 | z3, as.data.frame(z4))
Lines1 <- "09:50:00,315.79
09:50:30,325.43
09:51:00,315.53
09:51:30,313.73
09:52:00,316.11
09:52:30,331.65
09:53:00,325.31
09:53:30,334.33
09:54:00,
Dear all,
I'm looking for a function comparable to switch, to categorize a
continuous variable in a few levels. Off course that can be done with
a series of ifelse statements, but that looks rather clumsy. I looked
at switch, but couldn't figure out how to use it for this. I guess
that's not possi
Try this:
> library(doBy)
> summaryBy(breaks ~ ., warpbreaks, FUN = c(mean, sum, length))
wool tension breaks.mean breaks.sum breaks.length
1A L44.6401 9
2A M24.0216 9
3A H24.6221 9
Never mind, found the function :
cut(test,breaks=c(0,10,50,90,100),labels=c("lowest","low","high","highest"),include.lowest=T,right=F)
Cheers
Joris
On Mon, Nov 23, 2009 at 2:14 PM, joris meys wrote:
> Dear all,
>
> I'm looking for a function comparable to switch, to categorize a
> continuous va
On Nov 23, 2009, at 8:14 AM, joris meys wrote:
Dear all,
I'm looking for a function comparable to switch, to categorize a
continuous variable in a few levels.
?cut
Off course that can be done with
a series of ifelse statements, but that looks rather clumsy. I looked
at switch, but couldn'
On Mon, Nov 23, 2009 at 1:01 PM, David Winsemius wrote:
> It was a good read. We had a recent example submitted to r-help where
> I had occasion to test their "solution 2" (use OO.org' Calc) and found
> it to be just as bad at curve fitting for a polynomial as had been
> Excel. Take a look at the
Hi R users,
I'd like to know if anyone has come across problems wherein it was necessary
to check if strings contained all alphabets, some numbers or all numbers?
In my attempt to test if a string is numeric, alpha-numeric (also includes
if string is only alphabets) :
# Reproducible R code below
Dear Prof. Harrell,
Thank you very much for your prompt and very helpful response. I guess
that since a global statistic such as a chi-sq test is not applicable in
this case, the calibration curve itself from the calibration() is the
most informative alternative (most graphical methods reveal more
try this:
> mywords<- c("harry","met","sally","subway10","1800Movies","12345")
> grep("^[[:alpha:]]*$", mywords) # letters
[1] 1 2 3
> grep("^[[:digit:]]*$", mywords) # numbers
[1] 6
>
On Mon, Nov 23, 2009 at 8:28 AM, Harsh wrote:
> Hi R users,
> I'd like to know if anyone has come across prob
Added a little more:
> mywords<- c("harry","met","sally","subway10","1800Movies","12345", "not
> correct 123")
> all.letters <- grep("^[[:alpha:]]*$", mywords)
> all.numbers <- grep("^[[:digit:]]*$", mywords) # numbers
> mixed <- grep("^[[:digit:][:alpha:]]*$", mywords)
> all.letters
[1] 1 2 3
>
On Nov 23, 2009, at 7:24 AM, Barry Rowlingson wrote:
On Mon, Nov 23, 2009 at 1:01 PM, David Winsemius > wrote:
It was a good read. We had a recent example submitted to r-help where
I had occasion to test their "solution 2" (use OO.org' Calc) and
found
it to be just as bad at curve fitting
Thanks Duncan (and David). I couldn't get back to my computer until
today. I understand it pretty well now and I'm able to get what I need.
On a side note, I have had a hard time getting rgl to work. For the
moment, I have to compile without libpng and ftfonts, and when I load
the package I
In the example below, is there any way to get the top title, i.e. "Distribution
Comparisons", in a bit from the top margin?
Thanks agian
- Original Message
From: Jason Rupert
To: Peter Ehlers
Cc: R Project Help ; Me
Sent: Sat, November 21, 2009 12:31:04 AM
Subject: Re: [R] How
On 23/11/2009 8:55 AM, Marc Chiarini (Tufts) wrote:
Thanks Duncan (and David). I couldn't get back to my computer until
today. I understand it pretty well now and I'm able to get what I need.
On a side note, I have had a hard time getting rgl to work. For the
moment, I have to compile witho
>> mywords<- c("harry","met","sally","subway10","1800Movies","12345", "not
>> correct 123")
>> all.letters <- grep("^[[:alpha:]]*$", mywords)
>> all.numbers <- grep("^[[:digit:]]*$", mywords) # numbers
>> mixed <- grep("^[[:digit:][:alpha:]]*$", mywords)
mywords<- c("harry","met","sally","subway
> > are there any more packages that help decribe and explore data
> sets
package tdisplay at http://forums.cirad.fr/logiciel-R/viewtopic.php?t=2409
Details:
display-packageTool Box for Data Importation and Display
import Import Data From External Data Bases
On Nov 23, 2009, at 8:58 AM, Jason Rupert wrote:
In the example below, is there any way to get the top title, i.e.
"Distribution Comparisons", in a bit from the top margin?
You could use instead:
title("\nDistribution Comparisons", outer = TRUE)
And please correct the spelling of Poisson
Thanks Stephane, Thats a great help!
SL-16 wrote:
>
> Loops tend to dramatically increase computation time. You may re-write
> a vectorized version of your code if possible, i.e. use matrix
> algebra. Calculus is a lot faster if one can avoid loops (at least
> some of them) .
>
> Best,
> Steph
Hello, I would like to ask you a question.I have a program in R and I use the
readline method to ask the user some things,but i don´t use the R console
but I use Win console then not appear what I put.I put the code as you look
for:
cat("1- 24horas\n")
cat("2- 12horas\n")
cat("3- 8horas\n")
selec
Thanks Chuck!
It works! But Once I have the square root of this matrix, how do I convert it
to a real (not imaginary) matrix which has the same property? Is that
possible?
Best,
Simon
>Messaggio originale
>Da: cbe...@tajo.ucsd.edu
>Data: 21-nov-2009 18.11
>A: "simona.racio...@libero.it"
It works! But Once I have the square root of this matrix, how do I convert it
to a real (not imaginary) matrix which has the same property? Is that
possible?
Best,
Simon
>Messaggio originale
>Da: p.dalga...@biostat.ku.dk
>Data: 21-nov-2009 18.56
>A: "Charles C. Berry"
>Cc: "simona.racio
Dear all,
i use the following package/syntax to export data to excel:
library(xlsReadWrite)
write.xls( exportdata,pfad,colNames = TRUE,sheet = 1,from = 1,rowNames =
FALSE )
Everything is fine, but the format of the export is not the best. For
example, I every time have to adjust the column widt
Hi,
keine ahnung. Das liegt jetzt bei Hr. Feld. Frag mal bei ihm nach.
Grüße
Thushyanthan
r-help-requ...@r-project.org wrote:
Send R-help mailing list submissions to
r-help@r-project.org
To subscribe or unsubscribe via the World Wide Web, visit
https://stat.ethz.ch/mailman/
Hello,
I am fitting a Linear model using R. Now, i want to know how to test whether
my model is following the homoscadasticity and residuals being
random assumptions or not while fitting the model.
thanks a lot in advance,
Ashok Varma
[[alternative HTML version deleted]]
__
Hello,
I am using heatmap.2 from the gplots library to plot a small symmetrical
matrix.
This is the command:
heatmap.2(tempHeat,symm=T,trace="none",cexRow=0.7,cexCol=0.7,col="redgreen",density.info="none")
I have a couple of questions:
1) The range is from -0.2 to 0.4 and the colour scheme I
Jason Rupert wrote:
In the example below, is there any way to get the top title, i.e. "Distribution Comparisons", in a bit from the top margin?
Thanks agian
Your par(oma=...) needs to come _before_ plotting; make it the
first statement.
In addition, title() takes a line= argument; try line=
Hi all,
what is the reason why the anova() method for coxph objects does not work when
robust standard errors have been requested, e.g.,
fit <- coxph(Surv(futime, fustat) ~ resid.ds *rx + ecog.ps, data = ovarian,
robust = T)
anova(fit)
any pointers will be much appreciated.
Sincerely,
Mura
Dear R & Java users
I have the problems with calling R from Java (JRE6) on Windows. After
running, we have:
#
# A fatal error has been detected by the Java Runtime Environment:
#
# EXCEPTION_ACCESS_VIOLATION (0xc005) at pc=0x6c7330c0, pid=1436,
tid=6200
#
# JRE version: 6.0_17-b04
# Jav
i have a dataset with x and y values. i want to randomly select a point on
the x-axis between the smallest and largest x-value and use a y value of
zero for them.
Next, for each randomly selected point {x[i],0}i want to find the point in
the {x,y} space which is closest to them.
However, as seen
yonosoyelmejor wrote:
> Hello, I would like to ask you a question.I have a program in R and I use the
> readline method to ask the user some things,but i don´t use the R console
> but I use Win console then not appear what I put.I put the code as you look
> for:
>
> cat("1- 24horas\n")
> cat("2- 1
On Nov 23, 2009, at 10:02 AM, Daniel Brewer wrote:
Hello,
I am using heatmap.2 from the gplots library to plot a small
symmetrical matrix.
This is the command:
heatmap.
2
(tempHeat
,symm
=
T
,trace
="none",cexRow=0.7,cexCol=0.7,col="redgreen",density.info="none")
I have a couple
Use the RDCOMClient package from omegahat.org.
On Mon, Nov 23, 2009 at 11:02 AM, koj wrote:
>
> Dear all,
>
> i use the following package/syntax to export data to excel:
>
> library(xlsReadWrite)
> write.xls( exportdata,pfad,colNames = TRUE,sheet = 1,from = 1,rowNames =
> FALSE )
>
> Everything i
On Nov 23, 2009, at 7:02 AM, koj wrote:
Dear all,
i use the following package/syntax to export data to excel:
library(xlsReadWrite)
write.xls( exportdata,pfad,colNames = TRUE,sheet = 1,from =
1,rowNames =
FALSE )
Everything is fine, but the format of the export is not the best. For
exampl
Hi
I have been unable to find information on the following problem:
Error in get.gpar(): unable to find function "grid.Call"
Reinstalling R-2.10.0, platform: i386-pc-mingw32 did not help.
Before this message there was a "get.gpar" missing. We then transported
the source code from another mach
Dear Marco:
Look in "agricolae" package.
There is a Friedman test with and without replicates.
In this package is used the Conover's book as a reference.
Greetings,
Dr. D. José Trujillo Carmona
Dpt. of Mathematics
Fac. of Science of Badajoz
Univ. of Extremadura
Spain
From: Marco Chiarandini
Hi There,
I have a named List object.I want to access all the list elements that has
the same name
for example
The List
test <- list()
$d2
v1 v2 v3 v4
1 2 3 4 5
$d2
v1 v2 v3 v4
1 2 3 4 5
$d3
v1 v2 v3 v4
8 9 19 10
$d1
v1 v2 v3 v4
12 14 15 16
so if i say test[["d2"]] or test["d2"] i should get
Dear list members
I'm currently working on some topographic (elevation) data, and was
somewhat surprised that the 'topo.colors' and 'terrain.colors' are of
little to no use here.
The problem is that these functions only return a palette of colours;
they don't map depth values to colours. So if
Try this:
test[grep("d2", names(test))]
On Mon, Nov 23, 2009 at 2:53 PM, Rajasekaramya wrote:
>
> Hi There,
>
> I have a named List object.I want to access all the list elements that has
> the same name
> for example
> The List
> test <- list()
> $d2
> v1 v2 v3 v4
> 1 2 3 4 5
>
> $d2
> v1 v2 v3
Christian Hoffmann wrote:
Hi
I have been unable to find information on the following problem:
Error in get.gpar(): unable to find function "grid.Call"
Reinstalling R-2.10.0, platform: i386-pc-mingw32 did not help.
Before this message there was a "get.gpar" missing. We then transported
the
On Nov 23, 2009, at 11:52 AM, Karl Ove Hufthammer wrote:
Dear list members
I'm currently working on some topographic (elevation) data, and was
somewhat surprised that the 'topo.colors' and 'terrain.colors' are of
little to no use here.
The problem is that these functions only return a palette
If you want to control what gets printed in the output of your function, then
you need to get into creating classes and methods. Choose a class to return
from your function, and create a print method for that class, then when you run
your function the output will cause the print method to be ca
Hello,
I would like to find out how to get the fit from a mixture of poisson. For
example, suppose I know the
Y = 0.25*Poisson(2) + 0.75*Poisson(10)
then if I have say y = 4, how do I get the fitted value for y?
[[alternative HTML version deleted]]
___
ashok varma wrote:
Hello,
I am fitting a Linear model using R. Now, i want to know how to test whether
my model is following the homoscadasticity and residuals being
random assumptions or not while fitting the model.
See ?lm. For accessing residuals, see ?residuals. Or use plot() on a lm
o
When you attach() something, it loads it into memory and there it
stays. It is not a link, reference, or pointer to the original.
Changing the original (the version in the dataframe), which is what
you did, does not change the attached copy in memory. In essence, you
did a type conversion on on
I'm running cluster analysis on a data frame but when I calculate the distance
I get this warning "NAs introduced by coercion". What does this mean?
[[alternative HTML version deleted]]
__
R-help
Thank you for the link to the 32 bit Windows Oracle downloads for the
Instant Client.
That solved the problem. I'm now able to connect to Oracle database from R
using the RODBC library.
Thank you Mark!
-Melanie
On Wed, Nov 18, 2009 at 6:23 PM, Marc Schwartz wrote:
> Just to clarify on your fi
On Nov 20, 2009, at 1:27 PM, David Winsemius wrote:
On Nov 20, 2009, at 11:07 AM, RWilliam wrote:
In reply to suggestion by David W., setting an offset parameter
doesn't seem
to work as R is not recognizing the "X2" part of coxph(
Surv(Time,Censor)~X1, offset=log(4.3*X2), data= a ). Als
I would like to analyze XML data from MLB's website. I do the following
steps:
library(XML)
dat<-"http://gd2.mlb.com/components/game/mlb/year_2007/month_05/day_02/gid_2007_05_02_arimlb_lanmlb_1/inning/inning_1.xml";
example<- xmlTreeParse(dat, useInternalNodes=T)
ex<-xpathApply(example, "//i
I'm working on Loess fit models using R, once I have the fit accomplished,
I'm looking to back-out the equation of the fitted non-linear curve,
wondering if there is a way to determine this equation in R? I've been
looking but can't find any literature. For me, the graph of the function is
great, b
Hi,
I need to have both italics and standard font on the y axis.
This is my script:
plot(x,y,pch=16,xlab="metric",ylab="species CPUE")
I want species in italics and CPUE in standard text.
Any tips would be appreciated.
Thanks.
--
View this message in context:
http://old.nabble.com/Different-
Hi Cleland and Dennis,
thanks a lot for the answer.
Ashok Varma
On Mon, Nov 23, 2009 at 5:05 PM, Chuck Cleland wrote:
> On 11/23/2009 1:06 AM, ashok varma wrote:
> > hello,
> >
> > i am fitting a Linear model using R. I have to fit the model considering
> all
> > the interaction effects of or
I'm running cluster analysis on a data frame but when I calculate the
distance I get this warning "NAs introduced by coercion". What does this
mean?
--
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Hello,
I am posting this to R-help and Ecolog-L, in hopes that enough Ecologgers are R
users and enough R-help users are ecologists. Please forgive the cross-posting.
I deleted a number of species from a canonical correspondence analysis (CCA)
model after using the function goodness.cca in veg
Tena koe Michelle
?plotmath
For your particular example, try:
plot(1:10, 1:10, pch=16, xlab="metric", ylab=quote(~italic(species)~ '
CPUE'))
Depending on your default font, you might need to set the family
argument of par():
par(family='serif')
HTH
Peter Alspach
> -Original Message
Here is the way you can use grepl to get the various combinations:
> mywords<- c("harry","met","sally","subway10","1800Movies","12345",
+ "not correct 123", "")
>
> numbers <- grepl("^[[:digit:]]+$", mywords)
> letters <- grepl("^[[:alpha:]]+$", mywords)
> both <- grepl("^[[:digit:][:alpha:]]+$",
On Nov 23, 2009, at 2:03 PM, Christian Miner wrote:
I'm working on Loess fit models using R, once I have the fit
accomplished,
I'm looking to back-out the equation of the fitted non-linear curve,
wondering if there is a way to determine this equation in R? I've been
looking but can't find any
Hi Christian,
Do you have a reference to a publication where this has been done?
All the best,
Tom
On Nov 23, 2009, at 10:15 AM, Christian Miner wrote:
> it's a tricky maneuver. When I finish the fit, the predict function
> will give me the values, and I can smooth this out so it looks like
Check out the loess.demo function in the TeachingDemos package. Using this
function with your data will show the scatterplot with the loess curve. Then
if you click in the plot it will show the line/curve used to do the prediction
for that x-value, click on another x-value and you will see tha
Hello, R gurus. I've been trying to get R to do some data manipulation
for me, and so far have been stumped in figuring out any elegant way
to do so. Searches through the R-help archive haven't helped, so now
I'm trying plan B.
Suppose I have a dataframe that summarizes events that took place
betw
Thanks Christian. The client is always right ...
Tom
On Nov 23, 2009, at 10:32 AM, Christian Miner wrote:
> sorry, I don't. I have data that I can estimate, but my client wants
> to "What if..." 20 separate scenarios, and that requires a function.
>
> On Mon, Nov 23, 2009 at 12:22 PM, Thomas
Hi Ashok,
You can try :
*shapiro.test(**my.lm$resid**)*
But I remember reading that "good" tests for the normality assumptions
(specifically that of the residuals), do not exist as we would have hoped
them to.
Good luck,
Tal
Contact
Details:---
This is very helpful. Thank you very much.
Charles C. Berry wrote:
>
> On Fri, 20 Nov 2009, newbyr wrote:
>
>>
>> Hi,
>>
>> I'm looking for a function that will take a list of columns or data.frame
>> and corvert it to cartesian pairlist. For example for this data.frame
>> (see
>> below), I'd
If the client is always right, then what do they need us for?
If you need a function to reproducibly generate predictions, then use loess to
generate a set of predictions for a reasonably dense set of x-values, then use
approxfun or splinefun to create a function to interpolate for you. Then th
Thanks, I'll try that. What is the output of approxfun?
On Mon, Nov 23, 2009 at 1:03 PM, Greg Snow wrote:
> If the client is always right, then what do they need us for?
>
> If you need a function to reproducibly generate predictions, then use loess
> to generate a set of predictions for a reaso
Hi Jack,
Jack Tanner wrote:
About 2 years ago, Tobias Verbeke asked:
"I am looking for a way to capture the binary string that in normal use of
graphics devices will bewritten to (most commonly) a file connection... Is there a
way of capturing the binary `jpeg string'
[generated by jpeg()]?"
approxfun returns a function, give this function an x-value and it will give
you the prediction (linear interpolation from the points that you gave to
approxfun). The splinefun function also returns a function, but it gives a
spline interpolation rather than a linear one.
--
Gregory (Greg) L.
What if you wanted to do this with multiple x's, multivariate, rather than
just 1 x variable?
On Mon, Nov 23, 2009 at 1:09 PM, Greg Snow wrote:
> approxfun returns a function, give this function an x-value and it will
> give you the prediction (linear interpolation from the points that you gave
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